2.2.63 Problem 66
Internal
problem
ID
[13269]
Book
:
Handbook
of
exact
solutions
for
ordinary
differential
equations.
By
Polyanin
and
Zaitsev.
Second
edition
Section
:
Chapter
1,
section
1.2.
Riccati
Equation.
1.2.2.
Equations
Containing
Power
Functions
Problem
number
:
66
Date
solved
:
Friday, December 19, 2025 at 02:34:02 AM
CAS
classification
:
[_rational, _Riccati]
\begin{align*}
x^{3} y^{\prime }&=a \,x^{3} y^{2}+x \left (b x +c \right ) y+\alpha x +\beta \\
\end{align*}
Entering first order ode riccati solver\begin{align*}
x^{3} y^{\prime }&=a \,x^{3} y^{2}+x \left (b x +c \right ) y+\alpha x +\beta \\
\end{align*}
In canonical form the ODE is \begin{align*} y' &= F(x,y)\\ &= \frac {a \,x^{3} y^{2}+b \,x^{2} y +c x y +\alpha x +\beta }{x^{3}} \end{align*}
This is a Riccati ODE. Comparing the ODE to solve
\[
y' = a \,y^{2}+\frac {b y}{x}+\frac {c y}{x^{2}}+\frac {\alpha }{x^{2}}+\frac {\beta }{x^{3}}
\]
With Riccati ODE standard form \[ y' = f_0(x)+ f_1(x)y+f_2(x)y^{2} \]
Shows
that \(f_0(x)=\frac {\alpha x +\beta }{x^{3}}\), \(f_1(x)=\frac {b \,x^{2}+c x}{x^{3}}\) and \(f_2(x)=a\). Let \begin{align*} y &= \frac {-u'}{f_2 u} \\ &= \frac {-u'}{a u} \tag {1} \end{align*}
Using the above substitution in the given ODE results (after some simplification) in a second
order ODE to solve for \(u(x)\) which is
\begin{align*} f_2 u''(x) -\left ( f_2' + f_1 f_2 \right ) u'(x) + f_2^2 f_0 u(x) &= 0 \tag {2} \end{align*}
But
\begin{align*} f_2' &=0\\ f_1 f_2 &=\frac {\left (b \,x^{2}+c x \right ) a}{x^{3}}\\ f_2^2 f_0 &=\frac {a^{2} \left (\alpha x +\beta \right )}{x^{3}} \end{align*}
Substituting the above terms back in equation (2) gives
\[
a u^{\prime \prime }\left (x \right )-\frac {\left (b \,x^{2}+c x \right ) a u^{\prime }\left (x \right )}{x^{3}}+\frac {a^{2} \left (\alpha x +\beta \right ) u \left (x \right )}{x^{3}} = 0
\]
Unable to solve. Will ask Maple to solve
this ode now.
The solution for \(u \left (x \right )\) is
\begin{equation}
\tag{3} u \left (x \right ) = c_1 \,x^{\frac {1}{2}+\frac {b}{2}-\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}}{2}} {\mathrm e}^{-\frac {c}{x}} \operatorname {KummerM}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )+c_2 \,x^{\frac {1}{2}+\frac {b}{2}-\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}}{2}} {\mathrm e}^{-\frac {c}{x}} \operatorname {KummerU}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )
\end{equation}
Taking derivative gives \begin{equation}
\tag{4} u^{\prime }\left (x \right ) = \frac {c_1 \,x^{\frac {1}{2}+\frac {b}{2}-\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}}{2}} \left (\frac {1}{2}+\frac {b}{2}-\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}}{2}\right ) {\mathrm e}^{-\frac {c}{x}} \operatorname {KummerM}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )}{x}+\frac {c_1 \,x^{\frac {1}{2}+\frac {b}{2}-\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}}{2}} c \,{\mathrm e}^{-\frac {c}{x}} \operatorname {KummerM}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )}{x^{2}}-\frac {c_1 \,x^{\frac {1}{2}+\frac {b}{2}-\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}}{2}} {\mathrm e}^{-\frac {c}{x}} \left (\operatorname {KummerM}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}+1, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )-\operatorname {KummerM}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )\right ) \left (\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta \right )}{2 c x}+\frac {c_2 \,x^{\frac {1}{2}+\frac {b}{2}-\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}}{2}} \left (\frac {1}{2}+\frac {b}{2}-\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}}{2}\right ) {\mathrm e}^{-\frac {c}{x}} \operatorname {KummerU}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )}{x}+\frac {c_2 \,x^{\frac {1}{2}+\frac {b}{2}-\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}}{2}} c \,{\mathrm e}^{-\frac {c}{x}} \operatorname {KummerU}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )}{x^{2}}-\frac {c_2 \,x^{\frac {1}{2}+\frac {b}{2}-\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}}{2}} {\mathrm e}^{-\frac {c}{x}} \left (\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}-\sqrt {-4 a \alpha +b^{2}+2 b +1}\right ) \operatorname {KummerU}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}+1, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )-\operatorname {KummerU}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )\right ) \left (\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta \right )}{2 c x}
\end{equation}
Substituting equations (3,4) into (1) results in \begin{align*}
y &= \frac {-u'}{f_2 u} \\
y &= \frac {-u'}{a u} \\
y &= \frac {c_2 \left (\left (a \alpha +b +2\right ) c^{2}-\beta a \left (b +3\right ) c +a^{2} \beta ^{2}\right ) x \operatorname {KummerU}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +\left (b +5\right ) c -2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )+\left (\left (-c^{2}-c \left (b +2\right ) x +a x \beta \right ) c_1 \operatorname {KummerM}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )+\left (-c^{2}-c \left (b +2\right ) x +a x \beta \right ) c_2 \operatorname {KummerU}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )-\left (-\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c}{2}+\frac {\left (-b -3\right ) c}{2}+a \beta \right ) x \operatorname {KummerM}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +\left (b +5\right ) c -2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right ) c_1 \right ) c}{c^{2} x^{2} a \left (\operatorname {KummerU}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right ) c_2 +\operatorname {KummerM}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right ) c_1 \right )} \\
\end{align*}
Doing
change of constants, the above solution becomes \[
\text {Expression too large to display}
\]
Simplifying the above gives \begin{align*}
y &= \frac {\left (\left (a \alpha +b +2\right ) c^{2}-\beta a \left (b +3\right ) c +a^{2} \beta ^{2}\right ) x c_3 \operatorname {KummerU}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +\left (b +5\right ) c -2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )-c \left (\left (c^{2}+c \left (b +2\right ) x -a x \beta \right ) \operatorname {KummerM}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )-\left (-c^{2}-c \left (b +2\right ) x +a x \beta \right ) c_3 \operatorname {KummerU}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )+\left (-\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c}{2}+\frac {\left (-b -3\right ) c}{2}+a \beta \right ) \operatorname {KummerM}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +\left (b +5\right ) c -2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right ) x \right )}{c^{2} x^{2} a \left (\operatorname {KummerU}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right ) c_3 +\operatorname {KummerM}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )\right )} \\
\end{align*}
The solution \[
y = \frac {\left (\left (a \alpha +b +2\right ) c^{2}-\beta a \left (b +3\right ) c +a^{2} \beta ^{2}\right ) x c_3 \operatorname {KummerU}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +\left (b +5\right ) c -2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )-c \left (\left (c^{2}+c \left (b +2\right ) x -a x \beta \right ) \operatorname {KummerM}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )-\left (-c^{2}-c \left (b +2\right ) x +a x \beta \right ) c_3 \operatorname {KummerU}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )+\left (-\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c}{2}+\frac {\left (-b -3\right ) c}{2}+a \beta \right ) \operatorname {KummerM}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +\left (b +5\right ) c -2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right ) x \right )}{c^{2} x^{2} a \left (\operatorname {KummerU}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right ) c_3 +\operatorname {KummerM}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +c \left (b +3\right )-2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )\right )}
\]
was
found not to satisfy the ode or the IC. Hence it is removed.
2.2.63.1 ✓ Maple. Time used: 0.003 (sec). Leaf size: 438
ode:=x^3*diff(y(x),x) = x^3*a*y(x)^2+x*(b*x+c)*y(x)+alpha*x+beta;
dsolve(ode,y(x), singsol=all);
\[
y = \frac {\left (\left (a \alpha +b +2\right ) c^{2}-a \beta \left (b +3\right ) c +a^{2} \beta ^{2}\right ) x c_1 \operatorname {KummerU}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +\left (b +5\right ) c -2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )-c \left (\left (c^{2}+x \left (b +2\right ) c -a \beta x \right ) \operatorname {KummerM}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +\left (b +3\right ) c -2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )-\left (-c^{2}-x \left (b +2\right ) c +a \beta x \right ) c_1 \operatorname {KummerU}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +\left (b +3\right ) c -2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )+\left (-\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c}{2}+\frac {\left (-b -3\right ) c}{2}+a \beta \right ) \operatorname {KummerM}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +\left (b +5\right ) c -2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right ) x \right )}{x^{2} c^{2} a \left (\operatorname {KummerU}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +\left (b +3\right ) c -2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right ) c_1 +\operatorname {KummerM}\left (\frac {\sqrt {-4 a \alpha +b^{2}+2 b +1}\, c +\left (b +3\right ) c -2 a \beta }{2 c}, 1+\sqrt {-4 a \alpha +b^{2}+2 b +1}, \frac {c}{x}\right )\right )}
\]
Maple trace
Methods for first order ODEs:
--- Trying classification methods ---
trying a quadrature
trying 1st order linear
trying Bernoulli
trying separable
trying inverse linear
trying homogeneous types:
trying Chini
differential order: 1; looking for linear symmetries
trying exact
Looking for potential symmetries
trying Riccati
trying Riccati sub-methods:
trying Riccati to 2nd Order
-> Calling odsolve with the ODE, diff(diff(y(x),x),x) = (b*x+c)/x^2*diff(y(x
),x)-a*(alpha*x+beta)/x^3*y(x), y(x)
*** Sublevel 2 ***
Methods for second order ODEs:
--- Trying classification methods ---
trying a quadrature
checking if the LODE has constant coefficients
checking if the LODE is of Euler type
trying a symmetry of the form [xi=0, eta=F(x)]
checking if the LODE is missing y
-> Trying a Liouvillian solution using Kovacics algorithm
<- No Liouvillian solutions exists
-> Trying a solution in terms of special functions:
-> Bessel
-> elliptic
-> Legendre
-> Kummer
-> hyper3: Equivalence to 1F1 under a power @ Moebius
<- hyper3 successful: received ODE is equivalent to the 1F1 ODE
<- Kummer successful
<- special function solution successful
<- Riccati to 2nd Order successful
Maple step by step
\[ \begin {array}{lll} & {} & \textrm {Let's solve}\hspace {3pt} \\ {} & {} & x^{3} \left (\frac {d}{d x}y \left (x \right )\right )=a \,x^{3} y \left (x \right )^{2}+x \left (b x +c \right ) y \left (x \right )+\alpha x +\beta \\ \bullet & {} & \textrm {Highest derivative means the order of the ODE is}\hspace {3pt} 1 \\ {} & {} & \frac {d}{d x}y \left (x \right ) \\ \bullet & {} & \textrm {Solve for the highest derivative}\hspace {3pt} \\ {} & {} & \frac {d}{d x}y \left (x \right )=\frac {a \,x^{3} y \left (x \right )^{2}+x \left (b x +c \right ) y \left (x \right )+\alpha x +\beta }{x^{3}} \end {array} \]
2.2.63.2 ✓ Mathematica. Time used: 0.971 (sec). Leaf size: 1168
ode=x^3*D[y[x],x]==a*x^3*y[x]^2+x*(b*x+c)*y[x]+\[Alpha]*x+\[Beta];
ic={};
DSolve[{ode,ic},y[x],x,IncludeSingularSolutions->True]
\begin{align*} \text {Solution too large to show}\end{align*}
2.2.63.3 ✗ Sympy
from sympy import *
x = symbols("x")
Alpha = symbols("Alpha")
BETA = symbols("BETA")
a = symbols("a")
b = symbols("b")
c = symbols("c")
y = Function("y")
ode = Eq(-Alpha*x - BETA - a*x**3*y(x)**2 + x**3*Derivative(y(x), x) - x*(b*x + c)*y(x),0)
ics = {}
dsolve(ode,func=y(x),ics=ics)
Timed Out
Python version: 3.12.3 (main, Aug 14 2025, 17:47:21) [GCC 13.3.0]
Sympy version 1.14.0