Optimal. Leaf size=170 \[ \frac{b \left (11 a^2+4 \left (b^2+c^2\right )\right ) \sin (d+e x)}{6 e}-\frac{c \left (11 a^2+4 \left (b^2+c^2\right )\right ) \cos (d+e x)}{6 e}+\frac{1}{2} a x \left (2 a^2+3 \left (b^2+c^2\right )\right )-\frac{(c \cos (d+e x)-b \sin (d+e x)) (a+b \cos (d+e x)+c \sin (d+e x))^2}{3 e}-\frac{5 (a c \cos (d+e x)-a b \sin (d+e x)) (a+b \cos (d+e x)+c \sin (d+e x))}{6 e} \]
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Rubi [A] time = 0.186289, antiderivative size = 170, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {3120, 3146, 2637, 2638} \[ \frac{b \left (11 a^2+4 \left (b^2+c^2\right )\right ) \sin (d+e x)}{6 e}-\frac{c \left (11 a^2+4 \left (b^2+c^2\right )\right ) \cos (d+e x)}{6 e}+\frac{1}{2} a x \left (2 a^2+3 \left (b^2+c^2\right )\right )-\frac{(c \cos (d+e x)-b \sin (d+e x)) (a+b \cos (d+e x)+c \sin (d+e x))^2}{3 e}-\frac{5 (a c \cos (d+e x)-a b \sin (d+e x)) (a+b \cos (d+e x)+c \sin (d+e x))}{6 e} \]
Antiderivative was successfully verified.
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Rule 3120
Rule 3146
Rule 2637
Rule 2638
Rubi steps
\begin{align*} \int (a+b \cos (d+e x)+c \sin (d+e x))^3 \, dx &=-\frac{(c \cos (d+e x)-b \sin (d+e x)) (a+b \cos (d+e x)+c \sin (d+e x))^2}{3 e}+\frac{1}{3} \int (a+b \cos (d+e x)+c \sin (d+e x)) \left (3 a^2+2 \left (b^2+c^2\right )+5 a b \cos (d+e x)+5 a c \sin (d+e x)\right ) \, dx\\ &=-\frac{5 (a c \cos (d+e x)-a b \sin (d+e x)) (a+b \cos (d+e x)+c \sin (d+e x))}{6 e}-\frac{(c \cos (d+e x)-b \sin (d+e x)) (a+b \cos (d+e x)+c \sin (d+e x))^2}{3 e}+\frac{\int \left (3 a^2 \left (2 a^2+3 \left (b^2+c^2\right )\right )+a b \left (11 a^2+4 \left (b^2+c^2\right )\right ) \cos (d+e x)+a c \left (11 a^2+4 \left (b^2+c^2\right )\right ) \sin (d+e x)\right ) \, dx}{6 a}\\ &=\frac{1}{2} a \left (2 a^2+3 \left (b^2+c^2\right )\right ) x-\frac{5 (a c \cos (d+e x)-a b \sin (d+e x)) (a+b \cos (d+e x)+c \sin (d+e x))}{6 e}-\frac{(c \cos (d+e x)-b \sin (d+e x)) (a+b \cos (d+e x)+c \sin (d+e x))^2}{3 e}+\frac{1}{6} \left (b \left (11 a^2+4 \left (b^2+c^2\right )\right )\right ) \int \cos (d+e x) \, dx+\frac{1}{6} \left (c \left (11 a^2+4 \left (b^2+c^2\right )\right )\right ) \int \sin (d+e x) \, dx\\ &=\frac{1}{2} a \left (2 a^2+3 \left (b^2+c^2\right )\right ) x-\frac{c \left (11 a^2+4 \left (b^2+c^2\right )\right ) \cos (d+e x)}{6 e}+\frac{b \left (11 a^2+4 \left (b^2+c^2\right )\right ) \sin (d+e x)}{6 e}-\frac{5 (a c \cos (d+e x)-a b \sin (d+e x)) (a+b \cos (d+e x)+c \sin (d+e x))}{6 e}-\frac{(c \cos (d+e x)-b \sin (d+e x)) (a+b \cos (d+e x)+c \sin (d+e x))^2}{3 e}\\ \end{align*}
Mathematica [A] time = 0.437597, size = 144, normalized size = 0.85 \[ \frac{6 a \left (2 a^2+3 \left (b^2+c^2\right )\right ) (d+e x)+9 b \left (4 a^2+b^2+c^2\right ) \sin (d+e x)-9 c \left (4 a^2+b^2+c^2\right ) \cos (d+e x)+9 a \left (b^2-c^2\right ) \sin (2 (d+e x))-18 a b c \cos (2 (d+e x))+b \left (b^2-3 c^2\right ) \sin (3 (d+e x))+c \left (c^2-3 b^2\right ) \cos (3 (d+e x))}{12 e} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.06, size = 177, normalized size = 1. \begin{align*}{\frac{1}{e} \left ({a}^{3} \left ( ex+d \right ) +3\,\sin \left ( ex+d \right ){a}^{2}b-3\,{a}^{2}c\cos \left ( ex+d \right ) +3\,a{b}^{2} \left ( 1/2\,\sin \left ( ex+d \right ) \cos \left ( ex+d \right ) +1/2\,ex+d/2 \right ) -3\,abc \left ( \cos \left ( ex+d \right ) \right ) ^{2}+3\,a{c}^{2} \left ( -1/2\,\sin \left ( ex+d \right ) \cos \left ( ex+d \right ) +1/2\,ex+d/2 \right ) +{\frac{{b}^{3} \left ( 2+ \left ( \cos \left ( ex+d \right ) \right ) ^{2} \right ) \sin \left ( ex+d \right ) }{3}}- \left ( \cos \left ( ex+d \right ) \right ) ^{3}{b}^{2}c+b{c}^{2} \left ( \sin \left ( ex+d \right ) \right ) ^{3}-{\frac{{c}^{3} \left ( 2+ \left ( \sin \left ( ex+d \right ) \right ) ^{2} \right ) \cos \left ( ex+d \right ) }{3}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.998739, size = 255, normalized size = 1.5 \begin{align*} -\frac{b^{2} c \cos \left (e x + d\right )^{3}}{e} + \frac{b c^{2} \sin \left (e x + d\right )^{3}}{e} + a^{3} x - \frac{{\left (\sin \left (e x + d\right )^{3} - 3 \, \sin \left (e x + d\right )\right )} b^{3}}{3 \, e} + \frac{{\left (\cos \left (e x + d\right )^{3} - 3 \, \cos \left (e x + d\right )\right )} c^{3}}{3 \, e} - 3 \, a^{2}{\left (\frac{c \cos \left (e x + d\right )}{e} - \frac{b \sin \left (e x + d\right )}{e}\right )} - \frac{3}{4} \,{\left (\frac{4 \, b c \cos \left (e x + d\right )^{2}}{e} - \frac{{\left (2 \, e x + 2 \, d + \sin \left (2 \, e x + 2 \, d\right )\right )} b^{2}}{e} - \frac{{\left (2 \, e x + 2 \, d - \sin \left (2 \, e x + 2 \, d\right )\right )} c^{2}}{e}\right )} a \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.22173, size = 338, normalized size = 1.99 \begin{align*} -\frac{18 \, a b c \cos \left (e x + d\right )^{2} + 2 \,{\left (3 \, b^{2} c - c^{3}\right )} \cos \left (e x + d\right )^{3} - 3 \,{\left (2 \, a^{3} + 3 \, a b^{2} + 3 \, a c^{2}\right )} e x + 6 \,{\left (3 \, a^{2} c + c^{3}\right )} \cos \left (e x + d\right ) -{\left (18 \, a^{2} b + 4 \, b^{3} + 6 \, b c^{2} + 2 \,{\left (b^{3} - 3 \, b c^{2}\right )} \cos \left (e x + d\right )^{2} + 9 \,{\left (a b^{2} - a c^{2}\right )} \cos \left (e x + d\right )\right )} \sin \left (e x + d\right )}{6 \, e} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 0.90262, size = 294, normalized size = 1.73 \begin{align*} \begin{cases} a^{3} x + \frac{3 a^{2} b \sin{\left (d + e x \right )}}{e} - \frac{3 a^{2} c \cos{\left (d + e x \right )}}{e} + \frac{3 a b^{2} x \sin ^{2}{\left (d + e x \right )}}{2} + \frac{3 a b^{2} x \cos ^{2}{\left (d + e x \right )}}{2} + \frac{3 a b^{2} \sin{\left (d + e x \right )} \cos{\left (d + e x \right )}}{2 e} + \frac{3 a b c \sin ^{2}{\left (d + e x \right )}}{e} + \frac{3 a c^{2} x \sin ^{2}{\left (d + e x \right )}}{2} + \frac{3 a c^{2} x \cos ^{2}{\left (d + e x \right )}}{2} - \frac{3 a c^{2} \sin{\left (d + e x \right )} \cos{\left (d + e x \right )}}{2 e} + \frac{2 b^{3} \sin ^{3}{\left (d + e x \right )}}{3 e} + \frac{b^{3} \sin{\left (d + e x \right )} \cos ^{2}{\left (d + e x \right )}}{e} - \frac{b^{2} c \cos ^{3}{\left (d + e x \right )}}{e} + \frac{b c^{2} \sin ^{3}{\left (d + e x \right )}}{e} - \frac{c^{3} \sin ^{2}{\left (d + e x \right )} \cos{\left (d + e x \right )}}{e} - \frac{2 c^{3} \cos ^{3}{\left (d + e x \right )}}{3 e} & \text{for}\: e \neq 0 \\x \left (a + b \cos{\left (d \right )} + c \sin{\left (d \right )}\right )^{3} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.1238, size = 225, normalized size = 1.32 \begin{align*} -\frac{3}{2} \, a b c \cos \left (2 \, x e + 2 \, d\right ) e^{\left (-1\right )} - \frac{1}{12} \,{\left (3 \, b^{2} c - c^{3}\right )} \cos \left (3 \, x e + 3 \, d\right ) e^{\left (-1\right )} - \frac{3}{4} \,{\left (4 \, a^{2} c + b^{2} c + c^{3}\right )} \cos \left (x e + d\right ) e^{\left (-1\right )} + \frac{1}{12} \,{\left (b^{3} - 3 \, b c^{2}\right )} e^{\left (-1\right )} \sin \left (3 \, x e + 3 \, d\right ) + \frac{3}{4} \,{\left (a b^{2} - a c^{2}\right )} e^{\left (-1\right )} \sin \left (2 \, x e + 2 \, d\right ) + \frac{3}{4} \,{\left (4 \, a^{2} b + b^{3} + b c^{2}\right )} e^{\left (-1\right )} \sin \left (x e + d\right ) + \frac{1}{2} \,{\left (2 \, a^{3} + 3 \, a b^{2} + 3 \, a c^{2}\right )} x \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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