3.109 \(\int f^{a+b x^3} x^3 \, dx\)

Optimal. Leaf size=34 \[ -\frac{x^4 f^a \text{Gamma}\left (\frac{4}{3},-b x^3 \log (f)\right )}{3 \left (-b x^3 \log (f)\right )^{4/3}} \]

[Out]

-(f^a*x^4*Gamma[4/3, -(b*x^3*Log[f])])/(3*(-(b*x^3*Log[f]))^(4/3))

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Rubi [A]  time = 0.0224622, antiderivative size = 34, normalized size of antiderivative = 1., number of steps used = 1, number of rules used = 1, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.077, Rules used = {2218} \[ -\frac{x^4 f^a \text{Gamma}\left (\frac{4}{3},-b x^3 \log (f)\right )}{3 \left (-b x^3 \log (f)\right )^{4/3}} \]

Antiderivative was successfully verified.

[In]

Int[f^(a + b*x^3)*x^3,x]

[Out]

-(f^a*x^4*Gamma[4/3, -(b*x^3*Log[f])])/(3*(-(b*x^3*Log[f]))^(4/3))

Rule 2218

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))*((e_.) + (f_.)*(x_))^(m_.), x_Symbol] :> -Simp[(F^a*(e + f*
x)^(m + 1)*Gamma[(m + 1)/n, -(b*(c + d*x)^n*Log[F])])/(f*n*(-(b*(c + d*x)^n*Log[F]))^((m + 1)/n)), x] /; FreeQ
[{F, a, b, c, d, e, f, m, n}, x] && EqQ[d*e - c*f, 0]

Rubi steps

\begin{align*} \int f^{a+b x^3} x^3 \, dx &=-\frac{f^a x^4 \Gamma \left (\frac{4}{3},-b x^3 \log (f)\right )}{3 \left (-b x^3 \log (f)\right )^{4/3}}\\ \end{align*}

Mathematica [A]  time = 0.0056656, size = 34, normalized size = 1. \[ -\frac{x^4 f^a \text{Gamma}\left (\frac{4}{3},-b x^3 \log (f)\right )}{3 \left (-b x^3 \log (f)\right )^{4/3}} \]

Antiderivative was successfully verified.

[In]

Integrate[f^(a + b*x^3)*x^3,x]

[Out]

-(f^a*x^4*Gamma[4/3, -(b*x^3*Log[f])])/(3*(-(b*x^3*Log[f]))^(4/3))

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Maple [B]  time = 0.025, size = 109, normalized size = 3.2 \begin{align*} -{\frac{{f}^{a}}{3\,b} \left ( -{\frac{2\,x\pi \,\sqrt{3}}{9\,b\Gamma \left ( 2/3 \right ) } \left ( -b \right ) ^{{\frac{4}{3}}}\sqrt [3]{\ln \left ( f \right ) }{\frac{1}{\sqrt [3]{-b{x}^{3}\ln \left ( f \right ) }}}}+{\frac{x{{\rm e}^{b{x}^{3}\ln \left ( f \right ) }}}{b} \left ( -b \right ) ^{{\frac{4}{3}}}\sqrt [3]{\ln \left ( f \right ) }}+{\frac{x}{3\,b} \left ( -b \right ) ^{{\frac{4}{3}}}\sqrt [3]{\ln \left ( f \right ) }\Gamma \left ({\frac{1}{3}},-b{x}^{3}\ln \left ( f \right ) \right ){\frac{1}{\sqrt [3]{-b{x}^{3}\ln \left ( f \right ) }}}} \right ) \left ( \ln \left ( f \right ) \right ) ^{-{\frac{4}{3}}}{\frac{1}{\sqrt [3]{-b}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(f^(b*x^3+a)*x^3,x)

[Out]

-1/3*f^a/b/ln(f)^(4/3)/(-b)^(1/3)*(-2/9*x*(-b)^(4/3)*ln(f)^(1/3)/b*Pi*3^(1/2)/GAMMA(2/3)/(-b*x^3*ln(f))^(1/3)+
x*(-b)^(4/3)*ln(f)^(1/3)/b*exp(b*x^3*ln(f))+1/3*x*(-b)^(4/3)*ln(f)^(1/3)/b/(-b*x^3*ln(f))^(1/3)*GAMMA(1/3,-b*x
^3*ln(f)))

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Maxima [A]  time = 1.27188, size = 38, normalized size = 1.12 \begin{align*} -\frac{f^{a} x^{4} \Gamma \left (\frac{4}{3}, -b x^{3} \log \left (f\right )\right )}{3 \, \left (-b x^{3} \log \left (f\right )\right )^{\frac{4}{3}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f^(b*x^3+a)*x^3,x, algorithm="maxima")

[Out]

-1/3*f^a*x^4*gamma(4/3, -b*x^3*log(f))/(-b*x^3*log(f))^(4/3)

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Fricas [A]  time = 1.82996, size = 134, normalized size = 3.94 \begin{align*} \frac{3 \, b f^{b x^{3} + a} x \log \left (f\right ) - \left (-b \log \left (f\right )\right )^{\frac{2}{3}} f^{a} \Gamma \left (\frac{1}{3}, -b x^{3} \log \left (f\right )\right )}{9 \, b^{2} \log \left (f\right )^{2}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f^(b*x^3+a)*x^3,x, algorithm="fricas")

[Out]

1/9*(3*b*f^(b*x^3 + a)*x*log(f) - (-b*log(f))^(2/3)*f^a*gamma(1/3, -b*x^3*log(f)))/(b^2*log(f)^2)

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int f^{a + b x^{3}} x^{3}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f**(b*x**3+a)*x**3,x)

[Out]

Integral(f**(a + b*x**3)*x**3, x)

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int f^{b x^{3} + a} x^{3}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f^(b*x^3+a)*x^3,x, algorithm="giac")

[Out]

integrate(f^(b*x^3 + a)*x^3, x)