2.5.11 Problem 11

Internal problem ID [13330]
Book : Handbook of exact solutions for ordinary differential equations. By Polyanin and Zaitsev. Second edition
Section : Chapter 1, section 1.2. Riccati Equation. subsection 1.2.4-1. Equations with hyperbolic sine and cosine
Problem number : 11
Date solved : Sunday, January 18, 2026 at 07:19:36 PM
CAS classification : [_Riccati]

2.5.11.1 Solved using first_order_ode_riccati

20.287 (sec)

Entering first order ode riccati solver

\begin{align*} y^{\prime }&=\left (a \cosh \left (\lambda x \right )^{2}-\lambda \right ) y^{2}+a +\lambda -a \cosh \left (\lambda x \right )^{2} \\ \end{align*}

In canonical form the ODE is

\begin{align*} y' &= F(x,y)\\ &= y^{2} \cosh \left (\lambda x \right )^{2} a -\lambda y^{2}-a \cosh \left (\lambda x \right )^{2}+a +\lambda \end{align*}

This is a Riccati ODE. Comparing the ODE to solve

\[ y' = y^{2} \cosh \left (\lambda x \right )^{2} a -\lambda y^{2}-a \cosh \left (\lambda x \right )^{2}+a +\lambda \]

With Riccati ODE standard form

\[ y' = f_0(x)+ f_1(x)y+f_2(x)y^{2} \]

Shows that \(f_0(x)=-a \cosh \left (\lambda x \right )^{2}+a +\lambda \), \(f_1(x)=0\) and \(f_2(x)=a \cosh \left (\lambda x \right )^{2}-\lambda \). Let

\begin{align*} y &= \frac {-u'}{f_2 u} \\ &= \frac {-u'}{u \left (a \cosh \left (\lambda x \right )^{2}-\lambda \right )} \tag {1} \end{align*}

Using the above substitution in the given ODE results (after some simplification) in a second order ODE to solve for \(u(x)\) which is

\begin{align*} f_2 u''(x) -\left ( f_2' + f_1 f_2 \right ) u'(x) + f_2^2 f_0 u(x) &= 0 \tag {2} \end{align*}

But

\begin{align*} f_2' &=2 a \cosh \left (\lambda x \right ) \lambda \sinh \left (\lambda x \right )\\ f_1 f_2 &=0\\ f_2^2 f_0 &=\left (a \cosh \left (\lambda x \right )^{2}-\lambda \right )^{2} \left (-a \cosh \left (\lambda x \right )^{2}+a +\lambda \right ) \end{align*}

Substituting the above terms back in equation (2) gives

\[ \left (a \cosh \left (\lambda x \right )^{2}-\lambda \right ) u^{\prime \prime }\left (x \right )-2 a \cosh \left (\lambda x \right ) \lambda \sinh \left (\lambda x \right ) u^{\prime }\left (x \right )+\left (a \cosh \left (\lambda x \right )^{2}-\lambda \right )^{2} \left (-a \cosh \left (\lambda x \right )^{2}+a +\lambda \right ) u \left (x \right ) = 0 \]

Unable to solve. Will ask Maple to solve this ode now.

The solution for \(u \left (x \right )\) is

\begin{equation} \tag{3} u \left (x \right ) = c_1 \cosh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }}+c_2 \cosh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }} \int 2 \lambda \,{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} \left (a -\lambda \operatorname {sech}\left (\lambda x \right )^{2}\right )d x \end{equation}

Taking derivative gives

\begin{equation} \tag{4} u^{\prime }\left (x \right ) = c_1 \lambda \sinh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }}-\frac {c_1 \cosh \left (\lambda x \right ) a \sinh \left (2 \lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }}}{2}+c_2 \lambda \sinh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }} \int 2 \lambda \,{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} \left (a -\lambda \operatorname {sech}\left (\lambda x \right )^{2}\right )d x -\frac {c_2 \cosh \left (\lambda x \right ) a \sinh \left (2 \lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }} \int 2 \lambda \,{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} \left (a -\lambda \operatorname {sech}\left (\lambda x \right )^{2}\right )d x}{2}+2 c_2 \cosh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }} \lambda \,{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} \left (a -\lambda \operatorname {sech}\left (\lambda x \right )^{2}\right ) \end{equation}

Substituting equations (3,4) into (1) results in

\begin{align*} y &= \frac {-u'}{f_2 u} \\ y &= \frac {-u'}{u \left (a \cosh \left (\lambda x \right )^{2}-\lambda \right )} \\ y &= -\frac {c_1 \lambda \sinh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }}-\frac {c_1 \cosh \left (\lambda x \right ) a \sinh \left (2 \lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }}}{2}+c_2 \lambda \sinh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }} \int 2 \lambda \,{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} \left (a -\lambda \operatorname {sech}\left (\lambda x \right )^{2}\right )d x -\frac {c_2 \cosh \left (\lambda x \right ) a \sinh \left (2 \lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }} \int 2 \lambda \,{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} \left (a -\lambda \operatorname {sech}\left (\lambda x \right )^{2}\right )d x}{2}+2 c_2 \cosh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }} \lambda \,{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} \left (a -\lambda \operatorname {sech}\left (\lambda x \right )^{2}\right )}{\left (a \cosh \left (\lambda x \right )^{2}-\lambda \right ) \left (c_1 \cosh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }}+c_2 \cosh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }} \int 2 \lambda \,{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} \left (a -\lambda \operatorname {sech}\left (\lambda x \right )^{2}\right )d x \right )} \\ \end{align*}

Doing change of constants, the above solution becomes

\[ y = -\frac {\lambda \sinh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }}-\frac {\cosh \left (\lambda x \right ) a \sinh \left (2 \lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }}}{2}+c_3 \lambda \sinh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }} \int 2 \lambda \,{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} \left (a -\lambda \operatorname {sech}\left (\lambda x \right )^{2}\right )d x -\frac {c_3 \cosh \left (\lambda x \right ) a \sinh \left (2 \lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }} \int 2 \lambda \,{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} \left (a -\lambda \operatorname {sech}\left (\lambda x \right )^{2}\right )d x}{2}+2 c_3 \cosh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }} \lambda \,{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} \left (a -\lambda \operatorname {sech}\left (\lambda x \right )^{2}\right )}{\left (a \cosh \left (\lambda x \right )^{2}-\lambda \right ) \left (\cosh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }}+c_3 \cosh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }} \int 2 \lambda \,{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} \left (a -\lambda \operatorname {sech}\left (\lambda x \right )^{2}\right )d x \right )} \]

Summary of solutions found

\begin{align*} y &= -\frac {\lambda \sinh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }}-\frac {\cosh \left (\lambda x \right ) a \sinh \left (2 \lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }}}{2}+c_3 \lambda \sinh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }} \int 2 \lambda \,{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} \left (a -\lambda \operatorname {sech}\left (\lambda x \right )^{2}\right )d x -\frac {c_3 \cosh \left (\lambda x \right ) a \sinh \left (2 \lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }} \int 2 \lambda \,{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} \left (a -\lambda \operatorname {sech}\left (\lambda x \right )^{2}\right )d x}{2}+2 c_3 \cosh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }} \lambda \,{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} \left (a -\lambda \operatorname {sech}\left (\lambda x \right )^{2}\right )}{\left (a \cosh \left (\lambda x \right )^{2}-\lambda \right ) \left (\cosh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }}+c_3 \cosh \left (\lambda x \right ) {\mathrm e}^{-\frac {\cosh \left (2 \lambda x \right ) a}{4 \lambda }} \int 2 \lambda \,{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} \left (a -\lambda \operatorname {sech}\left (\lambda x \right )^{2}\right )d x \right )} \\ \end{align*}

2.5.11.2 ✓ Maple. Time used: 0.006 (sec). Leaf size: 104

ode:=diff(y(x),x) = (a*cosh(lambda*x)^2-lambda)*y(x)^2+a+lambda-a*cosh(lambda*x)^2; 
dsolve(ode,y(x), singsol=all);
 

\[ y = \frac {2 \lambda \int -{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} \left (a -\lambda \operatorname {sech}\left (\lambda x \right )^{2}\right )d x c_1 \tanh \left (\lambda x \right )+2 \,{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} c_1 \lambda \operatorname {sech}\left (\lambda x \right )^{2}-\tanh \left (\lambda x \right )}{2 \lambda \int -{\mathrm e}^{\frac {\cosh \left (2 \lambda x \right ) a}{2 \lambda }} \left (a -\lambda \operatorname {sech}\left (\lambda x \right )^{2}\right )d x c_1 -1} \]

Maple trace

Methods for first order ODEs: 
--- Trying classification methods --- 
trying a quadrature 
trying 1st order linear 
trying Bernoulli 
trying separable 
trying inverse linear 
trying homogeneous types: 
trying Chini 
differential order: 1; looking for linear symmetries 
trying exact 
Looking for potential symmetries 
trying Riccati 
trying Riccati sub-methods: 
   trying Riccati_symmetries 
   trying Riccati to 2nd Order 
   -> Calling odsolve with the ODE, diff(diff(y(x),x),x) = 2*a*cosh(lambda*x)* 
lambda*sinh(lambda*x)/(a*cosh(lambda*x)^2-lambda)*diff(y(x),x)+(a*cosh(lambda*x 
)^2-lambda)*(a*cosh(lambda*x)^2-a-lambda)*y(x), y(x) 
      *** Sublevel 2 *** 
      Methods for second order ODEs: 
      --- Trying classification methods --- 
      trying a symmetry of the form [xi=0, eta=F(x)] 
      checking if the LODE is missing y 
      -> Heun: Equivalence to the GHE or one of its 4 confluent cases under a \ 
power @ Moebius 
      -> trying a solution of the form r0(x) * Y + r1(x) * Y where Y = exp(int\ 
(r(x), dx)) * 2F1([a1, a2], [b1], f) 
      -> Trying changes of variables to rationalize or make the ODE simpler 
         trying a quadrature 
         checking if the LODE has constant coefficients 
         checking if the LODE is of Euler type 
         trying a symmetry of the form [xi=0, eta=F(x)] 
         checking if the LODE is missing y 
         -> Trying a Liouvillian solution using Kovacics algorithm 
            A Liouvillian solution exists 
            Reducible group (found an exponential solution) 
            Group is reducible, not completely reducible 
            Solution has integrals. Trying a special function solution free of \ 
integrals... 
            -> Trying a solution in terms of special functions: 
               -> Bessel 
               -> elliptic 
               -> Legendre 
               -> Kummer 
                  -> hyper3: Equivalence to 1F1 under a power @ Moebius 
               -> hypergeometric 
                  -> heuristic approach 
                  -> hyper3: Equivalence to 2F1, 1F1 or 0F1 under a power @ Mo\ 
ebius 
               -> Mathieu 
                  -> Equivalence to the rational form of Mathieu ODE under a p\ 
ower @ Moebius 
               -> Heun: Equivalence to the GHE or one of its 4 confluent cases \ 
under a power @ Moebius 
            No special function solution was found. 
         <- Kovacics algorithm successful 
         Change of variables used: 
            [x = 1/2*arccosh(t)/lambda] 
         Linear ODE actually solved: 
            (-4*a^3*t^3-4*a^3*t^2+24*a^2*lambda*t^2+4*a^3*t+16*a^2*lambda*t-48*\ 
a*lambda^2*t+4*a^3-8*a^2*lambda-16*a*lambda^2+32*lambda^3)*u(t)+(64*a*lambda^2*\ 
t-128*lambda^3*t+64*a*lambda^2)*diff(u(t),t)+(64*a*lambda^2*t^3+64*a*lambda^2*t\ 
^2-128*lambda^3*t^2-64*a*lambda^2*t-64*a*lambda^2+128*lambda^3)*diff(diff(u(t),\ 
t),t) = 0 
      <- change of variables successful 
   <- Riccati to 2nd Order successful
 

Maple step by step

\[ \begin {array}{lll} & {} & \textrm {Let's solve}\hspace {3pt} \\ {} & {} & \frac {d}{d x}y \left (x \right )=\left (a \cosh \left (\lambda x \right )^{2}-\lambda \right ) y \left (x \right )^{2}+a +\lambda -a \cosh \left (\lambda x \right )^{2} \\ \bullet & {} & \textrm {Highest derivative means the order of the ODE is}\hspace {3pt} 1 \\ {} & {} & \frac {d}{d x}y \left (x \right ) \\ \bullet & {} & \textrm {Solve for the highest derivative}\hspace {3pt} \\ {} & {} & \frac {d}{d x}y \left (x \right )=\left (a \cosh \left (\lambda x \right )^{2}-\lambda \right ) y \left (x \right )^{2}+a +\lambda -a \cosh \left (\lambda x \right )^{2} \end {array} \]

2.5.11.3 ✓ Mathematica. Time used: 11.405 (sec). Leaf size: 289

ode=D[y[x],x]==(a*Cosh[\[Lambda]*x]^2-\[Lambda])*y[x]^2+a+\[Lambda]-a*Cosh[\[Lambda]*x]^2; 
ic={}; 
DSolve[{ode,ic},y[x],x,IncludeSingularSolutions->True]
 

\begin{align*} y(x)&\to \frac {\text {sech}^2(\lambda x) \left (c_1 \sinh (2 \lambda x) \int _1^xe^{\frac {a \cosh ^2(\lambda K[1])}{\lambda }} \left (\lambda -a \cosh ^2(\lambda K[1])\right ) \text {sech}^2(\lambda K[1])dK[1]+2 c_1 e^{\frac {a \cosh ^2(\lambda x)}{\lambda }}+\sinh (2 \lambda x)\right )}{2+2 c_1 \int _1^xe^{\frac {a \cosh ^2(\lambda K[1])}{\lambda }} \left (\lambda -a \cosh ^2(\lambda K[1])\right ) \text {sech}^2(\lambda K[1])dK[1]}\\ y(x)&\to \frac {1}{2} \text {sech}^2(\lambda x) \left (\frac {2 e^{\frac {a \cosh ^2(\lambda x)}{\lambda }}}{\int _1^xe^{\frac {a \cosh ^2(\lambda K[1])}{\lambda }} \left (\lambda -a \cosh ^2(\lambda K[1])\right ) \text {sech}^2(\lambda K[1])dK[1]}+\sinh (2 \lambda x)\right )\\ y(x)&\to \frac {1}{2} \text {sech}^2(\lambda x) \left (\frac {2 e^{\frac {a \cosh ^2(\lambda x)}{\lambda }}}{\int _1^xe^{\frac {a \cosh ^2(\lambda K[1])}{\lambda }} \left (\lambda -a \cosh ^2(\lambda K[1])\right ) \text {sech}^2(\lambda K[1])dK[1]}+\sinh (2 \lambda x)\right ) \end{align*}

2.5.11.4 ✗ Sympy

from sympy import * 
x = symbols("x") 
a = symbols("a") 
lambda_ = symbols("lambda_") 
y = Function("y") 
ode = Eq(a*cosh(lambda_*x)**2 - a - lambda_ - (a*cosh(lambda_*x)**2 - lambda_)*y(x)**2 + Derivative(y(x), x),0) 
ics = {} 
dsolve(ode,func=y(x),ics=ics)
 

NotImplementedError : The given ODE -a*y(x)**2*cosh(lambda_*x)**2 + a*cosh(lambda_*x)**2 - a + lambd
 

Python version: 3.12.3 (main, Aug 14 2025, 17:47:21) [GCC 13.3.0] 
Sympy version 1.14.0
 

classify_ode(ode,func=y(x)) 
 
('factorable', '1st_power_series', 'lie_group')