Optimal. Leaf size=334 \[ x \log \left (x^4+\frac{1}{x^4}\right )-\frac{1}{2} \sqrt{2-\sqrt{2}} \log \left (x^2-\sqrt{2-\sqrt{2}} x+1\right )+\frac{1}{2} \sqrt{2-\sqrt{2}} \log \left (x^2+\sqrt{2-\sqrt{2}} x+1\right )-\frac{1}{2} \sqrt{2+\sqrt{2}} \log \left (x^2-\sqrt{2+\sqrt{2}} x+1\right )+\frac{1}{2} \sqrt{2+\sqrt{2}} \log \left (x^2+\sqrt{2+\sqrt{2}} x+1\right )-4 x-\sqrt{2+\sqrt{2}} \tan ^{-1}\left (\frac{\sqrt{2-\sqrt{2}}-2 x}{\sqrt{2+\sqrt{2}}}\right )-\sqrt{2-\sqrt{2}} \tan ^{-1}\left (\frac{\sqrt{2+\sqrt{2}}-2 x}{\sqrt{2-\sqrt{2}}}\right )+\sqrt{2+\sqrt{2}} \tan ^{-1}\left (\frac{2 x+\sqrt{2-\sqrt{2}}}{\sqrt{2+\sqrt{2}}}\right )+\sqrt{2-\sqrt{2}} \tan ^{-1}\left (\frac{2 x+\sqrt{2+\sqrt{2}}}{\sqrt{2-\sqrt{2}}}\right ) \]
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Rubi [A] time = 0.347468, antiderivative size = 334, normalized size of antiderivative = 1., number of steps used = 22, number of rules used = 9, integrand size = 8, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 1.125, Rules used = {2523, 12, 388, 213, 1169, 634, 618, 204, 628} \[ x \log \left (x^4+\frac{1}{x^4}\right )-\frac{1}{2} \sqrt{2-\sqrt{2}} \log \left (x^2-\sqrt{2-\sqrt{2}} x+1\right )+\frac{1}{2} \sqrt{2-\sqrt{2}} \log \left (x^2+\sqrt{2-\sqrt{2}} x+1\right )-\frac{1}{2} \sqrt{2+\sqrt{2}} \log \left (x^2-\sqrt{2+\sqrt{2}} x+1\right )+\frac{1}{2} \sqrt{2+\sqrt{2}} \log \left (x^2+\sqrt{2+\sqrt{2}} x+1\right )-4 x-\sqrt{2+\sqrt{2}} \tan ^{-1}\left (\frac{\sqrt{2-\sqrt{2}}-2 x}{\sqrt{2+\sqrt{2}}}\right )-\sqrt{2-\sqrt{2}} \tan ^{-1}\left (\frac{\sqrt{2+\sqrt{2}}-2 x}{\sqrt{2-\sqrt{2}}}\right )+\sqrt{2+\sqrt{2}} \tan ^{-1}\left (\frac{2 x+\sqrt{2-\sqrt{2}}}{\sqrt{2+\sqrt{2}}}\right )+\sqrt{2-\sqrt{2}} \tan ^{-1}\left (\frac{2 x+\sqrt{2+\sqrt{2}}}{\sqrt{2-\sqrt{2}}}\right ) \]
Antiderivative was successfully verified.
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Rule 2523
Rule 12
Rule 388
Rule 213
Rule 1169
Rule 634
Rule 618
Rule 204
Rule 628
Rubi steps
\begin{align*} \int \log \left (\frac{1}{x^4}+x^4\right ) \, dx &=x \log \left (\frac{1}{x^4}+x^4\right )-\int \frac{4 \left (-1+x^8\right )}{1+x^8} \, dx\\ &=x \log \left (\frac{1}{x^4}+x^4\right )-4 \int \frac{-1+x^8}{1+x^8} \, dx\\ &=-4 x+x \log \left (\frac{1}{x^4}+x^4\right )+8 \int \frac{1}{1+x^8} \, dx\\ &=-4 x+x \log \left (\frac{1}{x^4}+x^4\right )+\left (2 \sqrt{2}\right ) \int \frac{\sqrt{2}-x^2}{1-\sqrt{2} x^2+x^4} \, dx+\left (2 \sqrt{2}\right ) \int \frac{\sqrt{2}+x^2}{1+\sqrt{2} x^2+x^4} \, dx\\ &=-4 x+x \log \left (\frac{1}{x^4}+x^4\right )+\sqrt{2-\sqrt{2}} \int \frac{\sqrt{2 \left (2+\sqrt{2}\right )}-\left (1+\sqrt{2}\right ) x}{1-\sqrt{2+\sqrt{2}} x+x^2} \, dx+\sqrt{2-\sqrt{2}} \int \frac{\sqrt{2 \left (2+\sqrt{2}\right )}+\left (1+\sqrt{2}\right ) x}{1+\sqrt{2+\sqrt{2}} x+x^2} \, dx+\sqrt{2+\sqrt{2}} \int \frac{\sqrt{2 \left (2-\sqrt{2}\right )}-\left (-1+\sqrt{2}\right ) x}{1-\sqrt{2-\sqrt{2}} x+x^2} \, dx+\sqrt{2+\sqrt{2}} \int \frac{\sqrt{2 \left (2-\sqrt{2}\right )}+\left (-1+\sqrt{2}\right ) x}{1+\sqrt{2-\sqrt{2}} x+x^2} \, dx\\ &=-4 x+x \log \left (\frac{1}{x^4}+x^4\right )-\frac{1}{2} \sqrt{2-\sqrt{2}} \int \frac{-\sqrt{2-\sqrt{2}}+2 x}{1-\sqrt{2-\sqrt{2}} x+x^2} \, dx+\frac{1}{2} \sqrt{2-\sqrt{2}} \int \frac{\sqrt{2-\sqrt{2}}+2 x}{1+\sqrt{2-\sqrt{2}} x+x^2} \, dx+\frac{1}{2} \left (2-\sqrt{2}\right ) \int \frac{1}{1-\sqrt{2+\sqrt{2}} x+x^2} \, dx+\frac{1}{2} \left (2-\sqrt{2}\right ) \int \frac{1}{1+\sqrt{2+\sqrt{2}} x+x^2} \, dx-\frac{1}{2} \sqrt{2+\sqrt{2}} \int \frac{-\sqrt{2+\sqrt{2}}+2 x}{1-\sqrt{2+\sqrt{2}} x+x^2} \, dx+\frac{1}{2} \sqrt{2+\sqrt{2}} \int \frac{\sqrt{2+\sqrt{2}}+2 x}{1+\sqrt{2+\sqrt{2}} x+x^2} \, dx+\frac{1}{2} \left (2+\sqrt{2}\right ) \int \frac{1}{1-\sqrt{2-\sqrt{2}} x+x^2} \, dx+\frac{1}{2} \left (2+\sqrt{2}\right ) \int \frac{1}{1+\sqrt{2-\sqrt{2}} x+x^2} \, dx\\ &=-4 x-\frac{1}{2} \sqrt{2-\sqrt{2}} \log \left (1-\sqrt{2-\sqrt{2}} x+x^2\right )+\frac{1}{2} \sqrt{2-\sqrt{2}} \log \left (1+\sqrt{2-\sqrt{2}} x+x^2\right )-\frac{1}{2} \sqrt{2+\sqrt{2}} \log \left (1-\sqrt{2+\sqrt{2}} x+x^2\right )+\frac{1}{2} \sqrt{2+\sqrt{2}} \log \left (1+\sqrt{2+\sqrt{2}} x+x^2\right )+x \log \left (\frac{1}{x^4}+x^4\right )+\left (-2+\sqrt{2}\right ) \operatorname{Subst}\left (\int \frac{1}{-2+\sqrt{2}-x^2} \, dx,x,-\sqrt{2+\sqrt{2}}+2 x\right )+\left (-2+\sqrt{2}\right ) \operatorname{Subst}\left (\int \frac{1}{-2+\sqrt{2}-x^2} \, dx,x,\sqrt{2+\sqrt{2}}+2 x\right )-\left (2+\sqrt{2}\right ) \operatorname{Subst}\left (\int \frac{1}{-2-\sqrt{2}-x^2} \, dx,x,-\sqrt{2-\sqrt{2}}+2 x\right )-\left (2+\sqrt{2}\right ) \operatorname{Subst}\left (\int \frac{1}{-2-\sqrt{2}-x^2} \, dx,x,\sqrt{2-\sqrt{2}}+2 x\right )\\ &=-4 x-\sqrt{2+\sqrt{2}} \tan ^{-1}\left (\frac{\sqrt{2-\sqrt{2}}-2 x}{\sqrt{2+\sqrt{2}}}\right )-\sqrt{2-\sqrt{2}} \tan ^{-1}\left (\frac{\sqrt{2+\sqrt{2}}-2 x}{\sqrt{2-\sqrt{2}}}\right )+\sqrt{2+\sqrt{2}} \tan ^{-1}\left (\frac{\sqrt{2-\sqrt{2}}+2 x}{\sqrt{2+\sqrt{2}}}\right )+\sqrt{2-\sqrt{2}} \tan ^{-1}\left (\frac{\sqrt{2+\sqrt{2}}+2 x}{\sqrt{2-\sqrt{2}}}\right )-\frac{1}{2} \sqrt{2-\sqrt{2}} \log \left (1-\sqrt{2-\sqrt{2}} x+x^2\right )+\frac{1}{2} \sqrt{2-\sqrt{2}} \log \left (1+\sqrt{2-\sqrt{2}} x+x^2\right )-\frac{1}{2} \sqrt{2+\sqrt{2}} \log \left (1-\sqrt{2+\sqrt{2}} x+x^2\right )+\frac{1}{2} \sqrt{2+\sqrt{2}} \log \left (1+\sqrt{2+\sqrt{2}} x+x^2\right )+x \log \left (\frac{1}{x^4}+x^4\right )\\ \end{align*}
Mathematica [C] time = 0.0041239, size = 30, normalized size = 0.09 \[ 8 x \text{Hypergeometric2F1}\left (\frac{1}{8},1,\frac{9}{8},-x^8\right )+x \log \left (x^4+\frac{1}{x^4}\right )-4 x \]
Antiderivative was successfully verified.
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Maple [C] time = 0.015, size = 36, normalized size = 0.1 \begin{align*} x\ln \left ({\frac{{x}^{8}+1}{{x}^{4}}} \right ) -4\,x+\sum _{{\it \_R}={\it RootOf} \left ({{\it \_Z}}^{8}+1 \right ) }{\frac{\ln \left ( x-{\it \_R} \right ) }{{{\it \_R}}^{7}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} x \log \left (x^{8} + 1\right ) - 4 \, x \log \left (x\right ) - 4 \, x + 8 \, \int \frac{1}{x^{8} + 1}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.21965, size = 3152, normalized size = 9.44 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 1.19951, size = 26, normalized size = 0.08 \begin{align*} x \log{\left (x^{4} + \frac{1}{x^{4}} \right )} - 4 x - \operatorname{RootSum}{\left (t^{8} + 1, \left ( t \mapsto t \log{\left (- t + x \right )} \right )\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.12418, size = 335, normalized size = 1. \begin{align*} x \log \left (x^{4} + \frac{1}{x^{4}}\right ) + \sqrt{\sqrt{2} + 2} \arctan \left (\frac{2 \, x + \sqrt{-\sqrt{2} + 2}}{\sqrt{\sqrt{2} + 2}}\right ) + \sqrt{\sqrt{2} + 2} \arctan \left (\frac{2 \, x - \sqrt{-\sqrt{2} + 2}}{\sqrt{\sqrt{2} + 2}}\right ) + \sqrt{-\sqrt{2} + 2} \arctan \left (\frac{2 \, x + \sqrt{\sqrt{2} + 2}}{\sqrt{-\sqrt{2} + 2}}\right ) + \sqrt{-\sqrt{2} + 2} \arctan \left (\frac{2 \, x - \sqrt{\sqrt{2} + 2}}{\sqrt{-\sqrt{2} + 2}}\right ) + \frac{1}{2} \, \sqrt{\sqrt{2} + 2} \log \left (x^{2} + x \sqrt{\sqrt{2} + 2} + 1\right ) - \frac{1}{2} \, \sqrt{\sqrt{2} + 2} \log \left (x^{2} - x \sqrt{\sqrt{2} + 2} + 1\right ) + \frac{1}{2} \, \sqrt{-\sqrt{2} + 2} \log \left (x^{2} + x \sqrt{-\sqrt{2} + 2} + 1\right ) - \frac{1}{2} \, \sqrt{-\sqrt{2} + 2} \log \left (x^{2} - x \sqrt{-\sqrt{2} + 2} + 1\right ) - 4 \, x \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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