Optimal. Leaf size=73 \[ \frac{2}{5} \left (5+\sqrt{5}\right ) \log \left (-2 \sqrt{\sqrt{x+1}+1}-\sqrt{5}+1\right )+\frac{2}{5} \left (5-\sqrt{5}\right ) \log \left (-2 \sqrt{\sqrt{x+1}+1}+\sqrt{5}+1\right ) \]
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Rubi [A] time = 0.108042, antiderivative size = 73, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 2, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.105, Rules used = {632, 31} \[ \frac{2}{5} \left (5+\sqrt{5}\right ) \log \left (-2 \sqrt{\sqrt{x+1}+1}-\sqrt{5}+1\right )+\frac{2}{5} \left (5-\sqrt{5}\right ) \log \left (-2 \sqrt{\sqrt{x+1}+1}+\sqrt{5}+1\right ) \]
Antiderivative was successfully verified.
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Rule 632
Rule 31
Rubi steps
\begin{align*} \int \frac{1}{x-\sqrt{1+\sqrt{1+x}}} \, dx &=2 \operatorname{Subst}\left (\int \frac{x}{-1+x^2-\sqrt{1+x}} \, dx,x,\sqrt{1+x}\right )\\ &=4 \operatorname{Subst}\left (\int \frac{-1+x}{-1-x+x^2} \, dx,x,\sqrt{1+\sqrt{1+x}}\right )\\ &=\frac{1}{5} \left (2 \left (5-\sqrt{5}\right )\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{1}{2}-\frac{\sqrt{5}}{2}+x} \, dx,x,\sqrt{1+\sqrt{1+x}}\right )+\frac{1}{5} \left (2 \left (5+\sqrt{5}\right )\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{1}{2}+\frac{\sqrt{5}}{2}+x} \, dx,x,\sqrt{1+\sqrt{1+x}}\right )\\ &=\frac{2}{5} \left (5+\sqrt{5}\right ) \log \left (1-\sqrt{5}-2 \sqrt{1+\sqrt{1+x}}\right )+\frac{2}{5} \left (5-\sqrt{5}\right ) \log \left (1+\sqrt{5}-2 \sqrt{1+\sqrt{1+x}}\right )\\ \end{align*}
Mathematica [A] time = 0.0581307, size = 71, normalized size = 0.97 \[ \frac{1}{5} \left (2 \left (5+\sqrt{5}\right ) \log \left (-2 \sqrt{\sqrt{x+1}+1}-\sqrt{5}+1\right )-2 \left (\sqrt{5}-5\right ) \log \left (-2 \sqrt{\sqrt{x+1}+1}+\sqrt{5}+1\right )\right ) \]
Antiderivative was successfully verified.
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Maple [B] time = 0.104, size = 175, normalized size = 2.4 \begin{align*}{\frac{\sqrt{5}}{5}{\it Artanh} \left ({\frac{ \left ( 2\,x-1 \right ) \sqrt{5}}{5}} \right ) }+{\frac{\sqrt{5}}{5}{\it Artanh} \left ({\frac{\sqrt{5}}{5} \left ( 2\,\sqrt{1+x}+1 \right ) } \right ) }+{\frac{2\,\sqrt{5}}{5}{\it Artanh} \left ({\frac{\sqrt{5}}{5} \left ( 1+2\,\sqrt{1+\sqrt{1+x}} \right ) } \right ) }+{\frac{\ln \left ({x}^{2}-x-1 \right ) }{2}}+{\frac{\sqrt{5}}{5}{\it Artanh} \left ({\frac{\sqrt{5}}{5} \left ( 2\,\sqrt{1+x}-1 \right ) } \right ) }+{\frac{2\,\sqrt{5}}{5}{\it Artanh} \left ({\frac{\sqrt{5}}{5} \left ( 2\,\sqrt{1+\sqrt{1+x}}-1 \right ) } \right ) }+\ln \left ( \sqrt{1+x}-\sqrt{1+\sqrt{1+x}} \right ) -\ln \left ( \sqrt{1+x}+\sqrt{1+\sqrt{1+x}} \right ) +{\frac{1}{2}\ln \left ( x-\sqrt{1+x} \right ) }-{\frac{1}{2}\ln \left ( x+\sqrt{1+x} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.45819, size = 85, normalized size = 1.16 \begin{align*} -\frac{2}{5} \, \sqrt{5} \log \left (-\frac{\sqrt{5} - 2 \, \sqrt{\sqrt{x + 1} + 1} + 1}{\sqrt{5} + 2 \, \sqrt{\sqrt{x + 1} + 1} - 1}\right ) + 2 \, \log \left (\sqrt{x + 1} - \sqrt{\sqrt{x + 1} + 1}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.09437, size = 323, normalized size = 4.42 \begin{align*} \frac{2}{5} \, \sqrt{5} \log \left (\frac{2 \, x^{2} + \sqrt{5}{\left (3 \, x + 1\right )} +{\left (\sqrt{5}{\left (x + 2\right )} + 5 \, x\right )} \sqrt{x + 1} +{\left (\sqrt{5}{\left (x + 2\right )} +{\left (\sqrt{5}{\left (2 \, x - 1\right )} + 5\right )} \sqrt{x + 1} + 5 \, x\right )} \sqrt{\sqrt{x + 1} + 1} + 3 \, x + 3}{x^{2} - x - 1}\right ) + 2 \, \log \left (\sqrt{x + 1} - \sqrt{\sqrt{x + 1} + 1}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{x - \sqrt{\sqrt{x + 1} + 1}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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