3.519 \(\int (1-a^{m x})^3 \, dx\)

Optimal. Leaf size=50 \[ -\frac{3 a^{m x}}{m \log (a)}+\frac{3 a^{2 m x}}{2 m \log (a)}-\frac{a^{3 m x}}{3 m \log (a)}+x \]

[Out]

x - (3*a^(m*x))/(m*Log[a]) + (3*a^(2*m*x))/(2*m*Log[a]) - a^(3*m*x)/(3*m*Log[a])

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Rubi [A]  time = 0.0167983, antiderivative size = 50, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 11, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.182, Rules used = {2282, 43} \[ -\frac{3 a^{m x}}{m \log (a)}+\frac{3 a^{2 m x}}{2 m \log (a)}-\frac{a^{3 m x}}{3 m \log (a)}+x \]

Antiderivative was successfully verified.

[In]

Int[(1 - a^(m*x))^3,x]

[Out]

x - (3*a^(m*x))/(m*Log[a]) + (3*a^(2*m*x))/(2*m*Log[a]) - a^(3*m*x)/(3*m*Log[a])

Rule 2282

Int[u_, x_Symbol] :> With[{v = FunctionOfExponential[u, x]}, Dist[v/D[v, x], Subst[Int[FunctionOfExponentialFu
nction[u, x]/x, x], x, v], x]] /; FunctionOfExponentialQ[u, x] &&  !MatchQ[u, (w_)*((a_.)*(v_)^(n_))^(m_) /; F
reeQ[{a, m, n}, x] && IntegerQ[m*n]] &&  !MatchQ[u, E^((c_.)*((a_.) + (b_.)*x))*(F_)[v_] /; FreeQ[{a, b, c}, x
] && InverseFunctionQ[F[x]]]

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin{align*} \int \left (1-a^{m x}\right )^3 \, dx &=\frac{\operatorname{Subst}\left (\int \frac{(1-x)^3}{x} \, dx,x,a^{m x}\right )}{m \log (a)}\\ &=\frac{\operatorname{Subst}\left (\int \left (-3+\frac{1}{x}+3 x-x^2\right ) \, dx,x,a^{m x}\right )}{m \log (a)}\\ &=x-\frac{3 a^{m x}}{m \log (a)}+\frac{3 a^{2 m x}}{2 m \log (a)}-\frac{a^{3 m x}}{3 m \log (a)}\\ \end{align*}

Mathematica [A]  time = 0.025566, size = 35, normalized size = 0.7 \[ x-\frac{a^{m x} \left (-9 a^{m x}+2 a^{2 m x}+18\right )}{6 m \log (a)} \]

Antiderivative was successfully verified.

[In]

Integrate[(1 - a^(m*x))^3,x]

[Out]

x - (a^(m*x)*(18 - 9*a^(m*x) + 2*a^(2*m*x)))/(6*m*Log[a])

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Maple [A]  time = 0.002, size = 62, normalized size = 1.2 \begin{align*} -{\frac{ \left ({a}^{mx} \right ) ^{3}}{3\,m\ln \left ( a \right ) }}+{\frac{3\, \left ({a}^{mx} \right ) ^{2}}{2\,m\ln \left ( a \right ) }}-3\,{\frac{{a}^{mx}}{m\ln \left ( a \right ) }}+{\frac{\ln \left ({a}^{mx} \right ) }{m\ln \left ( a \right ) }} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1-a^(m*x))^3,x)

[Out]

-1/3/m/ln(a)*(a^(m*x))^3+3/2/m/ln(a)*(a^(m*x))^2-3*a^(m*x)/m/ln(a)+1/m/ln(a)*ln(a^(m*x))

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Maxima [A]  time = 0.930163, size = 62, normalized size = 1.24 \begin{align*} x - \frac{a^{3 \, m x}}{3 \, m \log \left (a\right )} + \frac{3 \, a^{2 \, m x}}{2 \, m \log \left (a\right )} - \frac{3 \, a^{m x}}{m \log \left (a\right )} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-a^(m*x))^3,x, algorithm="maxima")

[Out]

x - 1/3*a^(3*m*x)/(m*log(a)) + 3/2*a^(2*m*x)/(m*log(a)) - 3*a^(m*x)/(m*log(a))

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Fricas [A]  time = 1.93649, size = 97, normalized size = 1.94 \begin{align*} \frac{6 \, m x \log \left (a\right ) - 2 \, a^{3 \, m x} + 9 \, a^{2 \, m x} - 18 \, a^{m x}}{6 \, m \log \left (a\right )} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-a^(m*x))^3,x, algorithm="fricas")

[Out]

1/6*(6*m*x*log(a) - 2*a^(3*m*x) + 9*a^(2*m*x) - 18*a^(m*x))/(m*log(a))

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Sympy [A]  time = 0.137024, size = 71, normalized size = 1.42 \begin{align*} x + \begin{cases} \frac{- 2 a^{3 m x} m^{2} \log{\left (a \right )}^{2} + 9 a^{2 m x} m^{2} \log{\left (a \right )}^{2} - 18 a^{m x} m^{2} \log{\left (a \right )}^{2}}{6 m^{3} \log{\left (a \right )}^{3}} & \text{for}\: 6 m^{3} \log{\left (a \right )}^{3} \neq 0 \\- x & \text{otherwise} \end{cases} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-a**(m*x))**3,x)

[Out]

x + Piecewise(((-2*a**(3*m*x)*m**2*log(a)**2 + 9*a**(2*m*x)*m**2*log(a)**2 - 18*a**(m*x)*m**2*log(a)**2)/(6*m*
*3*log(a)**3), Ne(6*m**3*log(a)**3, 0)), (-x, True))

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Giac [A]  time = 1.08117, size = 54, normalized size = 1.08 \begin{align*} \frac{6 \, m x \log \left ({\left | a \right |}\right ) - 2 \, a^{3 \, m x} + 9 \, a^{2 \, m x} - 18 \, a^{m x}}{6 \, m \log \left (a\right )} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-a^(m*x))^3,x, algorithm="giac")

[Out]

1/6*(6*m*x*log(abs(a)) - 2*a^(3*m*x) + 9*a^(2*m*x) - 18*a^(m*x))/(m*log(a))