Optimal. Leaf size=148 \[ -\frac{(4 a c+3 b) \left (c+d x^2\right ) \sqrt{\frac{a c+a d x^2+b}{c+d x^2}}}{8 a^2 d^2}+\frac{b (4 a c+3 b) \tanh ^{-1}\left (\frac{\sqrt{\frac{a c+a d x^2+b}{c+d x^2}}}{\sqrt{a}}\right )}{8 a^{5/2} d^2}+\frac{\left (c+d x^2\right )^2 \sqrt{\frac{a c+a d x^2+b}{c+d x^2}}}{4 a d^2} \]
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Rubi [A] time = 0.464804, antiderivative size = 189, normalized size of antiderivative = 1.28, number of steps used = 8, number of rules used = 8, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.381, Rules used = {6722, 1975, 446, 80, 50, 63, 217, 206} \[ -\frac{(4 a c+3 b) \left (a \left (c+d x^2\right )+b\right )}{8 a^2 d^2 \sqrt{a+\frac{b}{c+d x^2}}}+\frac{b (4 a c+3 b) \sqrt{a \left (c+d x^2\right )+b} \tanh ^{-1}\left (\frac{\sqrt{a} \sqrt{c+d x^2}}{\sqrt{a \left (c+d x^2\right )+b}}\right )}{8 a^{5/2} d^2 \sqrt{c+d x^2} \sqrt{a+\frac{b}{c+d x^2}}}+\frac{\left (c+d x^2\right ) \left (a \left (c+d x^2\right )+b\right )}{4 a d^2 \sqrt{a+\frac{b}{c+d x^2}}} \]
Antiderivative was successfully verified.
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Rule 6722
Rule 1975
Rule 446
Rule 80
Rule 50
Rule 63
Rule 217
Rule 206
Rubi steps
\begin{align*} \int \frac{x^3}{\sqrt{a+\frac{b}{c+d x^2}}} \, dx &=\frac{\sqrt{b+a \left (c+d x^2\right )} \int \frac{x^3 \sqrt{c+d x^2}}{\sqrt{b+a \left (c+d x^2\right )}} \, dx}{\sqrt{c+d x^2} \sqrt{a+\frac{b}{c+d x^2}}}\\ &=\frac{\sqrt{b+a \left (c+d x^2\right )} \int \frac{x^3 \sqrt{c+d x^2}}{\sqrt{b+a c+a d x^2}} \, dx}{\sqrt{c+d x^2} \sqrt{a+\frac{b}{c+d x^2}}}\\ &=\frac{\sqrt{b+a \left (c+d x^2\right )} \operatorname{Subst}\left (\int \frac{x \sqrt{c+d x}}{\sqrt{b+a c+a d x}} \, dx,x,x^2\right )}{2 \sqrt{c+d x^2} \sqrt{a+\frac{b}{c+d x^2}}}\\ &=\frac{\left (c+d x^2\right ) \left (b+a \left (c+d x^2\right )\right )}{4 a d^2 \sqrt{a+\frac{b}{c+d x^2}}}-\frac{\left ((3 b+4 a c) \sqrt{b+a \left (c+d x^2\right )}\right ) \operatorname{Subst}\left (\int \frac{\sqrt{c+d x}}{\sqrt{b+a c+a d x}} \, dx,x,x^2\right )}{8 a d \sqrt{c+d x^2} \sqrt{a+\frac{b}{c+d x^2}}}\\ &=-\frac{(3 b+4 a c) \left (b+a \left (c+d x^2\right )\right )}{8 a^2 d^2 \sqrt{a+\frac{b}{c+d x^2}}}+\frac{\left (c+d x^2\right ) \left (b+a \left (c+d x^2\right )\right )}{4 a d^2 \sqrt{a+\frac{b}{c+d x^2}}}+\frac{\left (b (3 b+4 a c) \sqrt{b+a \left (c+d x^2\right )}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{c+d x} \sqrt{b+a c+a d x}} \, dx,x,x^2\right )}{16 a^2 d \sqrt{c+d x^2} \sqrt{a+\frac{b}{c+d x^2}}}\\ &=-\frac{(3 b+4 a c) \left (b+a \left (c+d x^2\right )\right )}{8 a^2 d^2 \sqrt{a+\frac{b}{c+d x^2}}}+\frac{\left (c+d x^2\right ) \left (b+a \left (c+d x^2\right )\right )}{4 a d^2 \sqrt{a+\frac{b}{c+d x^2}}}+\frac{\left (b (3 b+4 a c) \sqrt{b+a \left (c+d x^2\right )}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{b+a x^2}} \, dx,x,\sqrt{c+d x^2}\right )}{8 a^2 d^2 \sqrt{c+d x^2} \sqrt{a+\frac{b}{c+d x^2}}}\\ &=-\frac{(3 b+4 a c) \left (b+a \left (c+d x^2\right )\right )}{8 a^2 d^2 \sqrt{a+\frac{b}{c+d x^2}}}+\frac{\left (c+d x^2\right ) \left (b+a \left (c+d x^2\right )\right )}{4 a d^2 \sqrt{a+\frac{b}{c+d x^2}}}+\frac{\left (b (3 b+4 a c) \sqrt{b+a \left (c+d x^2\right )}\right ) \operatorname{Subst}\left (\int \frac{1}{1-a x^2} \, dx,x,\frac{\sqrt{c+d x^2}}{\sqrt{b+a \left (c+d x^2\right )}}\right )}{8 a^2 d^2 \sqrt{c+d x^2} \sqrt{a+\frac{b}{c+d x^2}}}\\ &=-\frac{(3 b+4 a c) \left (b+a \left (c+d x^2\right )\right )}{8 a^2 d^2 \sqrt{a+\frac{b}{c+d x^2}}}+\frac{\left (c+d x^2\right ) \left (b+a \left (c+d x^2\right )\right )}{4 a d^2 \sqrt{a+\frac{b}{c+d x^2}}}+\frac{b (3 b+4 a c) \sqrt{b+a \left (c+d x^2\right )} \tanh ^{-1}\left (\frac{\sqrt{a} \sqrt{c+d x^2}}{\sqrt{b+a \left (c+d x^2\right )}}\right )}{8 a^{5/2} d^2 \sqrt{c+d x^2} \sqrt{a+\frac{b}{c+d x^2}}}\\ \end{align*}
Mathematica [A] time = 0.163918, size = 101, normalized size = 0.68 \[ \frac{b (4 a c+3 b) \tanh ^{-1}\left (\frac{\sqrt{a+\frac{b}{c+d x^2}}}{\sqrt{a}}\right )-\sqrt{a} \left (c+d x^2\right ) \sqrt{\frac{a c+a d x^2+b}{c+d x^2}} \left (2 a \left (c-d x^2\right )+3 b\right )}{8 a^{5/2} d^2} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.013, size = 354, normalized size = 2.4 \begin{align*}{\frac{d{x}^{2}+c}{16\,{a}^{2}{d}^{2}}\sqrt{{\frac{ad{x}^{2}+ac+b}{d{x}^{2}+c}}} \left ( 4\,\sqrt{a{d}^{2}{x}^{4}+2\,acd{x}^{2}+bd{x}^{2}+{c}^{2}a+bc}\sqrt{a{d}^{2}}{x}^{2}ad+4\,\ln \left ( 1/2\,{\frac{2\,a{d}^{2}{x}^{2}+2\,acd+2\,\sqrt{a{d}^{2}{x}^{4}+2\,acd{x}^{2}+bd{x}^{2}+{c}^{2}a+bc}\sqrt{a{d}^{2}}+bd}{\sqrt{a{d}^{2}}}} \right ) abcd-4\,\sqrt{a{d}^{2}{x}^{4}+2\,acd{x}^{2}+bd{x}^{2}+{c}^{2}a+bc}\sqrt{a{d}^{2}}ac+3\,\ln \left ( 1/2\,{\frac{2\,a{d}^{2}{x}^{2}+2\,acd+2\,\sqrt{a{d}^{2}{x}^{4}+2\,acd{x}^{2}+bd{x}^{2}+{c}^{2}a+bc}\sqrt{a{d}^{2}}+bd}{\sqrt{a{d}^{2}}}} \right ){b}^{2}d-6\,\sqrt{a{d}^{2}{x}^{4}+2\,acd{x}^{2}+bd{x}^{2}+{c}^{2}a+bc}\sqrt{a{d}^{2}}b \right ){\frac{1}{\sqrt{ \left ( d{x}^{2}+c \right ) \left ( ad{x}^{2}+ac+b \right ) }}}{\frac{1}{\sqrt{a{d}^{2}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.3725, size = 761, normalized size = 5.14 \begin{align*} \left [\frac{{\left (4 \, a b c + 3 \, b^{2}\right )} \sqrt{a} \log \left (8 \, a^{2} d^{2} x^{4} + 8 \, a^{2} c^{2} + 8 \,{\left (2 \, a^{2} c + a b\right )} d x^{2} + 8 \, a b c + b^{2} + 4 \,{\left (2 \, a d^{2} x^{4} +{\left (4 \, a c + b\right )} d x^{2} + 2 \, a c^{2} + b c\right )} \sqrt{a} \sqrt{\frac{a d x^{2} + a c + b}{d x^{2} + c}}\right ) + 4 \,{\left (2 \, a^{2} d^{2} x^{4} - 3 \, a b d x^{2} - 2 \, a^{2} c^{2} - 3 \, a b c\right )} \sqrt{\frac{a d x^{2} + a c + b}{d x^{2} + c}}}{32 \, a^{3} d^{2}}, -\frac{{\left (4 \, a b c + 3 \, b^{2}\right )} \sqrt{-a} \arctan \left (\frac{{\left (2 \, a d x^{2} + 2 \, a c + b\right )} \sqrt{-a} \sqrt{\frac{a d x^{2} + a c + b}{d x^{2} + c}}}{2 \,{\left (a^{2} d x^{2} + a^{2} c + a b\right )}}\right ) - 2 \,{\left (2 \, a^{2} d^{2} x^{4} - 3 \, a b d x^{2} - 2 \, a^{2} c^{2} - 3 \, a b c\right )} \sqrt{\frac{a d x^{2} + a c + b}{d x^{2} + c}}}{16 \, a^{3} d^{2}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{3}}{\sqrt{\frac{a c + a d x^{2} + b}{c + d x^{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.33666, size = 262, normalized size = 1.77 \begin{align*} \frac{1}{8} \, \sqrt{a d^{2} x^{4} + 2 \, a c d x^{2} + b d x^{2} + a c^{2} + b c}{\left (\frac{2 \, x^{2}}{a d \mathrm{sgn}\left (d x^{2} + c\right )} - \frac{2 \, a c d \mathrm{sgn}\left (d x^{2} + c\right ) + 3 \, b d \mathrm{sgn}\left (d x^{2} + c\right )}{a^{2} d^{3}}\right )} - \frac{{\left (4 \, a b c + 3 \, b^{2}\right )} \log \left ({\left | -2 \, a^{\frac{3}{2}} c d - 2 \,{\left (\sqrt{a d^{2}} x^{2} - \sqrt{a d^{2} x^{4} + 2 \, a c d x^{2} + b d x^{2} + a c^{2} + b c}\right )} a{\left | d \right |} - \sqrt{a} b d \right |}\right )}{16 \, a^{\frac{5}{2}} d{\left | d \right |} \mathrm{sgn}\left (d x^{2} + c\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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