Optimal. Leaf size=51 \[ -\frac{2 \tanh ^{-1}\left (\frac{a-(b-c) \tan \left (\frac{x}{2}\right )}{\sqrt{a^2+b^2-c^2}}\right )}{\sqrt{a^2+b^2-c^2}} \]
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Rubi [A] time = 0.0717676, antiderivative size = 51, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.267, Rules used = {3166, 3124, 618, 206} \[ -\frac{2 \tanh ^{-1}\left (\frac{a-(b-c) \tan \left (\frac{x}{2}\right )}{\sqrt{a^2+b^2-c^2}}\right )}{\sqrt{a^2+b^2-c^2}} \]
Antiderivative was successfully verified.
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Rule 3166
Rule 3124
Rule 618
Rule 206
Rubi steps
\begin{align*} \int \frac{\csc (x)}{a+b \cot (x)+c \csc (x)} \, dx &=\int \frac{1}{c+b \cos (x)+a \sin (x)} \, dx\\ &=2 \operatorname{Subst}\left (\int \frac{1}{b+c+2 a x+(-b+c) x^2} \, dx,x,\tan \left (\frac{x}{2}\right )\right )\\ &=-\left (4 \operatorname{Subst}\left (\int \frac{1}{4 \left (a^2+b^2-c^2\right )-x^2} \, dx,x,2 a+2 (-b+c) \tan \left (\frac{x}{2}\right )\right )\right )\\ &=-\frac{2 \tanh ^{-1}\left (\frac{a-(b-c) \tan \left (\frac{x}{2}\right )}{\sqrt{a^2+b^2-c^2}}\right )}{\sqrt{a^2+b^2-c^2}}\\ \end{align*}
Mathematica [A] time = 0.0459554, size = 50, normalized size = 0.98 \[ -\frac{2 \tanh ^{-1}\left (\frac{a+(c-b) \tan \left (\frac{x}{2}\right )}{\sqrt{a^2+b^2-c^2}}\right )}{\sqrt{a^2+b^2-c^2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.042, size = 53, normalized size = 1. \begin{align*} -2\,{\frac{1}{\sqrt{-{a}^{2}-{b}^{2}+{c}^{2}}}\arctan \left ( 1/2\,{\frac{2\, \left ( b-c \right ) \tan \left ( x/2 \right ) -2\,a}{\sqrt{-{a}^{2}-{b}^{2}+{c}^{2}}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.1668, size = 799, normalized size = 15.67 \begin{align*} \left [\frac{\log \left (-\frac{a^{4} + 3 \, a^{2} b^{2} + 2 \, b^{4} +{\left (a^{2} - b^{2}\right )} c^{2} + 2 \,{\left (a^{2} b + b^{3}\right )} c \cos \left (x\right ) +{\left (a^{4} - b^{4} - 2 \,{\left (a^{2} - b^{2}\right )} c^{2}\right )} \cos \left (x\right )^{2} + 2 \,{\left ({\left (a^{3} + a b^{2}\right )} c -{\left (a^{3} b + a b^{3} - 2 \, a b c^{2}\right )} \cos \left (x\right )\right )} \sin \left (x\right ) - 2 \,{\left (2 \, a b c \cos \left (x\right )^{2} - a b c +{\left (a^{3} + a b^{2}\right )} \cos \left (x\right ) -{\left (a^{2} b + b^{3} -{\left (a^{2} - b^{2}\right )} c \cos \left (x\right )\right )} \sin \left (x\right )\right )} \sqrt{a^{2} + b^{2} - c^{2}}}{2 \, b c \cos \left (x\right ) -{\left (a^{2} - b^{2}\right )} \cos \left (x\right )^{2} + a^{2} + c^{2} + 2 \,{\left (a b \cos \left (x\right ) + a c\right )} \sin \left (x\right )}\right )}{2 \, \sqrt{a^{2} + b^{2} - c^{2}}}, \frac{\sqrt{-a^{2} - b^{2} + c^{2}} \arctan \left (\frac{{\left (b c \cos \left (x\right ) + a c \sin \left (x\right ) + a^{2} + b^{2}\right )} \sqrt{-a^{2} - b^{2} + c^{2}}}{{\left (a^{3} + a b^{2} - a c^{2}\right )} \cos \left (x\right ) -{\left (a^{2} b + b^{3} - b c^{2}\right )} \sin \left (x\right )}\right )}{a^{2} + b^{2} - c^{2}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\csc{\left (x \right )}}{a + b \cot{\left (x \right )} + c \csc{\left (x \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.17391, size = 99, normalized size = 1.94 \begin{align*} -\frac{2 \,{\left (\pi \left \lfloor \frac{x}{2 \, \pi } + \frac{1}{2} \right \rfloor \mathrm{sgn}\left (2 \, b - 2 \, c\right ) + \arctan \left (\frac{b \tan \left (\frac{1}{2} \, x\right ) - c \tan \left (\frac{1}{2} \, x\right ) - a}{\sqrt{-a^{2} - b^{2} + c^{2}}}\right )\right )}}{\sqrt{-a^{2} - b^{2} + c^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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