Optimal. Leaf size=74 \[ \frac{1}{12} (2 x+1) \left (x^2+x+1\right )^{5/2}+\frac{5}{64} (2 x+1) \left (x^2+x+1\right )^{3/2}+\frac{45}{512} (2 x+1) \sqrt{x^2+x+1}+\frac{135 \sinh ^{-1}\left (\frac{2 x+1}{\sqrt{3}}\right )}{1024} \]
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Rubi [A] time = 0.0190233, antiderivative size = 74, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 3, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.3, Rules used = {612, 619, 215} \[ \frac{1}{12} (2 x+1) \left (x^2+x+1\right )^{5/2}+\frac{5}{64} (2 x+1) \left (x^2+x+1\right )^{3/2}+\frac{45}{512} (2 x+1) \sqrt{x^2+x+1}+\frac{135 \sinh ^{-1}\left (\frac{2 x+1}{\sqrt{3}}\right )}{1024} \]
Antiderivative was successfully verified.
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Rule 612
Rule 619
Rule 215
Rubi steps
\begin{align*} \int \left (1+x+x^2\right )^{5/2} \, dx &=\frac{1}{12} (1+2 x) \left (1+x+x^2\right )^{5/2}+\frac{5}{8} \int \left (1+x+x^2\right )^{3/2} \, dx\\ &=\frac{5}{64} (1+2 x) \left (1+x+x^2\right )^{3/2}+\frac{1}{12} (1+2 x) \left (1+x+x^2\right )^{5/2}+\frac{45}{128} \int \sqrt{1+x+x^2} \, dx\\ &=\frac{45}{512} (1+2 x) \sqrt{1+x+x^2}+\frac{5}{64} (1+2 x) \left (1+x+x^2\right )^{3/2}+\frac{1}{12} (1+2 x) \left (1+x+x^2\right )^{5/2}+\frac{135 \int \frac{1}{\sqrt{1+x+x^2}} \, dx}{1024}\\ &=\frac{45}{512} (1+2 x) \sqrt{1+x+x^2}+\frac{5}{64} (1+2 x) \left (1+x+x^2\right )^{3/2}+\frac{1}{12} (1+2 x) \left (1+x+x^2\right )^{5/2}+\frac{\left (45 \sqrt{3}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1+\frac{x^2}{3}}} \, dx,x,1+2 x\right )}{1024}\\ &=\frac{45}{512} (1+2 x) \sqrt{1+x+x^2}+\frac{5}{64} (1+2 x) \left (1+x+x^2\right )^{3/2}+\frac{1}{12} (1+2 x) \left (1+x+x^2\right )^{5/2}+\frac{135 \sinh ^{-1}\left (\frac{1+2 x}{\sqrt{3}}\right )}{1024}\\ \end{align*}
Mathematica [A] time = 0.0206426, size = 56, normalized size = 0.76 \[ \frac{2 \sqrt{x^2+x+1} \left (256 x^5+640 x^4+1264 x^3+1256 x^2+1142 x+383\right )+405 \sinh ^{-1}\left (\frac{2 x+1}{\sqrt{3}}\right )}{3072} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.003, size = 58, normalized size = 0.8 \begin{align*}{\frac{1+2\,x}{12} \left ({x}^{2}+x+1 \right ) ^{{\frac{5}{2}}}}+{\frac{5+10\,x}{64} \left ({x}^{2}+x+1 \right ) ^{{\frac{3}{2}}}}+{\frac{45+90\,x}{512}\sqrt{{x}^{2}+x+1}}+{\frac{135}{1024}{\it Arcsinh} \left ({\frac{2\,\sqrt{3}}{3} \left ( x+{\frac{1}{2}} \right ) } \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.44686, size = 104, normalized size = 1.41 \begin{align*} \frac{1}{6} \,{\left (x^{2} + x + 1\right )}^{\frac{5}{2}} x + \frac{1}{12} \,{\left (x^{2} + x + 1\right )}^{\frac{5}{2}} + \frac{5}{32} \,{\left (x^{2} + x + 1\right )}^{\frac{3}{2}} x + \frac{5}{64} \,{\left (x^{2} + x + 1\right )}^{\frac{3}{2}} + \frac{45}{256} \, \sqrt{x^{2} + x + 1} x + \frac{45}{512} \, \sqrt{x^{2} + x + 1} + \frac{135}{1024} \, \operatorname{arsinh}\left (\frac{1}{3} \, \sqrt{3}{\left (2 \, x + 1\right )}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.18232, size = 176, normalized size = 2.38 \begin{align*} \frac{1}{1536} \,{\left (256 \, x^{5} + 640 \, x^{4} + 1264 \, x^{3} + 1256 \, x^{2} + 1142 \, x + 383\right )} \sqrt{x^{2} + x + 1} - \frac{135}{1024} \, \log \left (-2 \, x + 2 \, \sqrt{x^{2} + x + 1} - 1\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (x^{2} + x + 1\right )^{\frac{5}{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.06681, size = 73, normalized size = 0.99 \begin{align*} \frac{1}{1536} \,{\left (2 \,{\left (4 \,{\left (2 \,{\left (8 \,{\left (2 \, x + 5\right )} x + 79\right )} x + 157\right )} x + 571\right )} x + 383\right )} \sqrt{x^{2} + x + 1} - \frac{135}{1024} \, \log \left (-2 \, x + 2 \, \sqrt{x^{2} + x + 1} - 1\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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