Optimal. Leaf size=192 \[ -\frac{a c d \log \left (\sqrt [3]{b} x-\sqrt [3]{a+b x^3}\right )}{3 b^{2/3}}-\frac{2 a c d \tan ^{-1}\left (\frac{\frac{2 \sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}+1}{\sqrt{3}}\right )}{3 \sqrt{3} b^{2/3}}+\frac{1}{12} \sqrt [3]{a+b x^3} \left (6 c^2 x+8 c d x^2+3 d^2 x^3\right )+\frac{a c^2 x \left (\frac{b x^3}{a}+1\right )^{2/3} \, _2F_1\left (\frac{1}{3},\frac{2}{3};\frac{4}{3};-\frac{b x^3}{a}\right )}{2 \left (a+b x^3\right )^{2/3}}+\frac{a d^2 \sqrt [3]{a+b x^3}}{4 b} \]
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Rubi [A] time = 0.204067, antiderivative size = 245, normalized size of antiderivative = 1.28, number of steps used = 14, number of rules used = 13, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.684, Rules used = {1853, 1886, 261, 1893, 246, 245, 331, 292, 31, 634, 617, 204, 628} \[ -\frac{2 a c d \log \left (1-\frac{\sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}\right )}{9 b^{2/3}}+\frac{a c d \log \left (\frac{b^{2/3} x^2}{\left (a+b x^3\right )^{2/3}}+\frac{\sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}+1\right )}{9 b^{2/3}}-\frac{2 a c d \tan ^{-1}\left (\frac{\frac{2 \sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}+1}{\sqrt{3}}\right )}{3 \sqrt{3} b^{2/3}}+\frac{1}{12} \sqrt [3]{a+b x^3} \left (6 c^2 x+8 c d x^2+3 d^2 x^3\right )+\frac{a c^2 x \left (\frac{b x^3}{a}+1\right )^{2/3} \, _2F_1\left (\frac{1}{3},\frac{2}{3};\frac{4}{3};-\frac{b x^3}{a}\right )}{2 \left (a+b x^3\right )^{2/3}}+\frac{a d^2 \sqrt [3]{a+b x^3}}{4 b} \]
Antiderivative was successfully verified.
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Rule 1853
Rule 1886
Rule 261
Rule 1893
Rule 246
Rule 245
Rule 331
Rule 292
Rule 31
Rule 634
Rule 617
Rule 204
Rule 628
Rubi steps
\begin{align*} \int (c+d x)^2 \sqrt [3]{a+b x^3} \, dx &=\frac{1}{12} \sqrt [3]{a+b x^3} \left (6 c^2 x+8 c d x^2+3 d^2 x^3\right )+a \int \frac{\frac{c^2}{2}+\frac{2 c d x}{3}+\frac{d^2 x^2}{4}}{\left (a+b x^3\right )^{2/3}} \, dx\\ &=\frac{1}{12} \sqrt [3]{a+b x^3} \left (6 c^2 x+8 c d x^2+3 d^2 x^3\right )+a \int \frac{\frac{c^2}{2}+\frac{2 c d x}{3}}{\left (a+b x^3\right )^{2/3}} \, dx+\frac{1}{4} \left (a d^2\right ) \int \frac{x^2}{\left (a+b x^3\right )^{2/3}} \, dx\\ &=\frac{a d^2 \sqrt [3]{a+b x^3}}{4 b}+\frac{1}{12} \sqrt [3]{a+b x^3} \left (6 c^2 x+8 c d x^2+3 d^2 x^3\right )+a \int \left (\frac{c^2}{2 \left (a+b x^3\right )^{2/3}}+\frac{2 c d x}{3 \left (a+b x^3\right )^{2/3}}\right ) \, dx\\ &=\frac{a d^2 \sqrt [3]{a+b x^3}}{4 b}+\frac{1}{12} \sqrt [3]{a+b x^3} \left (6 c^2 x+8 c d x^2+3 d^2 x^3\right )+\frac{1}{2} \left (a c^2\right ) \int \frac{1}{\left (a+b x^3\right )^{2/3}} \, dx+\frac{1}{3} (2 a c d) \int \frac{x}{\left (a+b x^3\right )^{2/3}} \, dx\\ &=\frac{a d^2 \sqrt [3]{a+b x^3}}{4 b}+\frac{1}{12} \sqrt [3]{a+b x^3} \left (6 c^2 x+8 c d x^2+3 d^2 x^3\right )+\frac{1}{3} (2 a c d) \operatorname{Subst}\left (\int \frac{x}{1-b x^3} \, dx,x,\frac{x}{\sqrt [3]{a+b x^3}}\right )+\frac{\left (a c^2 \left (1+\frac{b x^3}{a}\right )^{2/3}\right ) \int \frac{1}{\left (1+\frac{b x^3}{a}\right )^{2/3}} \, dx}{2 \left (a+b x^3\right )^{2/3}}\\ &=\frac{a d^2 \sqrt [3]{a+b x^3}}{4 b}+\frac{1}{12} \sqrt [3]{a+b x^3} \left (6 c^2 x+8 c d x^2+3 d^2 x^3\right )+\frac{a c^2 x \left (1+\frac{b x^3}{a}\right )^{2/3} \, _2F_1\left (\frac{1}{3},\frac{2}{3};\frac{4}{3};-\frac{b x^3}{a}\right )}{2 \left (a+b x^3\right )^{2/3}}+\frac{(2 a c d) \operatorname{Subst}\left (\int \frac{1}{1-\sqrt [3]{b} x} \, dx,x,\frac{x}{\sqrt [3]{a+b x^3}}\right )}{9 \sqrt [3]{b}}-\frac{(2 a c d) \operatorname{Subst}\left (\int \frac{1-\sqrt [3]{b} x}{1+\sqrt [3]{b} x+b^{2/3} x^2} \, dx,x,\frac{x}{\sqrt [3]{a+b x^3}}\right )}{9 \sqrt [3]{b}}\\ &=\frac{a d^2 \sqrt [3]{a+b x^3}}{4 b}+\frac{1}{12} \sqrt [3]{a+b x^3} \left (6 c^2 x+8 c d x^2+3 d^2 x^3\right )+\frac{a c^2 x \left (1+\frac{b x^3}{a}\right )^{2/3} \, _2F_1\left (\frac{1}{3},\frac{2}{3};\frac{4}{3};-\frac{b x^3}{a}\right )}{2 \left (a+b x^3\right )^{2/3}}-\frac{2 a c d \log \left (1-\frac{\sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}\right )}{9 b^{2/3}}+\frac{(a c d) \operatorname{Subst}\left (\int \frac{\sqrt [3]{b}+2 b^{2/3} x}{1+\sqrt [3]{b} x+b^{2/3} x^2} \, dx,x,\frac{x}{\sqrt [3]{a+b x^3}}\right )}{9 b^{2/3}}-\frac{(a c d) \operatorname{Subst}\left (\int \frac{1}{1+\sqrt [3]{b} x+b^{2/3} x^2} \, dx,x,\frac{x}{\sqrt [3]{a+b x^3}}\right )}{3 \sqrt [3]{b}}\\ &=\frac{a d^2 \sqrt [3]{a+b x^3}}{4 b}+\frac{1}{12} \sqrt [3]{a+b x^3} \left (6 c^2 x+8 c d x^2+3 d^2 x^3\right )+\frac{a c^2 x \left (1+\frac{b x^3}{a}\right )^{2/3} \, _2F_1\left (\frac{1}{3},\frac{2}{3};\frac{4}{3};-\frac{b x^3}{a}\right )}{2 \left (a+b x^3\right )^{2/3}}-\frac{2 a c d \log \left (1-\frac{\sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}\right )}{9 b^{2/3}}+\frac{a c d \log \left (1+\frac{b^{2/3} x^2}{\left (a+b x^3\right )^{2/3}}+\frac{\sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}\right )}{9 b^{2/3}}+\frac{(2 a c d) \operatorname{Subst}\left (\int \frac{1}{-3-x^2} \, dx,x,1+\frac{2 \sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}\right )}{3 b^{2/3}}\\ &=\frac{a d^2 \sqrt [3]{a+b x^3}}{4 b}+\frac{1}{12} \sqrt [3]{a+b x^3} \left (6 c^2 x+8 c d x^2+3 d^2 x^3\right )-\frac{2 a c d \tan ^{-1}\left (\frac{1+\frac{2 \sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}}{\sqrt{3}}\right )}{3 \sqrt{3} b^{2/3}}+\frac{a c^2 x \left (1+\frac{b x^3}{a}\right )^{2/3} \, _2F_1\left (\frac{1}{3},\frac{2}{3};\frac{4}{3};-\frac{b x^3}{a}\right )}{2 \left (a+b x^3\right )^{2/3}}-\frac{2 a c d \log \left (1-\frac{\sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}\right )}{9 b^{2/3}}+\frac{a c d \log \left (1+\frac{b^{2/3} x^2}{\left (a+b x^3\right )^{2/3}}+\frac{\sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}\right )}{9 b^{2/3}}\\ \end{align*}
Mathematica [A] time = 0.0783356, size = 111, normalized size = 0.58 \[ \frac{\sqrt [3]{a+b x^3} \left (4 b c^2 x \, _2F_1\left (-\frac{1}{3},\frac{1}{3};\frac{4}{3};-\frac{b x^3}{a}\right )+d \left (4 b c x^2 \, _2F_1\left (-\frac{1}{3},\frac{2}{3};\frac{5}{3};-\frac{b x^3}{a}\right )+d \left (a+b x^3\right ) \sqrt [3]{\frac{b x^3}{a}+1}\right )\right )}{4 b \sqrt [3]{\frac{b x^3}{a}+1}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.03, size = 0, normalized size = 0. \begin{align*} \int \left ( dx+c \right ) ^{2}\sqrt [3]{b{x}^{3}+a}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b x^{3} + a\right )}^{\frac{1}{3}}{\left (d x + c\right )}^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 2.67772, size = 114, normalized size = 0.59 \begin{align*} \frac{\sqrt [3]{a} c^{2} x \Gamma \left (\frac{1}{3}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{3}, \frac{1}{3} \\ \frac{4}{3} \end{matrix}\middle |{\frac{b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac{4}{3}\right )} + \frac{2 \sqrt [3]{a} c d x^{2} \Gamma \left (\frac{2}{3}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{3}, \frac{2}{3} \\ \frac{5}{3} \end{matrix}\middle |{\frac{b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac{5}{3}\right )} + d^{2} \left (\begin{cases} \frac{\sqrt [3]{a} x^{3}}{3} & \text{for}\: b = 0 \\\frac{\left (a + b x^{3}\right )^{\frac{4}{3}}}{4 b} & \text{otherwise} \end{cases}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b x^{3} + a\right )}^{\frac{1}{3}}{\left (d x + c\right )}^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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