Optimal. Leaf size=141 \[ -\frac{\log \left (\frac{x^2}{\sqrt{x^4+2}}-\frac{\sqrt{2} x}{\sqrt [4]{x^4+2}}+1\right )}{4 \sqrt{2}}+\frac{\log \left (\frac{x^2}{\sqrt{x^4+2}}+\frac{\sqrt{2} x}{\sqrt [4]{x^4+2}}+1\right )}{4 \sqrt{2}}-\frac{\tan ^{-1}\left (1-\frac{\sqrt{2} x}{\sqrt [4]{x^4+2}}\right )}{2 \sqrt{2}}+\frac{\tan ^{-1}\left (\frac{\sqrt{2} x}{\sqrt [4]{x^4+2}}+1\right )}{2 \sqrt{2}} \]
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Rubi [A] time = 0.0602254, antiderivative size = 141, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 7, integrand size = 17, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.412, Rules used = {377, 211, 1165, 628, 1162, 617, 204} \[ -\frac{\log \left (\frac{x^2}{\sqrt{x^4+2}}-\frac{\sqrt{2} x}{\sqrt [4]{x^4+2}}+1\right )}{4 \sqrt{2}}+\frac{\log \left (\frac{x^2}{\sqrt{x^4+2}}+\frac{\sqrt{2} x}{\sqrt [4]{x^4+2}}+1\right )}{4 \sqrt{2}}-\frac{\tan ^{-1}\left (1-\frac{\sqrt{2} x}{\sqrt [4]{x^4+2}}\right )}{2 \sqrt{2}}+\frac{\tan ^{-1}\left (\frac{\sqrt{2} x}{\sqrt [4]{x^4+2}}+1\right )}{2 \sqrt{2}} \]
Antiderivative was successfully verified.
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Rule 377
Rule 211
Rule 1165
Rule 628
Rule 1162
Rule 617
Rule 204
Rubi steps
\begin{align*} \int \frac{1}{\left (1+x^4\right ) \sqrt [4]{2+x^4}} \, dx &=\operatorname{Subst}\left (\int \frac{1}{1+x^4} \, dx,x,\frac{x}{\sqrt [4]{2+x^4}}\right )\\ &=\frac{1}{2} \operatorname{Subst}\left (\int \frac{1-x^2}{1+x^4} \, dx,x,\frac{x}{\sqrt [4]{2+x^4}}\right )+\frac{1}{2} \operatorname{Subst}\left (\int \frac{1+x^2}{1+x^4} \, dx,x,\frac{x}{\sqrt [4]{2+x^4}}\right )\\ &=\frac{1}{4} \operatorname{Subst}\left (\int \frac{1}{1-\sqrt{2} x+x^2} \, dx,x,\frac{x}{\sqrt [4]{2+x^4}}\right )+\frac{1}{4} \operatorname{Subst}\left (\int \frac{1}{1+\sqrt{2} x+x^2} \, dx,x,\frac{x}{\sqrt [4]{2+x^4}}\right )-\frac{\operatorname{Subst}\left (\int \frac{\sqrt{2}+2 x}{-1-\sqrt{2} x-x^2} \, dx,x,\frac{x}{\sqrt [4]{2+x^4}}\right )}{4 \sqrt{2}}-\frac{\operatorname{Subst}\left (\int \frac{\sqrt{2}-2 x}{-1+\sqrt{2} x-x^2} \, dx,x,\frac{x}{\sqrt [4]{2+x^4}}\right )}{4 \sqrt{2}}\\ &=-\frac{\log \left (1+\frac{x^2}{\sqrt{2+x^4}}-\frac{\sqrt{2} x}{\sqrt [4]{2+x^4}}\right )}{4 \sqrt{2}}+\frac{\log \left (1+\frac{x^2}{\sqrt{2+x^4}}+\frac{\sqrt{2} x}{\sqrt [4]{2+x^4}}\right )}{4 \sqrt{2}}+\frac{\operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\frac{\sqrt{2} x}{\sqrt [4]{2+x^4}}\right )}{2 \sqrt{2}}-\frac{\operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\frac{\sqrt{2} x}{\sqrt [4]{2+x^4}}\right )}{2 \sqrt{2}}\\ &=-\frac{\tan ^{-1}\left (1-\frac{\sqrt{2} x}{\sqrt [4]{2+x^4}}\right )}{2 \sqrt{2}}+\frac{\tan ^{-1}\left (1+\frac{\sqrt{2} x}{\sqrt [4]{2+x^4}}\right )}{2 \sqrt{2}}-\frac{\log \left (1+\frac{x^2}{\sqrt{2+x^4}}-\frac{\sqrt{2} x}{\sqrt [4]{2+x^4}}\right )}{4 \sqrt{2}}+\frac{\log \left (1+\frac{x^2}{\sqrt{2+x^4}}+\frac{\sqrt{2} x}{\sqrt [4]{2+x^4}}\right )}{4 \sqrt{2}}\\ \end{align*}
Mathematica [A] time = 0.0484045, size = 120, normalized size = 0.85 \[ \frac{-\log \left (\frac{x^2}{\sqrt{x^4+2}}-\frac{\sqrt{2} x}{\sqrt [4]{x^4+2}}+1\right )+\log \left (\frac{x^2}{\sqrt{x^4+2}}+\frac{\sqrt{2} x}{\sqrt [4]{x^4+2}}+1\right )-2 \tan ^{-1}\left (1-\frac{\sqrt{2} x}{\sqrt [4]{x^4+2}}\right )+2 \tan ^{-1}\left (\frac{\sqrt{2} x}{\sqrt [4]{x^4+2}}+1\right )}{4 \sqrt{2}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.024, size = 0, normalized size = 0. \begin{align*} \int{\frac{1}{{x}^{4}+1}{\frac{1}{\sqrt [4]{{x}^{4}+2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (x^{4} + 2\right )}^{\frac{1}{4}}{\left (x^{4} + 1\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 49.4755, size = 1062, normalized size = 7.53 \begin{align*} \frac{1}{4} \, \sqrt{2} \arctan \left (\frac{\sqrt{2}{\left (x^{4} + 2\right )}^{\frac{3}{4}} x^{2} - \sqrt{2}{\left (x^{4} + 2\right )}^{\frac{5}{4}} -{\left (2 \, x^{5} - \sqrt{2}{\left (x^{4} + 2\right )}^{\frac{3}{4}} x^{2} - \sqrt{2}{\left (x^{4} + 2\right )}^{\frac{5}{4}} + 4 \, x\right )} \sqrt{\frac{x^{4} + \sqrt{2}{\left (x^{4} + 2\right )}^{\frac{1}{4}} x^{3} + 2 \, \sqrt{x^{4} + 2} x^{2} + \sqrt{2}{\left (x^{4} + 2\right )}^{\frac{3}{4}} x + 1}{x^{4} + 1}}}{2 \,{\left (x^{5} + 2 \, x\right )}}\right ) + \frac{1}{4} \, \sqrt{2} \arctan \left (\frac{\sqrt{2}{\left (x^{4} + 2\right )}^{\frac{3}{4}} x^{2} - \sqrt{2}{\left (x^{4} + 2\right )}^{\frac{5}{4}} +{\left (2 \, x^{5} + \sqrt{2}{\left (x^{4} + 2\right )}^{\frac{3}{4}} x^{2} + \sqrt{2}{\left (x^{4} + 2\right )}^{\frac{5}{4}} + 4 \, x\right )} \sqrt{\frac{x^{4} - \sqrt{2}{\left (x^{4} + 2\right )}^{\frac{1}{4}} x^{3} + 2 \, \sqrt{x^{4} + 2} x^{2} - \sqrt{2}{\left (x^{4} + 2\right )}^{\frac{3}{4}} x + 1}{x^{4} + 1}}}{2 \,{\left (x^{5} + 2 \, x\right )}}\right ) + \frac{1}{16} \, \sqrt{2} \log \left (\frac{4 \,{\left (x^{4} + \sqrt{2}{\left (x^{4} + 2\right )}^{\frac{1}{4}} x^{3} + 2 \, \sqrt{x^{4} + 2} x^{2} + \sqrt{2}{\left (x^{4} + 2\right )}^{\frac{3}{4}} x + 1\right )}}{x^{4} + 1}\right ) - \frac{1}{16} \, \sqrt{2} \log \left (\frac{4 \,{\left (x^{4} - \sqrt{2}{\left (x^{4} + 2\right )}^{\frac{1}{4}} x^{3} + 2 \, \sqrt{x^{4} + 2} x^{2} - \sqrt{2}{\left (x^{4} + 2\right )}^{\frac{3}{4}} x + 1\right )}}{x^{4} + 1}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (x^{4} + 1\right ) \sqrt [4]{x^{4} + 2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (x^{4} + 2\right )}^{\frac{1}{4}}{\left (x^{4} + 1\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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