Optimal. Leaf size=313 \[ -\text{PolyLog}\left (2,\frac{2 \left (1-\sqrt{x+1}\right )}{3-\sqrt{5}}\right )-\text{PolyLog}\left (2,\frac{2 \left (1-\sqrt{x+1}\right )}{3+\sqrt{5}}\right )-\text{PolyLog}\left (2,\frac{2 \left (\sqrt{x+1}+1\right )}{1-\sqrt{5}}\right )-\text{PolyLog}\left (2,\frac{2 \left (\sqrt{x+1}+1\right )}{1+\sqrt{5}}\right )+\log \left (\sqrt{x+1}-1\right ) \log \left (x+\sqrt{x+1}\right )+\log \left (\sqrt{x+1}+1\right ) \log \left (x+\sqrt{x+1}\right )-\log \left (\sqrt{x+1}-1\right ) \log \left (\frac{2 \sqrt{x+1}-\sqrt{5}+1}{3-\sqrt{5}}\right )-\log \left (\sqrt{x+1}+1\right ) \log \left (-\frac{2 \sqrt{x+1}-\sqrt{5}+1}{1+\sqrt{5}}\right )-\log \left (\sqrt{x+1}+1\right ) \log \left (-\frac{2 \sqrt{x+1}+\sqrt{5}+1}{1-\sqrt{5}}\right )-\log \left (\sqrt{x+1}-1\right ) \log \left (\frac{2 \sqrt{x+1}+\sqrt{5}+1}{3+\sqrt{5}}\right ) \]
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Rubi [A] time = 0.377384, antiderivative size = 313, normalized size of antiderivative = 1., number of steps used = 21, number of rules used = 7, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.5, Rules used = {2530, 2528, 2524, 2418, 2394, 2393, 2391} \[ -\text{PolyLog}\left (2,\frac{2 \left (1-\sqrt{x+1}\right )}{3-\sqrt{5}}\right )-\text{PolyLog}\left (2,\frac{2 \left (1-\sqrt{x+1}\right )}{3+\sqrt{5}}\right )-\text{PolyLog}\left (2,\frac{2 \left (\sqrt{x+1}+1\right )}{1-\sqrt{5}}\right )-\text{PolyLog}\left (2,\frac{2 \left (\sqrt{x+1}+1\right )}{1+\sqrt{5}}\right )+\log \left (\sqrt{x+1}-1\right ) \log \left (x+\sqrt{x+1}\right )+\log \left (\sqrt{x+1}+1\right ) \log \left (x+\sqrt{x+1}\right )-\log \left (\sqrt{x+1}-1\right ) \log \left (\frac{2 \sqrt{x+1}-\sqrt{5}+1}{3-\sqrt{5}}\right )-\log \left (\sqrt{x+1}+1\right ) \log \left (-\frac{2 \sqrt{x+1}-\sqrt{5}+1}{1+\sqrt{5}}\right )-\log \left (\sqrt{x+1}+1\right ) \log \left (-\frac{2 \sqrt{x+1}+\sqrt{5}+1}{1-\sqrt{5}}\right )-\log \left (\sqrt{x+1}-1\right ) \log \left (\frac{2 \sqrt{x+1}+\sqrt{5}+1}{3+\sqrt{5}}\right ) \]
Antiderivative was successfully verified.
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Rule 2530
Rule 2528
Rule 2524
Rule 2418
Rule 2394
Rule 2393
Rule 2391
Rubi steps
\begin{align*} \int \frac{\log \left (x+\sqrt{1+x}\right )}{x} \, dx &=2 \operatorname{Subst}\left (\int \frac{x \log \left (-1+x+x^2\right )}{-1+x^2} \, dx,x,\sqrt{1+x}\right )\\ &=2 \operatorname{Subst}\left (\int \left (\frac{\log \left (-1+x+x^2\right )}{2 (-1+x)}+\frac{\log \left (-1+x+x^2\right )}{2 (1+x)}\right ) \, dx,x,\sqrt{1+x}\right )\\ &=\operatorname{Subst}\left (\int \frac{\log \left (-1+x+x^2\right )}{-1+x} \, dx,x,\sqrt{1+x}\right )+\operatorname{Subst}\left (\int \frac{\log \left (-1+x+x^2\right )}{1+x} \, dx,x,\sqrt{1+x}\right )\\ &=\log \left (-1+\sqrt{1+x}\right ) \log \left (x+\sqrt{1+x}\right )+\log \left (1+\sqrt{1+x}\right ) \log \left (x+\sqrt{1+x}\right )-\operatorname{Subst}\left (\int \frac{(1+2 x) \log (-1+x)}{-1+x+x^2} \, dx,x,\sqrt{1+x}\right )-\operatorname{Subst}\left (\int \frac{(1+2 x) \log (1+x)}{-1+x+x^2} \, dx,x,\sqrt{1+x}\right )\\ &=\log \left (-1+\sqrt{1+x}\right ) \log \left (x+\sqrt{1+x}\right )+\log \left (1+\sqrt{1+x}\right ) \log \left (x+\sqrt{1+x}\right )-\operatorname{Subst}\left (\int \left (\frac{2 \log (-1+x)}{1-\sqrt{5}+2 x}+\frac{2 \log (-1+x)}{1+\sqrt{5}+2 x}\right ) \, dx,x,\sqrt{1+x}\right )-\operatorname{Subst}\left (\int \left (\frac{2 \log (1+x)}{1-\sqrt{5}+2 x}+\frac{2 \log (1+x)}{1+\sqrt{5}+2 x}\right ) \, dx,x,\sqrt{1+x}\right )\\ &=\log \left (-1+\sqrt{1+x}\right ) \log \left (x+\sqrt{1+x}\right )+\log \left (1+\sqrt{1+x}\right ) \log \left (x+\sqrt{1+x}\right )-2 \operatorname{Subst}\left (\int \frac{\log (-1+x)}{1-\sqrt{5}+2 x} \, dx,x,\sqrt{1+x}\right )-2 \operatorname{Subst}\left (\int \frac{\log (-1+x)}{1+\sqrt{5}+2 x} \, dx,x,\sqrt{1+x}\right )-2 \operatorname{Subst}\left (\int \frac{\log (1+x)}{1-\sqrt{5}+2 x} \, dx,x,\sqrt{1+x}\right )-2 \operatorname{Subst}\left (\int \frac{\log (1+x)}{1+\sqrt{5}+2 x} \, dx,x,\sqrt{1+x}\right )\\ &=\log \left (-1+\sqrt{1+x}\right ) \log \left (x+\sqrt{1+x}\right )+\log \left (1+\sqrt{1+x}\right ) \log \left (x+\sqrt{1+x}\right )-\log \left (-1+\sqrt{1+x}\right ) \log \left (\frac{1-\sqrt{5}+2 \sqrt{1+x}}{3-\sqrt{5}}\right )-\log \left (1+\sqrt{1+x}\right ) \log \left (-\frac{1-\sqrt{5}+2 \sqrt{1+x}}{1+\sqrt{5}}\right )-\log \left (1+\sqrt{1+x}\right ) \log \left (-\frac{1+\sqrt{5}+2 \sqrt{1+x}}{1-\sqrt{5}}\right )-\log \left (-1+\sqrt{1+x}\right ) \log \left (\frac{1+\sqrt{5}+2 \sqrt{1+x}}{3+\sqrt{5}}\right )+\operatorname{Subst}\left (\int \frac{\log \left (\frac{1-\sqrt{5}+2 x}{-1-\sqrt{5}}\right )}{1+x} \, dx,x,\sqrt{1+x}\right )+\operatorname{Subst}\left (\int \frac{\log \left (\frac{1-\sqrt{5}+2 x}{3-\sqrt{5}}\right )}{-1+x} \, dx,x,\sqrt{1+x}\right )+\operatorname{Subst}\left (\int \frac{\log \left (\frac{1+\sqrt{5}+2 x}{-1+\sqrt{5}}\right )}{1+x} \, dx,x,\sqrt{1+x}\right )+\operatorname{Subst}\left (\int \frac{\log \left (\frac{1+\sqrt{5}+2 x}{3+\sqrt{5}}\right )}{-1+x} \, dx,x,\sqrt{1+x}\right )\\ &=\log \left (-1+\sqrt{1+x}\right ) \log \left (x+\sqrt{1+x}\right )+\log \left (1+\sqrt{1+x}\right ) \log \left (x+\sqrt{1+x}\right )-\log \left (-1+\sqrt{1+x}\right ) \log \left (\frac{1-\sqrt{5}+2 \sqrt{1+x}}{3-\sqrt{5}}\right )-\log \left (1+\sqrt{1+x}\right ) \log \left (-\frac{1-\sqrt{5}+2 \sqrt{1+x}}{1+\sqrt{5}}\right )-\log \left (1+\sqrt{1+x}\right ) \log \left (-\frac{1+\sqrt{5}+2 \sqrt{1+x}}{1-\sqrt{5}}\right )-\log \left (-1+\sqrt{1+x}\right ) \log \left (\frac{1+\sqrt{5}+2 \sqrt{1+x}}{3+\sqrt{5}}\right )+\operatorname{Subst}\left (\int \frac{\log \left (1+\frac{2 x}{-1-\sqrt{5}}\right )}{x} \, dx,x,1+\sqrt{1+x}\right )+\operatorname{Subst}\left (\int \frac{\log \left (1+\frac{2 x}{3-\sqrt{5}}\right )}{x} \, dx,x,-1+\sqrt{1+x}\right )+\operatorname{Subst}\left (\int \frac{\log \left (1+\frac{2 x}{-1+\sqrt{5}}\right )}{x} \, dx,x,1+\sqrt{1+x}\right )+\operatorname{Subst}\left (\int \frac{\log \left (1+\frac{2 x}{3+\sqrt{5}}\right )}{x} \, dx,x,-1+\sqrt{1+x}\right )\\ &=\log \left (-1+\sqrt{1+x}\right ) \log \left (x+\sqrt{1+x}\right )+\log \left (1+\sqrt{1+x}\right ) \log \left (x+\sqrt{1+x}\right )-\log \left (-1+\sqrt{1+x}\right ) \log \left (\frac{1-\sqrt{5}+2 \sqrt{1+x}}{3-\sqrt{5}}\right )-\log \left (1+\sqrt{1+x}\right ) \log \left (-\frac{1-\sqrt{5}+2 \sqrt{1+x}}{1+\sqrt{5}}\right )-\log \left (1+\sqrt{1+x}\right ) \log \left (-\frac{1+\sqrt{5}+2 \sqrt{1+x}}{1-\sqrt{5}}\right )-\log \left (-1+\sqrt{1+x}\right ) \log \left (\frac{1+\sqrt{5}+2 \sqrt{1+x}}{3+\sqrt{5}}\right )-\text{Li}_2\left (-\frac{2 \left (-1+\sqrt{1+x}\right )}{3-\sqrt{5}}\right )-\text{Li}_2\left (-\frac{2 \left (-1+\sqrt{1+x}\right )}{3+\sqrt{5}}\right )-\text{Li}_2\left (\frac{2 \left (1+\sqrt{1+x}\right )}{1-\sqrt{5}}\right )-\text{Li}_2\left (\frac{2 \left (1+\sqrt{1+x}\right )}{1+\sqrt{5}}\right )\\ \end{align*}
Mathematica [A] time = 0.0863093, size = 303, normalized size = 0.97 \[ -\text{PolyLog}\left (2,\frac{2 \left (\sqrt{x+1}+1\right )}{1-\sqrt{5}}\right )+\text{PolyLog}\left (2,\frac{2 \sqrt{x+1}-\sqrt{5}+1}{3-\sqrt{5}}\right )+\text{PolyLog}\left (2,-\frac{2 \sqrt{x+1}-\sqrt{5}+1}{1+\sqrt{5}}\right )+\text{PolyLog}\left (2,\frac{2 \sqrt{x+1}+\sqrt{5}+1}{3+\sqrt{5}}\right )+\log \left (1-\sqrt{x+1}\right ) \log \left (x+\sqrt{x+1}\right )+\log \left (\sqrt{x+1}+1\right ) \log \left (x+\sqrt{x+1}\right )-\log \left (\frac{1}{2} \left (1+\sqrt{5}\right )\right ) \log \left (2 \sqrt{x+1}-\sqrt{5}+1\right )-\log \left (\frac{1}{2} \left (3-\sqrt{5}\right )\right ) \log \left (2 \sqrt{x+1}-\sqrt{5}+1\right )-\log \left (\frac{1}{2} \left (3+\sqrt{5}\right )\right ) \log \left (2 \sqrt{x+1}+\sqrt{5}+1\right )-\log \left (\sqrt{x+1}+1\right ) \log \left (-\frac{2 \sqrt{x+1}+\sqrt{5}+1}{1-\sqrt{5}}\right ) \]
Antiderivative was successfully verified.
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Maple [A] time = 0.017, size = 252, normalized size = 0.8 \begin{align*} \ln \left ( -1+\sqrt{1+x} \right ) \ln \left ( x+\sqrt{1+x} \right ) -\ln \left ( -1+\sqrt{1+x} \right ) \ln \left ({\frac{1}{\sqrt{5}-3} \left ( -1+\sqrt{5}-2\,\sqrt{1+x} \right ) } \right ) -\ln \left ( -1+\sqrt{1+x} \right ) \ln \left ({\frac{1}{3+\sqrt{5}} \left ( 1+\sqrt{5}+2\,\sqrt{1+x} \right ) } \right ) -{\it dilog} \left ({\frac{1}{\sqrt{5}-3} \left ( -1+\sqrt{5}-2\,\sqrt{1+x} \right ) } \right ) -{\it dilog} \left ({\frac{1}{3+\sqrt{5}} \left ( 1+\sqrt{5}+2\,\sqrt{1+x} \right ) } \right ) +\ln \left ( 1+\sqrt{1+x} \right ) \ln \left ( x+\sqrt{1+x} \right ) -\ln \left ( 1+\sqrt{1+x} \right ) \ln \left ({\frac{1}{\sqrt{5}+1} \left ( -1+\sqrt{5}-2\,\sqrt{1+x} \right ) } \right ) -\ln \left ( 1+\sqrt{1+x} \right ) \ln \left ({\frac{1}{\sqrt{5}-1} \left ( 1+\sqrt{5}+2\,\sqrt{1+x} \right ) } \right ) -{\it dilog} \left ({\frac{1}{\sqrt{5}+1} \left ( -1+\sqrt{5}-2\,\sqrt{1+x} \right ) } \right ) -{\it dilog} \left ({\frac{1}{\sqrt{5}-1} \left ( 1+\sqrt{5}+2\,\sqrt{1+x} \right ) } \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\log \left (x + \sqrt{x + 1}\right )}{x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\log \left (x + \sqrt{x + 1}\right )}{x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\log{\left (x + \sqrt{x + 1} \right )}}{x}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\log \left (x + \sqrt{x + 1}\right )}{x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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