Optimal. Leaf size=43 \[ -\frac{49}{5} \sin ^5(x)-\frac{49 \sin ^3(x)}{3}+63 \sin ^2(x)-49 \sin (x)-2 \log (1-\sin (x))+128 \log (\sin (x)+1) \]
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Rubi [A] time = 0.115741, antiderivative size = 43, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.217, Rules used = {3175, 3223, 1810, 633, 31} \[ -\frac{49}{5} \sin ^5(x)-\frac{49 \sin ^3(x)}{3}+63 \sin ^2(x)-49 \sin (x)-2 \log (1-\sin (x))+128 \log (\sin (x)+1) \]
Antiderivative was successfully verified.
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Rule 3175
Rule 3223
Rule 1810
Rule 633
Rule 31
Rubi steps
\begin{align*} \int \frac{\cos (x) \left (9-7 \sin ^3(x)\right )^2}{1-\sin ^2(x)} \, dx &=\int \sec (x) \left (9-7 \sin ^3(x)\right )^2 \, dx\\ &=\operatorname{Subst}\left (\int \frac{\left (9-7 x^3\right )^2}{1-x^2} \, dx,x,\sin (x)\right )\\ &=\operatorname{Subst}\left (\int \left (-49+126 x-49 x^2-49 x^4+\frac{2 (65-63 x)}{1-x^2}\right ) \, dx,x,\sin (x)\right )\\ &=-49 \sin (x)+63 \sin ^2(x)-\frac{49 \sin ^3(x)}{3}-\frac{49 \sin ^5(x)}{5}+2 \operatorname{Subst}\left (\int \frac{65-63 x}{1-x^2} \, dx,x,\sin (x)\right )\\ &=-49 \sin (x)+63 \sin ^2(x)-\frac{49 \sin ^3(x)}{3}-\frac{49 \sin ^5(x)}{5}+2 \operatorname{Subst}\left (\int \frac{1}{1-x} \, dx,x,\sin (x)\right )-128 \operatorname{Subst}\left (\int \frac{1}{-1-x} \, dx,x,\sin (x)\right )\\ &=-2 \log (1-\sin (x))+128 \log (1+\sin (x))-49 \sin (x)+63 \sin ^2(x)-\frac{49 \sin ^3(x)}{3}-\frac{49 \sin ^5(x)}{5}\\ \end{align*}
Mathematica [A] time = 0.0220506, size = 71, normalized size = 1.65 \[ -\frac{49}{5} \sin ^5(x)-\frac{49 \sin ^3(x)}{3}-49 \sin (x)-63 \cos ^2(x)+49 \tanh ^{-1}(\sin (x))+126 \log (\cos (x))-81 \log \left (\cos \left (\frac{x}{2}\right )-\sin \left (\frac{x}{2}\right )\right )+81 \log \left (\sin \left (\frac{x}{2}\right )+\cos \left (\frac{x}{2}\right )\right ) \]
Antiderivative was successfully verified.
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Maple [A] time = 0.024, size = 38, normalized size = 0.9 \begin{align*} -{\frac{49\, \left ( \sin \left ( x \right ) \right ) ^{5}}{5}}-{\frac{49\, \left ( \sin \left ( x \right ) \right ) ^{3}}{3}}+63\, \left ( \sin \left ( x \right ) \right ) ^{2}-49\,\sin \left ( x \right ) -2\,\ln \left ( \sin \left ( x \right ) -1 \right ) +128\,\ln \left ( 1+\sin \left ( x \right ) \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.94411, size = 50, normalized size = 1.16 \begin{align*} -\frac{49}{5} \, \sin \left (x\right )^{5} - \frac{49}{3} \, \sin \left (x\right )^{3} + 63 \, \sin \left (x\right )^{2} + 128 \, \log \left (\sin \left (x\right ) + 1\right ) - 2 \, \log \left (\sin \left (x\right ) - 1\right ) - 49 \, \sin \left (x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.23806, size = 140, normalized size = 3.26 \begin{align*} -63 \, \cos \left (x\right )^{2} - \frac{49}{15} \,{\left (3 \, \cos \left (x\right )^{4} - 11 \, \cos \left (x\right )^{2} + 23\right )} \sin \left (x\right ) + 128 \, \log \left (\sin \left (x\right ) + 1\right ) - 2 \, \log \left (-\sin \left (x\right ) + 1\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 4.25094, size = 44, normalized size = 1.02 \begin{align*} - 2 \log{\left (\sin{\left (x \right )} - 1 \right )} + 128 \log{\left (\sin{\left (x \right )} + 1 \right )} - \frac{49 \sin ^{5}{\left (x \right )}}{5} - \frac{49 \sin ^{3}{\left (x \right )}}{3} - 49 \sin{\left (x \right )} - 63 \cos ^{2}{\left (x \right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.11644, size = 53, normalized size = 1.23 \begin{align*} -\frac{49}{5} \, \sin \left (x\right )^{5} - \frac{49}{3} \, \sin \left (x\right )^{3} + 63 \, \sin \left (x\right )^{2} + 128 \, \log \left (\sin \left (x\right ) + 1\right ) - 2 \, \log \left (-\sin \left (x\right ) + 1\right ) - 49 \, \sin \left (x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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