Internal
problem
ID
[13765]
Book
:
Handbook
of
exact
solutions
for
ordinary
differential
equations.
By
Polyanin
and
Zaitsev.
Second
edition
Section
:
Chapter
2,
Second-Order
Differential
Equations.
section
2.1.2-3
Problem
number
:
104
Date
solved
:
Friday, December 19, 2025 at 12:05:56 PM
CAS
classification
:
[[_2nd_order, _with_linear_symmetries]]
ode:=x*diff(diff(y(x),x),x)+(x^(m+n)*a*b+a*n*x^n+b*x^m+1-2*n)*diff(y(x),x)+a^2*b*n*x^(2*n+m-1)*y(x) = 0; dsolve(ode,y(x), singsol=all);
Maple trace
Methods for second order ODEs: --- Trying classification methods --- trying a symmetry of the form [xi=0, eta=F(x)] checking if the LODE is missing y -> Trying an equivalence, under non-integer power transformations, to LODEs admitting Liouvillian solutions. -> Trying a solution in terms of special functions: -> Bessel -> elliptic -> Legendre -> Kummer -> hyper3: Equivalence to 1F1 under a power @ Moebius -> hypergeometric -> heuristic approach -> hyper3: Equivalence to 2F1, 1F1 or 0F1 under a power @ Moebius -> Mathieu -> Equivalence to the rational form of Mathieu ODE under a power @ Moebi\ us -> Heun: Equivalence to the GHE or one of its 4 confluent cases under a power \ @ Moebius -> Heun: Equivalence to the GHE or one of its 4 confluent cases under a power \ @ Moebius -> trying a solution of the form r0(x) * Y + r1(x) * Y where Y = exp(int(r(x),\ dx)) * 2F1([a1, a2], [b1], f) -> Trying changes of variables to rationalize or make the ODE simpler <- unable to find a useful change of variables trying a symmetry of the form [xi=0, eta=F(x)] trying differential order: 2; exact nonlinear trying symmetries linear in x and y(x) trying to convert to a linear ODE with constant coefficients trying 2nd order, integrating factor of the form mu(x,y) trying a symmetry of the form [xi=0, eta=F(x)] checking if the LODE is missing y -> Trying an equivalence, under non-integer power transformations, to LODEs admitting Liouvillian solutions. -> Trying a solution in terms of special functions: -> Bessel -> elliptic -> Legendre -> Whittaker -> hyper3: Equivalence to 1F1 under a power @ Moebius -> hypergeometric -> heuristic approach -> hyper3: Equivalence to 2F1, 1F1 or 0F1 under a power @ Moebius -> Mathieu -> Equivalence to the rational form of Mathieu ODE under a power @ Mo\ ebius -> Heun: Equivalence to the GHE or one of its 4 confluent cases under a pow\ er @ Moebius -> Heun: Equivalence to the GHE or one of its 4 confluent cases under a pow\ er @ Moebius -> trying a solution of the form r0(x) * Y + r1(x) * Y where Y = exp(int(r(\ x), dx)) * 2F1([a1, a2], [b1], f) -> Trying changes of variables to rationalize or make the ODE simpler <- unable to find a useful change of variables trying a symmetry of the form [xi=0, eta=F(x)] trying to convert to an ODE of Bessel type -> trying reduction of order to Riccati trying Riccati sub-methods: trying Riccati_symmetries -> trying a symmetry pattern of the form [F(x)*G(y), 0] -> trying a symmetry pattern of the form [0, F(x)*G(y)] -> trying a symmetry pattern of the form [F(x),G(x)*y+H(x)] --- Trying Lie symmetry methods, 2nd order --- -> Computing symmetries using: way = 3 [0, y] <- successful computation of symmetries. -> Computing symmetries using: way = 5
ode=x*D[y[x],{x,2}]+(a*b*x^(n+m)+a*n*x^n+b*x^m+1-2*n)*D[y[x],x]+a^2*b*n*x^(2*n+m-1)*y[x]==0; ic={}; DSolve[{ode,ic},y[x],x,IncludeSingularSolutions->True]
Not solved
from sympy import * x = symbols("x") a = symbols("a") b = symbols("b") m = symbols("m") n = symbols("n") y = Function("y") ode = Eq(a**2*b*n*x**(m + 2*n - 1)*y(x) + x*Derivative(y(x), (x, 2)) + (a*b*x**(m + n) + a*n*x**n + b*x**m - 2*n + 1)*Derivative(y(x), x),0) ics = {} dsolve(ode,func=y(x),ics=ics)
NotImplementedError : The given ODE -(-a**2*b*n*x**(m + 2*n - 1)*y(x) - x*Derivative(y(x), (x, 2)))/(a*b*x**(m + n) + a*n*x**n + b*x**m - 2*n + 1) + Derivative(y(x), x) cannot be solved by the factorable group method