3.49 \(\int \frac{x \cos (\sqrt{3} \sqrt{2+x^2})}{\sqrt{2+x^2}} \, dx\)

Optimal. Leaf size=22 \[ \frac{\sin \left (\sqrt{3} \sqrt{x^2+2}\right )}{\sqrt{3}} \]

[Out]

Sin[Sqrt[3]*Sqrt[2 + x^2]]/Sqrt[3]

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Rubi [A]  time = 0.189288, antiderivative size = 22, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.148, Rules used = {6715, 3432, 15, 2637} \[ \frac{\sin \left (\sqrt{3} \sqrt{x^2+2}\right )}{\sqrt{3}} \]

Antiderivative was successfully verified.

[In]

Int[(x*Cos[Sqrt[3]*Sqrt[2 + x^2]])/Sqrt[2 + x^2],x]

[Out]

Sin[Sqrt[3]*Sqrt[2 + x^2]]/Sqrt[3]

Rule 6715

Int[(u_)*(x_)^(m_.), x_Symbol] :> Dist[1/(m + 1), Subst[Int[SubstFor[x^(m + 1), u, x], x], x, x^(m + 1)], x] /
; FreeQ[m, x] && NeQ[m, -1] && FunctionOfQ[x^(m + 1), u, x]

Rule 3432

Int[((a_.) + Cos[(c_.) + (d_.)*((e_.) + (f_.)*(x_))^(n_)]*(b_.))^(p_.)*((g_.) + (h_.)*(x_))^(m_.), x_Symbol] :
> Dist[1/(n*f), Subst[Int[ExpandIntegrand[(a + b*Cos[c + d*x])^p, x^(1/n - 1)*(g - (e*h)/f + (h*x^(1/n))/f)^m,
x], x], x, (e + f*x)^n], x] /; FreeQ[{a, b, c, d, e, f, g, h, m}, x] && IGtQ[p, 0] && IntegerQ[1/n]

Rule 15

Int[(u_.)*((a_.)*(x_)^(n_))^(m_), x_Symbol] :> Dist[(a^IntPart[m]*(a*x^n)^FracPart[m])/x^(n*FracPart[m]), Int[
u*x^(m*n), x], x] /; FreeQ[{a, m, n}, x] &&  !IntegerQ[m]

Rule 2637

Int[sin[Pi/2 + (c_.) + (d_.)*(x_)], x_Symbol] :> Simp[Sin[c + d*x]/d, x] /; FreeQ[{c, d}, x]

Rubi steps

\begin{align*} \int \frac{x \cos \left (\sqrt{3} \sqrt{2+x^2}\right )}{\sqrt{2+x^2}} \, dx &=\frac{1}{2} \operatorname{Subst}\left (\int \frac{\cos \left (\sqrt{3} \sqrt{2+x}\right )}{\sqrt{2+x}} \, dx,x,x^2\right )\\ &=\operatorname{Subst}\left (\int \frac{x \cos \left (\sqrt{3} x\right )}{\sqrt{x^2}} \, dx,x,\sqrt{2+x^2}\right )\\ &=1 \operatorname{Subst}\left (\int \cos \left (\sqrt{3} x\right ) \, dx,x,\sqrt{2+x^2}\right )\\ &=\frac{\sin \left (\sqrt{3} \sqrt{2+x^2}\right )}{\sqrt{3}}\\ \end{align*}

Mathematica [A]  time = 0.0526874, size = 22, normalized size = 1. \[ \frac{\sin \left (\sqrt{3} \sqrt{x^2+2}\right )}{\sqrt{3}} \]

Antiderivative was successfully verified.

[In]

Integrate[(x*Cos[Sqrt[3]*Sqrt[2 + x^2]])/Sqrt[2 + x^2],x]

[Out]

Sin[Sqrt[3]*Sqrt[2 + x^2]]/Sqrt[3]

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Maple [A]  time = 0.015, size = 18, normalized size = 0.8 \begin{align*}{\frac{\sqrt{3}}{3}\sin \left ( \sqrt{3}\sqrt{{x}^{2}+2} \right ) } \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*cos(3^(1/2)*(x^2+2)^(1/2))/(x^2+2)^(1/2),x)

[Out]

1/3*sin(3^(1/2)*(x^2+2)^(1/2))*3^(1/2)

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Maxima [A]  time = 1.59016, size = 23, normalized size = 1.05 \begin{align*} \frac{1}{3} \, \sqrt{3} \sin \left (\sqrt{3} \sqrt{x^{2} + 2}\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*cos(3^(1/2)*(x^2+2)^(1/2))/(x^2+2)^(1/2),x, algorithm="maxima")

[Out]

1/3*sqrt(3)*sin(sqrt(3)*sqrt(x^2 + 2))

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Fricas [B]  time = 2.33569, size = 112, normalized size = 5.09 \begin{align*} \frac{2 \, \sqrt{3} \tan \left (\frac{1}{2} \, \sqrt{3} \sqrt{x^{2} + 2}\right )}{3 \,{\left (\tan \left (\frac{1}{2} \, \sqrt{3} \sqrt{x^{2} + 2}\right )^{2} + 1\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*cos(3^(1/2)*(x^2+2)^(1/2))/(x^2+2)^(1/2),x, algorithm="fricas")

[Out]

2/3*sqrt(3)*tan(1/2*sqrt(3)*sqrt(x^2 + 2))/(tan(1/2*sqrt(3)*sqrt(x^2 + 2))^2 + 1)

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Sympy [A]  time = 1.58456, size = 20, normalized size = 0.91 \begin{align*} \frac{\sqrt{3} \sin{\left (\sqrt{3} \sqrt{x^{2} + 2} \right )}}{3} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*cos(3**(1/2)*(x**2+2)**(1/2))/(x**2+2)**(1/2),x)

[Out]

sqrt(3)*sin(sqrt(3)*sqrt(x**2 + 2))/3

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Giac [A]  time = 1.09903, size = 23, normalized size = 1.05 \begin{align*} \frac{1}{3} \, \sqrt{3} \sin \left (\sqrt{3} \sqrt{x^{2} + 2}\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*cos(3^(1/2)*(x^2+2)^(1/2))/(x^2+2)^(1/2),x, algorithm="giac")

[Out]

1/3*sqrt(3)*sin(sqrt(3)*sqrt(x^2 + 2))