2.11.9 Problem 35

Internal problem ID [13397]
Book : Handbook of exact solutions for ordinary differential equations. By Polyanin and Zaitsev. Second edition
Section : Chapter 1, section 1.2. Riccati Equation. subsection 1.2.6-3. Equations with tangent.
Problem number : 35
Date solved : Friday, December 19, 2025 at 03:47:24 AM
CAS classification : [[_1st_order, `_with_symmetry_[F(x),G(x)]`], _Riccati]

\begin{align*} y^{\prime }&=a \tan \left (\lambda x +\mu \right )^{k} \left (y-b \,x^{n}-c \right )^{2}+b n \,x^{n -1} \\ \end{align*}

Entering first order ode riccati solver

\begin{align*} y^{\prime }&=a \tan \left (\lambda x +\mu \right )^{k} \left (y-b \,x^{n}-c \right )^{2}+b n \,x^{n -1} \\ \end{align*}

In canonical form the ODE is

\begin{align*} y' &= F(x,y)\\ &= \tan \left (\lambda x +\mu \right )^{k} x^{2 n} a \,b^{2}+2 \tan \left (\lambda x +\mu \right )^{k} x^{n} a b c -2 \tan \left (\lambda x +\mu \right )^{k} x^{n} a b y +\tan \left (\lambda x +\mu \right )^{k} a \,c^{2}-2 \tan \left (\lambda x +\mu \right )^{k} a c y +\tan \left (\lambda x +\mu \right )^{k} a \,y^{2}+b n \,x^{n -1} \end{align*}

This is a Riccati ODE. Comparing the ODE to solve

\[ y' = \left (\frac {\tan \left (\mu \right )}{1-\tan \left (\mu \right ) \tan \left (\lambda x \right )}+\frac {\tan \left (\lambda x \right )}{1-\tan \left (\mu \right ) \tan \left (\lambda x \right )}\right )^{k} x^{2 n} a \,b^{2}+2 \left (\frac {\tan \left (\mu \right )}{1-\tan \left (\mu \right ) \tan \left (\lambda x \right )}+\frac {\tan \left (\lambda x \right )}{1-\tan \left (\mu \right ) \tan \left (\lambda x \right )}\right )^{k} x^{n} a b c -2 \left (\frac {\tan \left (\mu \right )}{1-\tan \left (\mu \right ) \tan \left (\lambda x \right )}+\frac {\tan \left (\lambda x \right )}{1-\tan \left (\mu \right ) \tan \left (\lambda x \right )}\right )^{k} x^{n} a b y +\left (\frac {\tan \left (\mu \right )}{1-\tan \left (\mu \right ) \tan \left (\lambda x \right )}+\frac {\tan \left (\lambda x \right )}{1-\tan \left (\mu \right ) \tan \left (\lambda x \right )}\right )^{k} a \,c^{2}-2 \left (\frac {\tan \left (\mu \right )}{1-\tan \left (\mu \right ) \tan \left (\lambda x \right )}+\frac {\tan \left (\lambda x \right )}{1-\tan \left (\mu \right ) \tan \left (\lambda x \right )}\right )^{k} a c y +\left (\frac {\tan \left (\mu \right )}{1-\tan \left (\mu \right ) \tan \left (\lambda x \right )}+\frac {\tan \left (\lambda x \right )}{1-\tan \left (\mu \right ) \tan \left (\lambda x \right )}\right )^{k} a \,y^{2}+\frac {b \,x^{n} n}{x} \]

With Riccati ODE standard form

\[ y' = f_0(x)+ f_1(x)y+f_2(x)y^{2} \]

Shows that \(f_0(x)=\tan \left (\lambda x +\mu \right )^{k} x^{2 n} a \,b^{2}+2 \tan \left (\lambda x +\mu \right )^{k} x^{n} a b c +\tan \left (\lambda x +\mu \right )^{k} a \,c^{2}+b n \,x^{n -1}\), \(f_1(x)=-2 a b \,x^{n} \tan \left (\lambda x +\mu \right )^{k}-2 a c \tan \left (\lambda x +\mu \right )^{k}\) and \(f_2(x)=a \tan \left (\lambda x +\mu \right )^{k}\). Let

\begin{align*} y &= \frac {-u'}{f_2 u} \\ &= \frac {-u'}{a \tan \left (\lambda x +\mu \right )^{k} u} \tag {1} \end{align*}

Using the above substitution in the given ODE results (after some simplification) in a second order ODE to solve for \(u(x)\) which is

\begin{align*} f_2 u''(x) -\left ( f_2' + f_1 f_2 \right ) u'(x) + f_2^2 f_0 u(x) &= 0 \tag {2} \end{align*}

But

\begin{align*} f_2' &=\frac {a \tan \left (\lambda x +\mu \right )^{k} k \lambda \left (1+\tan \left (\lambda x +\mu \right )^{2}\right )}{\tan \left (\lambda x +\mu \right )}\\ f_1 f_2 &=\left (-2 a b \,x^{n} \tan \left (\lambda x +\mu \right )^{k}-2 a c \tan \left (\lambda x +\mu \right )^{k}\right ) a \tan \left (\lambda x +\mu \right )^{k}\\ f_2^2 f_0 &=a^{2} \tan \left (\lambda x +\mu \right )^{2 k} \left (\tan \left (\lambda x +\mu \right )^{k} x^{2 n} a \,b^{2}+2 \tan \left (\lambda x +\mu \right )^{k} x^{n} a b c +\tan \left (\lambda x +\mu \right )^{k} a \,c^{2}+b n \,x^{n -1}\right ) \end{align*}

Substituting the above terms back in equation (2) gives

\[ a \tan \left (\lambda x +\mu \right )^{k} u^{\prime \prime }\left (x \right )-\left (\frac {a \tan \left (\lambda x +\mu \right )^{k} k \lambda \left (1+\tan \left (\lambda x +\mu \right )^{2}\right )}{\tan \left (\lambda x +\mu \right )}+\left (-2 a b \,x^{n} \tan \left (\lambda x +\mu \right )^{k}-2 a c \tan \left (\lambda x +\mu \right )^{k}\right ) a \tan \left (\lambda x +\mu \right )^{k}\right ) u^{\prime }\left (x \right )+a^{2} \tan \left (\lambda x +\mu \right )^{2 k} \left (\tan \left (\lambda x +\mu \right )^{k} x^{2 n} a \,b^{2}+2 \tan \left (\lambda x +\mu \right )^{k} x^{n} a b c +\tan \left (\lambda x +\mu \right )^{k} a \,c^{2}+b n \,x^{n -1}\right ) u \left (x \right ) = 0 \]

Unable to solve. Will ask Maple to solve this ode now.

Unable to solve. Terminating.

2.11.9.1 ✓ Maple. Time used: 0.005 (sec). Leaf size: 42

ode:=diff(y(x),x) = a*tan(lambda*x+mu)^k*(y(x)-b*x^n-c)^2+b*n*x^(n-1); 
dsolve(ode,y(x), singsol=all);
 

\[ y = b \,x^{n}+c +\frac {1}{c_1 -a \int \left (-\frac {\tan \left (\mu \right )+\tan \left (\lambda x \right )}{\tan \left (\mu \right ) \tan \left (\lambda x \right )-1}\right )^{k}d x} \]

Maple trace

Methods for first order ODEs: 
--- Trying classification methods --- 
trying a quadrature 
trying 1st order linear 
trying Bernoulli 
trying separable 
trying inverse linear 
trying homogeneous types: 
trying Chini 
differential order: 1; looking for linear symmetries 
trying exact 
Looking for potential symmetries 
trying Riccati 
trying Riccati sub-methods: 
   <- Riccati particular case Kamke (d) successful
 

Maple step by step

\[ \begin {array}{lll} & {} & \textrm {Let's solve}\hspace {3pt} \\ {} & {} & \frac {d}{d x}y \left (x \right )=a \tan \left (\lambda x +\mu \right )^{k} \left (y \left (x \right )-b \,x^{13397}-c \right )^{2}+13397 b \,x^{13396} \\ \bullet & {} & \textrm {Highest derivative means the order of the ODE is}\hspace {3pt} 1 \\ {} & {} & \frac {d}{d x}y \left (x \right ) \\ \bullet & {} & \textrm {Solve for the highest derivative}\hspace {3pt} \\ {} & {} & \frac {d}{d x}y \left (x \right )=a \tan \left (\lambda x +\mu \right )^{k} \left (y \left (x \right )-b \,x^{13397}-c \right )^{2}+13397 b \,x^{13396} \end {array} \]

2.11.9.2 ✓ Mathematica. Time used: 0.924 (sec). Leaf size: 75

ode=D[y[x],x]==a*Tan[\[Lambda]*x+mu]^k*(y[x]-b*x^n-c)^2+b*n*x^(n-1); 
ic={}; 
DSolve[{ode,ic},y[x],x,IncludeSingularSolutions->True]
 

\begin{align*} y(x)&\to \frac {1}{-\frac {a \tan ^{k+1}(\mu +\lambda x) \operatorname {Hypergeometric2F1}\left (1,\frac {k+1}{2},\frac {k+3}{2},-\tan ^2(\mu +x \lambda )\right )}{(k+1) \lambda }+c_1}+b x^n+c\\ y(x)&\to b x^n+c \end{align*}

2.11.9.3 ✗ Sympy

from sympy import * 
x = symbols("x") 
a = symbols("a") 
b = symbols("b") 
c = symbols("c") 
k = symbols("k") 
lambda_ = symbols("lambda_") 
mu = symbols("mu") 
n = symbols("n") 
y = Function("y") 
ode = Eq(-a*(-b*x**n - c + y(x))**2*tan(lambda_*x + mu)**k - b*n*x**(n - 1) + Derivative(y(x), x),0) 
ics = {} 
dsolve(ode,func=y(x),ics=ics)
 

Timed Out
 

Python version: 3.12.3 (main, Aug 14 2025, 17:47:21) [GCC 13.3.0] 
Sympy version 1.14.0