2.5.7 Problem 7
Internal
problem
ID
[13326]
Book
:
Handbook
of
exact
solutions
for
ordinary
differential
equations.
By
Polyanin
and
Zaitsev.
Second
edition
Section
:
Chapter
1,
section
1.2.
Riccati
Equation.
subsection
1.2.4-1.
Equations
with
hyperbolic
sine
and
cosine
Problem
number
:
7
Date
solved
:
Wednesday, December 31, 2025 at 01:24:15 PM
CAS
classification
:
[_Riccati]
2.5.7.1 Solved using first_order_ode_riccati
9.112 (sec)
Entering first order ode riccati solver
\begin{align*}
\left (\sinh \left (\lambda x \right ) a +b \right ) \left (y^{\prime }-y^{2}\right )+\lambda ^{2} \sinh \left (\lambda x \right ) a&=0 \\
\end{align*}
In canonical form the ODE is \begin{align*} y' &= F(x,y)\\ &= \frac {\sinh \left (\lambda x \right ) y^{2} a -\lambda ^{2} \sinh \left (\lambda x \right ) a +y^{2} b}{\sinh \left (\lambda x \right ) a +b} \end{align*}
This is a Riccati ODE. Comparing the ODE to solve
\[
y' = \textit {the\_rhs}
\]
With Riccati ODE standard form \[ y' = f_0(x)+ f_1(x)y+f_2(x)y^{2} \]
Shows
that \(f_0(x)=-\frac {\lambda ^{2} \sinh \left (\lambda x \right ) a}{\sinh \left (\lambda x \right ) a +b}\), \(f_1(x)=0\) and \(f_2(x)=1\). Let \begin{align*} y &= \frac {-u'}{f_2 u} \\ &= \frac {-u'}{u} \tag {1} \end{align*}
Using the above substitution in the given ODE results (after some simplification) in a second
order ODE to solve for \(u(x)\) which is
\begin{align*} f_2 u''(x) -\left ( f_2' + f_1 f_2 \right ) u'(x) + f_2^2 f_0 u(x) &= 0 \tag {2} \end{align*}
But
\begin{align*} f_2' &=0\\ f_1 f_2 &=0\\ f_2^2 f_0 &=-\frac {\lambda ^{2} \sinh \left (\lambda x \right ) a}{\sinh \left (\lambda x \right ) a +b} \end{align*}
Substituting the above terms back in equation (2) gives
\[
u^{\prime \prime }\left (x \right )-\frac {\lambda ^{2} \sinh \left (\lambda x \right ) a u \left (x \right )}{\sinh \left (\lambda x \right ) a +b} = 0
\]
Unable to solve. Will ask Maple to solve
this ode now.
The solution for \(u \left (x \right )\) is
\begin{equation}
\tag{3} u \left (x \right ) = \frac {\left (\tanh \left (\frac {\lambda x}{2}\right )^{2} \operatorname {arctanh}\left (\frac {b \tanh \left (\frac {\lambda x}{2}\right )-a}{\sqrt {a^{2}+b^{2}}}\right ) a^{2} b^{3}+\tanh \left (\frac {\lambda x}{2}\right )^{2} \operatorname {arctanh}\left (\frac {b \tanh \left (\frac {\lambda x}{2}\right )-a}{\sqrt {a^{2}+b^{2}}}\right ) b^{5}-2 \tanh \left (\frac {\lambda x}{2}\right ) \operatorname {arctanh}\left (\frac {b \tanh \left (\frac {\lambda x}{2}\right )-a}{\sqrt {a^{2}+b^{2}}}\right ) a^{3} b^{2}-2 \tanh \left (\frac {\lambda x}{2}\right ) \operatorname {arctanh}\left (\frac {b \tanh \left (\frac {\lambda x}{2}\right )-a}{\sqrt {a^{2}+b^{2}}}\right ) a \,b^{4}+\tanh \left (\frac {\lambda x}{2}\right ) \left (a^{2}+b^{2}\right )^{{3}/{2}} a^{2}-\operatorname {arctanh}\left (\frac {b \tanh \left (\frac {\lambda x}{2}\right )-a}{\sqrt {a^{2}+b^{2}}}\right ) a^{2} b^{3}-\operatorname {arctanh}\left (\frac {b \tanh \left (\frac {\lambda x}{2}\right )-a}{\sqrt {a^{2}+b^{2}}}\right ) b^{5}+\left (a^{2}+b^{2}\right )^{{3}/{2}} a b \right ) \left (\sinh \left (\lambda x \right ) a +b \right ) c_1}{\tanh \left (\frac {\lambda x}{2}\right )^{2} b -2 a \tanh \left (\frac {\lambda x}{2}\right )-b}+c_2 \left (\sinh \left (\lambda x \right ) a +b \right )
\end{equation}
Taking derivative gives \begin{equation}
\tag{4} \text {Expression too large to display}
\end{equation}
Substituting equations (3,4) into (1) results in \begin{align*}
y &= \frac {-u'}{f_2 u} \\
y &= \frac {-u'}{u} \\
y &= \text {Expression too large to display} \\
\end{align*}
Doing change of constants, the above solution becomes \[
\text {Expression too large to display}
\]
Simplifying the above gives
\begin{align*}
y &= -\frac {2 \left (\left (a^{2} b^{2} \operatorname {arctanh}\left (\frac {-b \tanh \left (\frac {\lambda x}{2}\right )+a}{\sqrt {a^{2}+b^{2}}}\right )+b^{4} \operatorname {arctanh}\left (\frac {-b \tanh \left (\frac {\lambda x}{2}\right )+a}{\sqrt {a^{2}+b^{2}}}\right )-c_3 \right ) a \left (\cosh \left (\frac {\lambda x}{2}\right )^{2}-\frac {1}{2}\right ) \sqrt {a^{2}+b^{2}}+\frac {\left (a^{2}+b^{2}\right )^{2} \left (a^{2} \cosh \left (\frac {\lambda x}{2}\right )^{2}+a \sinh \left (\frac {\lambda x}{2}\right ) b \cosh \left (\frac {\lambda x}{2}\right )-\frac {a^{2}}{2}-\frac {b^{2}}{2}\right )}{2}\right ) \lambda }{\sqrt {a^{2}+b^{2}}\, \left (a \cosh \left (\frac {\lambda x}{2}\right ) \left (a^{2}+b^{2}\right )^{{3}/{2}} \left (a \sinh \left (\frac {\lambda x}{2}\right )+\cosh \left (\frac {\lambda x}{2}\right ) b \right )+2 \left (a^{2} b^{2} \operatorname {arctanh}\left (\frac {-b \tanh \left (\frac {\lambda x}{2}\right )+a}{\sqrt {a^{2}+b^{2}}}\right )+b^{4} \operatorname {arctanh}\left (\frac {-b \tanh \left (\frac {\lambda x}{2}\right )+a}{\sqrt {a^{2}+b^{2}}}\right )-c_3 \right ) \left (a \sinh \left (\frac {\lambda x}{2}\right ) \cosh \left (\frac {\lambda x}{2}\right )+\frac {b}{2}\right )\right )} \\
\end{align*}
Summary of solutions found
\begin{align*}
y &= -\frac {2 \left (\left (a^{2} b^{2} \operatorname {arctanh}\left (\frac {-b \tanh \left (\frac {\lambda x}{2}\right )+a}{\sqrt {a^{2}+b^{2}}}\right )+b^{4} \operatorname {arctanh}\left (\frac {-b \tanh \left (\frac {\lambda x}{2}\right )+a}{\sqrt {a^{2}+b^{2}}}\right )-c_3 \right ) a \left (\cosh \left (\frac {\lambda x}{2}\right )^{2}-\frac {1}{2}\right ) \sqrt {a^{2}+b^{2}}+\frac {\left (a^{2}+b^{2}\right )^{2} \left (a^{2} \cosh \left (\frac {\lambda x}{2}\right )^{2}+a \sinh \left (\frac {\lambda x}{2}\right ) b \cosh \left (\frac {\lambda x}{2}\right )-\frac {a^{2}}{2}-\frac {b^{2}}{2}\right )}{2}\right ) \lambda }{\sqrt {a^{2}+b^{2}}\, \left (a \cosh \left (\frac {\lambda x}{2}\right ) \left (a^{2}+b^{2}\right )^{{3}/{2}} \left (a \sinh \left (\frac {\lambda x}{2}\right )+\cosh \left (\frac {\lambda x}{2}\right ) b \right )+2 \left (a^{2} b^{2} \operatorname {arctanh}\left (\frac {-b \tanh \left (\frac {\lambda x}{2}\right )+a}{\sqrt {a^{2}+b^{2}}}\right )+b^{4} \operatorname {arctanh}\left (\frac {-b \tanh \left (\frac {\lambda x}{2}\right )+a}{\sqrt {a^{2}+b^{2}}}\right )-c_3 \right ) \left (a \sinh \left (\frac {\lambda x}{2}\right ) \cosh \left (\frac {\lambda x}{2}\right )+\frac {b}{2}\right )\right )} \\
\end{align*}
2.5.7.2 ✓ Maple. Time used: 0.005 (sec). Leaf size: 250
ode:=(sinh(lambda*x)*a+b)*(diff(y(x),x)-y(x)^2)+a*lambda^2*sinh(lambda*x) = 0;
dsolve(ode,y(x), singsol=all);
\[
y = -\frac {4 \left (a \left (\cosh \left (\frac {\lambda x}{2}\right )^{2}-\frac {1}{2}\right ) \left (\operatorname {arctanh}\left (\frac {-\tanh \left (\frac {\lambda x}{2}\right ) b +a}{\sqrt {a^{2}+b^{2}}}\right ) a^{2} b^{2}+\operatorname {arctanh}\left (\frac {-\tanh \left (\frac {\lambda x}{2}\right ) b +a}{\sqrt {a^{2}+b^{2}}}\right ) b^{4}-c_1 \right ) \sqrt {a^{2}+b^{2}}+\frac {\left (a^{2}+b^{2}\right )^{2} \left (a^{2} \cosh \left (\frac {\lambda x}{2}\right )^{2}+a b \cosh \left (\frac {\lambda x}{2}\right ) \sinh \left (\frac {\lambda x}{2}\right )-\frac {a^{2}}{2}-\frac {b^{2}}{2}\right )}{2}\right ) \lambda }{\sqrt {a^{2}+b^{2}}\, \left (2 a \cosh \left (\frac {\lambda x}{2}\right ) \left (a^{2}+b^{2}\right )^{{3}/{2}} \left (a \sinh \left (\frac {\lambda x}{2}\right )+b \cosh \left (\frac {\lambda x}{2}\right )\right )+4 \left (a \sinh \left (\frac {\lambda x}{2}\right ) \cosh \left (\frac {\lambda x}{2}\right )+\frac {b}{2}\right ) \left (\operatorname {arctanh}\left (\frac {-\tanh \left (\frac {\lambda x}{2}\right ) b +a}{\sqrt {a^{2}+b^{2}}}\right ) a^{2} b^{2}+\operatorname {arctanh}\left (\frac {-\tanh \left (\frac {\lambda x}{2}\right ) b +a}{\sqrt {a^{2}+b^{2}}}\right ) b^{4}-c_1 \right )\right )}
\]
Maple trace
Methods for first order ODEs:
--- Trying classification methods ---
trying a quadrature
trying 1st order linear
trying Bernoulli
trying separable
trying inverse linear
trying homogeneous types:
trying Chini
differential order: 1; looking for linear symmetries
trying exact
Looking for potential symmetries
trying Riccati
trying Riccati sub-methods:
trying Riccati_symmetries
trying Riccati to 2nd Order
-> Calling odsolve with the ODE, diff(diff(y(x),x),x) = 1/(a*sinh(lambda*x)+
b)*a*lambda^2*sinh(lambda*x)*y(x), y(x)
*** Sublevel 2 ***
Methods for second order ODEs:
--- Trying classification methods ---
trying a symmetry of the form [xi=0, eta=F(x)]
<- linear_1 successful
<- Riccati to 2nd Order successful
Maple step by step
\[ \begin {array}{lll} & {} & \textrm {Let's solve}\hspace {3pt} \\ {} & {} & \left (a \sinh \left (\lambda x \right )+b \right ) \left (\frac {d}{d x}y \left (x \right )-y \left (x \right )^{2}\right )+a \,\lambda ^{2} \sinh \left (\lambda x \right )=0 \\ \bullet & {} & \textrm {Highest derivative means the order of the ODE is}\hspace {3pt} 1 \\ {} & {} & \frac {d}{d x}y \left (x \right ) \\ \bullet & {} & \textrm {Solve for the highest derivative}\hspace {3pt} \\ {} & {} & \frac {d}{d x}y \left (x \right )=\frac {\sinh \left (\lambda x \right ) y \left (x \right )^{2} a -a \,\lambda ^{2} \sinh \left (\lambda x \right )+y \left (x \right )^{2} b}{a \sinh \left (\lambda x \right )+b} \end {array} \]
2.5.7.3 ✓ Mathematica. Time used: 11.48 (sec). Leaf size: 229
ode=(a*Sinh[\[Lambda]*x]+b)*(D[y[x],x]-y[x]^2)+a*\[Lambda]^2*Sinh[\[Lambda]*x]==0;
ic={};
DSolve[{ode,ic},y[x],x,IncludeSingularSolutions->True]
\[
\text {Solve}\left [\int _1^x-\frac {-a \sinh (\lambda K[1]) \lambda ^2+b y(x)^2+a \sinh (\lambda K[1]) y(x)^2}{(b+a \sinh (\lambda K[1])) (a \lambda \cosh (\lambda K[1])+b y(x)+a \sinh (\lambda K[1]) y(x))^2}dK[1]+\int _1^{y(x)}\left (\frac {1}{(a \lambda \cosh (x \lambda )+b K[2]+a K[2] \sinh (x \lambda ))^2}-\int _1^x\left (\frac {2 \left (-a \sinh (\lambda K[1]) \lambda ^2+b K[2]^2+a K[2]^2 \sinh (\lambda K[1])\right )}{(a \lambda \cosh (\lambda K[1])+b K[2]+a K[2] \sinh (\lambda K[1]))^3}-\frac {2 b K[2]+2 a \sinh (\lambda K[1]) K[2]}{(b+a \sinh (\lambda K[1])) (a \lambda \cosh (\lambda K[1])+b K[2]+a K[2] \sinh (\lambda K[1]))^2}\right )dK[1]\right )dK[2]=c_1,y(x)\right ]
\]
2.5.7.4 ✗ Sympy
from sympy import *
x = symbols("x")
a = symbols("a")
b = symbols("b")
lambda_ = symbols("lambda_")
y = Function("y")
ode = Eq(a*lambda_**2*sinh(lambda_*x) + (a*sinh(lambda_*x) + b)*(-y(x)**2 + Derivative(y(x), x)),0)
ics = {}
dsolve(ode,func=y(x),ics=ics)
NotImplementedError : The given ODE Derivative(y(x), x) - (-a*lambda_**2*sinh(lambda_*x) + a*y(x)**2*sinh(lambda_*x) + b*y(x)**2)/(a*sinh(lambda_*x) + b) cannot be solved by the factorable group method