3.66.20 \(\int \frac {-8+4 x^2-8 x^2 \log (x)+(-8+4 x^2) \log (-2+x^2)+((4 x-2 x^3) \log (x)+(4 x-2 x^3) \log (x) \log (-2+x^2)) \log ^3(\frac {1+2 \log (-2+x^2)+\log ^2(-2+x^2)}{\log ^2(x)})}{((-2 x+x^3) \log (x)+(-2 x+x^3) \log (x) \log (-2+x^2)) \log ^3(\frac {1+2 \log (-2+x^2)+\log ^2(-2+x^2)}{\log ^2(x)})} \, dx\)

Optimal. Leaf size=23 \[ 13-2 x+\frac {1}{\log ^2\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )} \]

________________________________________________________________________________________

Rubi [F]  time = 15.04, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {-8+4 x^2-8 x^2 \log (x)+\left (-8+4 x^2\right ) \log \left (-2+x^2\right )+\left (\left (4 x-2 x^3\right ) \log (x)+\left (4 x-2 x^3\right ) \log (x) \log \left (-2+x^2\right )\right ) \log ^3\left (\frac {1+2 \log \left (-2+x^2\right )+\log ^2\left (-2+x^2\right )}{\log ^2(x)}\right )}{\left (\left (-2 x+x^3\right ) \log (x)+\left (-2 x+x^3\right ) \log (x) \log \left (-2+x^2\right )\right ) \log ^3\left (\frac {1+2 \log \left (-2+x^2\right )+\log ^2\left (-2+x^2\right )}{\log ^2(x)}\right )} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Int[(-8 + 4*x^2 - 8*x^2*Log[x] + (-8 + 4*x^2)*Log[-2 + x^2] + ((4*x - 2*x^3)*Log[x] + (4*x - 2*x^3)*Log[x]*Log
[-2 + x^2])*Log[(1 + 2*Log[-2 + x^2] + Log[-2 + x^2]^2)/Log[x]^2]^3)/(((-2*x + x^3)*Log[x] + (-2*x + x^3)*Log[
x]*Log[-2 + x^2])*Log[(1 + 2*Log[-2 + x^2] + Log[-2 + x^2]^2)/Log[x]^2]^3),x]

[Out]

-2*x + 4*Defer[Int][1/((Sqrt[2] - x)*(1 + Log[-2 + x^2])*Log[(1 + Log[-2 + x^2])^2/Log[x]^2]^3), x] - 4*Defer[
Int][1/((Sqrt[2] + x)*(1 + Log[-2 + x^2])*Log[(1 + Log[-2 + x^2])^2/Log[x]^2]^3), x] + 4*Defer[Int][1/(x*Log[x
]*(1 + Log[-2 + x^2])*Log[(1 + Log[-2 + x^2])^2/Log[x]^2]^3), x] + 4*Defer[Int][Log[-2 + x^2]/(x*Log[x]*(1 + L
og[-2 + x^2])*Log[(1 + Log[-2 + x^2])^2/Log[x]^2]^3), x]

Rubi steps

\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {-4 \left (-2+x^2\right ) \left (1+\log \left (-2+x^2\right )\right )+2 x \log (x) \left (4 x+\left (-2+x^2\right ) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )\right )}{x \left (2-x^2\right ) \log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )} \, dx\\ &=\int \left (-2-\frac {4 \left (2-x^2+2 x^2 \log (x)+2 \log \left (-2+x^2\right )-x^2 \log \left (-2+x^2\right )\right )}{x \left (-2+x^2\right ) \log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )}\right ) \, dx\\ &=-2 x-4 \int \frac {2-x^2+2 x^2 \log (x)+2 \log \left (-2+x^2\right )-x^2 \log \left (-2+x^2\right )}{x \left (-2+x^2\right ) \log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )} \, dx\\ &=-2 x-4 \int \left (\frac {-2+x^2-2 x^2 \log (x)-2 \log \left (-2+x^2\right )+x^2 \log \left (-2+x^2\right )}{2 x \log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )}+\frac {2 x-x^3+2 x^3 \log (x)+2 x \log \left (-2+x^2\right )-x^3 \log \left (-2+x^2\right )}{2 \left (-2+x^2\right ) \log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )}\right ) \, dx\\ &=-2 x-2 \int \frac {-2+x^2-2 x^2 \log (x)-2 \log \left (-2+x^2\right )+x^2 \log \left (-2+x^2\right )}{x \log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )} \, dx-2 \int \frac {2 x-x^3+2 x^3 \log (x)+2 x \log \left (-2+x^2\right )-x^3 \log \left (-2+x^2\right )}{\left (-2+x^2\right ) \log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )} \, dx\\ &=-2 x-2 \int \left (\frac {2 x^3}{\left (-2+x^2\right ) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )}+\frac {2 x}{\left (-2+x^2\right ) \log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )}-\frac {x^3}{\left (-2+x^2\right ) \log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )}+\frac {2 x \log \left (-2+x^2\right )}{\left (-2+x^2\right ) \log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )}-\frac {x^3 \log \left (-2+x^2\right )}{\left (-2+x^2\right ) \log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )}\right ) \, dx-2 \int \frac {-2 x^2 \log (x)+\left (-2+x^2\right ) \left (1+\log \left (-2+x^2\right )\right )}{x \log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )} \, dx\\ &=-2 x-2 \int \left (-\frac {2 x}{\left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )}-\frac {2}{x \log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )}+\frac {x}{\log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )}-\frac {2 \log \left (-2+x^2\right )}{x \log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )}+\frac {x \log \left (-2+x^2\right )}{\log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )}\right ) \, dx+2 \int \frac {x^3}{\left (-2+x^2\right ) \log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )} \, dx+2 \int \frac {x^3 \log \left (-2+x^2\right )}{\left (-2+x^2\right ) \log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )} \, dx-4 \int \frac {x^3}{\left (-2+x^2\right ) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )} \, dx-4 \int \frac {x}{\left (-2+x^2\right ) \log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )} \, dx-4 \int \frac {x \log \left (-2+x^2\right )}{\left (-2+x^2\right ) \log (x) \left (1+\log \left (-2+x^2\right )\right ) \log ^3\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )} \, dx\\ &=\text {Rest of rules removed due to large latex content} \end {aligned} \end {gather*}

________________________________________________________________________________________

Mathematica [A]  time = 0.15, size = 22, normalized size = 0.96 \begin {gather*} -2 x+\frac {1}{\log ^2\left (\frac {\left (1+\log \left (-2+x^2\right )\right )^2}{\log ^2(x)}\right )} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(-8 + 4*x^2 - 8*x^2*Log[x] + (-8 + 4*x^2)*Log[-2 + x^2] + ((4*x - 2*x^3)*Log[x] + (4*x - 2*x^3)*Log[
x]*Log[-2 + x^2])*Log[(1 + 2*Log[-2 + x^2] + Log[-2 + x^2]^2)/Log[x]^2]^3)/(((-2*x + x^3)*Log[x] + (-2*x + x^3
)*Log[x]*Log[-2 + x^2])*Log[(1 + 2*Log[-2 + x^2] + Log[-2 + x^2]^2)/Log[x]^2]^3),x]

[Out]

-2*x + Log[(1 + Log[-2 + x^2])^2/Log[x]^2]^(-2)

________________________________________________________________________________________

fricas [B]  time = 0.54, size = 59, normalized size = 2.57 \begin {gather*} -\frac {2 \, x \log \left (\frac {\log \left (x^{2} - 2\right )^{2} + 2 \, \log \left (x^{2} - 2\right ) + 1}{\log \relax (x)^{2}}\right )^{2} - 1}{\log \left (\frac {\log \left (x^{2} - 2\right )^{2} + 2 \, \log \left (x^{2} - 2\right ) + 1}{\log \relax (x)^{2}}\right )^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((((-2*x^3+4*x)*log(x)*log(x^2-2)+(-2*x^3+4*x)*log(x))*log((log(x^2-2)^2+2*log(x^2-2)+1)/log(x)^2)^3+
(4*x^2-8)*log(x^2-2)-8*x^2*log(x)+4*x^2-8)/((x^3-2*x)*log(x)*log(x^2-2)+(x^3-2*x)*log(x))/log((log(x^2-2)^2+2*
log(x^2-2)+1)/log(x)^2)^3,x, algorithm="fricas")

[Out]

-(2*x*log((log(x^2 - 2)^2 + 2*log(x^2 - 2) + 1)/log(x)^2)^2 - 1)/log((log(x^2 - 2)^2 + 2*log(x^2 - 2) + 1)/log
(x)^2)^2

________________________________________________________________________________________

giac [B]  time = 69.36, size = 393, normalized size = 17.09 \begin {gather*} -2 \, x + \frac {x^{2} \log \left (x^{2} - 2\right ) - 2 \, x^{2} \log \relax (x) + x^{2} - 2 \, \log \left (x^{2} - 2\right ) - 2}{x^{2} \log \left (x^{2} - 2\right ) \log \left (\log \left (x^{2} - 2\right )^{2} + 2 \, \log \left (x^{2} - 2\right ) + 1\right )^{2} - 2 \, x^{2} \log \left (x^{2} - 2\right ) \log \left (\log \left (x^{2} - 2\right )^{2} + 2 \, \log \left (x^{2} - 2\right ) + 1\right ) \log \left (\log \relax (x)^{2}\right ) + 4 \, x^{2} \log \left (\log \left (x^{2} - 2\right )^{2} + 2 \, \log \left (x^{2} - 2\right ) + 1\right ) \log \relax (x) \log \left (\log \relax (x)^{2}\right ) + x^{2} \log \left (x^{2} - 2\right ) \log \left (\log \relax (x)^{2}\right )^{2} - 2 \, x^{2} \log \relax (x) \log \left (\log \relax (x)^{2}\right )^{2} - 2 \, x^{2} \log \left (\log \left (x^{2} - 2\right )^{2} + 2 \, \log \left (x^{2} - 2\right ) + 1\right )^{2} \log \relax (x) + x^{2} \log \left (\log \left (x^{2} - 2\right )^{2} + 2 \, \log \left (x^{2} - 2\right ) + 1\right )^{2} - 2 \, x^{2} \log \left (\log \left (x^{2} - 2\right )^{2} + 2 \, \log \left (x^{2} - 2\right ) + 1\right ) \log \left (\log \relax (x)^{2}\right ) + x^{2} \log \left (\log \relax (x)^{2}\right )^{2} - 2 \, \log \left (x^{2} - 2\right ) \log \left (\log \left (x^{2} - 2\right )^{2} + 2 \, \log \left (x^{2} - 2\right ) + 1\right )^{2} + 4 \, \log \left (x^{2} - 2\right ) \log \left (\log \left (x^{2} - 2\right )^{2} + 2 \, \log \left (x^{2} - 2\right ) + 1\right ) \log \left (\log \relax (x)^{2}\right ) - 2 \, \log \left (x^{2} - 2\right ) \log \left (\log \relax (x)^{2}\right )^{2} - 2 \, \log \left (\log \left (x^{2} - 2\right )^{2} + 2 \, \log \left (x^{2} - 2\right ) + 1\right )^{2} + 4 \, \log \left (\log \left (x^{2} - 2\right )^{2} + 2 \, \log \left (x^{2} - 2\right ) + 1\right ) \log \left (\log \relax (x)^{2}\right ) - 2 \, \log \left (\log \relax (x)^{2}\right )^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((((-2*x^3+4*x)*log(x)*log(x^2-2)+(-2*x^3+4*x)*log(x))*log((log(x^2-2)^2+2*log(x^2-2)+1)/log(x)^2)^3+
(4*x^2-8)*log(x^2-2)-8*x^2*log(x)+4*x^2-8)/((x^3-2*x)*log(x)*log(x^2-2)+(x^3-2*x)*log(x))/log((log(x^2-2)^2+2*
log(x^2-2)+1)/log(x)^2)^3,x, algorithm="giac")

[Out]

-2*x + (x^2*log(x^2 - 2) - 2*x^2*log(x) + x^2 - 2*log(x^2 - 2) - 2)/(x^2*log(x^2 - 2)*log(log(x^2 - 2)^2 + 2*l
og(x^2 - 2) + 1)^2 - 2*x^2*log(x^2 - 2)*log(log(x^2 - 2)^2 + 2*log(x^2 - 2) + 1)*log(log(x)^2) + 4*x^2*log(log
(x^2 - 2)^2 + 2*log(x^2 - 2) + 1)*log(x)*log(log(x)^2) + x^2*log(x^2 - 2)*log(log(x)^2)^2 - 2*x^2*log(x)*log(l
og(x)^2)^2 - 2*x^2*log(log(x^2 - 2)^2 + 2*log(x^2 - 2) + 1)^2*log(x) + x^2*log(log(x^2 - 2)^2 + 2*log(x^2 - 2)
+ 1)^2 - 2*x^2*log(log(x^2 - 2)^2 + 2*log(x^2 - 2) + 1)*log(log(x)^2) + x^2*log(log(x)^2)^2 - 2*log(x^2 - 2)*
log(log(x^2 - 2)^2 + 2*log(x^2 - 2) + 1)^2 + 4*log(x^2 - 2)*log(log(x^2 - 2)^2 + 2*log(x^2 - 2) + 1)*log(log(x
)^2) - 2*log(x^2 - 2)*log(log(x)^2)^2 - 2*log(log(x^2 - 2)^2 + 2*log(x^2 - 2) + 1)^2 + 4*log(log(x^2 - 2)^2 +
2*log(x^2 - 2) + 1)*log(log(x)^2) - 2*log(log(x)^2)^2)

________________________________________________________________________________________

maple [C]  time = 0.88, size = 290, normalized size = 12.61

method	result	size
risch	\(-2 x -\frac {4}{\left (\pi \mathrm {csgn}\left (i \left (\ln \left (x^{2}-2\right )+1\right )\right )^{2} \mathrm {csgn}\left (i \left (\ln \left (x^{2}-2\right )+1\right )^{2}\right )-2 \pi \,\mathrm {csgn}\left (i \left (\ln \left (x^{2}-2\right )+1\right )\right ) \mathrm {csgn}\left (i \left (\ln \left (x^{2}-2\right )+1\right )^{2}\right )^{2}+\pi \mathrm {csgn}\left (i \left (\ln \left (x^{2}-2\right )+1\right )^{2}\right )^{3}-\pi \,\mathrm {csgn}\left (i \left (\ln \left (x^{2}-2\right )+1\right )^{2}\right ) \mathrm {csgn}\left (\frac {i \left (\ln \left (x^{2}-2\right )+1\right )^{2}}{\ln \relax (x )^{2}}\right )^{2}+\pi \,\mathrm {csgn}\left (i \left (\ln \left (x^{2}-2\right )+1\right )^{2}\right ) \mathrm {csgn}\left (\frac {i \left (\ln \left (x^{2}-2\right )+1\right )^{2}}{\ln \relax (x )^{2}}\right ) \mathrm {csgn}\left (\frac {i}{\ln \relax (x )^{2}}\right )+\pi \mathrm {csgn}\left (\frac {i \left (\ln \left (x^{2}-2\right )+1\right )^{2}}{\ln \relax (x )^{2}}\right )^{3}-\pi \mathrm {csgn}\left (\frac {i \left (\ln \left (x^{2}-2\right )+1\right )^{2}}{\ln \relax (x )^{2}}\right )^{2} \mathrm {csgn}\left (\frac {i}{\ln \relax (x )^{2}}\right )-\pi \mathrm {csgn}\left (i \ln \relax (x )\right )^{2} \mathrm {csgn}\left (i \ln \relax (x )^{2}\right )+2 \pi \,\mathrm {csgn}\left (i \ln \relax (x )\right ) \mathrm {csgn}\left (i \ln \relax (x )^{2}\right )^{2}-\pi \mathrm {csgn}\left (i \ln \relax (x )^{2}\right )^{3}-4 i \ln \left (\ln \relax (x )\right )+4 i \ln \left (\ln \left (x^{2}-2\right )+1\right )\right )^{2}}\)	\(290\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((((-2*x^3+4*x)*ln(x)*ln(x^2-2)+(-2*x^3+4*x)*ln(x))*ln((ln(x^2-2)^2+2*ln(x^2-2)+1)/ln(x)^2)^3+(4*x^2-8)*ln(
x^2-2)-8*x^2*ln(x)+4*x^2-8)/((x^3-2*x)*ln(x)*ln(x^2-2)+(x^3-2*x)*ln(x))/ln((ln(x^2-2)^2+2*ln(x^2-2)+1)/ln(x)^2
)^3,x,method=_RETURNVERBOSE)

[Out]

-2*x-4/(Pi*csgn(I*(ln(x^2-2)+1))^2*csgn(I*(ln(x^2-2)+1)^2)-2*Pi*csgn(I*(ln(x^2-2)+1))*csgn(I*(ln(x^2-2)+1)^2)^
2+Pi*csgn(I*(ln(x^2-2)+1)^2)^3-Pi*csgn(I*(ln(x^2-2)+1)^2)*csgn(I/ln(x)^2*(ln(x^2-2)+1)^2)^2+Pi*csgn(I*(ln(x^2-
2)+1)^2)*csgn(I/ln(x)^2*(ln(x^2-2)+1)^2)*csgn(I/ln(x)^2)+Pi*csgn(I/ln(x)^2*(ln(x^2-2)+1)^2)^3-Pi*csgn(I/ln(x)^
2*(ln(x^2-2)+1)^2)^2*csgn(I/ln(x)^2)-Pi*csgn(I*ln(x))^2*csgn(I*ln(x)^2)+2*Pi*csgn(I*ln(x))*csgn(I*ln(x)^2)^2-P
i*csgn(I*ln(x)^2)^3-4*I*ln(ln(x))+4*I*ln(ln(x^2-2)+1))^2

________________________________________________________________________________________

maxima [B]  time = 0.45, size = 74, normalized size = 3.22 \begin {gather*} -\frac {8 \, x \log \left (\log \left (x^{2} - 2\right ) + 1\right )^{2} - 16 \, x \log \left (\log \left (x^{2} - 2\right ) + 1\right ) \log \left (\log \relax (x)\right ) + 8 \, x \log \left (\log \relax (x)\right )^{2} - 1}{4 \, {\left (\log \left (\log \left (x^{2} - 2\right ) + 1\right )^{2} - 2 \, \log \left (\log \left (x^{2} - 2\right ) + 1\right ) \log \left (\log \relax (x)\right ) + \log \left (\log \relax (x)\right )^{2}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((((-2*x^3+4*x)*log(x)*log(x^2-2)+(-2*x^3+4*x)*log(x))*log((log(x^2-2)^2+2*log(x^2-2)+1)/log(x)^2)^3+
(4*x^2-8)*log(x^2-2)-8*x^2*log(x)+4*x^2-8)/((x^3-2*x)*log(x)*log(x^2-2)+(x^3-2*x)*log(x))/log((log(x^2-2)^2+2*
log(x^2-2)+1)/log(x)^2)^3,x, algorithm="maxima")

[Out]

-1/4*(8*x*log(log(x^2 - 2) + 1)^2 - 16*x*log(log(x^2 - 2) + 1)*log(log(x)) + 8*x*log(log(x))^2 - 1)/(log(log(x
^2 - 2) + 1)^2 - 2*log(log(x^2 - 2) + 1)*log(log(x)) + log(log(x))^2)

________________________________________________________________________________________

mupad [B]  time = 4.53, size = 30, normalized size = 1.30 \begin {gather*} \frac {1}{{\ln \left (\frac {{\ln \left (x^2-2\right )}^2+2\,\ln \left (x^2-2\right )+1}{{\ln \relax (x)}^2}\right )}^2}-2\,x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-(log(x^2 - 2)*(4*x^2 - 8) - 8*x^2*log(x) + log((2*log(x^2 - 2) + log(x^2 - 2)^2 + 1)/log(x)^2)^3*(log(x)*
(4*x - 2*x^3) + log(x^2 - 2)*log(x)*(4*x - 2*x^3)) + 4*x^2 - 8)/(log((2*log(x^2 - 2) + log(x^2 - 2)^2 + 1)/log
(x)^2)^3*(log(x)*(2*x - x^3) + log(x^2 - 2)*log(x)*(2*x - x^3))),x)

[Out]

1/log((2*log(x^2 - 2) + log(x^2 - 2)^2 + 1)/log(x)^2)^2 - 2*x

________________________________________________________________________________________

sympy [A]  time = 1.07, size = 31, normalized size = 1.35 \begin {gather*} - 2 x + \frac {1}{\log {\left (\frac {\log {\left (x^{2} - 2 \right )}^{2} + 2 \log {\left (x^{2} - 2 \right )} + 1}{\log {\relax (x )}^{2}} \right )}^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((((-2*x**3+4*x)*ln(x)*ln(x**2-2)+(-2*x**3+4*x)*ln(x))*ln((ln(x**2-2)**2+2*ln(x**2-2)+1)/ln(x)**2)**3
+(4*x**2-8)*ln(x**2-2)-8*x**2*ln(x)+4*x**2-8)/((x**3-2*x)*ln(x)*ln(x**2-2)+(x**3-2*x)*ln(x))/ln((ln(x**2-2)**2
+2*ln(x**2-2)+1)/ln(x)**2)**3,x)

[Out]

-2*x + log((log(x**2 - 2)**2 + 2*log(x**2 - 2) + 1)/log(x)**2)**(-2)

________________________________________________________________________________________