3.14 \(\int \frac{1}{(3 a b+3 b^2 x+3 b c x^2+c^2 x^3)^3} \, dx\)

Optimal. Leaf size=305 \[ \frac{5 c^2 \left (\frac{b}{c}+x\right )}{18 b^2 \left (b^2-3 a c\right )^2 \left (3 a b+3 b^2 x+3 b c x^2+c^2 x^3\right )}-\frac{c \left (\frac{b}{c}+x\right )}{6 b \left (b^2-3 a c\right ) \left (3 a b+3 b^2 x+3 b c x^2+c^2 x^3\right )^2}+\frac{5 c^2 \log \left (-\sqrt [3]{b} \sqrt [3]{b^2-3 a c}+b+c x\right )}{27 b^{8/3} \left (b^2-3 a c\right )^{8/3}}-\frac{5 c^2 \log \left (\sqrt [3]{b} c \sqrt [3]{b^2-3 a c} \left (\frac{b}{c}+x\right )+b^{2/3} \left (b^2-3 a c\right )^{2/3}+c^2 \left (\frac{b}{c}+x\right )^2\right )}{54 b^{8/3} \left (b^2-3 a c\right )^{8/3}}-\frac{5 c^2 \tan ^{-1}\left (\frac{\frac{2 (b+c x)}{\sqrt [3]{b^2-3 a c}}+\sqrt [3]{b}}{\sqrt{3} \sqrt [3]{b}}\right )}{9 \sqrt{3} b^{8/3} \left (b^2-3 a c\right )^{8/3}} \]

[Out]

-(c*(b/c + x))/(6*b*(b^2 - 3*a*c)*(3*a*b + 3*b^2*x + 3*b*c*x^2 + c^2*x^3)^2) + (5*c^2*(b/c + x))/(18*b^2*(b^2
- 3*a*c)^2*(3*a*b + 3*b^2*x + 3*b*c*x^2 + c^2*x^3)) - (5*c^2*ArcTan[(b^(1/3) + (2*(b + c*x))/(b^2 - 3*a*c)^(1/
3))/(Sqrt[3]*b^(1/3))])/(9*Sqrt[3]*b^(8/3)*(b^2 - 3*a*c)^(8/3)) + (5*c^2*Log[b - b^(1/3)*(b^2 - 3*a*c)^(1/3) +
c*x])/(27*b^(8/3)*(b^2 - 3*a*c)^(8/3)) - (5*c^2*Log[b^(2/3)*(b^2 - 3*a*c)^(2/3) + b^(1/3)*c*(b^2 - 3*a*c)^(1/
3)*(b/c + x) + c^2*(b/c + x)^2])/(54*b^(8/3)*(b^2 - 3*a*c)^(8/3))

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Rubi [A]  time = 0.301938, antiderivative size = 305, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 8, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.296, Rules used = {2067, 199, 200, 31, 634, 617, 204, 628} \[ \frac{5 c^2 \left (\frac{b}{c}+x\right )}{18 b^2 \left (b^2-3 a c\right )^2 \left (3 a b+3 b^2 x+3 b c x^2+c^2 x^3\right )}-\frac{c \left (\frac{b}{c}+x\right )}{6 b \left (b^2-3 a c\right ) \left (3 a b+3 b^2 x+3 b c x^2+c^2 x^3\right )^2}+\frac{5 c^2 \log \left (-\sqrt [3]{b} \sqrt [3]{b^2-3 a c}+b+c x\right )}{27 b^{8/3} \left (b^2-3 a c\right )^{8/3}}-\frac{5 c^2 \log \left (\sqrt [3]{b} c \sqrt [3]{b^2-3 a c} \left (\frac{b}{c}+x\right )+b^{2/3} \left (b^2-3 a c\right )^{2/3}+c^2 \left (\frac{b}{c}+x\right )^2\right )}{54 b^{8/3} \left (b^2-3 a c\right )^{8/3}}-\frac{5 c^2 \tan ^{-1}\left (\frac{\frac{2 (b+c x)}{\sqrt [3]{b^2-3 a c}}+\sqrt [3]{b}}{\sqrt{3} \sqrt [3]{b}}\right )}{9 \sqrt{3} b^{8/3} \left (b^2-3 a c\right )^{8/3}} \]

Antiderivative was successfully verified.

[In]

Int[(3*a*b + 3*b^2*x + 3*b*c*x^2 + c^2*x^3)^(-3),x]

[Out]

-(c*(b/c + x))/(6*b*(b^2 - 3*a*c)*(3*a*b + 3*b^2*x + 3*b*c*x^2 + c^2*x^3)^2) + (5*c^2*(b/c + x))/(18*b^2*(b^2
- 3*a*c)^2*(3*a*b + 3*b^2*x + 3*b*c*x^2 + c^2*x^3)) - (5*c^2*ArcTan[(b^(1/3) + (2*(b + c*x))/(b^2 - 3*a*c)^(1/
3))/(Sqrt[3]*b^(1/3))])/(9*Sqrt[3]*b^(8/3)*(b^2 - 3*a*c)^(8/3)) + (5*c^2*Log[b - b^(1/3)*(b^2 - 3*a*c)^(1/3) +
c*x])/(27*b^(8/3)*(b^2 - 3*a*c)^(8/3)) - (5*c^2*Log[b^(2/3)*(b^2 - 3*a*c)^(2/3) + b^(1/3)*c*(b^2 - 3*a*c)^(1/
3)*(b/c + x) + c^2*(b/c + x)^2])/(54*b^(8/3)*(b^2 - 3*a*c)^(8/3))

Rule 2067

Int[(P3_)^(p_), x_Symbol] :> With[{a = Coeff[P3, x, 0], b = Coeff[P3, x, 1], c = Coeff[P3, x, 2], d = Coeff[P3
, x, 3]}, Subst[Int[Simp[(2*c^3 - 9*b*c*d + 27*a*d^2)/(27*d^2) - ((c^2 - 3*b*d)*x)/(3*d) + d*x^3, x]^p, x], x,
x + c/(3*d)] /; NeQ[c, 0]] /; FreeQ[p, x] && PolyQ[P3, x, 3]

Rule 199

Int[((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> -Simp[(x*(a + b*x^n)^(p + 1))/(a*n*(p + 1)), x] + Dist[(n*(p +
1) + 1)/(a*n*(p + 1)), Int[(a + b*x^n)^(p + 1), x], x] /; FreeQ[{a, b}, x] && IGtQ[n, 0] && LtQ[p, -1] && (In
tegerQ[2*p] || (n == 2 && IntegerQ[4*p]) || (n == 2 && IntegerQ[3*p]) || Denominator[p + 1/n] < Denominator[p]
)

Rule 200

Int[((a_) + (b_.)*(x_)^3)^(-1), x_Symbol] :> Dist[1/(3*Rt[a, 3]^2), Int[1/(Rt[a, 3] + Rt[b, 3]*x), x], x] + Di
st[1/(3*Rt[a, 3]^2), Int[(2*Rt[a, 3] - Rt[b, 3]*x)/(Rt[a, 3]^2 - Rt[a, 3]*Rt[b, 3]*x + Rt[b, 3]^2*x^2), x], x]
/; FreeQ[{a, b}, x]

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 634

Int[((d_.) + (e_.)*(x_))/((a_) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Dist[(2*c*d - b*e)/(2*c), Int[1/(a +
b*x + c*x^2), x], x] + Dist[e/(2*c), Int[(b + 2*c*x)/(a + b*x + c*x^2), x], x] /; FreeQ[{a, b, c, d, e}, x] &
& NeQ[2*c*d - b*e, 0] && NeQ[b^2 - 4*a*c, 0] &&  !NiceSqrtQ[b^2 - 4*a*c]

Rule 617

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[(a*c)/b^2]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + (2*c*x)/b], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 628

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[(d*Log[RemoveContent[a + b*x +
c*x^2, x]])/b, x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rubi steps

\begin{align*} \int \frac{1}{\left (3 a b+3 b^2 x+3 b c x^2+c^2 x^3\right )^3} \, dx &=\operatorname{Subst}\left (\int \frac{1}{\left (b \left (3 a-\frac{b^2}{c}\right )+c^2 x^3\right )^3} \, dx,x,\frac{b}{c}+x\right )\\ &=-\frac{c \left (\frac{b}{c}+x\right )}{6 b \left (b^2-3 a c\right ) \left (3 a b+3 b^2 x+3 b c x^2+c^2 x^3\right )^2}-\frac{(5 c) \operatorname{Subst}\left (\int \frac{1}{\left (b \left (3 a-\frac{b^2}{c}\right )+c^2 x^3\right )^2} \, dx,x,\frac{b}{c}+x\right )}{6 b \left (b^2-3 a c\right )}\\ &=-\frac{c \left (\frac{b}{c}+x\right )}{6 b \left (b^2-3 a c\right ) \left (3 a b+3 b^2 x+3 b c x^2+c^2 x^3\right )^2}+\frac{5 c (b+c x)}{18 b^2 \left (b^2-3 a c\right )^2 \left (3 a b+3 b^2 x+3 b c x^2+c^2 x^3\right )}+\frac{\left (5 c^2\right ) \operatorname{Subst}\left (\int \frac{1}{b \left (3 a-\frac{b^2}{c}\right )+c^2 x^3} \, dx,x,\frac{b}{c}+x\right )}{9 b^2 \left (b^2-3 a c\right )^2}\\ &=-\frac{c \left (\frac{b}{c}+x\right )}{6 b \left (b^2-3 a c\right ) \left (3 a b+3 b^2 x+3 b c x^2+c^2 x^3\right )^2}+\frac{5 c (b+c x)}{18 b^2 \left (b^2-3 a c\right )^2 \left (3 a b+3 b^2 x+3 b c x^2+c^2 x^3\right )}+\frac{\left (5 c^{8/3}\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{\sqrt [3]{b} \sqrt [3]{b^2-3 a c}}{\sqrt [3]{c}}+c^{2/3} x} \, dx,x,\frac{b}{c}+x\right )}{27 b^{8/3} \left (b^2-3 a c\right )^{8/3}}+\frac{\left (5 c^{8/3}\right ) \operatorname{Subst}\left (\int \frac{-\frac{2 \sqrt [3]{b} \sqrt [3]{b^2-3 a c}}{\sqrt [3]{c}}-c^{2/3} x}{\frac{b^{2/3} \left (b^2-3 a c\right )^{2/3}}{c^{2/3}}+\sqrt [3]{b} \sqrt [3]{c} \sqrt [3]{b^2-3 a c} x+c^{4/3} x^2} \, dx,x,\frac{b}{c}+x\right )}{27 b^{8/3} \left (b^2-3 a c\right )^{8/3}}\\ &=-\frac{c \left (\frac{b}{c}+x\right )}{6 b \left (b^2-3 a c\right ) \left (3 a b+3 b^2 x+3 b c x^2+c^2 x^3\right )^2}+\frac{5 c (b+c x)}{18 b^2 \left (b^2-3 a c\right )^2 \left (3 a b+3 b^2 x+3 b c x^2+c^2 x^3\right )}+\frac{5 c^2 \log \left (\sqrt [3]{b} \left (b^{2/3}-\sqrt [3]{b^2-3 a c}\right )+c x\right )}{27 b^{8/3} \left (b^2-3 a c\right )^{8/3}}-\frac{\left (5 c^2\right ) \operatorname{Subst}\left (\int \frac{\sqrt [3]{b} \sqrt [3]{c} \sqrt [3]{b^2-3 a c}+2 c^{4/3} x}{\frac{b^{2/3} \left (b^2-3 a c\right )^{2/3}}{c^{2/3}}+\sqrt [3]{b} \sqrt [3]{c} \sqrt [3]{b^2-3 a c} x+c^{4/3} x^2} \, dx,x,\frac{b}{c}+x\right )}{54 b^{8/3} \left (b^2-3 a c\right )^{8/3}}-\frac{\left (5 c^{7/3}\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{b^{2/3} \left (b^2-3 a c\right )^{2/3}}{c^{2/3}}+\sqrt [3]{b} \sqrt [3]{c} \sqrt [3]{b^2-3 a c} x+c^{4/3} x^2} \, dx,x,\frac{b}{c}+x\right )}{18 b^{7/3} \left (b^2-3 a c\right )^{7/3}}\\ &=-\frac{c \left (\frac{b}{c}+x\right )}{6 b \left (b^2-3 a c\right ) \left (3 a b+3 b^2 x+3 b c x^2+c^2 x^3\right )^2}+\frac{5 c (b+c x)}{18 b^2 \left (b^2-3 a c\right )^2 \left (3 a b+3 b^2 x+3 b c x^2+c^2 x^3\right )}+\frac{5 c^2 \log \left (\sqrt [3]{b} \left (b^{2/3}-\sqrt [3]{b^2-3 a c}\right )+c x\right )}{27 b^{8/3} \left (b^2-3 a c\right )^{8/3}}-\frac{5 c^2 \log \left (b^{2/3} \left (b^2-3 a c\right )^{2/3}+\sqrt [3]{b} \sqrt [3]{b^2-3 a c} (b+c x)+(b+c x)^2\right )}{54 b^{8/3} \left (b^2-3 a c\right )^{8/3}}+\frac{\left (5 c^2\right ) \operatorname{Subst}\left (\int \frac{1}{-3-x^2} \, dx,x,1+\frac{2 c \left (\frac{b}{c}+x\right )}{\sqrt [3]{b} \sqrt [3]{b^2-3 a c}}\right )}{9 b^{8/3} \left (b^2-3 a c\right )^{8/3}}\\ &=-\frac{c \left (\frac{b}{c}+x\right )}{6 b \left (b^2-3 a c\right ) \left (3 a b+3 b^2 x+3 b c x^2+c^2 x^3\right )^2}+\frac{5 c (b+c x)}{18 b^2 \left (b^2-3 a c\right )^2 \left (3 a b+3 b^2 x+3 b c x^2+c^2 x^3\right )}-\frac{5 c^2 \tan ^{-1}\left (\frac{1+\frac{2 (b+c x)}{\sqrt [3]{b} \sqrt [3]{b^2-3 a c}}}{\sqrt{3}}\right )}{9 \sqrt{3} b^{8/3} \left (b^2-3 a c\right )^{8/3}}+\frac{5 c^2 \log \left (\sqrt [3]{b} \left (b^{2/3}-\sqrt [3]{b^2-3 a c}\right )+c x\right )}{27 b^{8/3} \left (b^2-3 a c\right )^{8/3}}-\frac{5 c^2 \log \left (b^{2/3} \left (b^2-3 a c\right )^{2/3}+\sqrt [3]{b} \sqrt [3]{b^2-3 a c} (b+c x)+(b+c x)^2\right )}{54 b^{8/3} \left (b^2-3 a c\right )^{8/3}}\\ \end{align*}

Mathematica [C]  time = 0.079559, size = 149, normalized size = 0.49 \[ \frac{10 c^2 \text{RootSum}\left [3 \text{$\#$1}^2 b c+\text{$\#$1}^3 c^2+3 \text{$\#$1} b^2+3 a b\& ,\frac{\log (x-\text{$\#$1})}{\text{$\#$1}^2 c^2+2 \text{$\#$1} b c+b^2}\& \right ]-\frac{3 (b+c x) \left (-3 b c \left (8 a+5 c x^2\right )-15 b^2 c x+3 b^3-5 c^3 x^3\right )}{\left (3 a b+x \left (3 b^2+3 b c x+c^2 x^2\right )\right )^2}}{54 \left (b^3-3 a b c\right )^2} \]

Antiderivative was successfully verified.

[In]

Integrate[(3*a*b + 3*b^2*x + 3*b*c*x^2 + c^2*x^3)^(-3),x]

[Out]

((-3*(b + c*x)*(3*b^3 - 15*b^2*c*x - 5*c^3*x^3 - 3*b*c*(8*a + 5*c*x^2)))/(3*a*b + x*(3*b^2 + 3*b*c*x + c^2*x^2
))^2 + 10*c^2*RootSum[3*a*b + 3*b^2*#1 + 3*b*c*#1^2 + c^2*#1^3 & , Log[x - #1]/(b^2 + 2*b*c*#1 + c^2*#1^2) & ]
)/(54*(b^3 - 3*a*b*c)^2)

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Maple [C]  time = 0.014, size = 276, normalized size = 0.9 \begin{align*}{\frac{1}{ \left ({c}^{2}{x}^{3}+3\,bc{x}^{2}+3\,{b}^{2}x+3\,ab \right ) ^{2}} \left ({\frac{5\,{c}^{4}{x}^{4}}{18\,{b}^{2} \left ( 9\,{a}^{2}{c}^{2}-6\,a{b}^{2}c+{b}^{4} \right ) }}+{\frac{10\,{c}^{3}{x}^{3}}{9\,b \left ( 9\,{a}^{2}{c}^{2}-6\,a{b}^{2}c+{b}^{4} \right ) }}+{\frac{5\,{c}^{2}{x}^{2}}{27\,{a}^{2}{c}^{2}-18\,a{b}^{2}c+3\,{b}^{4}}}+{\frac{ \left ( 4\,ac+2\,{b}^{2} \right ) cx}{3\,b \left ( 9\,{a}^{2}{c}^{2}-6\,a{b}^{2}c+{b}^{4} \right ) }}+{\frac{8\,ac-{b}^{2}}{54\,{a}^{2}{c}^{2}-36\,a{b}^{2}c+6\,{b}^{4}}} \right ) }+{\frac{5\,{c}^{2}}{27\,{b}^{2} \left ( 9\,{a}^{2}{c}^{2}-6\,a{b}^{2}c+{b}^{4} \right ) }\sum _{{\it \_R}={\it RootOf} \left ({{\it \_Z}}^{3}{c}^{2}+3\,{{\it \_Z}}^{2}bc+3\,{\it \_Z}\,{b}^{2}+3\,ab \right ) }{\frac{\ln \left ( x-{\it \_R} \right ) }{{{\it \_R}}^{2}{c}^{2}+2\,{\it \_R}\,bc+{b}^{2}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(c^2*x^3+3*b*c*x^2+3*b^2*x+3*a*b)^3,x)

[Out]

(5/18*c^4/b^2/(9*a^2*c^2-6*a*b^2*c+b^4)*x^4+10/9/b*c^3/(9*a^2*c^2-6*a*b^2*c+b^4)*x^3+5/3*c^2/(9*a^2*c^2-6*a*b^
2*c+b^4)*x^2+2/3/b*(2*a*c+b^2)*c/(9*a^2*c^2-6*a*b^2*c+b^4)*x+1/6*(8*a*c-b^2)/(9*a^2*c^2-6*a*b^2*c+b^4))/(c^2*x
^3+3*b*c*x^2+3*b^2*x+3*a*b)^2+5/27*c^2/b^2/(9*a^2*c^2-6*a*b^2*c+b^4)*sum(1/(_R^2*c^2+2*_R*b*c+b^2)*ln(x-_R),_R
=RootOf(_Z^3*c^2+3*_Z^2*b*c+3*_Z*b^2+3*a*b))

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\frac{5}{6} \,{\left (\frac{2 \, \sqrt{3} \arctan \left (\frac{\sqrt{3} c x + \sqrt{3} b - \sqrt{3}{\left (-b^{3} + 3 \, a b c\right )}^{\frac{1}{3}}}{c x + b +{\left (-b^{3} + 3 \, a b c\right )}^{\frac{1}{3}}}\right )}{{\left (b^{6} - 6 \, a b^{4} c + 9 \, a^{2} b^{2} c^{2}\right )}^{\frac{1}{3}}} - \frac{\log \left ({\left (\sqrt{3} c x + \sqrt{3} b - \sqrt{3}{\left (-b^{3} + 3 \, a b c\right )}^{\frac{1}{3}}\right )}^{2} +{\left (c x + b +{\left (-b^{3} + 3 \, a b c\right )}^{\frac{1}{3}}\right )}^{2}\right )}{{\left (b^{6} - 6 \, a b^{4} c + 9 \, a^{2} b^{2} c^{2}\right )}^{\frac{1}{3}}} + \frac{2 \, \log \left ({\left | c x + b +{\left (-b^{3} + 3 \, a b c\right )}^{\frac{1}{3}} \right |}\right )}{{\left (b^{6} - 6 \, a b^{4} c + 9 \, a^{2} b^{2} c^{2}\right )}^{\frac{1}{3}}}\right )} c^{2}}{9 \,{\left (b^{6} - 6 \, a b^{4} c + 9 \, a^{2} b^{2} c^{2}\right )}} + \frac{5 \, c^{4} x^{4} + 20 \, b c^{3} x^{3} + 30 \, b^{2} c^{2} x^{2} - 3 \, b^{4} + 24 \, a b^{2} c + 12 \,{\left (b^{3} c + 2 \, a b c^{2}\right )} x}{18 \,{\left (9 \, a^{2} b^{8} - 54 \, a^{3} b^{6} c + 81 \, a^{4} b^{4} c^{2} +{\left (b^{6} c^{4} - 6 \, a b^{4} c^{5} + 9 \, a^{2} b^{2} c^{6}\right )} x^{6} + 6 \,{\left (b^{7} c^{3} - 6 \, a b^{5} c^{4} + 9 \, a^{2} b^{3} c^{5}\right )} x^{5} + 15 \,{\left (b^{8} c^{2} - 6 \, a b^{6} c^{3} + 9 \, a^{2} b^{4} c^{4}\right )} x^{4} + 6 \,{\left (3 \, b^{9} c - 17 \, a b^{7} c^{2} + 21 \, a^{2} b^{5} c^{3} + 9 \, a^{3} b^{3} c^{4}\right )} x^{3} + 9 \,{\left (b^{10} - 4 \, a b^{8} c - 3 \, a^{2} b^{6} c^{2} + 18 \, a^{3} b^{4} c^{3}\right )} x^{2} + 18 \,{\left (a b^{9} - 6 \, a^{2} b^{7} c + 9 \, a^{3} b^{5} c^{2}\right )} x\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(c^2*x^3+3*b*c*x^2+3*b^2*x+3*a*b)^3,x, algorithm="maxima")

[Out]

5/9*c^2*integrate(1/(c^2*x^3 + 3*b*c*x^2 + 3*b^2*x + 3*a*b), x)/(b^6 - 6*a*b^4*c + 9*a^2*b^2*c^2) + 1/18*(5*c^
4*x^4 + 20*b*c^3*x^3 + 30*b^2*c^2*x^2 - 3*b^4 + 24*a*b^2*c + 12*(b^3*c + 2*a*b*c^2)*x)/(9*a^2*b^8 - 54*a^3*b^6
*c + 81*a^4*b^4*c^2 + (b^6*c^4 - 6*a*b^4*c^5 + 9*a^2*b^2*c^6)*x^6 + 6*(b^7*c^3 - 6*a*b^5*c^4 + 9*a^2*b^3*c^5)*
x^5 + 15*(b^8*c^2 - 6*a*b^6*c^3 + 9*a^2*b^4*c^4)*x^4 + 6*(3*b^9*c - 17*a*b^7*c^2 + 21*a^2*b^5*c^3 + 9*a^3*b^3*
c^4)*x^3 + 9*(b^10 - 4*a*b^8*c - 3*a^2*b^6*c^2 + 18*a^3*b^4*c^3)*x^2 + 18*(a*b^9 - 6*a^2*b^7*c + 9*a^3*b^5*c^2
)*x)

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Fricas [B]  time = 1.46634, size = 2731, normalized size = 8.95 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(c^2*x^3+3*b*c*x^2+3*b^2*x+3*a*b)^3,x, algorithm="fricas")

[Out]

-1/54*(9*b^10 - 126*a*b^8*c + 513*a^2*b^6*c^2 - 648*a^3*b^4*c^3 - 15*(b^6*c^4 - 6*a*b^4*c^5 + 9*a^2*b^2*c^6)*x
^4 - 60*(b^7*c^3 - 6*a*b^5*c^4 + 9*a^2*b^3*c^5)*x^3 - 90*(b^8*c^2 - 6*a*b^6*c^3 + 9*a^2*b^4*c^4)*x^2 + 10*sqrt
(3)*(9*a^2*b^5*c^2 - 27*a^3*b^3*c^3 + (b^3*c^6 - 3*a*b*c^7)*x^6 + 6*(b^4*c^5 - 3*a*b^2*c^6)*x^5 + 15*(b^5*c^4
- 3*a*b^3*c^5)*x^4 + 6*(3*b^6*c^3 - 8*a*b^4*c^4 - 3*a^2*b^2*c^5)*x^3 + 9*(b^7*c^2 - a*b^5*c^3 - 6*a^2*b^3*c^4)
*x^2 + 18*(a*b^6*c^2 - 3*a^2*b^4*c^3)*x)*(b^6 - 6*a*b^4*c + 9*a^2*b^2*c^2)^(1/6)*arctan(1/3*(2*sqrt(3)*(b^6 -
6*a*b^4*c + 9*a^2*b^2*c^2)^(2/3)*(c*x + b) + sqrt(3)*(b^6 - 6*a*b^4*c + 9*a^2*b^2*c^2)^(1/3)*(b^3 - 3*a*b*c))/
(b^6 - 6*a*b^4*c + 9*a^2*b^2*c^2)^(5/6)) + 5*(c^6*x^6 + 6*b*c^5*x^5 + 15*b^2*c^4*x^4 + 18*a*b^3*c^2*x + 9*a^2*
b^2*c^2 + 6*(3*b^3*c^3 + a*b*c^4)*x^3 + 9*(b^4*c^2 + 2*a*b^2*c^3)*x^2)*(b^6 - 6*a*b^4*c + 9*a^2*b^2*c^2)^(2/3)
*log(-b^5 + 3*a*b^3*c - (b^3*c^2 - 3*a*b*c^3)*x^2 - 2*(b^4*c - 3*a*b^2*c^2)*x - (b^6 - 6*a*b^4*c + 9*a^2*b^2*c
^2)^(2/3)*(c*x + b) - (b^6 - 6*a*b^4*c + 9*a^2*b^2*c^2)^(1/3)*(b^3 - 3*a*b*c)) - 10*(c^6*x^6 + 6*b*c^5*x^5 + 1
5*b^2*c^4*x^4 + 18*a*b^3*c^2*x + 9*a^2*b^2*c^2 + 6*(3*b^3*c^3 + a*b*c^4)*x^3 + 9*(b^4*c^2 + 2*a*b^2*c^3)*x^2)*
(b^6 - 6*a*b^4*c + 9*a^2*b^2*c^2)^(2/3)*log(-b^4 + 3*a*b^2*c - (b^3*c - 3*a*b*c^2)*x + (b^6 - 6*a*b^4*c + 9*a^
2*b^2*c^2)^(2/3)) - 36*(b^9*c - 4*a*b^7*c^2 - 3*a^2*b^5*c^3 + 18*a^3*b^3*c^4)*x)/(9*a^2*b^14 - 108*a^3*b^12*c
+ 486*a^4*b^10*c^2 - 972*a^5*b^8*c^3 + 729*a^6*b^6*c^4 + (b^12*c^4 - 12*a*b^10*c^5 + 54*a^2*b^8*c^6 - 108*a^3*
b^6*c^7 + 81*a^4*b^4*c^8)*x^6 + 6*(b^13*c^3 - 12*a*b^11*c^4 + 54*a^2*b^9*c^5 - 108*a^3*b^7*c^6 + 81*a^4*b^5*c^
7)*x^5 + 15*(b^14*c^2 - 12*a*b^12*c^3 + 54*a^2*b^10*c^4 - 108*a^3*b^8*c^5 + 81*a^4*b^6*c^6)*x^4 + 6*(3*b^15*c
- 35*a*b^13*c^2 + 150*a^2*b^11*c^3 - 270*a^3*b^9*c^4 + 135*a^4*b^7*c^5 + 81*a^5*b^5*c^6)*x^3 + 9*(b^16 - 10*a*
b^14*c + 30*a^2*b^12*c^2 - 135*a^4*b^8*c^4 + 162*a^5*b^6*c^5)*x^2 + 18*(a*b^15 - 12*a^2*b^13*c + 54*a^3*b^11*c
^2 - 108*a^4*b^9*c^3 + 81*a^5*b^7*c^4)*x)

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Sympy [A]  time = 5.97428, size = 474, normalized size = 1.55 \begin{align*} \frac{24 a b^{2} c - 3 b^{4} + 30 b^{2} c^{2} x^{2} + 20 b c^{3} x^{3} + 5 c^{4} x^{4} + x \left (24 a b c^{2} + 12 b^{3} c\right )}{1458 a^{4} b^{4} c^{2} - 972 a^{3} b^{6} c + 162 a^{2} b^{8} + x^{6} \left (162 a^{2} b^{2} c^{6} - 108 a b^{4} c^{5} + 18 b^{6} c^{4}\right ) + x^{5} \left (972 a^{2} b^{3} c^{5} - 648 a b^{5} c^{4} + 108 b^{7} c^{3}\right ) + x^{4} \left (2430 a^{2} b^{4} c^{4} - 1620 a b^{6} c^{3} + 270 b^{8} c^{2}\right ) + x^{3} \left (972 a^{3} b^{3} c^{4} + 2268 a^{2} b^{5} c^{3} - 1836 a b^{7} c^{2} + 324 b^{9} c\right ) + x^{2} \left (2916 a^{3} b^{4} c^{3} - 486 a^{2} b^{6} c^{2} - 648 a b^{8} c + 162 b^{10}\right ) + x \left (2916 a^{3} b^{5} c^{2} - 1944 a^{2} b^{7} c + 324 a b^{9}\right )} + \operatorname{RootSum}{\left (t^{3} \left (129140163 a^{8} b^{8} c^{8} - 344373768 a^{7} b^{10} c^{7} + 401769396 a^{6} b^{12} c^{6} - 267846264 a^{5} b^{14} c^{5} + 111602610 a^{4} b^{16} c^{4} - 29760696 a^{3} b^{18} c^{3} + 4960116 a^{2} b^{20} c^{2} - 472392 a b^{22} c + 19683 b^{24}\right ) - 125 c^{6}, \left ( t \mapsto t \log{\left (x + \frac{729 t a^{3} b^{3} c^{3} - 729 t a^{2} b^{5} c^{2} + 243 t a b^{7} c - 27 t b^{9} + 5 b c^{2}}{5 c^{3}} \right )} \right )\right )} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(c**2*x**3+3*b*c*x**2+3*b**2*x+3*a*b)**3,x)

[Out]

(24*a*b**2*c - 3*b**4 + 30*b**2*c**2*x**2 + 20*b*c**3*x**3 + 5*c**4*x**4 + x*(24*a*b*c**2 + 12*b**3*c))/(1458*
a**4*b**4*c**2 - 972*a**3*b**6*c + 162*a**2*b**8 + x**6*(162*a**2*b**2*c**6 - 108*a*b**4*c**5 + 18*b**6*c**4)
+ x**5*(972*a**2*b**3*c**5 - 648*a*b**5*c**4 + 108*b**7*c**3) + x**4*(2430*a**2*b**4*c**4 - 1620*a*b**6*c**3 +
270*b**8*c**2) + x**3*(972*a**3*b**3*c**4 + 2268*a**2*b**5*c**3 - 1836*a*b**7*c**2 + 324*b**9*c) + x**2*(2916
*a**3*b**4*c**3 - 486*a**2*b**6*c**2 - 648*a*b**8*c + 162*b**10) + x*(2916*a**3*b**5*c**2 - 1944*a**2*b**7*c +
324*a*b**9)) + RootSum(_t**3*(129140163*a**8*b**8*c**8 - 344373768*a**7*b**10*c**7 + 401769396*a**6*b**12*c**
6 - 267846264*a**5*b**14*c**5 + 111602610*a**4*b**16*c**4 - 29760696*a**3*b**18*c**3 + 4960116*a**2*b**20*c**2
- 472392*a*b**22*c + 19683*b**24) - 125*c**6, Lambda(_t, _t*log(x + (729*_t*a**3*b**3*c**3 - 729*_t*a**2*b**5
*c**2 + 243*_t*a*b**7*c - 27*_t*b**9 + 5*b*c**2)/(5*c**3))))

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Giac [B]  time = 1.28468, size = 817, normalized size = 2.68 \begin{align*} \frac{5}{27} \, \sqrt{3} \left (\frac{c^{6}}{b^{24} - 24 \, a b^{22} c + 252 \, a^{2} b^{20} c^{2} - 1512 \, a^{3} b^{18} c^{3} + 5670 \, a^{4} b^{16} c^{4} - 13608 \, a^{5} b^{14} c^{5} + 20412 \, a^{6} b^{12} c^{6} - 17496 \, a^{7} b^{10} c^{7} + 6561 \, a^{8} b^{8} c^{8}}\right )^{\frac{1}{3}} \arctan \left (\frac{\sqrt{3} c x + \sqrt{3} b - \sqrt{3}{\left (-b^{3} + 3 \, a b c\right )}^{\frac{1}{3}}}{c x + b +{\left (-b^{3} + 3 \, a b c\right )}^{\frac{1}{3}}}\right ) - \frac{5}{54} \, \left (\frac{c^{6}}{b^{24} - 24 \, a b^{22} c + 252 \, a^{2} b^{20} c^{2} - 1512 \, a^{3} b^{18} c^{3} + 5670 \, a^{4} b^{16} c^{4} - 13608 \, a^{5} b^{14} c^{5} + 20412 \, a^{6} b^{12} c^{6} - 17496 \, a^{7} b^{10} c^{7} + 6561 \, a^{8} b^{8} c^{8}}\right )^{\frac{1}{3}} \log \left ({\left (\sqrt{3} c x + \sqrt{3} b - \sqrt{3}{\left (-b^{3} + 3 \, a b c\right )}^{\frac{1}{3}}\right )}^{2} +{\left (c x + b +{\left (-b^{3} + 3 \, a b c\right )}^{\frac{1}{3}}\right )}^{2}\right ) + \frac{5}{27} \, \left (\frac{c^{6}}{b^{24} - 24 \, a b^{22} c + 252 \, a^{2} b^{20} c^{2} - 1512 \, a^{3} b^{18} c^{3} + 5670 \, a^{4} b^{16} c^{4} - 13608 \, a^{5} b^{14} c^{5} + 20412 \, a^{6} b^{12} c^{6} - 17496 \, a^{7} b^{10} c^{7} + 6561 \, a^{8} b^{8} c^{8}}\right )^{\frac{1}{3}} \log \left ({\left | 9 \, b^{7} - 54 \, a b^{5} c + 81 \, a^{2} b^{3} c^{2} + 9 \,{\left (b^{6} c - 6 \, a b^{4} c^{2} + 9 \, a^{2} b^{2} c^{3}\right )} x + 9 \,{\left (b^{6} - 6 \, a b^{4} c + 9 \, a^{2} b^{2} c^{2}\right )}{\left (-b^{3} + 3 \, a b c\right )}^{\frac{1}{3}} \right |}\right ) + \frac{5 \, c^{4} x^{4} + 20 \, b c^{3} x^{3} + 30 \, b^{2} c^{2} x^{2} + 12 \, b^{3} c x + 24 \, a b c^{2} x - 3 \, b^{4} + 24 \, a b^{2} c}{18 \,{\left (b^{6} - 6 \, a b^{4} c + 9 \, a^{2} b^{2} c^{2}\right )}{\left (c^{2} x^{3} + 3 \, b c x^{2} + 3 \, b^{2} x + 3 \, a b\right )}^{2}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(c^2*x^3+3*b*c*x^2+3*b^2*x+3*a*b)^3,x, algorithm="giac")

[Out]

5/27*sqrt(3)*(c^6/(b^24 - 24*a*b^22*c + 252*a^2*b^20*c^2 - 1512*a^3*b^18*c^3 + 5670*a^4*b^16*c^4 - 13608*a^5*b
^14*c^5 + 20412*a^6*b^12*c^6 - 17496*a^7*b^10*c^7 + 6561*a^8*b^8*c^8))^(1/3)*arctan((sqrt(3)*c*x + sqrt(3)*b -
sqrt(3)*(-b^3 + 3*a*b*c)^(1/3))/(c*x + b + (-b^3 + 3*a*b*c)^(1/3))) - 5/54*(c^6/(b^24 - 24*a*b^22*c + 252*a^2
*b^20*c^2 - 1512*a^3*b^18*c^3 + 5670*a^4*b^16*c^4 - 13608*a^5*b^14*c^5 + 20412*a^6*b^12*c^6 - 17496*a^7*b^10*c
^7 + 6561*a^8*b^8*c^8))^(1/3)*log((sqrt(3)*c*x + sqrt(3)*b - sqrt(3)*(-b^3 + 3*a*b*c)^(1/3))^2 + (c*x + b + (-
b^3 + 3*a*b*c)^(1/3))^2) + 5/27*(c^6/(b^24 - 24*a*b^22*c + 252*a^2*b^20*c^2 - 1512*a^3*b^18*c^3 + 5670*a^4*b^1
6*c^4 - 13608*a^5*b^14*c^5 + 20412*a^6*b^12*c^6 - 17496*a^7*b^10*c^7 + 6561*a^8*b^8*c^8))^(1/3)*log(abs(9*b^7
- 54*a*b^5*c + 81*a^2*b^3*c^2 + 9*(b^6*c - 6*a*b^4*c^2 + 9*a^2*b^2*c^3)*x + 9*(b^6 - 6*a*b^4*c + 9*a^2*b^2*c^2
)*(-b^3 + 3*a*b*c)^(1/3))) + 1/18*(5*c^4*x^4 + 20*b*c^3*x^3 + 30*b^2*c^2*x^2 + 12*b^3*c*x + 24*a*b*c^2*x - 3*b
^4 + 24*a*b^2*c)/((b^6 - 6*a*b^4*c + 9*a^2*b^2*c^2)*(c^2*x^3 + 3*b*c*x^2 + 3*b^2*x + 3*a*b)^2)