Optimal. Leaf size=255 \[ \frac{b e^2 (b c-a d) \text{Ei}\left (\frac{e}{c+d x}\right )}{d^3}-\frac{e (b c-a d)^2 \text{Ei}\left (\frac{e}{c+d x}\right )}{d^3}-\frac{b e (c+d x) (b c-a d) e^{\frac{e}{c+d x}}}{d^3}-\frac{b (c+d x)^2 (b c-a d) e^{\frac{e}{c+d x}}}{d^3}+\frac{(c+d x) (b c-a d)^2 e^{\frac{e}{c+d x}}}{d^3}-\frac{b^2 e^3 \text{Ei}\left (\frac{e}{c+d x}\right )}{6 d^3}+\frac{b^2 e^2 (c+d x) e^{\frac{e}{c+d x}}}{6 d^3}+\frac{b^2 e (c+d x)^2 e^{\frac{e}{c+d x}}}{6 d^3}+\frac{b^2 (c+d x)^3 e^{\frac{e}{c+d x}}}{3 d^3} \]
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Rubi [A] time = 0.256185, antiderivative size = 255, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 4, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.21, Rules used = {2226, 2206, 2210, 2214} \[ \frac{b e^2 (b c-a d) \text{Ei}\left (\frac{e}{c+d x}\right )}{d^3}-\frac{e (b c-a d)^2 \text{Ei}\left (\frac{e}{c+d x}\right )}{d^3}-\frac{b e (c+d x) (b c-a d) e^{\frac{e}{c+d x}}}{d^3}-\frac{b (c+d x)^2 (b c-a d) e^{\frac{e}{c+d x}}}{d^3}+\frac{(c+d x) (b c-a d)^2 e^{\frac{e}{c+d x}}}{d^3}-\frac{b^2 e^3 \text{Ei}\left (\frac{e}{c+d x}\right )}{6 d^3}+\frac{b^2 e^2 (c+d x) e^{\frac{e}{c+d x}}}{6 d^3}+\frac{b^2 e (c+d x)^2 e^{\frac{e}{c+d x}}}{6 d^3}+\frac{b^2 (c+d x)^3 e^{\frac{e}{c+d x}}}{3 d^3} \]
Antiderivative was successfully verified.
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Rule 2226
Rule 2206
Rule 2210
Rule 2214
Rubi steps
\begin{align*} \int e^{\frac{e}{c+d x}} (a+b x)^2 \, dx &=\int \left (\frac{(-b c+a d)^2 e^{\frac{e}{c+d x}}}{d^2}-\frac{2 b (b c-a d) e^{\frac{e}{c+d x}} (c+d x)}{d^2}+\frac{b^2 e^{\frac{e}{c+d x}} (c+d x)^2}{d^2}\right ) \, dx\\ &=\frac{b^2 \int e^{\frac{e}{c+d x}} (c+d x)^2 \, dx}{d^2}-\frac{(2 b (b c-a d)) \int e^{\frac{e}{c+d x}} (c+d x) \, dx}{d^2}+\frac{(b c-a d)^2 \int e^{\frac{e}{c+d x}} \, dx}{d^2}\\ &=\frac{(b c-a d)^2 e^{\frac{e}{c+d x}} (c+d x)}{d^3}-\frac{b (b c-a d) e^{\frac{e}{c+d x}} (c+d x)^2}{d^3}+\frac{b^2 e^{\frac{e}{c+d x}} (c+d x)^3}{3 d^3}+\frac{\left (b^2 e\right ) \int e^{\frac{e}{c+d x}} (c+d x) \, dx}{3 d^2}-\frac{(b (b c-a d) e) \int e^{\frac{e}{c+d x}} \, dx}{d^2}+\frac{\left ((b c-a d)^2 e\right ) \int \frac{e^{\frac{e}{c+d x}}}{c+d x} \, dx}{d^2}\\ &=\frac{(b c-a d)^2 e^{\frac{e}{c+d x}} (c+d x)}{d^3}-\frac{b (b c-a d) e e^{\frac{e}{c+d x}} (c+d x)}{d^3}-\frac{b (b c-a d) e^{\frac{e}{c+d x}} (c+d x)^2}{d^3}+\frac{b^2 e e^{\frac{e}{c+d x}} (c+d x)^2}{6 d^3}+\frac{b^2 e^{\frac{e}{c+d x}} (c+d x)^3}{3 d^3}-\frac{(b c-a d)^2 e \text{Ei}\left (\frac{e}{c+d x}\right )}{d^3}+\frac{\left (b^2 e^2\right ) \int e^{\frac{e}{c+d x}} \, dx}{6 d^2}-\frac{\left (b (b c-a d) e^2\right ) \int \frac{e^{\frac{e}{c+d x}}}{c+d x} \, dx}{d^2}\\ &=\frac{(b c-a d)^2 e^{\frac{e}{c+d x}} (c+d x)}{d^3}-\frac{b (b c-a d) e e^{\frac{e}{c+d x}} (c+d x)}{d^3}+\frac{b^2 e^2 e^{\frac{e}{c+d x}} (c+d x)}{6 d^3}-\frac{b (b c-a d) e^{\frac{e}{c+d x}} (c+d x)^2}{d^3}+\frac{b^2 e e^{\frac{e}{c+d x}} (c+d x)^2}{6 d^3}+\frac{b^2 e^{\frac{e}{c+d x}} (c+d x)^3}{3 d^3}-\frac{(b c-a d)^2 e \text{Ei}\left (\frac{e}{c+d x}\right )}{d^3}+\frac{b (b c-a d) e^2 \text{Ei}\left (\frac{e}{c+d x}\right )}{d^3}+\frac{\left (b^2 e^3\right ) \int \frac{e^{\frac{e}{c+d x}}}{c+d x} \, dx}{6 d^2}\\ &=\frac{(b c-a d)^2 e^{\frac{e}{c+d x}} (c+d x)}{d^3}-\frac{b (b c-a d) e e^{\frac{e}{c+d x}} (c+d x)}{d^3}+\frac{b^2 e^2 e^{\frac{e}{c+d x}} (c+d x)}{6 d^3}-\frac{b (b c-a d) e^{\frac{e}{c+d x}} (c+d x)^2}{d^3}+\frac{b^2 e e^{\frac{e}{c+d x}} (c+d x)^2}{6 d^3}+\frac{b^2 e^{\frac{e}{c+d x}} (c+d x)^3}{3 d^3}-\frac{(b c-a d)^2 e \text{Ei}\left (\frac{e}{c+d x}\right )}{d^3}+\frac{b (b c-a d) e^2 \text{Ei}\left (\frac{e}{c+d x}\right )}{d^3}-\frac{b^2 e^3 \text{Ei}\left (\frac{e}{c+d x}\right )}{6 d^3}\\ \end{align*}
Mathematica [A] time = 0.199511, size = 170, normalized size = 0.67 \[ \frac{d x e^{\frac{e}{c+d x}} \left (6 a^2 d^2+6 a b d (d x+e)+b^2 \left (-4 c e+2 d^2 x^2+d e x+e^2\right )\right )-e \left (6 a^2 d^2+6 a b d (e-2 c)+b^2 \left (6 c^2-6 c e+e^2\right )\right ) \text{Ei}\left (\frac{e}{c+d x}\right )}{6 d^3}+\frac{c e^{\frac{e}{c+d x}} \left (6 a^2 d^2+6 a b d (e-c)+b^2 \left (2 c^2-5 c e+e^2\right )\right )}{6 d^3} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.007, size = 356, normalized size = 1.4 \begin{align*} -{\frac{e}{d} \left ({a}^{2} \left ( -{\frac{dx+c}{e}{{\rm e}^{{\frac{e}{dx+c}}}}}-{\it Ei} \left ( 1,-{\frac{e}{dx+c}} \right ) \right ) +{\frac{{b}^{2}{e}^{2}}{{d}^{2}} \left ( -{\frac{ \left ( dx+c \right ) ^{3}}{3\,{e}^{3}}{{\rm e}^{{\frac{e}{dx+c}}}}}-{\frac{ \left ( dx+c \right ) ^{2}}{6\,{e}^{2}}{{\rm e}^{{\frac{e}{dx+c}}}}}-{\frac{dx+c}{6\,e}{{\rm e}^{{\frac{e}{dx+c}}}}}-{\frac{1}{6}{\it Ei} \left ( 1,-{\frac{e}{dx+c}} \right ) } \right ) }+{\frac{{c}^{2}{b}^{2}}{{d}^{2}} \left ( -{\frac{dx+c}{e}{{\rm e}^{{\frac{e}{dx+c}}}}}-{\it Ei} \left ( 1,-{\frac{e}{dx+c}} \right ) \right ) }+2\,{\frac{abe}{d} \left ( -1/2\,{\frac{ \left ( dx+c \right ) ^{2}}{{e}^{2}}{{\rm e}^{{\frac{e}{dx+c}}}}}-1/2\,{\frac{dx+c}{e}{{\rm e}^{{\frac{e}{dx+c}}}}}-1/2\,{\it Ei} \left ( 1,-{\frac{e}{dx+c}} \right ) \right ) }-2\,{\frac{{b}^{2}ec}{{d}^{2}} \left ( -1/2\,{\frac{ \left ( dx+c \right ) ^{2}}{{e}^{2}}{{\rm e}^{{\frac{e}{dx+c}}}}}-1/2\,{\frac{dx+c}{e}{{\rm e}^{{\frac{e}{dx+c}}}}}-1/2\,{\it Ei} \left ( 1,-{\frac{e}{dx+c}} \right ) \right ) }-2\,{\frac{abc}{d} \left ( -{\frac{dx+c}{e}{{\rm e}^{{\frac{e}{dx+c}}}}}-{\it Ei} \left ( 1,-{\frac{e}{dx+c}} \right ) \right ) } \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{{\left (2 \, b^{2} d^{2} x^{3} +{\left (6 \, a b d^{2} + b^{2} d e\right )} x^{2} +{\left (6 \, a^{2} d^{2} + 6 \, a b d e -{\left (4 \, c e - e^{2}\right )} b^{2}\right )} x\right )} e^{\left (\frac{e}{d x + c}\right )}}{6 \, d^{2}} + \int -\frac{{\left (6 \, a b c^{2} d e -{\left (4 \, c^{3} e - c^{2} e^{2}\right )} b^{2} -{\left (6 \, a^{2} d^{3} e - 6 \,{\left (2 \, c d^{2} e - d^{2} e^{2}\right )} a b +{\left (6 \, c^{2} d e - 6 \, c d e^{2} + d e^{3}\right )} b^{2}\right )} x\right )} e^{\left (\frac{e}{d x + c}\right )}}{6 \,{\left (d^{4} x^{2} + 2 \, c d^{3} x + c^{2} d^{2}\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.54076, size = 408, normalized size = 1.6 \begin{align*} -\frac{{\left (b^{2} e^{3} - 6 \,{\left (b^{2} c - a b d\right )} e^{2} + 6 \,{\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} e\right )}{\rm Ei}\left (\frac{e}{d x + c}\right ) -{\left (2 \, b^{2} d^{3} x^{3} + 2 \, b^{2} c^{3} - 6 \, a b c^{2} d + 6 \, a^{2} c d^{2} + b^{2} c e^{2} +{\left (6 \, a b d^{3} + b^{2} d^{2} e\right )} x^{2} -{\left (5 \, b^{2} c^{2} - 6 \, a b c d\right )} e +{\left (6 \, a^{2} d^{3} + b^{2} d e^{2} - 2 \,{\left (2 \, b^{2} c d - 3 \, a b d^{2}\right )} e\right )} x\right )} e^{\left (\frac{e}{d x + c}\right )}}{6 \, d^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (a + b x\right )^{2} e^{\frac{e}{c + d x}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b x + a\right )}^{2} e^{\left (\frac{e}{d x + c}\right )}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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