Optimal. Leaf size=50 \[ \frac{1}{2} e^x x^2 \sin (x)-\frac{1}{2} e^x x^2 \cos (x)-\frac{1}{2} e^x \sin (x)+e^x x \cos (x)-\frac{1}{2} e^x \cos (x) \]
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Rubi [A] time = 0.107696, antiderivative size = 50, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 5, integrand size = 9, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.556, Rules used = {4432, 4465, 14, 4433, 4466} \[ \frac{1}{2} e^x x^2 \sin (x)-\frac{1}{2} e^x x^2 \cos (x)-\frac{1}{2} e^x \sin (x)+e^x x \cos (x)-\frac{1}{2} e^x \cos (x) \]
Antiderivative was successfully verified.
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Rule 4432
Rule 4465
Rule 14
Rule 4433
Rule 4466
Rubi steps
\begin{align*} \int e^x x^2 \sin (x) \, dx &=-\frac{1}{2} e^x x^2 \cos (x)+\frac{1}{2} e^x x^2 \sin (x)-2 \int x \left (-\frac{1}{2} e^x \cos (x)+\frac{1}{2} e^x \sin (x)\right ) \, dx\\ &=-\frac{1}{2} e^x x^2 \cos (x)+\frac{1}{2} e^x x^2 \sin (x)-2 \int \left (-\frac{1}{2} e^x x \cos (x)+\frac{1}{2} e^x x \sin (x)\right ) \, dx\\ &=-\frac{1}{2} e^x x^2 \cos (x)+\frac{1}{2} e^x x^2 \sin (x)+\int e^x x \cos (x) \, dx-\int e^x x \sin (x) \, dx\\ &=e^x x \cos (x)-\frac{1}{2} e^x x^2 \cos (x)+\frac{1}{2} e^x x^2 \sin (x)+\int \left (-\frac{1}{2} e^x \cos (x)+\frac{1}{2} e^x \sin (x)\right ) \, dx-\int \left (\frac{1}{2} e^x \cos (x)+\frac{1}{2} e^x \sin (x)\right ) \, dx\\ &=e^x x \cos (x)-\frac{1}{2} e^x x^2 \cos (x)+\frac{1}{2} e^x x^2 \sin (x)-2 \left (\frac{1}{2} \int e^x \cos (x) \, dx\right )\\ &=e^x x \cos (x)-\frac{1}{2} e^x x^2 \cos (x)+\frac{1}{2} e^x x^2 \sin (x)-2 \left (\frac{1}{4} e^x \cos (x)+\frac{1}{4} e^x \sin (x)\right )\\ \end{align*}
Mathematica [A] time = 0.0357919, size = 25, normalized size = 0.5 \[ \frac{1}{2} e^x \left (\left (x^2-1\right ) \sin (x)-(x-1)^2 \cos (x)\right ) \]
Antiderivative was successfully verified.
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Maple [A] time = 0.003, size = 27, normalized size = 0.5 \begin{align*} \left ( -{\frac{{x}^{2}}{2}}+x-{\frac{1}{2}} \right ){{\rm e}^{x}}\cos \left ( x \right ) + \left ({\frac{{x}^{2}}{2}}-{\frac{1}{2}} \right ){{\rm e}^{x}}\sin \left ( x \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.979202, size = 35, normalized size = 0.7 \begin{align*} -\frac{1}{2} \,{\left (x^{2} - 2 \, x + 1\right )} \cos \left (x\right ) e^{x} + \frac{1}{2} \,{\left (x^{2} - 1\right )} e^{x} \sin \left (x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.74131, size = 81, normalized size = 1.62 \begin{align*} -\frac{1}{2} \,{\left (x^{2} - 2 \, x + 1\right )} \cos \left (x\right ) e^{x} + \frac{1}{2} \,{\left (x^{2} - 1\right )} e^{x} \sin \left (x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 2.10396, size = 48, normalized size = 0.96 \begin{align*} \frac{x^{2} e^{x} \sin{\left (x \right )}}{2} - \frac{x^{2} e^{x} \cos{\left (x \right )}}{2} + x e^{x} \cos{\left (x \right )} - \frac{e^{x} \sin{\left (x \right )}}{2} - \frac{e^{x} \cos{\left (x \right )}}{2} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.09025, size = 34, normalized size = 0.68 \begin{align*} -\frac{1}{2} \,{\left ({\left (x^{2} - 2 \, x + 1\right )} \cos \left (x\right ) -{\left (x^{2} - 1\right )} \sin \left (x\right )\right )} e^{x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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