Optimal. Leaf size=83 \[ \frac{a \log \left (a+b \cot \left (\frac{d}{2}+\frac{e x}{2}+\frac{\pi }{4}\right )\right )}{4 b^3 e}-\frac{a \cos (d+e x)-b \sin (d+e x)}{4 b^2 e (a \sin (d+e x)+a+b \cos (d+e x))} \]
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Rubi [A] time = 0.0495658, antiderivative size = 83, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.167, Rules used = {3129, 12, 3123, 31} \[ \frac{a \log \left (a+b \cot \left (\frac{d}{2}+\frac{e x}{2}+\frac{\pi }{4}\right )\right )}{4 b^3 e}-\frac{a \cos (d+e x)-b \sin (d+e x)}{4 b^2 e (a \sin (d+e x)+a+b \cos (d+e x))} \]
Antiderivative was successfully verified.
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Rule 3129
Rule 12
Rule 3123
Rule 31
Rubi steps
\begin{align*} \int \frac{1}{(2 a+2 b \cos (d+e x)+2 a \sin (d+e x))^2} \, dx &=-\frac{a \cos (d+e x)-b \sin (d+e x)}{4 b^2 e (a+b \cos (d+e x)+a \sin (d+e x))}+\frac{\int -\frac{2 a}{2 a+2 b \cos (d+e x)+2 a \sin (d+e x)} \, dx}{4 b^2}\\ &=-\frac{a \cos (d+e x)-b \sin (d+e x)}{4 b^2 e (a+b \cos (d+e x)+a \sin (d+e x))}-\frac{a \int \frac{1}{2 a+2 b \cos (d+e x)+2 a \sin (d+e x)} \, dx}{2 b^2}\\ &=-\frac{a \cos (d+e x)-b \sin (d+e x)}{4 b^2 e (a+b \cos (d+e x)+a \sin (d+e x))}+\frac{a \operatorname{Subst}\left (\int \frac{1}{2 a+2 b x} \, dx,x,\cot \left (\frac{\pi }{4}+\frac{1}{2} (d+e x)\right )\right )}{2 b^2 e}\\ &=\frac{a \log \left (a+b \cot \left (\frac{d}{2}+\frac{\pi }{4}+\frac{e x}{2}\right )\right )}{4 b^3 e}-\frac{a \cos (d+e x)-b \sin (d+e x)}{4 b^2 e (a+b \cos (d+e x)+a \sin (d+e x))}\\ \end{align*}
Mathematica [A] time = 0.506601, size = 162, normalized size = 1.95 \[ \frac{\frac{b \left (a^2+b^2\right ) \sin \left (\frac{1}{2} (d+e x)\right )}{(a+b) \left ((a-b) \sin \left (\frac{1}{2} (d+e x)\right )+(a+b) \cos \left (\frac{1}{2} (d+e x)\right )\right )}+a \log \left ((a-b) \sin \left (\frac{1}{2} (d+e x)\right )+(a+b) \cos \left (\frac{1}{2} (d+e x)\right )\right )-a \log \left (\sin \left (\frac{1}{2} (d+e x)\right )+\cos \left (\frac{1}{2} (d+e x)\right )\right )+\frac{b \sin \left (\frac{1}{2} (d+e x)\right )}{\sin \left (\frac{1}{2} (d+e x)\right )+\cos \left (\frac{1}{2} (d+e x)\right )}}{4 b^3 e} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.162, size = 166, normalized size = 2. \begin{align*} -{\frac{1}{4\,{b}^{2}e} \left ( 1+\tan \left ({\frac{d}{2}}+{\frac{ex}{2}} \right ) \right ) ^{-1}}-{\frac{a}{4\,{b}^{3}e}\ln \left ( 1+\tan \left ({\frac{d}{2}}+{\frac{ex}{2}} \right ) \right ) }-{\frac{{a}^{2}}{4\,{b}^{2}e \left ( a-b \right ) } \left ( a\tan \left ({\frac{d}{2}}+{\frac{ex}{2}} \right ) -b\tan \left ({\frac{d}{2}}+{\frac{ex}{2}} \right ) +a+b \right ) ^{-1}}-{\frac{1}{4\,e \left ( a-b \right ) } \left ( a\tan \left ({\frac{d}{2}}+{\frac{ex}{2}} \right ) -b\tan \left ({\frac{d}{2}}+{\frac{ex}{2}} \right ) +a+b \right ) ^{-1}}+{\frac{a}{4\,{b}^{3}e}\ln \left ( a\tan \left ({\frac{d}{2}}+{\frac{ex}{2}} \right ) -b\tan \left ({\frac{d}{2}}+{\frac{ex}{2}} \right ) +a+b \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.0459, size = 250, normalized size = 3.01 \begin{align*} -\frac{\frac{2 \,{\left (a^{2} + \frac{{\left (a^{2} - a b + b^{2}\right )} \sin \left (e x + d\right )}{\cos \left (e x + d\right ) + 1}\right )}}{a^{2} b^{2} - b^{4} + \frac{2 \,{\left (a^{2} b^{2} - a b^{3}\right )} \sin \left (e x + d\right )}{\cos \left (e x + d\right ) + 1} + \frac{{\left (a^{2} b^{2} - 2 \, a b^{3} + b^{4}\right )} \sin \left (e x + d\right )^{2}}{{\left (\cos \left (e x + d\right ) + 1\right )}^{2}}} - \frac{a \log \left (-a - b - \frac{{\left (a - b\right )} \sin \left (e x + d\right )}{\cos \left (e x + d\right ) + 1}\right )}{b^{3}} + \frac{a \log \left (\frac{\sin \left (e x + d\right )}{\cos \left (e x + d\right ) + 1} + 1\right )}{b^{3}}}{4 \, e} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.36147, size = 377, normalized size = 4.54 \begin{align*} -\frac{2 \, a b \cos \left (e x + d\right ) - 2 \, b^{2} \sin \left (e x + d\right ) -{\left (a b \cos \left (e x + d\right ) + a^{2} \sin \left (e x + d\right ) + a^{2}\right )} \log \left (2 \, a b \cos \left (e x + d\right ) + a^{2} + b^{2} +{\left (a^{2} - b^{2}\right )} \sin \left (e x + d\right )\right ) +{\left (a b \cos \left (e x + d\right ) + a^{2} \sin \left (e x + d\right ) + a^{2}\right )} \log \left (\sin \left (e x + d\right ) + 1\right )}{8 \,{\left (b^{4} e \cos \left (e x + d\right ) + a b^{3} e \sin \left (e x + d\right ) + a b^{3} e\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.20223, size = 250, normalized size = 3.01 \begin{align*} \frac{1}{4} \,{\left (\frac{{\left (a^{2} - a b\right )} \log \left ({\left | a \tan \left (\frac{1}{2} \, x e + \frac{1}{2} \, d\right ) - b \tan \left (\frac{1}{2} \, x e + \frac{1}{2} \, d\right ) + a + b \right |}\right )}{a b^{3} - b^{4}} - \frac{2 \,{\left (a^{2} \tan \left (\frac{1}{2} \, x e + \frac{1}{2} \, d\right ) - a b \tan \left (\frac{1}{2} \, x e + \frac{1}{2} \, d\right ) + b^{2} \tan \left (\frac{1}{2} \, x e + \frac{1}{2} \, d\right ) + a^{2}\right )}}{{\left (a b^{2} - b^{3}\right )}{\left (a \tan \left (\frac{1}{2} \, x e + \frac{1}{2} \, d\right )^{2} - b \tan \left (\frac{1}{2} \, x e + \frac{1}{2} \, d\right )^{2} + 2 \, a \tan \left (\frac{1}{2} \, x e + \frac{1}{2} \, d\right ) + a + b\right )}} - \frac{a \log \left ({\left | \tan \left (\frac{1}{2} \, x e + \frac{1}{2} \, d\right ) + 1 \right |}\right )}{b^{3}}\right )} e^{\left (-1\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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