3.409 \(\int e^{\frac{e}{(c+d x)^2}} (a+b x)^3 \, dx\)

Optimal. Leaf size=322 \[ \frac{2 \sqrt{\pi } b^2 e^{3/2} (b c-a d) \text{Erfi}\left (\frac{\sqrt{e}}{c+d x}\right )}{d^4}-\frac{b^2 (c+d x)^3 (b c-a d) e^{\frac{e}{(c+d x)^2}}}{d^4}-\frac{2 b^2 e (c+d x) (b c-a d) e^{\frac{e}{(c+d x)^2}}}{d^4}+\frac{\sqrt{\pi } \sqrt{e} (b c-a d)^3 \text{Erfi}\left (\frac{\sqrt{e}}{c+d x}\right )}{d^4}-\frac{3 b e (b c-a d)^2 \text{Ei}\left (\frac{e}{(c+d x)^2}\right )}{2 d^4}+\frac{3 b (c+d x)^2 (b c-a d)^2 e^{\frac{e}{(c+d x)^2}}}{2 d^4}-\frac{(c+d x) (b c-a d)^3 e^{\frac{e}{(c+d x)^2}}}{d^4}-\frac{b^3 e^2 \text{Ei}\left (\frac{e}{(c+d x)^2}\right )}{4 d^4}+\frac{b^3 (c+d x)^4 e^{\frac{e}{(c+d x)^2}}}{4 d^4}+\frac{b^3 e (c+d x)^2 e^{\frac{e}{(c+d x)^2}}}{4 d^4} \]

[Out]

-(((b*c - a*d)^3*E^(e/(c + d*x)^2)*(c + d*x))/d^4) - (2*b^2*(b*c - a*d)*e*E^(e/(c + d*x)^2)*(c + d*x))/d^4 + (
3*b*(b*c - a*d)^2*E^(e/(c + d*x)^2)*(c + d*x)^2)/(2*d^4) + (b^3*e*E^(e/(c + d*x)^2)*(c + d*x)^2)/(4*d^4) - (b^
2*(b*c - a*d)*E^(e/(c + d*x)^2)*(c + d*x)^3)/d^4 + (b^3*E^(e/(c + d*x)^2)*(c + d*x)^4)/(4*d^4) + ((b*c - a*d)^
3*Sqrt[e]*Sqrt[Pi]*Erfi[Sqrt[e]/(c + d*x)])/d^4 + (2*b^2*(b*c - a*d)*e^(3/2)*Sqrt[Pi]*Erfi[Sqrt[e]/(c + d*x)])
/d^4 - (3*b*(b*c - a*d)^2*e*ExpIntegralEi[e/(c + d*x)^2])/(2*d^4) - (b^3*e^2*ExpIntegralEi[e/(c + d*x)^2])/(4*
d^4)

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Rubi [A]  time = 0.338777, antiderivative size = 322, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 6, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.316, Rules used = {2226, 2206, 2211, 2204, 2214, 2210} \[ \frac{2 \sqrt{\pi } b^2 e^{3/2} (b c-a d) \text{Erfi}\left (\frac{\sqrt{e}}{c+d x}\right )}{d^4}-\frac{b^2 (c+d x)^3 (b c-a d) e^{\frac{e}{(c+d x)^2}}}{d^4}-\frac{2 b^2 e (c+d x) (b c-a d) e^{\frac{e}{(c+d x)^2}}}{d^4}+\frac{\sqrt{\pi } \sqrt{e} (b c-a d)^3 \text{Erfi}\left (\frac{\sqrt{e}}{c+d x}\right )}{d^4}-\frac{3 b e (b c-a d)^2 \text{Ei}\left (\frac{e}{(c+d x)^2}\right )}{2 d^4}+\frac{3 b (c+d x)^2 (b c-a d)^2 e^{\frac{e}{(c+d x)^2}}}{2 d^4}-\frac{(c+d x) (b c-a d)^3 e^{\frac{e}{(c+d x)^2}}}{d^4}-\frac{b^3 e^2 \text{Ei}\left (\frac{e}{(c+d x)^2}\right )}{4 d^4}+\frac{b^3 (c+d x)^4 e^{\frac{e}{(c+d x)^2}}}{4 d^4}+\frac{b^3 e (c+d x)^2 e^{\frac{e}{(c+d x)^2}}}{4 d^4} \]

Antiderivative was successfully verified.

[In]

Int[E^(e/(c + d*x)^2)*(a + b*x)^3,x]

[Out]

-(((b*c - a*d)^3*E^(e/(c + d*x)^2)*(c + d*x))/d^4) - (2*b^2*(b*c - a*d)*e*E^(e/(c + d*x)^2)*(c + d*x))/d^4 + (
3*b*(b*c - a*d)^2*E^(e/(c + d*x)^2)*(c + d*x)^2)/(2*d^4) + (b^3*e*E^(e/(c + d*x)^2)*(c + d*x)^2)/(4*d^4) - (b^
2*(b*c - a*d)*E^(e/(c + d*x)^2)*(c + d*x)^3)/d^4 + (b^3*E^(e/(c + d*x)^2)*(c + d*x)^4)/(4*d^4) + ((b*c - a*d)^
3*Sqrt[e]*Sqrt[Pi]*Erfi[Sqrt[e]/(c + d*x)])/d^4 + (2*b^2*(b*c - a*d)*e^(3/2)*Sqrt[Pi]*Erfi[Sqrt[e]/(c + d*x)])
/d^4 - (3*b*(b*c - a*d)^2*e*ExpIntegralEi[e/(c + d*x)^2])/(2*d^4) - (b^3*e^2*ExpIntegralEi[e/(c + d*x)^2])/(4*
d^4)

Rule 2226

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))*(u_), x_Symbol] :> Int[ExpandLinearProduct[F^(a + b*(c + d*
x)^n), u, c, d, x], x] /; FreeQ[{F, a, b, c, d, n}, x] && PolynomialQ[u, x]

Rule 2206

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_)), x_Symbol] :> Simp[((c + d*x)*F^(a + b*(c + d*x)^n))/d, x]
- Dist[b*n*Log[F], Int[(c + d*x)^n*F^(a + b*(c + d*x)^n), x], x] /; FreeQ[{F, a, b, c, d}, x] && IntegerQ[2/n]
&& ILtQ[n, 0]

Rule 2211

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Dist[1/(d*(m + 1))
, Subst[Int[F^(a + b*x^2), x], x, (c + d*x)^(m + 1)], x] /; FreeQ[{F, a, b, c, d, m, n}, x] && EqQ[n, 2*(m + 1
)]

Rule 2204

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[(F^a*Sqrt[Pi]*Erfi[(c + d*x)*Rt[b*Log[F], 2
]])/(2*d*Rt[b*Log[F], 2]), x] /; FreeQ[{F, a, b, c, d}, x] && PosQ[b]

Rule 2214

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Simp[((c + d*x)^(m
+ 1)*F^(a + b*(c + d*x)^n))/(d*(m + 1)), x] - Dist[(b*n*Log[F])/(m + 1), Int[(c + d*x)^(m + n)*F^(a + b*(c +
d*x)^n), x], x] /; FreeQ[{F, a, b, c, d}, x] && IntegerQ[(2*(m + 1))/n] && LtQ[-4, (m + 1)/n, 5] && IntegerQ[n
] && ((GtQ[n, 0] && LtQ[m, -1]) || (GtQ[-n, 0] && LeQ[-n, m + 1]))

Rule 2210

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x_)), x_Symbol] :> Simp[(F^a*ExpIntegralEi[
b*(c + d*x)^n*Log[F]])/(f*n), x] /; FreeQ[{F, a, b, c, d, e, f, n}, x] && EqQ[d*e - c*f, 0]

Rubi steps

\begin{align*} \int e^{\frac{e}{(c+d x)^2}} (a+b x)^3 \, dx &=\int \left (\frac{(-b c+a d)^3 e^{\frac{e}{(c+d x)^2}}}{d^3}+\frac{3 b (b c-a d)^2 e^{\frac{e}{(c+d x)^2}} (c+d x)}{d^3}-\frac{3 b^2 (b c-a d) e^{\frac{e}{(c+d x)^2}} (c+d x)^2}{d^3}+\frac{b^3 e^{\frac{e}{(c+d x)^2}} (c+d x)^3}{d^3}\right ) \, dx\\ &=\frac{b^3 \int e^{\frac{e}{(c+d x)^2}} (c+d x)^3 \, dx}{d^3}-\frac{\left (3 b^2 (b c-a d)\right ) \int e^{\frac{e}{(c+d x)^2}} (c+d x)^2 \, dx}{d^3}+\frac{\left (3 b (b c-a d)^2\right ) \int e^{\frac{e}{(c+d x)^2}} (c+d x) \, dx}{d^3}-\frac{(b c-a d)^3 \int e^{\frac{e}{(c+d x)^2}} \, dx}{d^3}\\ &=-\frac{(b c-a d)^3 e^{\frac{e}{(c+d x)^2}} (c+d x)}{d^4}+\frac{3 b (b c-a d)^2 e^{\frac{e}{(c+d x)^2}} (c+d x)^2}{2 d^4}-\frac{b^2 (b c-a d) e^{\frac{e}{(c+d x)^2}} (c+d x)^3}{d^4}+\frac{b^3 e^{\frac{e}{(c+d x)^2}} (c+d x)^4}{4 d^4}+\frac{\left (b^3 e\right ) \int e^{\frac{e}{(c+d x)^2}} (c+d x) \, dx}{2 d^3}-\frac{\left (2 b^2 (b c-a d) e\right ) \int e^{\frac{e}{(c+d x)^2}} \, dx}{d^3}+\frac{\left (3 b (b c-a d)^2 e\right ) \int \frac{e^{\frac{e}{(c+d x)^2}}}{c+d x} \, dx}{d^3}-\frac{\left (2 (b c-a d)^3 e\right ) \int \frac{e^{\frac{e}{(c+d x)^2}}}{(c+d x)^2} \, dx}{d^3}\\ &=-\frac{(b c-a d)^3 e^{\frac{e}{(c+d x)^2}} (c+d x)}{d^4}-\frac{2 b^2 (b c-a d) e e^{\frac{e}{(c+d x)^2}} (c+d x)}{d^4}+\frac{3 b (b c-a d)^2 e^{\frac{e}{(c+d x)^2}} (c+d x)^2}{2 d^4}+\frac{b^3 e e^{\frac{e}{(c+d x)^2}} (c+d x)^2}{4 d^4}-\frac{b^2 (b c-a d) e^{\frac{e}{(c+d x)^2}} (c+d x)^3}{d^4}+\frac{b^3 e^{\frac{e}{(c+d x)^2}} (c+d x)^4}{4 d^4}-\frac{3 b (b c-a d)^2 e \text{Ei}\left (\frac{e}{(c+d x)^2}\right )}{2 d^4}+\frac{\left (2 (b c-a d)^3 e\right ) \operatorname{Subst}\left (\int e^{e x^2} \, dx,x,\frac{1}{c+d x}\right )}{d^4}+\frac{\left (b^3 e^2\right ) \int \frac{e^{\frac{e}{(c+d x)^2}}}{c+d x} \, dx}{2 d^3}-\frac{\left (4 b^2 (b c-a d) e^2\right ) \int \frac{e^{\frac{e}{(c+d x)^2}}}{(c+d x)^2} \, dx}{d^3}\\ &=-\frac{(b c-a d)^3 e^{\frac{e}{(c+d x)^2}} (c+d x)}{d^4}-\frac{2 b^2 (b c-a d) e e^{\frac{e}{(c+d x)^2}} (c+d x)}{d^4}+\frac{3 b (b c-a d)^2 e^{\frac{e}{(c+d x)^2}} (c+d x)^2}{2 d^4}+\frac{b^3 e e^{\frac{e}{(c+d x)^2}} (c+d x)^2}{4 d^4}-\frac{b^2 (b c-a d) e^{\frac{e}{(c+d x)^2}} (c+d x)^3}{d^4}+\frac{b^3 e^{\frac{e}{(c+d x)^2}} (c+d x)^4}{4 d^4}+\frac{(b c-a d)^3 \sqrt{e} \sqrt{\pi } \text{erfi}\left (\frac{\sqrt{e}}{c+d x}\right )}{d^4}-\frac{3 b (b c-a d)^2 e \text{Ei}\left (\frac{e}{(c+d x)^2}\right )}{2 d^4}-\frac{b^3 e^2 \text{Ei}\left (\frac{e}{(c+d x)^2}\right )}{4 d^4}+\frac{\left (4 b^2 (b c-a d) e^2\right ) \operatorname{Subst}\left (\int e^{e x^2} \, dx,x,\frac{1}{c+d x}\right )}{d^4}\\ &=-\frac{(b c-a d)^3 e^{\frac{e}{(c+d x)^2}} (c+d x)}{d^4}-\frac{2 b^2 (b c-a d) e e^{\frac{e}{(c+d x)^2}} (c+d x)}{d^4}+\frac{3 b (b c-a d)^2 e^{\frac{e}{(c+d x)^2}} (c+d x)^2}{2 d^4}+\frac{b^3 e e^{\frac{e}{(c+d x)^2}} (c+d x)^2}{4 d^4}-\frac{b^2 (b c-a d) e^{\frac{e}{(c+d x)^2}} (c+d x)^3}{d^4}+\frac{b^3 e^{\frac{e}{(c+d x)^2}} (c+d x)^4}{4 d^4}+\frac{(b c-a d)^3 \sqrt{e} \sqrt{\pi } \text{erfi}\left (\frac{\sqrt{e}}{c+d x}\right )}{d^4}+\frac{2 b^2 (b c-a d) e^{3/2} \sqrt{\pi } \text{erfi}\left (\frac{\sqrt{e}}{c+d x}\right )}{d^4}-\frac{3 b (b c-a d)^2 e \text{Ei}\left (\frac{e}{(c+d x)^2}\right )}{2 d^4}-\frac{b^3 e^2 \text{Ei}\left (\frac{e}{(c+d x)^2}\right )}{4 d^4}\\ \end{align*}

Mathematica [A]  time = 0.307828, size = 243, normalized size = 0.75 \[ \frac{4 \sqrt{\pi } \sqrt{e} (b c-a d) \left (a^2 d^2-2 a b c d+b^2 \left (c^2+2 e\right )\right ) \text{Erfi}\left (\frac{\sqrt{e}}{c+d x}\right )-b e \left (6 a^2 d^2-12 a b c d+b^2 \left (6 c^2+e\right )\right ) \text{Ei}\left (\frac{e}{(c+d x)^2}\right )+d x e^{\frac{e}{(c+d x)^2}} \left (6 a^2 b d^3 x+4 a^3 d^3+4 a b^2 d \left (d^2 x^2+2 e\right )+b^3 \left (-6 c e+d^3 x^3+d e x\right )\right )}{4 d^4}-\frac{c e^{\frac{e}{(c+d x)^2}} \left (6 a^2 b c d^2-4 a^3 d^3-4 a b^2 d \left (c^2+2 e\right )+b^3 \left (c^3+7 c e\right )\right )}{4 d^4} \]

Antiderivative was successfully verified.

[In]

Integrate[E^(e/(c + d*x)^2)*(a + b*x)^3,x]

[Out]

-(c*(6*a^2*b*c*d^2 - 4*a^3*d^3 - 4*a*b^2*d*(c^2 + 2*e) + b^3*(c^3 + 7*c*e))*E^(e/(c + d*x)^2))/(4*d^4) + (d*E^
(e/(c + d*x)^2)*x*(4*a^3*d^3 + 6*a^2*b*d^3*x + 4*a*b^2*d*(2*e + d^2*x^2) + b^3*(-6*c*e + d*e*x + d^3*x^3)) + 4
*(b*c - a*d)*Sqrt[e]*(-2*a*b*c*d + a^2*d^2 + b^2*(c^2 + 2*e))*Sqrt[Pi]*Erfi[Sqrt[e]/(c + d*x)] - b*e*(-12*a*b*
c*d + 6*a^2*d^2 + b^2*(6*c^2 + e))*ExpIntegralEi[e/(c + d*x)^2])/(4*d^4)

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Maple [A]  time = 0.018, size = 560, normalized size = 1.7 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(e/(d*x+c)^2)*(b*x+a)^3,x)

[Out]

-1/d*(a^3*(-(d*x+c)*exp(e/(d*x+c)^2)+e*Pi^(1/2)/(-e)^(1/2)*erf((-e)^(1/2)/(d*x+c)))+b^3/d^3*(-1/4*(d*x+c)^4*ex
p(e/(d*x+c)^2)+1/2*e*(-1/2*exp(e/(d*x+c)^2)*(d*x+c)^2-1/2*e*Ei(1,-e/(d*x+c)^2)))+3*b^2/d^2*a*(-1/3*(d*x+c)^3*e
xp(e/(d*x+c)^2)+2/3*e*(-(d*x+c)*exp(e/(d*x+c)^2)+e*Pi^(1/2)/(-e)^(1/2)*erf((-e)^(1/2)/(d*x+c))))-3*b^3/d^3*c*(
-1/3*(d*x+c)^3*exp(e/(d*x+c)^2)+2/3*e*(-(d*x+c)*exp(e/(d*x+c)^2)+e*Pi^(1/2)/(-e)^(1/2)*erf((-e)^(1/2)/(d*x+c))
))+3*b/d*a^2*(-1/2*exp(e/(d*x+c)^2)*(d*x+c)^2-1/2*e*Ei(1,-e/(d*x+c)^2))+3*b^3/d^3*c^2*(-1/2*exp(e/(d*x+c)^2)*(
d*x+c)^2-1/2*e*Ei(1,-e/(d*x+c)^2))-b^3/d^3*c^3*(-(d*x+c)*exp(e/(d*x+c)^2)+e*Pi^(1/2)/(-e)^(1/2)*erf((-e)^(1/2)
/(d*x+c)))-6*b^2/d^2*c*a*(-1/2*exp(e/(d*x+c)^2)*(d*x+c)^2-1/2*e*Ei(1,-e/(d*x+c)^2))-3*b/d*c*a^2*(-(d*x+c)*exp(
e/(d*x+c)^2)+e*Pi^(1/2)/(-e)^(1/2)*erf((-e)^(1/2)/(d*x+c)))+3*b^2/d^2*c^2*a*(-(d*x+c)*exp(e/(d*x+c)^2)+e*Pi^(1
/2)/(-e)^(1/2)*erf((-e)^(1/2)/(d*x+c))))

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \frac{{\left (b^{3} d^{3} x^{4} + 4 \, a b^{2} d^{3} x^{3} +{\left (6 \, a^{2} b d^{3} + b^{3} d e\right )} x^{2} + 2 \,{\left (2 \, a^{3} d^{3} - 3 \, b^{3} c e + 4 \, a b^{2} d e\right )} x\right )} e^{\left (\frac{e}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right )}}{4 \, d^{3}} + \int \frac{{\left (3 \, b^{3} c^{4} e - 4 \, a b^{2} c^{3} d e -{\left (12 \, a b^{2} c d^{3} e - 6 \, a^{2} b d^{4} e -{\left (6 \, c^{2} d^{2} e + d^{2} e^{2}\right )} b^{3}\right )} x^{2} + 2 \,{\left (2 \, a^{3} d^{4} e - 2 \,{\left (3 \, c^{2} d^{2} e - 2 \, d^{2} e^{2}\right )} a b^{2} +{\left (4 \, c^{3} d e - 3 \, c d e^{2}\right )} b^{3}\right )} x\right )} e^{\left (\frac{e}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right )}}{2 \,{\left (d^{6} x^{3} + 3 \, c d^{5} x^{2} + 3 \, c^{2} d^{4} x + c^{3} d^{3}\right )}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(e/(d*x+c)^2)*(b*x+a)^3,x, algorithm="maxima")

[Out]

1/4*(b^3*d^3*x^4 + 4*a*b^2*d^3*x^3 + (6*a^2*b*d^3 + b^3*d*e)*x^2 + 2*(2*a^3*d^3 - 3*b^3*c*e + 4*a*b^2*d*e)*x)*
e^(e/(d^2*x^2 + 2*c*d*x + c^2))/d^3 + integrate(1/2*(3*b^3*c^4*e - 4*a*b^2*c^3*d*e - (12*a*b^2*c*d^3*e - 6*a^2
*b*d^4*e - (6*c^2*d^2*e + d^2*e^2)*b^3)*x^2 + 2*(2*a^3*d^4*e - 2*(3*c^2*d^2*e - 2*d^2*e^2)*a*b^2 + (4*c^3*d*e
- 3*c*d*e^2)*b^3)*x)*e^(e/(d^2*x^2 + 2*c*d*x + c^2))/(d^6*x^3 + 3*c*d^5*x^2 + 3*c^2*d^4*x + c^3*d^3), x)

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Fricas [A]  time = 1.64628, size = 635, normalized size = 1.97 \begin{align*} -\frac{4 \, \sqrt{\pi }{\left (b^{3} c^{3} d - 3 \, a b^{2} c^{2} d^{2} + 3 \, a^{2} b c d^{3} - a^{3} d^{4} + 2 \,{\left (b^{3} c d - a b^{2} d^{2}\right )} e\right )} \sqrt{-\frac{e}{d^{2}}} \operatorname{erf}\left (\frac{d \sqrt{-\frac{e}{d^{2}}}}{d x + c}\right ) +{\left (b^{3} e^{2} + 6 \,{\left (b^{3} c^{2} - 2 \, a b^{2} c d + a^{2} b d^{2}\right )} e\right )}{\rm Ei}\left (\frac{e}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right ) -{\left (b^{3} d^{4} x^{4} + 4 \, a b^{2} d^{4} x^{3} - b^{3} c^{4} + 4 \, a b^{2} c^{3} d - 6 \, a^{2} b c^{2} d^{2} + 4 \, a^{3} c d^{3} +{\left (6 \, a^{2} b d^{4} + b^{3} d^{2} e\right )} x^{2} -{\left (7 \, b^{3} c^{2} - 8 \, a b^{2} c d\right )} e + 2 \,{\left (2 \, a^{3} d^{4} -{\left (3 \, b^{3} c d - 4 \, a b^{2} d^{2}\right )} e\right )} x\right )} e^{\left (\frac{e}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right )}}{4 \, d^{4}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(e/(d*x+c)^2)*(b*x+a)^3,x, algorithm="fricas")

[Out]

-1/4*(4*sqrt(pi)*(b^3*c^3*d - 3*a*b^2*c^2*d^2 + 3*a^2*b*c*d^3 - a^3*d^4 + 2*(b^3*c*d - a*b^2*d^2)*e)*sqrt(-e/d
^2)*erf(d*sqrt(-e/d^2)/(d*x + c)) + (b^3*e^2 + 6*(b^3*c^2 - 2*a*b^2*c*d + a^2*b*d^2)*e)*Ei(e/(d^2*x^2 + 2*c*d*
x + c^2)) - (b^3*d^4*x^4 + 4*a*b^2*d^4*x^3 - b^3*c^4 + 4*a*b^2*c^3*d - 6*a^2*b*c^2*d^2 + 4*a^3*c*d^3 + (6*a^2*
b*d^4 + b^3*d^2*e)*x^2 - (7*b^3*c^2 - 8*a*b^2*c*d)*e + 2*(2*a^3*d^4 - (3*b^3*c*d - 4*a*b^2*d^2)*e)*x)*e^(e/(d^
2*x^2 + 2*c*d*x + c^2)))/d^4

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(e/(d*x+c)**2)*(b*x+a)**3,x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b x + a\right )}^{3} e^{\left (\frac{e}{{\left (d x + c\right )}^{2}}\right )}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(e/(d*x+c)^2)*(b*x+a)^3,x, algorithm="giac")

[Out]

integrate((b*x + a)^3*e^(e/(d*x + c)^2), x)