Optimal. Leaf size=31 \[ \frac{\sqrt{1-x^2}}{5 x+4}+\frac{3}{5 (5 x+4)} \]
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Rubi [A] time = 0.654172, antiderivative size = 31, normalized size of antiderivative = 1., number of steps used = 31, number of rules used = 13, integrand size = 43, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.302, Rules used = {6742, 277, 216, 266, 50, 63, 206, 733, 844, 725, 735, 264, 731} \[ \frac{\sqrt{1-x^2}}{5 x+4}+\frac{3}{5 (5 x+4)} \]
Antiderivative was successfully verified.
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Rule 6742
Rule 277
Rule 216
Rule 266
Rule 50
Rule 63
Rule 206
Rule 733
Rule 844
Rule 725
Rule 735
Rule 264
Rule 731
Rubi steps
\begin{align*} \int \frac{-1+\sqrt{1-x^2}}{\sqrt{1-x^2} \left (2+x-2 \sqrt{1-x^2}\right )^2} \, dx &=\int \left (\frac{1}{\left (-2-x+2 \sqrt{1-x^2}\right )^2}-\frac{1}{\sqrt{1-x^2} \left (-2-x+2 \sqrt{1-x^2}\right )^2}\right ) \, dx\\ &=\int \frac{1}{\left (-2-x+2 \sqrt{1-x^2}\right )^2} \, dx-\int \frac{1}{\sqrt{1-x^2} \left (-2-x+2 \sqrt{1-x^2}\right )^2} \, dx\\ &=-\int \left (\frac{1}{2 x^2}-\frac{1}{x}+\frac{15}{2 (4+5 x)^2}+\frac{5}{4+5 x}+\frac{1}{2 x^2 \sqrt{1-x^2}}-\frac{1}{x \sqrt{1-x^2}}+\frac{9}{2 (4+5 x)^2 \sqrt{1-x^2}}+\frac{5}{(4+5 x) \sqrt{1-x^2}}\right ) \, dx+\int \left (\frac{1}{2 x^2}-\frac{1}{x}+\frac{9}{2 (4+5 x)^2}+\frac{5}{4+5 x}+\frac{\sqrt{1-x^2}}{2 x^2}-\frac{\sqrt{1-x^2}}{x}+\frac{15 \sqrt{1-x^2}}{2 (4+5 x)^2}+\frac{5 \sqrt{1-x^2}}{4+5 x}\right ) \, dx\\ &=\frac{3}{5 (4+5 x)}-\frac{1}{2} \int \frac{1}{x^2 \sqrt{1-x^2}} \, dx+\frac{1}{2} \int \frac{\sqrt{1-x^2}}{x^2} \, dx-\frac{9}{2} \int \frac{1}{(4+5 x)^2 \sqrt{1-x^2}} \, dx-5 \int \frac{1}{(4+5 x) \sqrt{1-x^2}} \, dx+5 \int \frac{\sqrt{1-x^2}}{4+5 x} \, dx+\frac{15}{2} \int \frac{\sqrt{1-x^2}}{(4+5 x)^2} \, dx+\int \frac{1}{x \sqrt{1-x^2}} \, dx-\int \frac{\sqrt{1-x^2}}{x} \, dx\\ &=\frac{3}{5 (4+5 x)}+\sqrt{1-x^2}+\frac{\sqrt{1-x^2}}{4+5 x}-\frac{1}{2} \int \frac{1}{\sqrt{1-x^2}} \, dx+\frac{1}{2} \operatorname{Subst}\left (\int \frac{1}{\sqrt{1-x} x} \, dx,x,x^2\right )-\frac{1}{2} \operatorname{Subst}\left (\int \frac{\sqrt{1-x}}{x} \, dx,x,x^2\right )-\frac{3}{2} \int \frac{x}{(4+5 x) \sqrt{1-x^2}} \, dx+2 \int \frac{1}{(4+5 x) \sqrt{1-x^2}} \, dx+5 \operatorname{Subst}\left (\int \frac{1}{9-x^2} \, dx,x,\frac{5+4 x}{\sqrt{1-x^2}}\right )+\int \frac{5+4 x}{(4+5 x) \sqrt{1-x^2}} \, dx\\ &=\frac{3}{5 (4+5 x)}+\frac{\sqrt{1-x^2}}{4+5 x}-\frac{1}{2} \sin ^{-1}(x)+\frac{5}{3} \tanh ^{-1}\left (\frac{5+4 x}{3 \sqrt{1-x^2}}\right )-\frac{3}{10} \int \frac{1}{\sqrt{1-x^2}} \, dx-\frac{1}{2} \operatorname{Subst}\left (\int \frac{1}{\sqrt{1-x} x} \, dx,x,x^2\right )+\frac{4}{5} \int \frac{1}{\sqrt{1-x^2}} \, dx+\frac{6}{5} \int \frac{1}{(4+5 x) \sqrt{1-x^2}} \, dx+\frac{9}{5} \int \frac{1}{(4+5 x) \sqrt{1-x^2}} \, dx-2 \operatorname{Subst}\left (\int \frac{1}{9-x^2} \, dx,x,\frac{5+4 x}{\sqrt{1-x^2}}\right )-\operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,\sqrt{1-x^2}\right )\\ &=\frac{3}{5 (4+5 x)}+\frac{\sqrt{1-x^2}}{4+5 x}+\tanh ^{-1}\left (\frac{5+4 x}{3 \sqrt{1-x^2}}\right )-\tanh ^{-1}\left (\sqrt{1-x^2}\right )-\frac{6}{5} \operatorname{Subst}\left (\int \frac{1}{9-x^2} \, dx,x,\frac{5+4 x}{\sqrt{1-x^2}}\right )-\frac{9}{5} \operatorname{Subst}\left (\int \frac{1}{9-x^2} \, dx,x,\frac{5+4 x}{\sqrt{1-x^2}}\right )+\operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,\sqrt{1-x^2}\right )\\ &=\frac{3}{5 (4+5 x)}+\frac{\sqrt{1-x^2}}{4+5 x}\\ \end{align*}
Mathematica [A] time = 0.18001, size = 23, normalized size = 0.74 \[ \frac{5 \sqrt{1-x^2}+3}{25 x+20} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.004, size = 32, normalized size = 1. \begin{align*}{\frac{1}{5}\sqrt{- \left ( x+{\frac{4}{5}} \right ) ^{2}+{\frac{8\,x}{5}}+{\frac{41}{25}}} \left ( x+{\frac{4}{5}} \right ) ^{-1}}+{\frac{3}{20+25\,x}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{1}{56} \, \sqrt{7} \log \left (\frac{3 \, x - 2 \, \sqrt{7} - 2}{3 \, x + 2 \, \sqrt{7} - 2}\right ) - \int -\frac{100 \, x^{7} + 285 \, x^{6} + 264 \, x^{5} + 80 \, x^{4}}{8 \,{\left (21 \, x^{9} + 278 \, x^{8} + 283 \, x^{7} - 2022 \, x^{6} - 3632 \, x^{5} + 2256 \, x^{4} + 7424 \, x^{3} + 1536 \, x^{2} - 8 \,{\left (9 \, x^{8} + 12 \, x^{7} - 101 \, x^{6} - 172 \, x^{5} + 284 \, x^{4} + 672 \, x^{3} + 64 \, x^{2} - 512 \, x - 256\right )} \sqrt{x + 1} \sqrt{-x + 1} - 4096 \, x - 2048\right )}}\,{d x} - \frac{1}{24} \, \log \left (x + 2\right ) + \frac{1}{16} \, \log \left (x + 1\right ) - \frac{1}{48} \, \log \left (x - 1\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.62737, size = 65, normalized size = 2.1 \begin{align*} \frac{25 \, x + 20 \, \sqrt{-x^{2} + 1} + 32}{20 \,{\left (5 \, x + 4\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{1 - x^{2}} - 1}{\sqrt{- \left (x - 1\right ) \left (x + 1\right )} \left (x - 2 \sqrt{1 - x^{2}} + 2\right )^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.23758, size = 92, normalized size = 2.97 \begin{align*} \frac{\frac{5 \,{\left (\sqrt{-x^{2} + 1} - 1\right )}}{x} - 4}{4 \,{\left (\frac{5 \,{\left (\sqrt{-x^{2} + 1} - 1\right )}}{x} - \frac{2 \,{\left (\sqrt{-x^{2} + 1} - 1\right )}^{2}}{x^{2}} - 2\right )}} + \frac{3}{5 \,{\left (5 \, x + 4\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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