Optimal. Leaf size=36 \[ -\frac{x}{\sqrt{2}}+x-\frac{\tan ^{-1}\left (\frac{\sin (x) \cos (x)}{\sin ^2(x)+\sqrt{2}+1}\right )}{\sqrt{2}} \]
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Rubi [A] time = 0.0377339, antiderivative size = 36, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.231, Rules used = {3171, 3181, 203} \[ -\frac{x}{\sqrt{2}}+x-\frac{\tan ^{-1}\left (\frac{\sin (x) \cos (x)}{\sin ^2(x)+\sqrt{2}+1}\right )}{\sqrt{2}} \]
Antiderivative was successfully verified.
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Rule 3171
Rule 3181
Rule 203
Rubi steps
\begin{align*} \int \frac{\sin ^2(x)}{1+\sin ^2(x)} \, dx &=x-\int \frac{1}{1+\sin ^2(x)} \, dx\\ &=x-\operatorname{Subst}\left (\int \frac{1}{1+2 x^2} \, dx,x,\tan (x)\right )\\ &=x-\frac{x}{\sqrt{2}}-\frac{\tan ^{-1}\left (\frac{\cos (x) \sin (x)}{1+\sqrt{2}+\sin ^2(x)}\right )}{\sqrt{2}}\\ \end{align*}
Mathematica [A] time = 0.0288295, size = 18, normalized size = 0.5 \[ x-\frac{\tan ^{-1}\left (\sqrt{2} \tan (x)\right )}{\sqrt{2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.019, size = 15, normalized size = 0.4 \begin{align*} -{\frac{\sqrt{2}\arctan \left ( \tan \left ( x \right ) \sqrt{2} \right ) }{2}}+x \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.44985, size = 19, normalized size = 0.53 \begin{align*} -\frac{1}{2} \, \sqrt{2} \arctan \left (\sqrt{2} \tan \left (x\right )\right ) + x \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.21058, size = 105, normalized size = 2.92 \begin{align*} \frac{1}{4} \, \sqrt{2} \arctan \left (\frac{3 \, \sqrt{2} \cos \left (x\right )^{2} - 2 \, \sqrt{2}}{4 \, \cos \left (x\right ) \sin \left (x\right )}\right ) + x \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] time = 64.5499, size = 581, normalized size = 16.14 \begin{align*} \frac{7 \sqrt{2} x \sqrt{3 - 2 \sqrt{2}} \sqrt{2 \sqrt{2} + 3}}{7 \sqrt{2} \sqrt{3 - 2 \sqrt{2}} \sqrt{2 \sqrt{2} + 3} + 10 \sqrt{3 - 2 \sqrt{2}} \sqrt{2 \sqrt{2} + 3}} + \frac{10 x \sqrt{3 - 2 \sqrt{2}} \sqrt{2 \sqrt{2} + 3}}{7 \sqrt{2} \sqrt{3 - 2 \sqrt{2}} \sqrt{2 \sqrt{2} + 3} + 10 \sqrt{3 - 2 \sqrt{2}} \sqrt{2 \sqrt{2} + 3}} - \frac{3 \sqrt{2 \sqrt{2} + 3} \left (\operatorname{atan}{\left (\frac{\tan{\left (\frac{x}{2} \right )}}{\sqrt{3 - 2 \sqrt{2}}} \right )} + \pi \left \lfloor{\frac{\frac{x}{2} - \frac{\pi }{2}}{\pi }}\right \rfloor \right )}{7 \sqrt{2} \sqrt{3 - 2 \sqrt{2}} \sqrt{2 \sqrt{2} + 3} + 10 \sqrt{3 - 2 \sqrt{2}} \sqrt{2 \sqrt{2} + 3}} - \frac{2 \sqrt{2} \sqrt{2 \sqrt{2} + 3} \left (\operatorname{atan}{\left (\frac{\tan{\left (\frac{x}{2} \right )}}{\sqrt{3 - 2 \sqrt{2}}} \right )} + \pi \left \lfloor{\frac{\frac{x}{2} - \frac{\pi }{2}}{\pi }}\right \rfloor \right )}{7 \sqrt{2} \sqrt{3 - 2 \sqrt{2}} \sqrt{2 \sqrt{2} + 3} + 10 \sqrt{3 - 2 \sqrt{2}} \sqrt{2 \sqrt{2} + 3}} - \frac{17 \sqrt{3 - 2 \sqrt{2}} \left (\operatorname{atan}{\left (\frac{\tan{\left (\frac{x}{2} \right )}}{\sqrt{2 \sqrt{2} + 3}} \right )} + \pi \left \lfloor{\frac{\frac{x}{2} - \frac{\pi }{2}}{\pi }}\right \rfloor \right )}{7 \sqrt{2} \sqrt{3 - 2 \sqrt{2}} \sqrt{2 \sqrt{2} + 3} + 10 \sqrt{3 - 2 \sqrt{2}} \sqrt{2 \sqrt{2} + 3}} - \frac{12 \sqrt{2} \sqrt{3 - 2 \sqrt{2}} \left (\operatorname{atan}{\left (\frac{\tan{\left (\frac{x}{2} \right )}}{\sqrt{2 \sqrt{2} + 3}} \right )} + \pi \left \lfloor{\frac{\frac{x}{2} - \frac{\pi }{2}}{\pi }}\right \rfloor \right )}{7 \sqrt{2} \sqrt{3 - 2 \sqrt{2}} \sqrt{2 \sqrt{2} + 3} + 10 \sqrt{3 - 2 \sqrt{2}} \sqrt{2 \sqrt{2} + 3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.09124, size = 65, normalized size = 1.81 \begin{align*} -\frac{1}{2} \, \sqrt{2}{\left (x + \arctan \left (-\frac{\sqrt{2} \sin \left (2 \, x\right ) - 2 \, \sin \left (2 \, x\right )}{\sqrt{2} \cos \left (2 \, x\right ) + \sqrt{2} - 2 \, \cos \left (2 \, x\right ) + 2}\right )\right )} + x \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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