2.8.7 Problem 16

Internal problem ID [13359]
Book : Handbook of exact solutions for ordinary differential equations. By Polyanin and Zaitsev. Second edition
Section : Chapter 1, section 1.2. Riccati Equation. subsection 1.2.5-2
Problem number : 16
Date solved : Sunday, January 18, 2026 at 07:29:33 PM
CAS classification : [_Riccati]

2.8.7.1 Solved using first_order_ode_riccati_by_guessing_particular_solution

0.209 (sec)

Entering first order ode riccati guess solver

\begin{align*} y^{\prime }&=a \ln \left (x \right )^{n} y^{2}+b \ln \left (x \right )^{m} y+b c \ln \left (x \right )^{m}-a \,c^{2} \ln \left (x \right )^{n} \\ \end{align*}

This is a Riccati ODE. Comparing the above ODE to solve with the Riccati standard form

\[ y' = f_0(x)+ f_1(x)y+f_2(x)y^{2} \]

Shows that

\begin{align*} f_0(x) & =-a \,c^{2} \ln \left (x \right )^{n}+b c \ln \left (x \right )^{m}\\ f_1(x) & =\ln \left (x \right )^{m} b\\ f_2(x) &=a \ln \left (x \right )^{n} \end{align*}

Using trial and error, the following particular solution was found

\[ y_p = -c \]

Since a particular solution is known, then the general solution is given by

\begin{align*} y &= y_p + \frac { \phi (x) }{ c_1 - \int { \phi (x) f_2 \,dx} } \end{align*}

Where

\begin{align*} \phi (x) &= e^{ \int 2 f_2 y_p + f_1 \,dx } \end{align*}

Evaluating the above gives the general solution as

\[ y = -c +\frac {{\mathrm e}^{\int \left (-2 \ln \left (x \right )^{n} a c +\ln \left (x \right )^{m} b \right )d x}}{c_1 -\int {\mathrm e}^{\int \left (-2 \ln \left (x \right )^{n} a c +\ln \left (x \right )^{m} b \right )d x} \ln \left (x \right )^{n} a d x} \]

Summary of solutions found

\begin{align*} y &= -c +\frac {{\mathrm e}^{\int \left (-2 \ln \left (x \right )^{n} a c +\ln \left (x \right )^{m} b \right )d x}}{c_1 -\int {\mathrm e}^{\int \left (-2 \ln \left (x \right )^{n} a c +\ln \left (x \right )^{m} b \right )d x} \ln \left (x \right )^{n} a d x} \\ \end{align*}

2.8.7.2 ✓ Maple. Time used: 0.006 (sec). Leaf size: 99

ode:=diff(y(x),x) = a*ln(x)^n*y(x)^2+b*ln(x)^m*y(x)+b*c*ln(x)^m-a*c^2*ln(x)^n; 
dsolve(ode,y(x), singsol=all);
 

\[ y = \frac {-\int \ln \left (x \right )^{n} {\mathrm e}^{-\int \left (2 \ln \left (x \right )^{n} a c -\ln \left (x \right )^{m} b \right )d x}d x a c -c_1 c -{\mathrm e}^{-\int \left (2 \ln \left (x \right )^{n} a c -\ln \left (x \right )^{m} b \right )d x}}{c_1 +a \int \ln \left (x \right )^{n} {\mathrm e}^{-\int \left (2 \ln \left (x \right )^{n} a c -\ln \left (x \right )^{m} b \right )d x}d x} \]

Maple trace

Methods for first order ODEs: 
--- Trying classification methods --- 
trying a quadrature 
trying 1st order linear 
trying Bernoulli 
trying separable 
trying inverse linear 
trying homogeneous types: 
trying Chini 
differential order: 1; looking for linear symmetries 
trying exact 
Looking for potential symmetries 
trying Riccati 
trying Riccati sub-methods: 
   trying Riccati_symmetries 
   trying Riccati to 2nd Order 
   -> Calling odsolve with the ODE, diff(diff(y(x),x),x) = (ln(x)*ln(x)^m*b*x+n 
)/x/ln(x)*diff(y(x),x)+a*ln(x)^n*c*(ln(x)^n*a*c-ln(x)^m*b)*y(x), y(x) 
      *** Sublevel 2 *** 
      Methods for second order ODEs: 
      --- Trying classification methods --- 
      trying a symmetry of the form [xi=0, eta=F(x)] 
      checking if the LODE is missing y 
      -> Heun: Equivalence to the GHE or one of its 4 confluent cases under a \ 
power @ Moebius 
      -> trying a solution of the form r0(x) * Y + r1(x) * Y where Y = exp(int\ 
(r(x), dx)) * 2F1([a1, a2], [b1], f) 
      -> Trying changes of variables to rationalize or make the ODE simpler 
         trying a symmetry of the form [xi=0, eta=F(x)] 
         checking if the LODE is missing y 
         -> Heun: Equivalence to the GHE or one of its 4 confluent cases under \ 
a power @ Moebius 
         -> trying a solution of the form r0(x) * Y + r1(x) * Y where Y = exp(\ 
int(r(x), dx)) * 2F1([a1, a2], [b1], f) 
            trying a symmetry of the form [xi=0, eta=F(x)] 
            trying 2nd order exact linear 
            trying symmetries linear in x and y(x) 
            trying to convert to a linear ODE with constant coefficients 
      <- unable to find a useful change of variables 
         trying a symmetry of the form [xi=0, eta=F(x)] 
         trying 2nd order exact linear 
         trying symmetries linear in x and y(x) 
         trying to convert to a linear ODE with constant coefficients 
         trying 2nd order, integrating factor of the form mu(x,y) 
         trying a symmetry of the form [xi=0, eta=F(x)] 
         checking if the LODE is missing y 
         -> Heun: Equivalence to the GHE or one of its 4 confluent cases under \ 
a power @ Moebius 
         -> trying a solution of the form r0(x) * Y + r1(x) * Y where Y = exp(\ 
int(r(x), dx)) * 2F1([a1, a2], [b1], f) 
         -> Trying changes of variables to rationalize or make the ODE simpler 
            trying a symmetry of the form [xi=0, eta=F(x)] 
            checking if the LODE is missing y 
            -> Heun: Equivalence to the GHE or one of its 4 confluent cases und\ 
er a power @ Moebius 
            -> trying a solution of the form r0(x) * Y + r1(x) * Y where Y = e\ 
xp(int(r(x), dx)) * 2F1([a1, a2], [b1], f) 
               trying a symmetry of the form [xi=0, eta=F(x)] 
               trying 2nd order exact linear 
               trying symmetries linear in x and y(x) 
               trying to convert to a linear ODE with constant coefficients 
         <- unable to find a useful change of variables 
            trying a symmetry of the form [xi=0, eta=F(x)] 
         trying to convert to an ODE of Bessel type 
   -> Trying a change of variables to reduce to Bernoulli 
   -> Calling odsolve with the ODE, diff(y(x),x)-(a*ln(x)^n*y(x)^2+y(x)+ln(x)^m 
*b*y(x)*x+x^2*(b*c*ln(x)^m-a*c^2*ln(x)^n))/x, y(x), explicit 
      *** Sublevel 2 *** 
      Methods for first order ODEs: 
      --- Trying classification methods --- 
      trying a quadrature 
      trying 1st order linear 
      trying Bernoulli 
      trying separable 
      trying inverse linear 
      trying homogeneous types: 
      trying Chini 
      differential order: 1; looking for linear symmetries 
      trying exact 
      Looking for potential symmetries 
      trying Riccati 
      trying Riccati sub-methods: 
         trying Riccati_symmetries 
      trying inverse_Riccati 
      trying 1st order ODE linearizable_by_differentiation 
   -> trying a symmetry pattern of the form [F(x)*G(y), 0] 
   -> trying a symmetry pattern of the form [0, F(x)*G(y)] 
   <- symmetry pattern of the form [0, F(x)*G(y)] successful 
   <- Riccati with symmetry pattern of the form [0,F(x)*G(y)] successful
 

Maple step by step

\[ \begin {array}{lll} & {} & \textrm {Let's solve}\hspace {3pt} \\ {} & {} & \frac {d}{d x}y \left (x \right )=a \ln \left (x \right )^{13359} y \left (x \right )^{2}+b \ln \left (x \right )^{m} y \left (x \right )+b c \ln \left (x \right )^{m}-a \,c^{2} \ln \left (x \right )^{13359} \\ \bullet & {} & \textrm {Highest derivative means the order of the ODE is}\hspace {3pt} 1 \\ {} & {} & \frac {d}{d x}y \left (x \right ) \\ \bullet & {} & \textrm {Solve for the highest derivative}\hspace {3pt} \\ {} & {} & \frac {d}{d x}y \left (x \right )=a \ln \left (x \right )^{13359} y \left (x \right )^{2}+b \ln \left (x \right )^{m} y \left (x \right )+b c \ln \left (x \right )^{m}-a \,c^{2} \ln \left (x \right )^{13359} \end {array} \]

2.8.7.3 ✓ Mathematica. Time used: 0.975 (sec). Leaf size: 290

ode=D[y[x],x]==a*(Log[x])^n*y[x]^2+b*(Log[x])^m*y[x]+b*c*(Log[x])^m-a*c^2*(Log[x])^n; 
ic={}; 
DSolve[{ode,ic},y[x],x,IncludeSingularSolutions->True]
 

\[ \text {Solve}\left [\int _1^x\frac {\exp \left (-\int _1^{K[2]}\left (2 a c \log ^n(K[1])-b \log ^m(K[1])\right )dK[1]\right ) \left (-b \log ^m(K[2])+a c \log ^n(K[2])-a y(x) \log ^n(K[2])\right )}{a b (m-n) (c+y(x))}dK[2]+\int _1^{y(x)}\left (\frac {\exp \left (-\int _1^x\left (2 a c \log ^n(K[1])-b \log ^m(K[1])\right )dK[1]\right )}{a b (m-n) (c+K[3])^2}-\int _1^x\left (-\frac {\exp \left (-\int _1^{K[2]}\left (2 a c \log ^n(K[1])-b \log ^m(K[1])\right )dK[1]\right ) \log ^n(K[2])}{b (m-n) (c+K[3])}-\frac {\exp \left (-\int _1^{K[2]}\left (2 a c \log ^n(K[1])-b \log ^m(K[1])\right )dK[1]\right ) \left (-b \log ^m(K[2])+a c \log ^n(K[2])-a K[3] \log ^n(K[2])\right )}{a b (m-n) (c+K[3])^2}\right )dK[2]\right )dK[3]=c_1,y(x)\right ] \]

2.8.7.4 ✗ Sympy

from sympy import * 
x = symbols("x") 
a = symbols("a") 
b = symbols("b") 
c = symbols("c") 
m = symbols("m") 
n = symbols("n") 
y = Function("y") 
ode = Eq(a*c**2*log(x)**n - a*y(x)**2*log(x)**n - b*c*log(x)**m - b*y(x)*log(x)**m + Derivative(y(x), x),0) 
ics = {} 
dsolve(ode,func=y(x),ics=ics)
 

Timed Out
 

Python version: 3.12.3 (main, Aug 14 2025, 17:47:21) [GCC 13.3.0] 
Sympy version 1.14.0