Optimal. Leaf size=76 \[ \frac{\sqrt{\pi } e^{-\frac{(m+1)^2}{4 n^2}} (d+e x)^{m+1} \left ((d+e x)^n\right )^{-\frac{m+1}{n}} \text{Erfi}\left (\frac{2 n \log \left ((d+e x)^n\right )+m+1}{2 n}\right )}{2 e n} \]
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Rubi [A] time = 0.156927, antiderivative size = 76, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.15, Rules used = {2276, 2234, 2204} \[ \frac{\sqrt{\pi } e^{-\frac{(m+1)^2}{4 n^2}} (d+e x)^{m+1} \left ((d+e x)^n\right )^{-\frac{m+1}{n}} \text{Erfi}\left (\frac{2 n \log \left ((d+e x)^n\right )+m+1}{2 n}\right )}{2 e n} \]
Antiderivative was successfully verified.
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Rule 2276
Rule 2234
Rule 2204
Rubi steps
\begin{align*} \int e^{\log ^2\left ((d+e x)^n\right )} (d+e x)^m \, dx &=\frac{\operatorname{Subst}\left (\int e^{\log ^2\left (x^n\right )} x^m \, dx,x,d+e x\right )}{e}\\ &=\frac{\left ((d+e x)^{1+m} \left ((d+e x)^n\right )^{-\frac{1+m}{n}}\right ) \operatorname{Subst}\left (\int e^{\frac{(1+m) x}{n}+x^2} \, dx,x,\log \left ((d+e x)^n\right )\right )}{e n}\\ &=\frac{\left (e^{-\frac{(1+m)^2}{4 n^2}} (d+e x)^{1+m} \left ((d+e x)^n\right )^{-\frac{1+m}{n}}\right ) \operatorname{Subst}\left (\int e^{\frac{1}{4} \left (\frac{1+m}{n}+2 x\right )^2} \, dx,x,\log \left ((d+e x)^n\right )\right )}{e n}\\ &=\frac{e^{-\frac{(1+m)^2}{4 n^2}} \sqrt{\pi } (d+e x)^{1+m} \left ((d+e x)^n\right )^{-\frac{1+m}{n}} \text{erfi}\left (\frac{1+m+2 n \log \left ((d+e x)^n\right )}{2 n}\right )}{2 e n}\\ \end{align*}
Mathematica [F] time = 0.085411, size = 0, normalized size = 0. \[ \int e^{\log ^2\left ((d+e x)^n\right )} (d+e x)^m \, dx \]
Verification is Not applicable to the result.
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Maple [F] time = 0.079, size = 0, normalized size = 0. \begin{align*} \int{{\rm e}^{ \left ( \ln \left ( \left ( ex+d \right ) ^{n} \right ) \right ) ^{2}}} \left ( ex+d \right ) ^{m}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (e x + d\right )}^{m} e^{\left (\log \left ({\left (e x + d\right )}^{n}\right )^{2}\right )}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.02208, size = 151, normalized size = 1.99 \begin{align*} \frac{\sqrt{\pi } \sqrt{n^{2}} \operatorname{erfi}\left (\frac{{\left (2 \, n^{2} \log \left (e x + d\right ) + m + 1\right )} \sqrt{n^{2}}}{2 \, n^{2}}\right ) e^{\left (-\frac{m^{2} + 2 \, m + 1}{4 \, n^{2}}\right )}}{2 \, e n} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (d + e x\right )^{m} e^{\log{\left (\left (d + e x\right )^{n} \right )}^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.32825, size = 76, normalized size = 1. \begin{align*} -\frac{\sqrt{\pi } i \operatorname{erf}\left (i n \log \left (x e + d\right ) + \frac{i m}{2 \, n} + \frac{i}{2 \, n}\right ) e^{\left (-\frac{m^{2}}{4 \, n^{2}} - \frac{m}{2 \, n^{2}} - \frac{1}{4 \, n^{2}} - 1\right )}}{2 \, n} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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