Optimal. Leaf size=89 \[ i \text{PolyLog}\left (2,1-\frac{2}{1+i x}\right )+\frac{x}{4 \left (x^2+1\right )}+\frac{1}{2} x^2 \tan ^{-1}(x)-\frac{\tan ^{-1}(x)}{2 \left (x^2+1\right )}-\frac{x}{2}+i \tan ^{-1}(x)^2+\frac{3}{4} \tan ^{-1}(x)+2 \log \left (\frac{2}{1+i x}\right ) \tan ^{-1}(x) \]
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Rubi [A] time = 0.234194, antiderivative size = 89, normalized size of antiderivative = 1., number of steps used = 17, number of rules used = 11, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.846, Rules used = {4964, 4916, 4852, 321, 203, 4920, 4854, 2402, 2315, 4930, 199} \[ i \text{PolyLog}\left (2,1-\frac{2}{1+i x}\right )+\frac{x}{4 \left (x^2+1\right )}+\frac{1}{2} x^2 \tan ^{-1}(x)-\frac{\tan ^{-1}(x)}{2 \left (x^2+1\right )}-\frac{x}{2}+i \tan ^{-1}(x)^2+\frac{3}{4} \tan ^{-1}(x)+2 \log \left (\frac{2}{1+i x}\right ) \tan ^{-1}(x) \]
Antiderivative was successfully verified.
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Rule 4964
Rule 4916
Rule 4852
Rule 321
Rule 203
Rule 4920
Rule 4854
Rule 2402
Rule 2315
Rule 4930
Rule 199
Rubi steps
\begin{align*} \int \frac{x^5 \tan ^{-1}(x)}{\left (1+x^2\right )^2} \, dx &=-\int \frac{x^3 \tan ^{-1}(x)}{\left (1+x^2\right )^2} \, dx+\int \frac{x^3 \tan ^{-1}(x)}{1+x^2} \, dx\\ &=\int x \tan ^{-1}(x) \, dx+\int \frac{x \tan ^{-1}(x)}{\left (1+x^2\right )^2} \, dx-2 \int \frac{x \tan ^{-1}(x)}{1+x^2} \, dx\\ &=\frac{1}{2} x^2 \tan ^{-1}(x)-\frac{\tan ^{-1}(x)}{2 \left (1+x^2\right )}+\frac{1}{2} \int \frac{1}{\left (1+x^2\right )^2} \, dx-\frac{1}{2} \int \frac{x^2}{1+x^2} \, dx-2 \left (-\frac{1}{2} i \tan ^{-1}(x)^2-\int \frac{\tan ^{-1}(x)}{i-x} \, dx\right )\\ &=-\frac{x}{2}+\frac{x}{4 \left (1+x^2\right )}+\frac{1}{2} x^2 \tan ^{-1}(x)-\frac{\tan ^{-1}(x)}{2 \left (1+x^2\right )}+\frac{1}{4} \int \frac{1}{1+x^2} \, dx+\frac{1}{2} \int \frac{1}{1+x^2} \, dx-2 \left (-\frac{1}{2} i \tan ^{-1}(x)^2-\tan ^{-1}(x) \log \left (\frac{2}{1+i x}\right )+\int \frac{\log \left (\frac{2}{1+i x}\right )}{1+x^2} \, dx\right )\\ &=-\frac{x}{2}+\frac{x}{4 \left (1+x^2\right )}+\frac{3}{4} \tan ^{-1}(x)+\frac{1}{2} x^2 \tan ^{-1}(x)-\frac{\tan ^{-1}(x)}{2 \left (1+x^2\right )}-2 \left (-\frac{1}{2} i \tan ^{-1}(x)^2-\tan ^{-1}(x) \log \left (\frac{2}{1+i x}\right )-i \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1+i x}\right )\right )\\ &=-\frac{x}{2}+\frac{x}{4 \left (1+x^2\right )}+\frac{3}{4} \tan ^{-1}(x)+\frac{1}{2} x^2 \tan ^{-1}(x)-\frac{\tan ^{-1}(x)}{2 \left (1+x^2\right )}-2 \left (-\frac{1}{2} i \tan ^{-1}(x)^2-\tan ^{-1}(x) \log \left (\frac{2}{1+i x}\right )-\frac{1}{2} i \text{Li}_2\left (1-\frac{2}{1+i x}\right )\right )\\ \end{align*}
Mathematica [A] time = 0.201496, size = 70, normalized size = 0.79 \[ \frac{1}{8} \left (-8 i \text{PolyLog}\left (2,-e^{2 i \tan ^{-1}(x)}\right )+4 \left (x^2+1\right ) \tan ^{-1}(x)-4 x-8 i \tan ^{-1}(x)^2+16 \tan ^{-1}(x) \log \left (1+e^{2 i \tan ^{-1}(x)}\right )+\sin \left (2 \tan ^{-1}(x)\right )-2 \tan ^{-1}(x) \cos \left (2 \tan ^{-1}(x)\right )\right ) \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.018, size = 149, normalized size = 1.7 \begin{align*}{\frac{{x}^{2}\arctan \left ( x \right ) }{2}}-\arctan \left ( x \right ) \ln \left ({x}^{2}+1 \right ) -{\frac{\arctan \left ( x \right ) }{2\,{x}^{2}+2}}-{\frac{x}{2}}+{\frac{x}{4\,{x}^{2}+4}}+{\frac{3\,\arctan \left ( x \right ) }{4}}+{\frac{i}{4}} \left ( \ln \left ( x-i \right ) \right ) ^{2}+{\frac{i}{2}}\ln \left ( -{\frac{i}{2}} \left ( x+i \right ) \right ) \ln \left ( x-i \right ) -{\frac{i}{2}}\ln \left ( x-i \right ) \ln \left ({x}^{2}+1 \right ) +{\frac{i}{2}}{\it dilog} \left ( -{\frac{i}{2}} \left ( x+i \right ) \right ) -{\frac{i}{2}}\ln \left ({\frac{i}{2}} \left ( x-i \right ) \right ) \ln \left ( x+i \right ) -{\frac{i}{4}} \left ( \ln \left ( x+i \right ) \right ) ^{2}+{\frac{i}{2}}\ln \left ( x+i \right ) \ln \left ({x}^{2}+1 \right ) -{\frac{i}{2}}{\it dilog} \left ({\frac{i}{2}} \left ( x-i \right ) \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{5} \arctan \left (x\right )}{{\left (x^{2} + 1\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{x^{5} \arctan \left (x\right )}{x^{4} + 2 \, x^{2} + 1}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: RecursionError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{5} \arctan \left (x\right )}{{\left (x^{2} + 1\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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