3.226 \(\int \frac{1}{(c+d x+e x^2) \sqrt{a+b x^4}} \, dx\)

Optimal. Leaf size=1605 \[ \text{result too large to display} \]

[Out]

-((e^2*ArcTan[(Sqrt[2]*Sqrt[-(b*d^4) + 4*b*c*d^2*e - 2*b*c^2*e^2 - 2*a*e^4 - b*d*Sqrt[d^2 - 4*c*e]*(d^2 - 2*c*
e)]*x)/(e*(d + Sqrt[d^2 - 4*c*e])*Sqrt[a + b*x^4])])/(Sqrt[2]*Sqrt[d^2 - 4*c*e]*Sqrt[-2*a*e^4 - b*(d^4 - 4*c*d
^2*e + 2*c^2*e^2 + d^3*Sqrt[d^2 - 4*c*e] - 2*c*d*e*Sqrt[d^2 - 4*c*e])])) + (e^2*ArcTan[(Sqrt[2]*Sqrt[-(b*d^4)
+ 4*b*c*d^2*e - 2*b*c^2*e^2 - 2*a*e^4 + b*d*Sqrt[d^2 - 4*c*e]*(d^2 - 2*c*e)]*x)/(e*(d - Sqrt[d^2 - 4*c*e])*Sqr
t[a + b*x^4])])/(Sqrt[2]*Sqrt[d^2 - 4*c*e]*Sqrt[-2*a*e^4 - b*(d^4 - 4*c*d^2*e + 2*c^2*e^2 - d^3*Sqrt[d^2 - 4*c
*e] + 2*c*d*e*Sqrt[d^2 - 4*c*e])]) - (e^2*ArcTanh[(4*a*e^2 + b*(d - Sqrt[d^2 - 4*c*e])^2*x^2)/(2*Sqrt[2]*Sqrt[
b*d^4 - 4*b*c*d^2*e + 2*b*c^2*e^2 + 2*a*e^4 - b*d*Sqrt[d^2 - 4*c*e]*(d^2 - 2*c*e)]*Sqrt[a + b*x^4])])/(Sqrt[2]
*Sqrt[d^2 - 4*c*e]*Sqrt[b*d^4 - 4*b*c*d^2*e + 2*b*c^2*e^2 + 2*a*e^4 - b*d*Sqrt[d^2 - 4*c*e]*(d^2 - 2*c*e)]) +
(e^2*ArcTanh[(4*a*e^2 + b*(d + Sqrt[d^2 - 4*c*e])^2*x^2)/(2*Sqrt[2]*Sqrt[b*d^4 - 4*b*c*d^2*e + 2*b*c^2*e^2 + 2
*a*e^4 + b*d*Sqrt[d^2 - 4*c*e]*(d^2 - 2*c*e)]*Sqrt[a + b*x^4])])/(Sqrt[2]*Sqrt[d^2 - 4*c*e]*Sqrt[b*d^4 - 4*b*c
*d^2*e + 2*b*c^2*e^2 + 2*a*e^4 + b*d*Sqrt[d^2 - 4*c*e]*(d^2 - 2*c*e)]) + (b^(1/4)*e*(d - Sqrt[d^2 - 4*c*e])*(S
qrt[a] + Sqrt[b]*x^2)*Sqrt[(a + b*x^4)/(Sqrt[a] + Sqrt[b]*x^2)^2]*EllipticF[2*ArcTan[(b^(1/4)*x)/a^(1/4)], 1/2
])/(2*a^(1/4)*Sqrt[d^2 - 4*c*e]*(2*Sqrt[a]*e^2 + Sqrt[b]*(d^2 - 2*c*e - d*Sqrt[d^2 - 4*c*e]))*Sqrt[a + b*x^4])
- (b^(1/4)*e*(d + Sqrt[d^2 - 4*c*e])*(Sqrt[a] + Sqrt[b]*x^2)*Sqrt[(a + b*x^4)/(Sqrt[a] + Sqrt[b]*x^2)^2]*Elli
pticF[2*ArcTan[(b^(1/4)*x)/a^(1/4)], 1/2])/(2*a^(1/4)*Sqrt[d^2 - 4*c*e]*(2*Sqrt[a]*e^2 + Sqrt[b]*(d^2 - 2*c*e
+ d*Sqrt[d^2 - 4*c*e]))*Sqrt[a + b*x^4]) + (e*(2*Sqrt[a]*e^2 - Sqrt[b]*(d^2 - 2*c*e - d*Sqrt[d^2 - 4*c*e]))*(S
qrt[a] + Sqrt[b]*x^2)*Sqrt[(a + b*x^4)/(Sqrt[a] + Sqrt[b]*x^2)^2]*EllipticPi[(2*Sqrt[a]*e^2 + Sqrt[b]*(d^2 - 2
*c*e - d*Sqrt[d^2 - 4*c*e]))^2/(4*Sqrt[a]*Sqrt[b]*e^2*(d - Sqrt[d^2 - 4*c*e])^2), 2*ArcTan[(b^(1/4)*x)/a^(1/4)
], 1/2])/(2*a^(1/4)*b^(1/4)*Sqrt[d^2 - 4*c*e]*(d - Sqrt[d^2 - 4*c*e])*(2*Sqrt[a]*e^2 + Sqrt[b]*(d^2 - 2*c*e -
d*Sqrt[d^2 - 4*c*e]))*Sqrt[a + b*x^4]) - (e*(2*Sqrt[a]*e^2 - Sqrt[b]*(d^2 - 2*c*e + d*Sqrt[d^2 - 4*c*e]))*(Sqr
t[a] + Sqrt[b]*x^2)*Sqrt[(a + b*x^4)/(Sqrt[a] + Sqrt[b]*x^2)^2]*EllipticPi[(2*Sqrt[a]*e^2 + Sqrt[b]*(d^2 - 2*c
*e + d*Sqrt[d^2 - 4*c*e]))^2/(4*Sqrt[a]*Sqrt[b]*e^2*(d + Sqrt[d^2 - 4*c*e])^2), 2*ArcTan[(b^(1/4)*x)/a^(1/4)],
1/2])/(2*a^(1/4)*b^(1/4)*Sqrt[d^2 - 4*c*e]*(d + Sqrt[d^2 - 4*c*e])*(2*Sqrt[a]*e^2 + Sqrt[b]*(d^2 - 2*c*e + d*
Sqrt[d^2 - 4*c*e]))*Sqrt[a + b*x^4])

________________________________________________________________________________________

Rubi [A]  time = 9.67962, antiderivative size = 1605, normalized size of antiderivative = 1., number of steps used = 16, number of rules used = 8, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {6728, 1725, 1217, 220, 1707, 1248, 725, 206} \[ \text{result too large to display} \]

Antiderivative was successfully verified.

[In]

Int[1/((c + d*x + e*x^2)*Sqrt[a + b*x^4]),x]

[Out]

-((e^2*ArcTan[(Sqrt[2]*Sqrt[-(b*d^4) + 4*b*c*d^2*e - 2*b*c^2*e^2 - 2*a*e^4 - b*d*Sqrt[d^2 - 4*c*e]*(d^2 - 2*c*
e)]*x)/(e*(d + Sqrt[d^2 - 4*c*e])*Sqrt[a + b*x^4])])/(Sqrt[2]*Sqrt[d^2 - 4*c*e]*Sqrt[-2*a*e^4 - b*(d^4 - 4*c*d
^2*e + 2*c^2*e^2 + d^3*Sqrt[d^2 - 4*c*e] - 2*c*d*e*Sqrt[d^2 - 4*c*e])])) + (e^2*ArcTan[(Sqrt[2]*Sqrt[-(b*d^4)
+ 4*b*c*d^2*e - 2*b*c^2*e^2 - 2*a*e^4 + b*d*Sqrt[d^2 - 4*c*e]*(d^2 - 2*c*e)]*x)/(e*(d - Sqrt[d^2 - 4*c*e])*Sqr
t[a + b*x^4])])/(Sqrt[2]*Sqrt[d^2 - 4*c*e]*Sqrt[-2*a*e^4 - b*(d^4 - 4*c*d^2*e + 2*c^2*e^2 - d^3*Sqrt[d^2 - 4*c
*e] + 2*c*d*e*Sqrt[d^2 - 4*c*e])]) - (e^2*ArcTanh[(4*a*e^2 + b*(d - Sqrt[d^2 - 4*c*e])^2*x^2)/(2*Sqrt[2]*Sqrt[
b*d^4 - 4*b*c*d^2*e + 2*b*c^2*e^2 + 2*a*e^4 - b*d*Sqrt[d^2 - 4*c*e]*(d^2 - 2*c*e)]*Sqrt[a + b*x^4])])/(Sqrt[2]
*Sqrt[d^2 - 4*c*e]*Sqrt[b*d^4 - 4*b*c*d^2*e + 2*b*c^2*e^2 + 2*a*e^4 - b*d*Sqrt[d^2 - 4*c*e]*(d^2 - 2*c*e)]) +
(e^2*ArcTanh[(4*a*e^2 + b*(d + Sqrt[d^2 - 4*c*e])^2*x^2)/(2*Sqrt[2]*Sqrt[b*d^4 - 4*b*c*d^2*e + 2*b*c^2*e^2 + 2
*a*e^4 + b*d*Sqrt[d^2 - 4*c*e]*(d^2 - 2*c*e)]*Sqrt[a + b*x^4])])/(Sqrt[2]*Sqrt[d^2 - 4*c*e]*Sqrt[b*d^4 - 4*b*c
*d^2*e + 2*b*c^2*e^2 + 2*a*e^4 + b*d*Sqrt[d^2 - 4*c*e]*(d^2 - 2*c*e)]) + (b^(1/4)*e*(d - Sqrt[d^2 - 4*c*e])*(S
qrt[a] + Sqrt[b]*x^2)*Sqrt[(a + b*x^4)/(Sqrt[a] + Sqrt[b]*x^2)^2]*EllipticF[2*ArcTan[(b^(1/4)*x)/a^(1/4)], 1/2
])/(2*a^(1/4)*Sqrt[d^2 - 4*c*e]*(2*Sqrt[a]*e^2 + Sqrt[b]*(d^2 - 2*c*e - d*Sqrt[d^2 - 4*c*e]))*Sqrt[a + b*x^4])
- (b^(1/4)*e*(d + Sqrt[d^2 - 4*c*e])*(Sqrt[a] + Sqrt[b]*x^2)*Sqrt[(a + b*x^4)/(Sqrt[a] + Sqrt[b]*x^2)^2]*Elli
pticF[2*ArcTan[(b^(1/4)*x)/a^(1/4)], 1/2])/(2*a^(1/4)*Sqrt[d^2 - 4*c*e]*(2*Sqrt[a]*e^2 + Sqrt[b]*(d^2 - 2*c*e
+ d*Sqrt[d^2 - 4*c*e]))*Sqrt[a + b*x^4]) + (e*(2*Sqrt[a]*e^2 - Sqrt[b]*(d^2 - 2*c*e - d*Sqrt[d^2 - 4*c*e]))*(S
qrt[a] + Sqrt[b]*x^2)*Sqrt[(a + b*x^4)/(Sqrt[a] + Sqrt[b]*x^2)^2]*EllipticPi[(2*Sqrt[a]*e^2 + Sqrt[b]*(d^2 - 2
*c*e - d*Sqrt[d^2 - 4*c*e]))^2/(4*Sqrt[a]*Sqrt[b]*e^2*(d - Sqrt[d^2 - 4*c*e])^2), 2*ArcTan[(b^(1/4)*x)/a^(1/4)
], 1/2])/(2*a^(1/4)*b^(1/4)*Sqrt[d^2 - 4*c*e]*(d - Sqrt[d^2 - 4*c*e])*(2*Sqrt[a]*e^2 + Sqrt[b]*(d^2 - 2*c*e -
d*Sqrt[d^2 - 4*c*e]))*Sqrt[a + b*x^4]) - (e*(2*Sqrt[a]*e^2 - Sqrt[b]*(d^2 - 2*c*e + d*Sqrt[d^2 - 4*c*e]))*(Sqr
t[a] + Sqrt[b]*x^2)*Sqrt[(a + b*x^4)/(Sqrt[a] + Sqrt[b]*x^2)^2]*EllipticPi[(2*Sqrt[a]*e^2 + Sqrt[b]*(d^2 - 2*c
*e + d*Sqrt[d^2 - 4*c*e]))^2/(4*Sqrt[a]*Sqrt[b]*e^2*(d + Sqrt[d^2 - 4*c*e])^2), 2*ArcTan[(b^(1/4)*x)/a^(1/4)],
1/2])/(2*a^(1/4)*b^(1/4)*Sqrt[d^2 - 4*c*e]*(d + Sqrt[d^2 - 4*c*e])*(2*Sqrt[a]*e^2 + Sqrt[b]*(d^2 - 2*c*e + d*
Sqrt[d^2 - 4*c*e]))*Sqrt[a + b*x^4])

Rule 6728

Int[(u_)/((a_.) + (b_.)*(x_)^(n_.) + (c_.)*(x_)^(n2_.)), x_Symbol] :> With[{v = RationalFunctionExpand[u/(a +
b*x^n + c*x^(2*n)), x]}, Int[v, x] /; SumQ[v]] /; FreeQ[{a, b, c}, x] && EqQ[n2, 2*n] && IGtQ[n, 0]

Rule 1725

Int[1/(((d_) + (e_.)*(x_))*Sqrt[(a_) + (c_.)*(x_)^4]), x_Symbol] :> Dist[d, Int[1/((d^2 - e^2*x^2)*Sqrt[a + c*
x^4]), x], x] - Dist[e, Int[x/((d^2 - e^2*x^2)*Sqrt[a + c*x^4]), x], x] /; FreeQ[{a, c, d, e}, x]

Rule 1217

Int[1/(((d_) + (e_.)*(x_)^2)*Sqrt[(a_) + (c_.)*(x_)^4]), x_Symbol] :> With[{q = Rt[c/a, 2]}, Dist[(c*d + a*e*q
)/(c*d^2 - a*e^2), Int[1/Sqrt[a + c*x^4], x], x] - Dist[(a*e*(e + d*q))/(c*d^2 - a*e^2), Int[(1 + q*x^2)/((d +
e*x^2)*Sqrt[a + c*x^4]), x], x]] /; FreeQ[{a, c, d, e}, x] && NeQ[c*d^2 + a*e^2, 0] && NeQ[c*d^2 - a*e^2, 0]
&& PosQ[c/a]

Rule 220

Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[b/a, 4]}, Simp[((1 + q^2*x^2)*Sqrt[(a + b*x^4)/(a*(
1 + q^2*x^2)^2)]*EllipticF[2*ArcTan[q*x], 1/2])/(2*q*Sqrt[a + b*x^4]), x]] /; FreeQ[{a, b}, x] && PosQ[b/a]

Rule 1707

Int[((A_) + (B_.)*(x_)^2)/(((d_) + (e_.)*(x_)^2)*Sqrt[(a_) + (c_.)*(x_)^4]), x_Symbol] :> With[{q = Rt[B/A, 2]
}, -Simp[((B*d - A*e)*ArcTan[(Rt[(c*d)/e + (a*e)/d, 2]*x)/Sqrt[a + c*x^4]])/(2*d*e*Rt[(c*d)/e + (a*e)/d, 2]),
x] + Simp[((B*d + A*e)*(A + B*x^2)*Sqrt[(A^2*(a + c*x^4))/(a*(A + B*x^2)^2)]*EllipticPi[Cancel[-((B*d - A*e)^2
/(4*d*e*A*B))], 2*ArcTan[q*x], 1/2])/(4*d*e*A*q*Sqrt[a + c*x^4]), x]] /; FreeQ[{a, c, d, e, A, B}, x] && NeQ[c
*d^2 + a*e^2, 0] && NeQ[c*d^2 - a*e^2, 0] && PosQ[c/a] && EqQ[c*A^2 - a*B^2, 0]

Rule 1248

Int[(x_)*((d_) + (e_.)*(x_)^2)^(q_.)*((a_) + (c_.)*(x_)^4)^(p_.), x_Symbol] :> Dist[1/2, Subst[Int[(d + e*x)^q
*(a + c*x^2)^p, x], x, x^2], x] /; FreeQ[{a, c, d, e, p, q}, x]

Rule 725

Int[1/(((d_) + (e_.)*(x_))*Sqrt[(a_) + (c_.)*(x_)^2]), x_Symbol] :> -Subst[Int[1/(c*d^2 + a*e^2 - x^2), x], x,
(a*e - c*d*x)/Sqrt[a + c*x^2]] /; FreeQ[{a, c, d, e}, x]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin{align*} \int \frac{1}{\left (c+d x+e x^2\right ) \sqrt{a+b x^4}} \, dx &=\int \left (\frac{2 e}{\sqrt{d^2-4 c e} \left (d-\sqrt{d^2-4 c e}+2 e x\right ) \sqrt{a+b x^4}}-\frac{2 e}{\sqrt{d^2-4 c e} \left (d+\sqrt{d^2-4 c e}+2 e x\right ) \sqrt{a+b x^4}}\right ) \, dx\\ &=\frac{(2 e) \int \frac{1}{\left (d-\sqrt{d^2-4 c e}+2 e x\right ) \sqrt{a+b x^4}} \, dx}{\sqrt{d^2-4 c e}}-\frac{(2 e) \int \frac{1}{\left (d+\sqrt{d^2-4 c e}+2 e x\right ) \sqrt{a+b x^4}} \, dx}{\sqrt{d^2-4 c e}}\\ &=-\frac{\left (4 e^2\right ) \int \frac{x}{\left (\left (d-\sqrt{d^2-4 c e}\right )^2-4 e^2 x^2\right ) \sqrt{a+b x^4}} \, dx}{\sqrt{d^2-4 c e}}+\frac{\left (4 e^2\right ) \int \frac{x}{\left (\left (d+\sqrt{d^2-4 c e}\right )^2-4 e^2 x^2\right ) \sqrt{a+b x^4}} \, dx}{\sqrt{d^2-4 c e}}-\left (2 e \left (1-\frac{d}{\sqrt{d^2-4 c e}}\right )\right ) \int \frac{1}{\left (\left (d-\sqrt{d^2-4 c e}\right )^2-4 e^2 x^2\right ) \sqrt{a+b x^4}} \, dx-\left (2 e \left (1+\frac{d}{\sqrt{d^2-4 c e}}\right )\right ) \int \frac{1}{\left (\left (d+\sqrt{d^2-4 c e}\right )^2-4 e^2 x^2\right ) \sqrt{a+b x^4}} \, dx\\ &=-\frac{\left (2 e^2\right ) \operatorname{Subst}\left (\int \frac{1}{\left (\left (d-\sqrt{d^2-4 c e}\right )^2-4 e^2 x\right ) \sqrt{a+b x^2}} \, dx,x,x^2\right )}{\sqrt{d^2-4 c e}}+\frac{\left (2 e^2\right ) \operatorname{Subst}\left (\int \frac{1}{\left (\left (d+\sqrt{d^2-4 c e}\right )^2-4 e^2 x\right ) \sqrt{a+b x^2}} \, dx,x,x^2\right )}{\sqrt{d^2-4 c e}}-\frac{\left (\sqrt{b} e \left (1-\frac{d}{\sqrt{d^2-4 c e}}\right )\right ) \int \frac{1}{\sqrt{a+b x^4}} \, dx}{2 \sqrt{a} e^2+\sqrt{b} \left (d^2-2 c e-d \sqrt{d^2-4 c e}\right )}-\frac{\left (4 \sqrt{a} e^3 \left (1-\frac{d}{\sqrt{d^2-4 c e}}\right )\right ) \int \frac{1+\frac{\sqrt{b} x^2}{\sqrt{a}}}{\left (\left (d-\sqrt{d^2-4 c e}\right )^2-4 e^2 x^2\right ) \sqrt{a+b x^4}} \, dx}{2 \sqrt{a} e^2+\sqrt{b} \left (d^2-2 c e-d \sqrt{d^2-4 c e}\right )}-\frac{\left (\sqrt{b} e \left (1+\frac{d}{\sqrt{d^2-4 c e}}\right )\right ) \int \frac{1}{\sqrt{a+b x^4}} \, dx}{2 \sqrt{a} e^2+\sqrt{b} \left (d^2-2 c e+d \sqrt{d^2-4 c e}\right )}-\frac{\left (4 \sqrt{a} e^3 \left (1+\frac{d}{\sqrt{d^2-4 c e}}\right )\right ) \int \frac{1+\frac{\sqrt{b} x^2}{\sqrt{a}}}{\left (\left (d+\sqrt{d^2-4 c e}\right )^2-4 e^2 x^2\right ) \sqrt{a+b x^4}} \, dx}{2 \sqrt{a} e^2+\sqrt{b} \left (d^2-2 c e+d \sqrt{d^2-4 c e}\right )}\\ &=-\frac{e^2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{-b d^4+4 b c d^2 e-2 b c^2 e^2-2 a e^4-b d \sqrt{d^2-4 c e} \left (d^2-2 c e\right )} x}{e \left (d+\sqrt{d^2-4 c e}\right ) \sqrt{a+b x^4}}\right )}{\sqrt{2} \sqrt{d^2-4 c e} \sqrt{-2 a e^4-b \left (d^4-4 c d^2 e+2 c^2 e^2+d^3 \sqrt{d^2-4 c e}-2 c d e \sqrt{d^2-4 c e}\right )}}+\frac{e^2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{-b d^4+4 b c d^2 e-2 b c^2 e^2-2 a e^4+b d \sqrt{d^2-4 c e} \left (d^2-2 c e\right )} x}{e \left (d-\sqrt{d^2-4 c e}\right ) \sqrt{a+b x^4}}\right )}{\sqrt{2} \sqrt{d^2-4 c e} \sqrt{-2 a e^4-b \left (d^4-4 c d^2 e+2 c^2 e^2-d^3 \sqrt{d^2-4 c e}+2 c d e \sqrt{d^2-4 c e}\right )}}-\frac{\sqrt [4]{b} e \left (1-\frac{d}{\sqrt{d^2-4 c e}}\right ) \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{2 \sqrt [4]{a} \left (2 \sqrt{a} e^2+\sqrt{b} \left (d^2-2 c e-d \sqrt{d^2-4 c e}\right )\right ) \sqrt{a+b x^4}}-\frac{\sqrt [4]{b} e \left (1+\frac{d}{\sqrt{d^2-4 c e}}\right ) \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{2 \sqrt [4]{a} \left (2 \sqrt{a} e^2+\sqrt{b} \left (d^2-2 c e+d \sqrt{d^2-4 c e}\right )\right ) \sqrt{a+b x^4}}-\frac{\sqrt [4]{a} e \left (1-\frac{d}{\sqrt{d^2-4 c e}}\right ) \left (4 e^2-\frac{\sqrt{b} \left (d-\sqrt{d^2-4 c e}\right )^2}{\sqrt{a}}\right ) \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} \Pi \left (\frac{\left (2 \sqrt{a} e^2+\sqrt{b} \left (d^2-2 c e-d \sqrt{d^2-4 c e}\right )\right )^2}{4 \sqrt{a} \sqrt{b} e^2 \left (d-\sqrt{d^2-4 c e}\right )^2};2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{4 \sqrt [4]{b} \left (d-\sqrt{d^2-4 c e}\right )^2 \left (2 \sqrt{a} e^2+\sqrt{b} \left (d^2-2 c e-d \sqrt{d^2-4 c e}\right )\right ) \sqrt{a+b x^4}}-\frac{\sqrt [4]{a} e \left (1+\frac{d}{\sqrt{d^2-4 c e}}\right ) \left (4 e^2-\frac{\sqrt{b} \left (d+\sqrt{d^2-4 c e}\right )^2}{\sqrt{a}}\right ) \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} \Pi \left (\frac{\left (2 \sqrt{a} e^2+\sqrt{b} \left (d^2-2 c e+d \sqrt{d^2-4 c e}\right )\right )^2}{4 \sqrt{a} \sqrt{b} e^2 \left (d+\sqrt{d^2-4 c e}\right )^2};2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{4 \sqrt [4]{b} \left (d+\sqrt{d^2-4 c e}\right )^2 \left (2 \sqrt{a} e^2+\sqrt{b} \left (d^2-2 c e+d \sqrt{d^2-4 c e}\right )\right ) \sqrt{a+b x^4}}+\frac{\left (2 e^2\right ) \operatorname{Subst}\left (\int \frac{1}{16 a e^4+b \left (d-\sqrt{d^2-4 c e}\right )^4-x^2} \, dx,x,\frac{-4 a e^2-b \left (d-\sqrt{d^2-4 c e}\right )^2 x^2}{\sqrt{a+b x^4}}\right )}{\sqrt{d^2-4 c e}}-\frac{\left (2 e^2\right ) \operatorname{Subst}\left (\int \frac{1}{16 a e^4+b \left (d+\sqrt{d^2-4 c e}\right )^4-x^2} \, dx,x,\frac{-4 a e^2-b \left (d+\sqrt{d^2-4 c e}\right )^2 x^2}{\sqrt{a+b x^4}}\right )}{\sqrt{d^2-4 c e}}\\ &=-\frac{e^2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{-b d^4+4 b c d^2 e-2 b c^2 e^2-2 a e^4-b d \sqrt{d^2-4 c e} \left (d^2-2 c e\right )} x}{e \left (d+\sqrt{d^2-4 c e}\right ) \sqrt{a+b x^4}}\right )}{\sqrt{2} \sqrt{d^2-4 c e} \sqrt{-2 a e^4-b \left (d^4-4 c d^2 e+2 c^2 e^2+d^3 \sqrt{d^2-4 c e}-2 c d e \sqrt{d^2-4 c e}\right )}}+\frac{e^2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{-b d^4+4 b c d^2 e-2 b c^2 e^2-2 a e^4+b d \sqrt{d^2-4 c e} \left (d^2-2 c e\right )} x}{e \left (d-\sqrt{d^2-4 c e}\right ) \sqrt{a+b x^4}}\right )}{\sqrt{2} \sqrt{d^2-4 c e} \sqrt{-2 a e^4-b \left (d^4-4 c d^2 e+2 c^2 e^2-d^3 \sqrt{d^2-4 c e}+2 c d e \sqrt{d^2-4 c e}\right )}}-\frac{e^2 \tanh ^{-1}\left (\frac{4 a e^2+b \left (d-\sqrt{d^2-4 c e}\right )^2 x^2}{2 \sqrt{2} \sqrt{b d^4-4 b c d^2 e+2 b c^2 e^2+2 a e^4-b d \sqrt{d^2-4 c e} \left (d^2-2 c e\right )} \sqrt{a+b x^4}}\right )}{\sqrt{2} \sqrt{d^2-4 c e} \sqrt{b d^4-4 b c d^2 e+2 b c^2 e^2+2 a e^4-b d \sqrt{d^2-4 c e} \left (d^2-2 c e\right )}}+\frac{e^2 \tanh ^{-1}\left (\frac{4 a e^2+b \left (d+\sqrt{d^2-4 c e}\right )^2 x^2}{2 \sqrt{2} \sqrt{b d^4-4 b c d^2 e+2 b c^2 e^2+2 a e^4+b d \sqrt{d^2-4 c e} \left (d^2-2 c e\right )} \sqrt{a+b x^4}}\right )}{\sqrt{2} \sqrt{d^2-4 c e} \sqrt{b d^4-4 b c d^2 e+2 b c^2 e^2+2 a e^4+b d \sqrt{d^2-4 c e} \left (d^2-2 c e\right )}}-\frac{\sqrt [4]{b} e \left (1-\frac{d}{\sqrt{d^2-4 c e}}\right ) \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{2 \sqrt [4]{a} \left (2 \sqrt{a} e^2+\sqrt{b} \left (d^2-2 c e-d \sqrt{d^2-4 c e}\right )\right ) \sqrt{a+b x^4}}-\frac{\sqrt [4]{b} e \left (1+\frac{d}{\sqrt{d^2-4 c e}}\right ) \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{2 \sqrt [4]{a} \left (2 \sqrt{a} e^2+\sqrt{b} \left (d^2-2 c e+d \sqrt{d^2-4 c e}\right )\right ) \sqrt{a+b x^4}}-\frac{\sqrt [4]{a} e \left (1-\frac{d}{\sqrt{d^2-4 c e}}\right ) \left (4 e^2-\frac{\sqrt{b} \left (d-\sqrt{d^2-4 c e}\right )^2}{\sqrt{a}}\right ) \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} \Pi \left (\frac{\left (2 \sqrt{a} e^2+\sqrt{b} \left (d^2-2 c e-d \sqrt{d^2-4 c e}\right )\right )^2}{4 \sqrt{a} \sqrt{b} e^2 \left (d-\sqrt{d^2-4 c e}\right )^2};2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{4 \sqrt [4]{b} \left (d-\sqrt{d^2-4 c e}\right )^2 \left (2 \sqrt{a} e^2+\sqrt{b} \left (d^2-2 c e-d \sqrt{d^2-4 c e}\right )\right ) \sqrt{a+b x^4}}-\frac{\sqrt [4]{a} e \left (1+\frac{d}{\sqrt{d^2-4 c e}}\right ) \left (4 e^2-\frac{\sqrt{b} \left (d+\sqrt{d^2-4 c e}\right )^2}{\sqrt{a}}\right ) \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} \Pi \left (\frac{\left (2 \sqrt{a} e^2+\sqrt{b} \left (d^2-2 c e+d \sqrt{d^2-4 c e}\right )\right )^2}{4 \sqrt{a} \sqrt{b} e^2 \left (d+\sqrt{d^2-4 c e}\right )^2};2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{4 \sqrt [4]{b} \left (d+\sqrt{d^2-4 c e}\right )^2 \left (2 \sqrt{a} e^2+\sqrt{b} \left (d^2-2 c e+d \sqrt{d^2-4 c e}\right )\right ) \sqrt{a+b x^4}}\\ \end{align*}

Mathematica [C]  time = 7.37276, size = 1416, normalized size = 0.88 \[ -\frac{i \sqrt{1-\frac{i \sqrt{b} x^2}{\sqrt{a}}} \sqrt{\frac{i \sqrt{b} x^2}{\sqrt{a}}+1} \Pi \left (-\frac{2 i \sqrt{a} e^2}{\sqrt{b} \left (-d^2+2 c e-\sqrt{d^4-4 c d^2 e}\right )};\left .i \sinh ^{-1}\left (\sqrt{\frac{i \sqrt{b}}{\sqrt{a}}} x\right )\right |-1\right ) d^2}{\sqrt{\frac{i \sqrt{b}}{\sqrt{a}}} e \left (-d^2+2 c e-\sqrt{d^4-4 c d^2 e}\right ) \left (\frac{d^2-2 c e+\sqrt{d^4-4 c d^2 e}}{2 e^2}-\frac{d^2-2 c e-\sqrt{d^4-4 c d^2 e}}{2 e^2}\right ) \sqrt{b x^4+a}}-\frac{i \sqrt{1-\frac{i \sqrt{b} x^2}{\sqrt{a}}} \sqrt{\frac{i \sqrt{b} x^2}{\sqrt{a}}+1} \Pi \left (-\frac{2 i \sqrt{a} e^2}{\sqrt{b} \left (-d^2+2 c e+\sqrt{d^4-4 c d^2 e}\right )};\left .i \sinh ^{-1}\left (\sqrt{\frac{i \sqrt{b}}{\sqrt{a}}} x\right )\right |-1\right ) d^2}{\sqrt{\frac{i \sqrt{b}}{\sqrt{a}}} e \left (-d^2+2 c e+\sqrt{d^4-4 c d^2 e}\right ) \left (\frac{d^2-2 c e-\sqrt{d^4-4 c d^2 e}}{2 e^2}-\frac{d^2-2 c e+\sqrt{d^4-4 c d^2 e}}{2 e^2}\right ) \sqrt{b x^4+a}}-\frac{\sqrt{2} e^2 \left (\frac{\tanh ^{-1}\left (\frac{2 a e^2+b \left (d^2-\sqrt{d^2-4 c e} d-2 c e\right ) x^2}{\sqrt{4 a e^4+b \left (2 d^4-2 \sqrt{d^2-4 c e} d^3-8 c e d^2+4 c e \sqrt{d^2-4 c e} d+4 c^2 e^2\right )} \sqrt{b x^4+a}}\right )}{2 \sqrt{2 a e^4+b \left (d^4-\sqrt{d^2-4 c e} d^3-4 c e d^2+2 c e \sqrt{d^2-4 c e} d+2 c^2 e^2\right )}}-\frac{\tanh ^{-1}\left (\frac{2 a e^2+b \left (d^2+\sqrt{d^2-4 c e} d-2 c e\right ) x^2}{\sqrt{4 a e^4+2 b \left (d^4+\sqrt{d^2-4 c e} d^3-4 c e d^2-2 c e \sqrt{d^2-4 c e} d+2 c^2 e^2\right )} \sqrt{b x^4+a}}\right )}{2 \sqrt{2 a e^4+b \left (d^4+\sqrt{d^2-4 c e} d^3-4 c e d^2-2 c e \sqrt{d^2-4 c e} d+2 c^2 e^2\right )}}\right )}{\sqrt{d^2-4 c e}}-\frac{i \sqrt{d^4-4 c d^2 e} \sqrt{1-\frac{i \sqrt{b} x^2}{\sqrt{a}}} \sqrt{\frac{i \sqrt{b} x^2}{\sqrt{a}}+1} \Pi \left (-\frac{2 i \sqrt{a} e^2}{\sqrt{b} \left (-d^2+2 c e-\sqrt{d^4-4 c d^2 e}\right )};\left .i \sinh ^{-1}\left (\sqrt{\frac{i \sqrt{b}}{\sqrt{a}}} x\right )\right |-1\right )}{\sqrt{\frac{i \sqrt{b}}{\sqrt{a}}} e \left (-d^2+2 c e-\sqrt{d^4-4 c d^2 e}\right ) \left (\frac{d^2-2 c e+\sqrt{d^4-4 c d^2 e}}{2 e^2}-\frac{d^2-2 c e-\sqrt{d^4-4 c d^2 e}}{2 e^2}\right ) \sqrt{b x^4+a}}+\frac{i \sqrt{d^4-4 c d^2 e} \sqrt{1-\frac{i \sqrt{b} x^2}{\sqrt{a}}} \sqrt{\frac{i \sqrt{b} x^2}{\sqrt{a}}+1} \Pi \left (-\frac{2 i \sqrt{a} e^2}{\sqrt{b} \left (-d^2+2 c e+\sqrt{d^4-4 c d^2 e}\right )};\left .i \sinh ^{-1}\left (\sqrt{\frac{i \sqrt{b}}{\sqrt{a}}} x\right )\right |-1\right )}{\sqrt{\frac{i \sqrt{b}}{\sqrt{a}}} e \left (-d^2+2 c e+\sqrt{d^4-4 c d^2 e}\right ) \left (\frac{d^2-2 c e-\sqrt{d^4-4 c d^2 e}}{2 e^2}-\frac{d^2-2 c e+\sqrt{d^4-4 c d^2 e}}{2 e^2}\right ) \sqrt{b x^4+a}} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[1/((c + d*x + e*x^2)*Sqrt[a + b*x^4]),x]

[Out]

-((Sqrt[2]*e^2*(ArcTanh[(2*a*e^2 + b*(d^2 - 2*c*e - d*Sqrt[d^2 - 4*c*e])*x^2)/(Sqrt[4*a*e^4 + b*(2*d^4 - 8*c*d
^2*e + 4*c^2*e^2 - 2*d^3*Sqrt[d^2 - 4*c*e] + 4*c*d*e*Sqrt[d^2 - 4*c*e])]*Sqrt[a + b*x^4])]/(2*Sqrt[2*a*e^4 + b
*(d^4 - 4*c*d^2*e + 2*c^2*e^2 - d^3*Sqrt[d^2 - 4*c*e] + 2*c*d*e*Sqrt[d^2 - 4*c*e])]) - ArcTanh[(2*a*e^2 + b*(d
^2 - 2*c*e + d*Sqrt[d^2 - 4*c*e])*x^2)/(Sqrt[4*a*e^4 + 2*b*(d^4 - 4*c*d^2*e + 2*c^2*e^2 + d^3*Sqrt[d^2 - 4*c*e
] - 2*c*d*e*Sqrt[d^2 - 4*c*e])]*Sqrt[a + b*x^4])]/(2*Sqrt[2*a*e^4 + b*(d^4 - 4*c*d^2*e + 2*c^2*e^2 + d^3*Sqrt[
d^2 - 4*c*e] - 2*c*d*e*Sqrt[d^2 - 4*c*e])])))/Sqrt[d^2 - 4*c*e]) - (I*d^2*Sqrt[1 - (I*Sqrt[b]*x^2)/Sqrt[a]]*Sq
rt[1 + (I*Sqrt[b]*x^2)/Sqrt[a]]*EllipticPi[((-2*I)*Sqrt[a]*e^2)/(Sqrt[b]*(-d^2 + 2*c*e - Sqrt[d^4 - 4*c*d^2*e]
)), I*ArcSinh[Sqrt[(I*Sqrt[b])/Sqrt[a]]*x], -1])/(Sqrt[(I*Sqrt[b])/Sqrt[a]]*e*(-d^2 + 2*c*e - Sqrt[d^4 - 4*c*d
^2*e])*(-(d^2 - 2*c*e - Sqrt[d^4 - 4*c*d^2*e])/(2*e^2) + (d^2 - 2*c*e + Sqrt[d^4 - 4*c*d^2*e])/(2*e^2))*Sqrt[a
+ b*x^4]) - (I*Sqrt[d^4 - 4*c*d^2*e]*Sqrt[1 - (I*Sqrt[b]*x^2)/Sqrt[a]]*Sqrt[1 + (I*Sqrt[b]*x^2)/Sqrt[a]]*Elli
pticPi[((-2*I)*Sqrt[a]*e^2)/(Sqrt[b]*(-d^2 + 2*c*e - Sqrt[d^4 - 4*c*d^2*e])), I*ArcSinh[Sqrt[(I*Sqrt[b])/Sqrt[
a]]*x], -1])/(Sqrt[(I*Sqrt[b])/Sqrt[a]]*e*(-d^2 + 2*c*e - Sqrt[d^4 - 4*c*d^2*e])*(-(d^2 - 2*c*e - Sqrt[d^4 - 4
*c*d^2*e])/(2*e^2) + (d^2 - 2*c*e + Sqrt[d^4 - 4*c*d^2*e])/(2*e^2))*Sqrt[a + b*x^4]) - (I*d^2*Sqrt[1 - (I*Sqrt
[b]*x^2)/Sqrt[a]]*Sqrt[1 + (I*Sqrt[b]*x^2)/Sqrt[a]]*EllipticPi[((-2*I)*Sqrt[a]*e^2)/(Sqrt[b]*(-d^2 + 2*c*e + S
qrt[d^4 - 4*c*d^2*e])), I*ArcSinh[Sqrt[(I*Sqrt[b])/Sqrt[a]]*x], -1])/(Sqrt[(I*Sqrt[b])/Sqrt[a]]*e*(-d^2 + 2*c*
e + Sqrt[d^4 - 4*c*d^2*e])*((d^2 - 2*c*e - Sqrt[d^4 - 4*c*d^2*e])/(2*e^2) - (d^2 - 2*c*e + Sqrt[d^4 - 4*c*d^2*
e])/(2*e^2))*Sqrt[a + b*x^4]) + (I*Sqrt[d^4 - 4*c*d^2*e]*Sqrt[1 - (I*Sqrt[b]*x^2)/Sqrt[a]]*Sqrt[1 + (I*Sqrt[b]
*x^2)/Sqrt[a]]*EllipticPi[((-2*I)*Sqrt[a]*e^2)/(Sqrt[b]*(-d^2 + 2*c*e + Sqrt[d^4 - 4*c*d^2*e])), I*ArcSinh[Sqr
t[(I*Sqrt[b])/Sqrt[a]]*x], -1])/(Sqrt[(I*Sqrt[b])/Sqrt[a]]*e*(-d^2 + 2*c*e + Sqrt[d^4 - 4*c*d^2*e])*((d^2 - 2*
c*e - Sqrt[d^4 - 4*c*d^2*e])/(2*e^2) - (d^2 - 2*c*e + Sqrt[d^4 - 4*c*d^2*e])/(2*e^2))*Sqrt[a + b*x^4])

________________________________________________________________________________________

Maple [C]  time = 0.069, size = 1153, normalized size = 0.7 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(e*x^2+d*x+c)/(b*x^4+a)^(1/2),x)

[Out]

-1/2/(-4*c*e+d^2)^(1/2)/(1/2*b/e^4*d^4-1/2*b/e^4*d^3*(-4*c*e+d^2)^(1/2)-2*b/e^3*c*d^2+b/e^3*(-4*c*e+d^2)^(1/2)
*c*d+b/e^2*c^2+a)^(1/2)*arctanh(1/2/(1/2*b/e^4*d^4-1/2*b/e^4*d^3*(-4*c*e+d^2)^(1/2)-2*b/e^3*c*d^2+b/e^3*(-4*c*
e+d^2)^(1/2)*c*d+b/e^2*c^2+a)^(1/2)/(b*x^4+a)^(1/2)*b*x^2/e^2*d^2-1/2/(1/2*b/e^4*d^4-1/2*b/e^4*d^3*(-4*c*e+d^2
)^(1/2)-2*b/e^3*c*d^2+b/e^3*(-4*c*e+d^2)^(1/2)*c*d+b/e^2*c^2+a)^(1/2)/(b*x^4+a)^(1/2)*b*x^2/e^2*d*(-4*c*e+d^2)
^(1/2)-1/(1/2*b/e^4*d^4-1/2*b/e^4*d^3*(-4*c*e+d^2)^(1/2)-2*b/e^3*c*d^2+b/e^3*(-4*c*e+d^2)^(1/2)*c*d+b/e^2*c^2+
a)^(1/2)/(b*x^4+a)^(1/2)*b*x^2/e*c+1/(1/2*b/e^4*d^4-1/2*b/e^4*d^3*(-4*c*e+d^2)^(1/2)-2*b/e^3*c*d^2+b/e^3*(-4*c
*e+d^2)^(1/2)*c*d+b/e^2*c^2+a)^(1/2)/(b*x^4+a)^(1/2)*a)-2/(-4*c*e+d^2)^(1/2)/(I/a^(1/2)*b^(1/2))^(1/2)*e/(-d+(
-4*c*e+d^2)^(1/2))*(1-I/a^(1/2)*b^(1/2)*x^2)^(1/2)*(1+I/a^(1/2)*b^(1/2)*x^2)^(1/2)/(b*x^4+a)^(1/2)*EllipticPi(
x*(I/a^(1/2)*b^(1/2))^(1/2),-4*I*a^(1/2)/b^(1/2)*e^2/(-d+(-4*c*e+d^2)^(1/2))^2,(-I/a^(1/2)*b^(1/2))^(1/2)/(I/a
^(1/2)*b^(1/2))^(1/2))+1/2/(-4*c*e+d^2)^(1/2)/(1/2*b/e^4*d^4+1/2*b/e^4*d^3*(-4*c*e+d^2)^(1/2)-2*b/e^3*c*d^2-b/
e^3*(-4*c*e+d^2)^(1/2)*c*d+b/e^2*c^2+a)^(1/2)*arctanh(1/2/(1/2*b/e^4*d^4+1/2*b/e^4*d^3*(-4*c*e+d^2)^(1/2)-2*b/
e^3*c*d^2-b/e^3*(-4*c*e+d^2)^(1/2)*c*d+b/e^2*c^2+a)^(1/2)/(b*x^4+a)^(1/2)*b*x^2/e^2*d^2+1/2/(1/2*b/e^4*d^4+1/2
*b/e^4*d^3*(-4*c*e+d^2)^(1/2)-2*b/e^3*c*d^2-b/e^3*(-4*c*e+d^2)^(1/2)*c*d+b/e^2*c^2+a)^(1/2)/(b*x^4+a)^(1/2)*b*
x^2/e^2*d*(-4*c*e+d^2)^(1/2)-1/(1/2*b/e^4*d^4+1/2*b/e^4*d^3*(-4*c*e+d^2)^(1/2)-2*b/e^3*c*d^2-b/e^3*(-4*c*e+d^2
)^(1/2)*c*d+b/e^2*c^2+a)^(1/2)/(b*x^4+a)^(1/2)*b*x^2/e*c+1/(1/2*b/e^4*d^4+1/2*b/e^4*d^3*(-4*c*e+d^2)^(1/2)-2*b
/e^3*c*d^2-b/e^3*(-4*c*e+d^2)^(1/2)*c*d+b/e^2*c^2+a)^(1/2)/(b*x^4+a)^(1/2)*a)-2/(-4*c*e+d^2)^(1/2)/(I/a^(1/2)*
b^(1/2))^(1/2)/(d+(-4*c*e+d^2)^(1/2))*e*(1-I/a^(1/2)*b^(1/2)*x^2)^(1/2)*(1+I/a^(1/2)*b^(1/2)*x^2)^(1/2)/(b*x^4
+a)^(1/2)*EllipticPi(x*(I/a^(1/2)*b^(1/2))^(1/2),-4*I*a^(1/2)/b^(1/2)/(d+(-4*c*e+d^2)^(1/2))^2*e^2,(-I/a^(1/2)
*b^(1/2))^(1/2)/(I/a^(1/2)*b^(1/2))^(1/2))

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\sqrt{b x^{4} + a}{\left (e x^{2} + d x + c\right )}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x^2+d*x+c)/(b*x^4+a)^(1/2),x, algorithm="maxima")

[Out]

integrate(1/(sqrt(b*x^4 + a)*(e*x^2 + d*x + c)), x)

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Fricas [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x^2+d*x+c)/(b*x^4+a)^(1/2),x, algorithm="fricas")

[Out]

Timed out

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\sqrt{a + b x^{4}} \left (c + d x + e x^{2}\right )}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x**2+d*x+c)/(b*x**4+a)**(1/2),x)

[Out]

Integral(1/(sqrt(a + b*x**4)*(c + d*x + e*x**2)), x)

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\sqrt{b x^{4} + a}{\left (e x^{2} + d x + c\right )}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x^2+d*x+c)/(b*x^4+a)^(1/2),x, algorithm="giac")

[Out]

integrate(1/(sqrt(b*x^4 + a)*(e*x^2 + d*x + c)), x)