Optimal. Leaf size=46 \[ -\frac{e^x \cos (x)}{1-\sin (x)}+(2+2 i) e^{(1+i) x} \, _2F_1\left (1-i,2;2-i;-i e^{i x}\right ) \]
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Rubi [A] time = 0.128552, antiderivative size = 48, normalized size of antiderivative = 1.04, number of steps used = 7, number of rules used = 6, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {4462, 4459, 4442, 2194, 2251, 2288} \[ -4 i e^x \text{Hypergeometric2F1}\left (-i,1,1-i,-i e^{i x}\right )+2 i e^x+\frac{e^x \cos (x)}{1-\sin (x)} \]
Antiderivative was successfully verified.
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Rule 4462
Rule 4459
Rule 4442
Rule 2194
Rule 2251
Rule 2288
Rubi steps
\begin{align*} \int \frac{e^x (1-\cos (x))}{1-\sin (x)} \, dx &=-\left (2 \int \frac{e^x \cos (x)}{1-\sin (x)} \, dx\right )+\int \frac{e^x (1+\cos (x))}{1-\sin (x)} \, dx\\ &=\frac{e^x \cos (x)}{1-\sin (x)}-2 \int e^x \tan \left (\frac{\pi }{4}+\frac{x}{2}\right ) \, dx\\ &=\frac{e^x \cos (x)}{1-\sin (x)}-2 i \int \left (-e^x+\frac{2 e^x}{1+e^{2 i \left (\frac{\pi }{4}+\frac{x}{2}\right )}}\right ) \, dx\\ &=\frac{e^x \cos (x)}{1-\sin (x)}+2 i \int e^x \, dx-4 i \int \frac{e^x}{1+e^{2 i \left (\frac{\pi }{4}+\frac{x}{2}\right )}} \, dx\\ &=2 i e^x-4 i e^x \, _2F_1\left (-i,1;1-i;-i e^{i x}\right )+\frac{e^x \cos (x)}{1-\sin (x)}\\ \end{align*}
Mathematica [A] time = 0.700616, size = 72, normalized size = 1.57 \[ \frac{1}{2} (\cos (x)-1) \csc ^2\left (\frac{x}{2}\right ) \left (4 i (\sinh (x)+\cosh (x)) \, _2F_1(-i,1;1-i;\sin (x)-i \cos (x))-\frac{e^x \left ((1+2 i) \cot \left (\frac{x}{2}\right )+(1-2 i)\right )}{\cot \left (\frac{x}{2}\right )-1}\right ) \]
Antiderivative was successfully verified.
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Maple [F] time = 0.079, size = 0, normalized size = 0. \begin{align*} \int{\frac{{{\rm e}^{x}} \left ( 1-\cos \left ( x \right ) \right ) }{1-\sin \left ( x \right ) }}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{2 \,{\left (\cos \left (x\right ) e^{x} - 2 \,{\left (\cos \left (x\right )^{2} + \sin \left (x\right )^{2} - 2 \, \sin \left (x\right ) + 1\right )} \int \frac{\cos \left (x\right ) e^{x}}{\cos \left (x\right )^{2} + \sin \left (x\right )^{2} - 2 \, \sin \left (x\right ) + 1}\,{d x}\right )}}{\cos \left (x\right )^{2} + \sin \left (x\right )^{2} - 2 \, \sin \left (x\right ) + 1} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (\cos \left (x\right ) - 1\right )} e^{x}}{\sin \left (x\right ) - 1}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (\cos{\left (x \right )} - 1\right ) e^{x}}{\sin{\left (x \right )} - 1}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (\cos \left (x\right ) - 1\right )} e^{x}}{\sin \left (x\right ) - 1}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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