Optimal. Leaf size=157 \[ \frac{c \tan (2 a+2 b x) \sec ^3(2 a+2 b x)}{7 b \sqrt{c \sec (2 a+2 b x)-c}}-\frac{6 \tan (2 a+2 b x) (c \sec (2 a+2 b x)-c)^{3/2}}{35 b c}-\frac{4 \tan (2 a+2 b x) \sqrt{c \sec (2 a+2 b x)-c}}{35 b}-\frac{2 c \tan (2 a+2 b x)}{5 b \sqrt{c \sec (2 a+2 b x)-c}} \]
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Rubi [A] time = 0.445167, antiderivative size = 157, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.161, Rules used = {4397, 3803, 3800, 4001, 3792} \[ \frac{c \tan (2 a+2 b x) \sec ^3(2 a+2 b x)}{7 b \sqrt{c \sec (2 a+2 b x)-c}}-\frac{6 \tan (2 a+2 b x) (c \sec (2 a+2 b x)-c)^{3/2}}{35 b c}-\frac{4 \tan (2 a+2 b x) \sqrt{c \sec (2 a+2 b x)-c}}{35 b}-\frac{2 c \tan (2 a+2 b x)}{5 b \sqrt{c \sec (2 a+2 b x)-c}} \]
Antiderivative was successfully verified.
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Rule 4397
Rule 3803
Rule 3800
Rule 4001
Rule 3792
Rubi steps
\begin{align*} \int \sec ^4(2 (a+b x)) \sqrt{c \tan (a+b x) \tan (2 (a+b x))} \, dx &=\int \sec ^4(2 a+2 b x) \sqrt{-c+c \sec (2 a+2 b x)} \, dx\\ &=\frac{c \sec ^3(2 a+2 b x) \tan (2 a+2 b x)}{7 b \sqrt{-c+c \sec (2 a+2 b x)}}-\frac{6}{7} \int \sec ^3(2 a+2 b x) \sqrt{-c+c \sec (2 a+2 b x)} \, dx\\ &=\frac{c \sec ^3(2 a+2 b x) \tan (2 a+2 b x)}{7 b \sqrt{-c+c \sec (2 a+2 b x)}}-\frac{6 (-c+c \sec (2 a+2 b x))^{3/2} \tan (2 a+2 b x)}{35 b c}-\frac{12 \int \sec (2 a+2 b x) \sqrt{-c+c \sec (2 a+2 b x)} \left (\frac{3 c}{2}+c \sec (2 a+2 b x)\right ) \, dx}{35 c}\\ &=\frac{c \sec ^3(2 a+2 b x) \tan (2 a+2 b x)}{7 b \sqrt{-c+c \sec (2 a+2 b x)}}-\frac{4 \sqrt{-c+c \sec (2 a+2 b x)} \tan (2 a+2 b x)}{35 b}-\frac{6 (-c+c \sec (2 a+2 b x))^{3/2} \tan (2 a+2 b x)}{35 b c}-\frac{2}{5} \int \sec (2 a+2 b x) \sqrt{-c+c \sec (2 a+2 b x)} \, dx\\ &=-\frac{2 c \tan (2 a+2 b x)}{5 b \sqrt{-c+c \sec (2 a+2 b x)}}+\frac{c \sec ^3(2 a+2 b x) \tan (2 a+2 b x)}{7 b \sqrt{-c+c \sec (2 a+2 b x)}}-\frac{4 \sqrt{-c+c \sec (2 a+2 b x)} \tan (2 a+2 b x)}{35 b}-\frac{6 (-c+c \sec (2 a+2 b x))^{3/2} \tan (2 a+2 b x)}{35 b c}\\ \end{align*}
Mathematica [A] time = 0.234057, size = 64, normalized size = 0.41 \[ -\frac{(7 \cos (3 (a+b x))+2 \cos (7 (a+b x))) \csc (a+b x) \sec ^3(2 (a+b x)) \sqrt{c \tan (a+b x) \tan (2 (a+b x))}}{35 b} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.642, size = 98, normalized size = 0.6 \begin{align*} -{\frac{\sqrt{2}\sqrt{4}\cos \left ( bx+a \right ) \left ( 128\, \left ( \cos \left ( bx+a \right ) \right ) ^{6}-224\, \left ( \cos \left ( bx+a \right ) \right ) ^{4}+140\, \left ( \cos \left ( bx+a \right ) \right ) ^{2}-35 \right ) }{70\,b\sin \left ( bx+a \right ) \left ( 2\, \left ( \cos \left ( bx+a \right ) \right ) ^{2}-1 \right ) ^{3}}\sqrt{{\frac{c \left ( \sin \left ( bx+a \right ) \right ) ^{2}}{2\, \left ( \cos \left ( bx+a \right ) \right ) ^{2}-1}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.05686, size = 273, normalized size = 1.74 \begin{align*} -\frac{\sqrt{2}{\left (35 \, \tan \left (b x + a\right )^{6} - 35 \, \tan \left (b x + a\right )^{4} + 49 \, \tan \left (b x + a\right )^{2} - 9\right )} \sqrt{-\frac{c \tan \left (b x + a\right )^{2}}{\tan \left (b x + a\right )^{2} - 1}}}{35 \,{\left (b \tan \left (b x + a\right )^{7} - 3 \, b \tan \left (b x + a\right )^{5} + 3 \, b \tan \left (b x + a\right )^{3} - b \tan \left (b x + a\right )\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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