Optimal. Leaf size=267 \[ \frac{b^2 d^2 f \log ^2(F) F^{a-\frac{b f}{d e-c f}} \text{Ei}\left (\frac{b d (e+f x) \log (F)}{(d e-c f) (c+d x)}\right )}{2 (d e-c f)^4}-\frac{b d^2 \log (F) F^{a-\frac{b f}{d e-c f}} \text{Ei}\left (\frac{b d (e+f x) \log (F)}{(d e-c f) (c+d x)}\right )}{(d e-c f)^3}+\frac{d^2 F^{a+\frac{b}{c+d x}}}{2 f (d e-c f)^2}-\frac{b d^2 \log (F) F^{a+\frac{b}{c+d x}}}{2 (d e-c f)^3}-\frac{F^{a+\frac{b}{c+d x}}}{2 f (e+f x)^2}+\frac{b d \log (F) F^{a+\frac{b}{c+d x}}}{2 (e+f x) (d e-c f)^2} \]
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Rubi [A] time = 1.91399, antiderivative size = 267, normalized size of antiderivative = 1., number of steps used = 18, number of rules used = 7, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {2223, 6742, 2209, 2210, 2222, 2228, 2178} \[ \frac{b^2 d^2 f \log ^2(F) F^{a-\frac{b f}{d e-c f}} \text{Ei}\left (\frac{b d (e+f x) \log (F)}{(d e-c f) (c+d x)}\right )}{2 (d e-c f)^4}-\frac{b d^2 \log (F) F^{a-\frac{b f}{d e-c f}} \text{Ei}\left (\frac{b d (e+f x) \log (F)}{(d e-c f) (c+d x)}\right )}{(d e-c f)^3}+\frac{d^2 F^{a+\frac{b}{c+d x}}}{2 f (d e-c f)^2}-\frac{b d^2 \log (F) F^{a+\frac{b}{c+d x}}}{2 (d e-c f)^3}-\frac{F^{a+\frac{b}{c+d x}}}{2 f (e+f x)^2}+\frac{b d \log (F) F^{a+\frac{b}{c+d x}}}{2 (e+f x) (d e-c f)^2} \]
Antiderivative was successfully verified.
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Rule 2223
Rule 6742
Rule 2209
Rule 2210
Rule 2222
Rule 2228
Rule 2178
Rubi steps
\begin{align*} \int \frac{F^{a+\frac{b}{c+d x}}}{(e+f x)^3} \, dx &=-\frac{F^{a+\frac{b}{c+d x}}}{2 f (e+f x)^2}-\frac{(b d \log (F)) \int \frac{F^{a+\frac{b}{c+d x}}}{(c+d x)^2 (e+f x)^2} \, dx}{2 f}\\ &=-\frac{F^{a+\frac{b}{c+d x}}}{2 f (e+f x)^2}-\frac{(b d \log (F)) \int \left (\frac{d^2 F^{a+\frac{b}{c+d x}}}{(d e-c f)^2 (c+d x)^2}-\frac{2 d^2 f F^{a+\frac{b}{c+d x}}}{(d e-c f)^3 (c+d x)}+\frac{f^2 F^{a+\frac{b}{c+d x}}}{(d e-c f)^2 (e+f x)^2}+\frac{2 d f^2 F^{a+\frac{b}{c+d x}}}{(d e-c f)^3 (e+f x)}\right ) \, dx}{2 f}\\ &=-\frac{F^{a+\frac{b}{c+d x}}}{2 f (e+f x)^2}+\frac{\left (b d^3 \log (F)\right ) \int \frac{F^{a+\frac{b}{c+d x}}}{c+d x} \, dx}{(d e-c f)^3}-\frac{\left (b d^2 f \log (F)\right ) \int \frac{F^{a+\frac{b}{c+d x}}}{e+f x} \, dx}{(d e-c f)^3}-\frac{\left (b d^3 \log (F)\right ) \int \frac{F^{a+\frac{b}{c+d x}}}{(c+d x)^2} \, dx}{2 f (d e-c f)^2}-\frac{(b d f \log (F)) \int \frac{F^{a+\frac{b}{c+d x}}}{(e+f x)^2} \, dx}{2 (d e-c f)^2}\\ &=\frac{d^2 F^{a+\frac{b}{c+d x}}}{2 f (d e-c f)^2}-\frac{F^{a+\frac{b}{c+d x}}}{2 f (e+f x)^2}+\frac{b d F^{a+\frac{b}{c+d x}} \log (F)}{2 (d e-c f)^2 (e+f x)}-\frac{b d^2 F^a \text{Ei}\left (\frac{b \log (F)}{c+d x}\right ) \log (F)}{(d e-c f)^3}-\frac{\left (b d^3 \log (F)\right ) \int \frac{F^{a+\frac{b}{c+d x}}}{c+d x} \, dx}{(d e-c f)^3}+\frac{\left (b d^2 \log (F)\right ) \int \frac{F^{a+\frac{b}{c+d x}}}{(c+d x) (e+f x)} \, dx}{(d e-c f)^2}+\frac{\left (b^2 d^2 \log ^2(F)\right ) \int \frac{F^{a+\frac{b}{c+d x}}}{(c+d x)^2 (e+f x)} \, dx}{2 (d e-c f)^2}\\ &=\frac{d^2 F^{a+\frac{b}{c+d x}}}{2 f (d e-c f)^2}-\frac{F^{a+\frac{b}{c+d x}}}{2 f (e+f x)^2}+\frac{b d F^{a+\frac{b}{c+d x}} \log (F)}{2 (d e-c f)^2 (e+f x)}-\frac{\left (b d^2 \log (F)\right ) \operatorname{Subst}\left (\int \frac{F^{a-\frac{b f}{d e-c f}+\frac{b d x}{d e-c f}}}{x} \, dx,x,\frac{e+f x}{c+d x}\right )}{(d e-c f)^3}+\frac{\left (b^2 d^2 \log ^2(F)\right ) \int \left (\frac{d F^{a+\frac{b}{c+d x}}}{(d e-c f) (c+d x)^2}-\frac{d f F^{a+\frac{b}{c+d x}}}{(d e-c f)^2 (c+d x)}+\frac{f^2 F^{a+\frac{b}{c+d x}}}{(d e-c f)^2 (e+f x)}\right ) \, dx}{2 (d e-c f)^2}\\ &=\frac{d^2 F^{a+\frac{b}{c+d x}}}{2 f (d e-c f)^2}-\frac{F^{a+\frac{b}{c+d x}}}{2 f (e+f x)^2}+\frac{b d F^{a+\frac{b}{c+d x}} \log (F)}{2 (d e-c f)^2 (e+f x)}-\frac{b d^2 F^{a-\frac{b f}{d e-c f}} \text{Ei}\left (\frac{b d (e+f x) \log (F)}{(d e-c f) (c+d x)}\right ) \log (F)}{(d e-c f)^3}-\frac{\left (b^2 d^3 f \log ^2(F)\right ) \int \frac{F^{a+\frac{b}{c+d x}}}{c+d x} \, dx}{2 (d e-c f)^4}+\frac{\left (b^2 d^2 f^2 \log ^2(F)\right ) \int \frac{F^{a+\frac{b}{c+d x}}}{e+f x} \, dx}{2 (d e-c f)^4}+\frac{\left (b^2 d^3 \log ^2(F)\right ) \int \frac{F^{a+\frac{b}{c+d x}}}{(c+d x)^2} \, dx}{2 (d e-c f)^3}\\ &=\frac{d^2 F^{a+\frac{b}{c+d x}}}{2 f (d e-c f)^2}-\frac{F^{a+\frac{b}{c+d x}}}{2 f (e+f x)^2}-\frac{b d^2 F^{a+\frac{b}{c+d x}} \log (F)}{2 (d e-c f)^3}+\frac{b d F^{a+\frac{b}{c+d x}} \log (F)}{2 (d e-c f)^2 (e+f x)}-\frac{b d^2 F^{a-\frac{b f}{d e-c f}} \text{Ei}\left (\frac{b d (e+f x) \log (F)}{(d e-c f) (c+d x)}\right ) \log (F)}{(d e-c f)^3}+\frac{b^2 d^2 f F^a \text{Ei}\left (\frac{b \log (F)}{c+d x}\right ) \log ^2(F)}{2 (d e-c f)^4}+\frac{\left (b^2 d^3 f \log ^2(F)\right ) \int \frac{F^{a+\frac{b}{c+d x}}}{c+d x} \, dx}{2 (d e-c f)^4}-\frac{\left (b^2 d^2 f \log ^2(F)\right ) \int \frac{F^{a+\frac{b}{c+d x}}}{(c+d x) (e+f x)} \, dx}{2 (d e-c f)^3}\\ &=\frac{d^2 F^{a+\frac{b}{c+d x}}}{2 f (d e-c f)^2}-\frac{F^{a+\frac{b}{c+d x}}}{2 f (e+f x)^2}-\frac{b d^2 F^{a+\frac{b}{c+d x}} \log (F)}{2 (d e-c f)^3}+\frac{b d F^{a+\frac{b}{c+d x}} \log (F)}{2 (d e-c f)^2 (e+f x)}-\frac{b d^2 F^{a-\frac{b f}{d e-c f}} \text{Ei}\left (\frac{b d (e+f x) \log (F)}{(d e-c f) (c+d x)}\right ) \log (F)}{(d e-c f)^3}+\frac{\left (b^2 d^2 f \log ^2(F)\right ) \operatorname{Subst}\left (\int \frac{F^{a-\frac{b f}{d e-c f}+\frac{b d x}{d e-c f}}}{x} \, dx,x,\frac{e+f x}{c+d x}\right )}{2 (d e-c f)^4}\\ &=\frac{d^2 F^{a+\frac{b}{c+d x}}}{2 f (d e-c f)^2}-\frac{F^{a+\frac{b}{c+d x}}}{2 f (e+f x)^2}-\frac{b d^2 F^{a+\frac{b}{c+d x}} \log (F)}{2 (d e-c f)^3}+\frac{b d F^{a+\frac{b}{c+d x}} \log (F)}{2 (d e-c f)^2 (e+f x)}-\frac{b d^2 F^{a-\frac{b f}{d e-c f}} \text{Ei}\left (\frac{b d (e+f x) \log (F)}{(d e-c f) (c+d x)}\right ) \log (F)}{(d e-c f)^3}+\frac{b^2 d^2 f F^{a-\frac{b f}{d e-c f}} \text{Ei}\left (\frac{b d (e+f x) \log (F)}{(d e-c f) (c+d x)}\right ) \log ^2(F)}{2 (d e-c f)^4}\\ \end{align*}
Mathematica [F] time = 0.65279, size = 0, normalized size = 0. \[ \int \frac{F^{a+\frac{b}{c+d x}}}{(e+f x)^3} \, dx \]
Verification is Not applicable to the result.
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Maple [A] time = 0.15, size = 506, normalized size = 1.9 \begin{align*} -{\frac{ \left ( \ln \left ( F \right ) \right ) ^{2}{b}^{2}{d}^{2}f{F}^{a}}{2\, \left ( cf-de \right ) ^{4}}{F}^{{\frac{b}{dx+c}}} \left ({\frac{b\ln \left ( F \right ) }{dx+c}}+\ln \left ( F \right ) a-{\frac{\ln \left ( F \right ) acf}{cf-de}}+{\frac{\ln \left ( F \right ) ade}{cf-de}}-{\frac{\ln \left ( F \right ) bf}{cf-de}} \right ) ^{-2}}-{\frac{ \left ( \ln \left ( F \right ) \right ) ^{2}{b}^{2}{d}^{2}f{F}^{a}}{2\, \left ( cf-de \right ) ^{4}}{F}^{{\frac{b}{dx+c}}} \left ({\frac{b\ln \left ( F \right ) }{dx+c}}+\ln \left ( F \right ) a-{\frac{\ln \left ( F \right ) acf}{cf-de}}+{\frac{\ln \left ( F \right ) ade}{cf-de}}-{\frac{\ln \left ( F \right ) bf}{cf-de}} \right ) ^{-1}}-{\frac{ \left ( \ln \left ( F \right ) \right ) ^{2}{b}^{2}{d}^{2}f}{2\, \left ( cf-de \right ) ^{4}}{F}^{{\frac{acf-ade+bf}{cf-de}}}{\it Ei} \left ( 1,-{\frac{b\ln \left ( F \right ) }{dx+c}}-\ln \left ( F \right ) a-{\frac{-\ln \left ( F \right ) acf+\ln \left ( F \right ) ade-\ln \left ( F \right ) bf}{cf-de}} \right ) }-{\frac{\ln \left ( F \right ) b{d}^{2}{F}^{a}}{ \left ( cf-de \right ) ^{3}}{F}^{{\frac{b}{dx+c}}} \left ({\frac{b\ln \left ( F \right ) }{dx+c}}+\ln \left ( F \right ) a-{\frac{\ln \left ( F \right ) acf}{cf-de}}+{\frac{\ln \left ( F \right ) ade}{cf-de}}-{\frac{\ln \left ( F \right ) bf}{cf-de}} \right ) ^{-1}}-{\frac{\ln \left ( F \right ) b{d}^{2}}{ \left ( cf-de \right ) ^{3}}{F}^{{\frac{acf-ade+bf}{cf-de}}}{\it Ei} \left ( 1,-{\frac{b\ln \left ( F \right ) }{dx+c}}-\ln \left ( F \right ) a-{\frac{-\ln \left ( F \right ) acf+\ln \left ( F \right ) ade-\ln \left ( F \right ) bf}{cf-de}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{F^{a + \frac{b}{d x + c}}}{{\left (f x + e\right )}^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.63569, size = 1116, normalized size = 4.18 \begin{align*} \frac{{\left ({\left (b^{2} d^{2} f^{3} x^{2} + 2 \, b^{2} d^{2} e f^{2} x + b^{2} d^{2} e^{2} f\right )} \log \left (F\right )^{2} - 2 \,{\left (b d^{3} e^{3} - b c d^{2} e^{2} f +{\left (b d^{3} e f^{2} - b c d^{2} f^{3}\right )} x^{2} + 2 \,{\left (b d^{3} e^{2} f - b c d^{2} e f^{2}\right )} x\right )} \log \left (F\right )\right )} F^{\frac{a d e -{\left (a c + b\right )} f}{d e - c f}}{\rm Ei}\left (\frac{{\left (b d f x + b d e\right )} \log \left (F\right )}{c d e - c^{2} f +{\left (d^{2} e - c d f\right )} x}\right ) +{\left (2 \, c d^{3} e^{3} - 5 \, c^{2} d^{2} e^{2} f + 4 \, c^{3} d e f^{2} - c^{4} f^{3} +{\left (d^{4} e^{2} f - 2 \, c d^{3} e f^{2} + c^{2} d^{2} f^{3}\right )} x^{2} + 2 \,{\left (d^{4} e^{3} - 2 \, c d^{3} e^{2} f + c^{2} d^{2} e f^{2}\right )} x -{\left (b c d^{2} e^{2} f - b c^{2} d e f^{2} +{\left (b d^{3} e f^{2} - b c d^{2} f^{3}\right )} x^{2} +{\left (b d^{3} e^{2} f - b c^{2} d f^{3}\right )} x\right )} \log \left (F\right )\right )} F^{\frac{a d x + a c + b}{d x + c}}}{2 \,{\left (d^{4} e^{6} - 4 \, c d^{3} e^{5} f + 6 \, c^{2} d^{2} e^{4} f^{2} - 4 \, c^{3} d e^{3} f^{3} + c^{4} e^{2} f^{4} +{\left (d^{4} e^{4} f^{2} - 4 \, c d^{3} e^{3} f^{3} + 6 \, c^{2} d^{2} e^{2} f^{4} - 4 \, c^{3} d e f^{5} + c^{4} f^{6}\right )} x^{2} + 2 \,{\left (d^{4} e^{5} f - 4 \, c d^{3} e^{4} f^{2} + 6 \, c^{2} d^{2} e^{3} f^{3} - 4 \, c^{3} d e^{2} f^{4} + c^{4} e f^{5}\right )} x\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{F^{a + \frac{b}{d x + c}}}{{\left (f x + e\right )}^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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