3.61 \(\int \frac{1}{8+24 x+8 x^2-15 x^3+8 x^4} \, dx\)

Optimal. Leaf size=263 \[ \frac{1}{4} \sqrt{\frac{3}{13}} \tan ^{-1}\left (\frac{-5 x^2+12 x+8}{\sqrt{39} x^2}\right )-\frac{1}{8} \sqrt{\frac{235 \sqrt{517}-5167}{40326}} \log \left (\left (\frac{4}{x}+3\right )^2-\sqrt{2 \left (19+\sqrt{517}\right )} \left (\frac{4}{x}+3\right )+\sqrt{517}\right )+\frac{1}{8} \sqrt{\frac{235 \sqrt{517}-5167}{40326}} \log \left (\left (\frac{4}{x}+3\right )^2+\sqrt{2 \left (19+\sqrt{517}\right )} \left (\frac{4}{x}+3\right )+\sqrt{517}\right )-\frac{1}{4} \sqrt{\frac{5167+235 \sqrt{517}}{40326}} \tan ^{-1}\left (\frac{\frac{8}{x}-\sqrt{2 \left (19+\sqrt{517}\right )}+6}{\sqrt{2 \left (\sqrt{517}-19\right )}}\right )-\frac{1}{4} \sqrt{\frac{5167+235 \sqrt{517}}{40326}} \tan ^{-1}\left (\frac{\frac{8}{x}+\sqrt{2 \left (19+\sqrt{517}\right )}+6}{\sqrt{2 \left (\sqrt{517}-19\right )}}\right ) \]

[Out]

-(Sqrt[(5167 + 235*Sqrt[517])/40326]*ArcTan[(6 - Sqrt[2*(19 + Sqrt[517])] + 8/x)/Sqrt[2*(-19 + Sqrt[517])]])/4
- (Sqrt[(5167 + 235*Sqrt[517])/40326]*ArcTan[(6 + Sqrt[2*(19 + Sqrt[517])] + 8/x)/Sqrt[2*(-19 + Sqrt[517])]])
/4 + (Sqrt[3/13]*ArcTan[(8 + 12*x - 5*x^2)/(Sqrt[39]*x^2)])/4 - (Sqrt[(-5167 + 235*Sqrt[517])/40326]*Log[Sqrt[
517] - Sqrt[2*(19 + Sqrt[517])]*(3 + 4/x) + (3 + 4/x)^2])/8 + (Sqrt[(-5167 + 235*Sqrt[517])/40326]*Log[Sqrt[51
7] + Sqrt[2*(19 + Sqrt[517])]*(3 + 4/x) + (3 + 4/x)^2])/8

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Rubi [A]  time = 0.492824, antiderivative size = 263, normalized size of antiderivative = 1., number of steps used = 16, number of rules used = 9, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.409, Rules used = {2069, 12, 1673, 1169, 634, 618, 204, 628, 1107} \[ \frac{1}{4} \sqrt{\frac{3}{13}} \tan ^{-1}\left (\frac{-5 x^2+12 x+8}{\sqrt{39} x^2}\right )-\frac{1}{8} \sqrt{\frac{235 \sqrt{517}-5167}{40326}} \log \left (\left (\frac{4}{x}+3\right )^2-\sqrt{2 \left (19+\sqrt{517}\right )} \left (\frac{4}{x}+3\right )+\sqrt{517}\right )+\frac{1}{8} \sqrt{\frac{235 \sqrt{517}-5167}{40326}} \log \left (\left (\frac{4}{x}+3\right )^2+\sqrt{2 \left (19+\sqrt{517}\right )} \left (\frac{4}{x}+3\right )+\sqrt{517}\right )-\frac{1}{4} \sqrt{\frac{5167+235 \sqrt{517}}{40326}} \tan ^{-1}\left (\frac{\frac{8}{x}-\sqrt{2 \left (19+\sqrt{517}\right )}+6}{\sqrt{2 \left (\sqrt{517}-19\right )}}\right )-\frac{1}{4} \sqrt{\frac{5167+235 \sqrt{517}}{40326}} \tan ^{-1}\left (\frac{\frac{8}{x}+\sqrt{2 \left (19+\sqrt{517}\right )}+6}{\sqrt{2 \left (\sqrt{517}-19\right )}}\right ) \]

Antiderivative was successfully verified.

[In]

Int[(8 + 24*x + 8*x^2 - 15*x^3 + 8*x^4)^(-1),x]

[Out]

-(Sqrt[(5167 + 235*Sqrt[517])/40326]*ArcTan[(6 - Sqrt[2*(19 + Sqrt[517])] + 8/x)/Sqrt[2*(-19 + Sqrt[517])]])/4
- (Sqrt[(5167 + 235*Sqrt[517])/40326]*ArcTan[(6 + Sqrt[2*(19 + Sqrt[517])] + 8/x)/Sqrt[2*(-19 + Sqrt[517])]])
/4 + (Sqrt[3/13]*ArcTan[(8 + 12*x - 5*x^2)/(Sqrt[39]*x^2)])/4 - (Sqrt[(-5167 + 235*Sqrt[517])/40326]*Log[Sqrt[
517] - Sqrt[2*(19 + Sqrt[517])]*(3 + 4/x) + (3 + 4/x)^2])/8 + (Sqrt[(-5167 + 235*Sqrt[517])/40326]*Log[Sqrt[51
7] + Sqrt[2*(19 + Sqrt[517])]*(3 + 4/x) + (3 + 4/x)^2])/8

Rule 2069

Int[(P4_)^(p_), x_Symbol] :> With[{a = Coeff[P4, x, 0], b = Coeff[P4, x, 1], c = Coeff[P4, x, 2], d = Coeff[P4
, x, 3], e = Coeff[P4, x, 4]}, Dist[-16*a^2, Subst[Int[(1*((a*(-3*b^4 + 16*a*b^2*c - 64*a^2*b*d + 256*a^3*e -
32*a^2*(3*b^2 - 8*a*c)*x^2 + 256*a^4*x^4))/(b - 4*a*x)^4)^p)/(b - 4*a*x)^2, x], x, b/(4*a) + 1/x], x] /; NeQ[a
, 0] && NeQ[b, 0] && EqQ[b^3 - 4*a*b*c + 8*a^2*d, 0]] /; FreeQ[p, x] && PolyQ[P4, x, 4] && IntegerQ[2*p] &&  !
IGtQ[p, 0]

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 1673

Int[(Pq_)*((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4)^(p_), x_Symbol] :> Module[{q = Expon[Pq, x], k}, Int[Sum[Coeff[
Pq, x, 2*k]*x^(2*k), {k, 0, q/2}]*(a + b*x^2 + c*x^4)^p, x] + Int[x*Sum[Coeff[Pq, x, 2*k + 1]*x^(2*k), {k, 0,
(q - 1)/2}]*(a + b*x^2 + c*x^4)^p, x]] /; FreeQ[{a, b, c, p}, x] && PolyQ[Pq, x] &&  !PolyQ[Pq, x^2]

Rule 1169

Int[((d_) + (e_.)*(x_)^2)/((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[a/c, 2]}, With[{r =
Rt[2*q - b/c, 2]}, Dist[1/(2*c*q*r), Int[(d*r - (d - e*q)*x)/(q - r*x + x^2), x], x] + Dist[1/(2*c*q*r), Int[(
d*r + (d - e*q)*x)/(q + r*x + x^2), x], x]]] /; FreeQ[{a, b, c, d, e}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2
- b*d*e + a*e^2, 0] && NegQ[b^2 - 4*a*c]

Rule 634

Int[((d_.) + (e_.)*(x_))/((a_) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Dist[(2*c*d - b*e)/(2*c), Int[1/(a +
b*x + c*x^2), x], x] + Dist[e/(2*c), Int[(b + 2*c*x)/(a + b*x + c*x^2), x], x] /; FreeQ[{a, b, c, d, e}, x] &
& NeQ[2*c*d - b*e, 0] && NeQ[b^2 - 4*a*c, 0] &&  !NiceSqrtQ[b^2 - 4*a*c]

Rule 618

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Dist[-2, Subst[Int[1/Simp[b^2 - 4*a*c - x^2, x], x]
, x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 628

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[(d*Log[RemoveContent[a + b*x +
c*x^2, x]])/b, x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rule 1107

Int[(x_)*((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4)^(p_.), x_Symbol] :> Dist[1/2, Subst[Int[(a + b*x + c*x^2)^p, x],
x, x^2], x] /; FreeQ[{a, b, c, p}, x]

Rubi steps

\begin{align*} \int \frac{1}{8+24 x+8 x^2-15 x^3+8 x^4} \, dx &=-\left (1024 \operatorname{Subst}\left (\int \frac{(24-32 x)^2}{8 \left (2117632-2490368 x^2+1048576 x^4\right )} \, dx,x,\frac{3}{4}+\frac{1}{x}\right )\right )\\ &=-\left (128 \operatorname{Subst}\left (\int \frac{(24-32 x)^2}{2117632-2490368 x^2+1048576 x^4} \, dx,x,\frac{3}{4}+\frac{1}{x}\right )\right )\\ &=-\left (128 \operatorname{Subst}\left (\int -\frac{1536 x}{2117632-2490368 x^2+1048576 x^4} \, dx,x,\frac{3}{4}+\frac{1}{x}\right )\right )-128 \operatorname{Subst}\left (\int \frac{576+1024 x^2}{2117632-2490368 x^2+1048576 x^4} \, dx,x,\frac{3}{4}+\frac{1}{x}\right )\\ &=196608 \operatorname{Subst}\left (\int \frac{x}{2117632-2490368 x^2+1048576 x^4} \, dx,x,\frac{3}{4}+\frac{1}{x}\right )-\frac{\operatorname{Subst}\left (\int \frac{144 \sqrt{2 \left (19+\sqrt{517}\right )}-\left (576-64 \sqrt{517}\right ) x}{\frac{\sqrt{517}}{16}-\frac{1}{2} \sqrt{\frac{1}{2} \left (19+\sqrt{517}\right )} x+x^2} \, dx,x,\frac{3}{4}+\frac{1}{x}\right )}{256 \sqrt{1034 \left (19+\sqrt{517}\right )}}-\frac{\operatorname{Subst}\left (\int \frac{144 \sqrt{2 \left (19+\sqrt{517}\right )}+\left (576-64 \sqrt{517}\right ) x}{\frac{\sqrt{517}}{16}+\frac{1}{2} \sqrt{\frac{1}{2} \left (19+\sqrt{517}\right )} x+x^2} \, dx,x,\frac{3}{4}+\frac{1}{x}\right )}{256 \sqrt{1034 \left (19+\sqrt{517}\right )}}\\ &=98304 \operatorname{Subst}\left (\int \frac{1}{2117632-2490368 x+1048576 x^2} \, dx,x,\left (\frac{3}{4}+\frac{1}{x}\right )^2\right )-\frac{\left (517+9 \sqrt{517}\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{\sqrt{517}}{16}-\frac{1}{2} \sqrt{\frac{1}{2} \left (19+\sqrt{517}\right )} x+x^2} \, dx,x,\frac{3}{4}+\frac{1}{x}\right )}{16544}-\frac{\left (517+9 \sqrt{517}\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{\sqrt{517}}{16}+\frac{1}{2} \sqrt{\frac{1}{2} \left (19+\sqrt{517}\right )} x+x^2} \, dx,x,\frac{3}{4}+\frac{1}{x}\right )}{16544}-\frac{1}{8} \sqrt{\frac{-5167+235 \sqrt{517}}{40326}} \operatorname{Subst}\left (\int \frac{-\frac{1}{2} \sqrt{\frac{1}{2} \left (19+\sqrt{517}\right )}+2 x}{\frac{\sqrt{517}}{16}-\frac{1}{2} \sqrt{\frac{1}{2} \left (19+\sqrt{517}\right )} x+x^2} \, dx,x,\frac{3}{4}+\frac{1}{x}\right )+\frac{1}{8} \sqrt{\frac{-5167+235 \sqrt{517}}{40326}} \operatorname{Subst}\left (\int \frac{\frac{1}{2} \sqrt{\frac{1}{2} \left (19+\sqrt{517}\right )}+2 x}{\frac{\sqrt{517}}{16}+\frac{1}{2} \sqrt{\frac{1}{2} \left (19+\sqrt{517}\right )} x+x^2} \, dx,x,\frac{3}{4}+\frac{1}{x}\right )\\ &=-\frac{1}{8} \sqrt{\frac{-5167+235 \sqrt{517}}{40326}} \log \left (\sqrt{517}-\sqrt{2 \left (19+\sqrt{517}\right )} \left (3+\frac{4}{x}\right )+\left (3+\frac{4}{x}\right )^2\right )+\frac{1}{8} \sqrt{\frac{-5167+235 \sqrt{517}}{40326}} \log \left (\sqrt{517}+\sqrt{2 \left (19+\sqrt{517}\right )} \left (3+\frac{4}{x}\right )+\left (3+\frac{4}{x}\right )^2\right )-196608 \operatorname{Subst}\left (\int \frac{1}{-2680059592704-x^2} \, dx,x,-2490368+2097152 \left (\frac{3}{4}+\frac{1}{x}\right )^2\right )+\frac{\left (517+9 \sqrt{517}\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{1}{8} \left (19-\sqrt{517}\right )-x^2} \, dx,x,-\frac{1}{2} \sqrt{\frac{1}{2} \left (19+\sqrt{517}\right )}+2 \left (\frac{3}{4}+\frac{1}{x}\right )\right )}{8272}+\frac{\left (517+9 \sqrt{517}\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{1}{8} \left (19-\sqrt{517}\right )-x^2} \, dx,x,\frac{1}{4} \left (6+\sqrt{2 \left (19+\sqrt{517}\right )}+\frac{8}{x}\right )\right )}{8272}\\ &=-\frac{1}{4} \sqrt{\frac{3}{13}} \tan ^{-1}\left (\frac{19-\left (3+\frac{4}{x}\right )^2}{2 \sqrt{39}}\right )-\frac{1}{4} \sqrt{\frac{5167+235 \sqrt{517}}{40326}} \tan ^{-1}\left (\frac{6+\sqrt{2 \left (19+\sqrt{517}\right )}+\frac{8}{x}}{\sqrt{2 \left (-19+\sqrt{517}\right )}}\right )-\frac{1}{4} \sqrt{\frac{5167+235 \sqrt{517}}{40326}} \tan ^{-1}\left (\frac{8+\left (6-\sqrt{2 \left (19+\sqrt{517}\right )}\right ) x}{\sqrt{2 \left (-19+\sqrt{517}\right )} x}\right )-\frac{1}{8} \sqrt{\frac{-5167+235 \sqrt{517}}{40326}} \log \left (\sqrt{517}-\sqrt{2 \left (19+\sqrt{517}\right )} \left (3+\frac{4}{x}\right )+\left (3+\frac{4}{x}\right )^2\right )+\frac{1}{8} \sqrt{\frac{-5167+235 \sqrt{517}}{40326}} \log \left (\sqrt{517}+\sqrt{2 \left (19+\sqrt{517}\right )} \left (3+\frac{4}{x}\right )+\left (3+\frac{4}{x}\right )^2\right )\\ \end{align*}

Mathematica [C]  time = 0.0096563, size = 55, normalized size = 0.21 \[ \text{RootSum}\left [8 \text{$\#$1}^4-15 \text{$\#$1}^3+8 \text{$\#$1}^2+24 \text{$\#$1}+8\& ,\frac{\log (x-\text{$\#$1})}{32 \text{$\#$1}^3-45 \text{$\#$1}^2+16 \text{$\#$1}+24}\& \right ] \]

Antiderivative was successfully verified.

[In]

Integrate[(8 + 24*x + 8*x^2 - 15*x^3 + 8*x^4)^(-1),x]

[Out]

RootSum[8 + 24*#1 + 8*#1^2 - 15*#1^3 + 8*#1^4 & , Log[x - #1]/(24 + 16*#1 - 45*#1^2 + 32*#1^3) & ]

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Maple [C]  time = 0.005, size = 49, normalized size = 0.2 \begin{align*} \sum _{{\it \_R}={\it RootOf} \left ( 8\,{{\it \_Z}}^{4}-15\,{{\it \_Z}}^{3}+8\,{{\it \_Z}}^{2}+24\,{\it \_Z}+8 \right ) }{\frac{\ln \left ( x-{\it \_R} \right ) }{32\,{{\it \_R}}^{3}-45\,{{\it \_R}}^{2}+16\,{\it \_R}+24}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(8*x^4-15*x^3+8*x^2+24*x+8),x)

[Out]

sum(1/(32*_R^3-45*_R^2+16*_R+24)*ln(x-_R),_R=RootOf(8*_Z^4-15*_Z^3+8*_Z^2+24*_Z+8))

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{8 \, x^{4} - 15 \, x^{3} + 8 \, x^{2} + 24 \, x + 8}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(8*x^4-15*x^3+8*x^2+24*x+8),x, algorithm="maxima")

[Out]

integrate(1/(8*x^4 - 15*x^3 + 8*x^2 + 24*x + 8), x)

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Fricas [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(8*x^4-15*x^3+8*x^2+24*x+8),x, algorithm="fricas")

[Out]

Timed out

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Sympy [A]  time = 0.851635, size = 41, normalized size = 0.16 \begin{align*} \operatorname{RootSum}{\left (50326848 t^{4} + 765960 t^{2} + 12753 t + 64, \left ( t \mapsto t \log{\left (\frac{100785893208 t^{3}}{4758335} - \frac{1430512512 t^{2}}{4758335} + \frac{72982352521 t}{223641745} + x + \frac{2270349121}{1789133960} \right )} \right )\right )} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(8*x**4-15*x**3+8*x**2+24*x+8),x)

[Out]

RootSum(50326848*_t**4 + 765960*_t**2 + 12753*_t + 64, Lambda(_t, _t*log(100785893208*_t**3/4758335 - 14305125
12*_t**2/4758335 + 72982352521*_t/223641745 + x + 2270349121/1789133960)))

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{8 \, x^{4} - 15 \, x^{3} + 8 \, x^{2} + 24 \, x + 8}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(8*x^4-15*x^3+8*x^2+24*x+8),x, algorithm="giac")

[Out]

integrate(1/(8*x^4 - 15*x^3 + 8*x^2 + 24*x + 8), x)