Optimal. Leaf size=16 \[ -A \tanh ^{-1}\left (\frac{A \tan (z)}{B}\right )-B z \]
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Rubi [A] time = 0.0859799, antiderivative size = 16, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 39, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.128, Rules used = {12, 3191, 391, 203, 206} \[ -A \tanh ^{-1}\left (\frac{A \tan (z)}{B}\right )-B z \]
Antiderivative was successfully verified.
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Rule 12
Rule 3191
Rule 391
Rule 203
Rule 206
Rubi steps
\begin{align*} \int \frac{\left (-A^2-B^2\right ) \cos ^2(z)}{B \left (1-\frac{\left (A^2+B^2\right ) \sin ^2(z)}{B^2}\right )} \, dz &=-\frac{\left (A^2+B^2\right ) \int \frac{\cos ^2(z)}{1-\frac{\left (A^2+B^2\right ) \sin ^2(z)}{B^2}} \, dz}{B}\\ &=-\frac{\left (A^2+B^2\right ) \operatorname{Subst}\left (\int \frac{1}{\left (1+z^2\right ) \left (1+\left (1-\frac{A^2+B^2}{B^2}\right ) z^2\right )} \, dz,z,\tan (z)\right )}{B}\\ &=-\frac{A^2 \operatorname{Subst}\left (\int \frac{1}{1+\left (1-\frac{A^2+B^2}{B^2}\right ) z^2} \, dz,z,\tan (z)\right )}{B}-B \operatorname{Subst}\left (\int \frac{1}{1+z^2} \, dz,z,\tan (z)\right )\\ &=-B z-A \tanh ^{-1}\left (\frac{A \tan (z)}{B}\right )\\ \end{align*}
Mathematica [B] time = 0.0902899, size = 35, normalized size = 2.19 \[ -\frac{B \left (A^2+B^2\right ) \left (A \tanh ^{-1}\left (\frac{A \tan (z)}{B}\right )+B z\right )}{A^2 B+B^3} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.036, size = 127, normalized size = 7.9 \begin{align*}{\frac{{A}^{3}\ln \left ( A\tan \left ( z \right ) -B \right ) }{2\,{A}^{2}+2\,{B}^{2}}}+{\frac{A{B}^{2}\ln \left ( A\tan \left ( z \right ) -B \right ) }{2\,{A}^{2}+2\,{B}^{2}}}-{\frac{B\arctan \left ( \tan \left ( z \right ) \right ){A}^{2}}{{A}^{2}+{B}^{2}}}-{\frac{\arctan \left ( \tan \left ( z \right ) \right ){B}^{3}}{{A}^{2}+{B}^{2}}}-{\frac{{A}^{3}\ln \left ( A\tan \left ( z \right ) +B \right ) }{2\,{A}^{2}+2\,{B}^{2}}}-{\frac{A{B}^{2}\ln \left ( A\tan \left ( z \right ) +B \right ) }{2\,{A}^{2}+2\,{B}^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.41742, size = 93, normalized size = 5.81 \begin{align*} -\frac{{\left (A^{2} + B^{2}\right )}{\left (\frac{2 \, B^{2} z}{A^{2} + B^{2}} + \frac{A B \log \left (A \tan \left (z\right ) + B\right )}{A^{2} + B^{2}} - \frac{A B \log \left (A \tan \left (z\right ) - B\right )}{A^{2} + B^{2}}\right )}}{2 \, B} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.73631, size = 177, normalized size = 11.06 \begin{align*} -B z - \frac{1}{4} \, A \log \left (2 \, A B \cos \left (z\right ) \sin \left (z\right ) -{\left (A^{2} - B^{2}\right )} \cos \left (z\right )^{2} + A^{2}\right ) + \frac{1}{4} \, A \log \left (-2 \, A B \cos \left (z\right ) \sin \left (z\right ) -{\left (A^{2} - B^{2}\right )} \cos \left (z\right )^{2} + A^{2}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.11659, size = 112, normalized size = 7. \begin{align*} -\frac{{\left (\frac{A^{3} B \log \left ({\left | A \tan \left (z\right ) + B \right |}\right )}{A^{4} + A^{2} B^{2}} - \frac{A^{3} B \log \left ({\left | A \tan \left (z\right ) - B \right |}\right )}{A^{4} + A^{2} B^{2}} + \frac{2 \, B^{2} z}{A^{2} + B^{2}}\right )}{\left (A^{2} + B^{2}\right )}}{2 \, B} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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