Optimal. Leaf size=161 \[ -\frac{\left (a^2+3 b^2\right ) \cos ^5(c+d x)}{5 d}+\frac{\left (2 a^2+3 b^2\right ) \cos ^3(c+d x)}{3 d}-\frac{\left (a^2+b^2\right ) \cos (c+d x)}{d}-\frac{a b \sin ^5(c+d x) \cos (c+d x)}{3 d}-\frac{5 a b \sin ^3(c+d x) \cos (c+d x)}{12 d}-\frac{5 a b \sin (c+d x) \cos (c+d x)}{8 d}+\frac{5 a b x}{8}+\frac{b^2 \cos ^7(c+d x)}{7 d} \]
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Rubi [A] time = 0.269948, antiderivative size = 161, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 6, integrand size = 30, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {4393, 2789, 2635, 8, 3013, 373} \[ -\frac{\left (a^2+3 b^2\right ) \cos ^5(c+d x)}{5 d}+\frac{\left (2 a^2+3 b^2\right ) \cos ^3(c+d x)}{3 d}-\frac{\left (a^2+b^2\right ) \cos (c+d x)}{d}-\frac{a b \sin ^5(c+d x) \cos (c+d x)}{3 d}-\frac{5 a b \sin ^3(c+d x) \cos (c+d x)}{12 d}-\frac{5 a b \sin (c+d x) \cos (c+d x)}{8 d}+\frac{5 a b x}{8}+\frac{b^2 \cos ^7(c+d x)}{7 d} \]
Antiderivative was successfully verified.
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Rule 4393
Rule 2789
Rule 2635
Rule 8
Rule 3013
Rule 373
Rubi steps
\begin{align*} \int \sin (c+d x) \left (a \sin ^2(c+d x)+b \sin ^3(c+d x)\right )^2 \, dx &=\int \sin ^5(c+d x) (a+b \sin (c+d x))^2 \, dx\\ &=(2 a b) \int \sin ^6(c+d x) \, dx+\int \sin ^5(c+d x) \left (a^2+b^2 \sin ^2(c+d x)\right ) \, dx\\ &=-\frac{a b \cos (c+d x) \sin ^5(c+d x)}{3 d}+\frac{1}{3} (5 a b) \int \sin ^4(c+d x) \, dx-\frac{\operatorname{Subst}\left (\int \left (1-x^2\right )^2 \left (a^2+b^2-b^2 x^2\right ) \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac{5 a b \cos (c+d x) \sin ^3(c+d x)}{12 d}-\frac{a b \cos (c+d x) \sin ^5(c+d x)}{3 d}+\frac{1}{4} (5 a b) \int \sin ^2(c+d x) \, dx-\frac{\operatorname{Subst}\left (\int \left (a^2 \left (1+\frac{b^2}{a^2}\right )-\left (2 a^2+3 b^2\right ) x^2+\left (a^2+3 b^2\right ) x^4-b^2 x^6\right ) \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac{\left (a^2+b^2\right ) \cos (c+d x)}{d}+\frac{\left (2 a^2+3 b^2\right ) \cos ^3(c+d x)}{3 d}-\frac{\left (a^2+3 b^2\right ) \cos ^5(c+d x)}{5 d}+\frac{b^2 \cos ^7(c+d x)}{7 d}-\frac{5 a b \cos (c+d x) \sin (c+d x)}{8 d}-\frac{5 a b \cos (c+d x) \sin ^3(c+d x)}{12 d}-\frac{a b \cos (c+d x) \sin ^5(c+d x)}{3 d}+\frac{1}{8} (5 a b) \int 1 \, dx\\ &=\frac{5 a b x}{8}-\frac{\left (a^2+b^2\right ) \cos (c+d x)}{d}+\frac{\left (2 a^2+3 b^2\right ) \cos ^3(c+d x)}{3 d}-\frac{\left (a^2+3 b^2\right ) \cos ^5(c+d x)}{5 d}+\frac{b^2 \cos ^7(c+d x)}{7 d}-\frac{5 a b \cos (c+d x) \sin (c+d x)}{8 d}-\frac{5 a b \cos (c+d x) \sin ^3(c+d x)}{12 d}-\frac{a b \cos (c+d x) \sin ^5(c+d x)}{3 d}\\ \end{align*}
Mathematica [A] time = 0.208935, size = 134, normalized size = 0.83 \[ \frac{-525 \left (8 a^2+7 b^2\right ) \cos (c+d x)+35 \left (20 a^2+21 b^2\right ) \cos (3 (c+d x))-84 a^2 \cos (5 (c+d x))-3150 a b \sin (2 (c+d x))+630 a b \sin (4 (c+d x))-70 a b \sin (6 (c+d x))+4200 a b c+4200 a b d x-147 b^2 \cos (5 (c+d x))+15 b^2 \cos (7 (c+d x))}{6720 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.018, size = 125, normalized size = 0.8 \begin{align*}{\frac{1}{d} \left ( -{\frac{{b}^{2}\cos \left ( dx+c \right ) }{7} \left ({\frac{16}{5}}+ \left ( \sin \left ( dx+c \right ) \right ) ^{6}+{\frac{6\, \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{5}}+{\frac{8\, \left ( \sin \left ( dx+c \right ) \right ) ^{2}}{5}} \right ) }+2\,ab \left ( -1/6\, \left ( \left ( \sin \left ( dx+c \right ) \right ) ^{5}+5/4\, \left ( \sin \left ( dx+c \right ) \right ) ^{3}+{\frac{15\,\sin \left ( dx+c \right ) }{8}} \right ) \cos \left ( dx+c \right ) +{\frac{5\,dx}{16}}+{\frac{5\,c}{16}} \right ) -{\frac{{a}^{2}\cos \left ( dx+c \right ) }{5} \left ({\frac{8}{3}}+ \left ( \sin \left ( dx+c \right ) \right ) ^{4}+{\frac{4\, \left ( \sin \left ( dx+c \right ) \right ) ^{2}}{3}} \right ) } \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.971191, size = 177, normalized size = 1.1 \begin{align*} -\frac{224 \,{\left (3 \, \cos \left (d x + c\right )^{5} - 10 \, \cos \left (d x + c\right )^{3} + 15 \, \cos \left (d x + c\right )\right )} a^{2} - 35 \,{\left (4 \, \sin \left (2 \, d x + 2 \, c\right )^{3} + 60 \, d x + 60 \, c + 9 \, \sin \left (4 \, d x + 4 \, c\right ) - 48 \, \sin \left (2 \, d x + 2 \, c\right )\right )} a b - 96 \,{\left (5 \, \cos \left (d x + c\right )^{7} - 21 \, \cos \left (d x + c\right )^{5} + 35 \, \cos \left (d x + c\right )^{3} - 35 \, \cos \left (d x + c\right )\right )} b^{2}}{3360 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.30429, size = 321, normalized size = 1.99 \begin{align*} \frac{120 \, b^{2} \cos \left (d x + c\right )^{7} - 168 \,{\left (a^{2} + 3 \, b^{2}\right )} \cos \left (d x + c\right )^{5} + 525 \, a b d x + 280 \,{\left (2 \, a^{2} + 3 \, b^{2}\right )} \cos \left (d x + c\right )^{3} - 840 \,{\left (a^{2} + b^{2}\right )} \cos \left (d x + c\right ) - 35 \,{\left (8 \, a b \cos \left (d x + c\right )^{5} - 26 \, a b \cos \left (d x + c\right )^{3} + 33 \, a b \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{840 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 8.14724, size = 326, normalized size = 2.02 \begin{align*} \begin{cases} - \frac{a^{2} \sin ^{4}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{d} - \frac{4 a^{2} \sin ^{2}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{3 d} - \frac{8 a^{2} \cos ^{5}{\left (c + d x \right )}}{15 d} + \frac{5 a b x \sin ^{6}{\left (c + d x \right )}}{8} + \frac{15 a b x \sin ^{4}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{8} + \frac{15 a b x \sin ^{2}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{8} + \frac{5 a b x \cos ^{6}{\left (c + d x \right )}}{8} - \frac{11 a b \sin ^{5}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{8 d} - \frac{5 a b \sin ^{3}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{3 d} - \frac{5 a b \sin{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{8 d} - \frac{b^{2} \sin ^{6}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{d} - \frac{2 b^{2} \sin ^{4}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{d} - \frac{8 b^{2} \sin ^{2}{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{5 d} - \frac{16 b^{2} \cos ^{7}{\left (c + d x \right )}}{35 d} & \text{for}\: d \neq 0 \\x \left (a \sin ^{2}{\left (c \right )} + b \sin ^{3}{\left (c \right )}\right )^{2} \sin{\left (c \right )} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.12286, size = 193, normalized size = 1.2 \begin{align*} \frac{5}{8} \, a b x + \frac{b^{2} \cos \left (7 \, d x + 7 \, c\right )}{448 \, d} - \frac{a b \sin \left (6 \, d x + 6 \, c\right )}{96 \, d} + \frac{3 \, a b \sin \left (4 \, d x + 4 \, c\right )}{32 \, d} - \frac{15 \, a b \sin \left (2 \, d x + 2 \, c\right )}{32 \, d} - \frac{{\left (4 \, a^{2} + 7 \, b^{2}\right )} \cos \left (5 \, d x + 5 \, c\right )}{320 \, d} + \frac{{\left (20 \, a^{2} + 21 \, b^{2}\right )} \cos \left (3 \, d x + 3 \, c\right )}{192 \, d} - \frac{5 \,{\left (8 \, a^{2} + 7 \, b^{2}\right )} \cos \left (d x + c\right )}{64 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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