2.1.77 \(u_x u_y = 1\)

problem number 77

Added May 27, 2019.

From UMN Math 5587 HW2, Fall 2016, problem 5(a).

Solve for \(u(x,y)\) \begin {align*} u_x u_y = 1 \end {align*}

Mathematica


\[\left \{\left \{u(x,y)\to \frac {x}{c_2}+c_2 y+c_1\right \}\right \}\]

Maple


\[u \left (x , y\right ) = y \mathit {\_c}_{2}+c_{1}+c_{2}+\frac {x}{\mathit {\_c}_{2}}\]

Hand solution

Solve \(u_{x}u_{y}=1\). Let \(u=f\left ( x\right ) +g\left ( y\right ) \). The pde becomes \(f^{\prime }\left ( x\right ) g^{\prime }\left ( y\right ) =1\) or \(f^{\prime }\left ( x\right ) =\frac {1}{g^{\prime }\left ( y\right ) }\). Hence both are constant, say \(\lambda \). Therefore \(f^{\prime }\left ( x\right ) =\lambda \) or \(f\left ( x\right ) =\lambda x+C_{1}\) and similarly, \(\frac {1}{g^{\prime }\left ( y\right ) }=\lambda \) or \(g^{\prime }\left ( y\right ) =\frac {1}{\lambda }\) or \(g\left ( y\right ) =\frac {y}{\lambda }+C_{2}\). Therefore the solution becomes\begin {align*} u\left ( x,y\right ) & =f\left ( x\right ) +g\left ( y\right ) \\ & =\lambda x+C_{1}+\frac {y}{\lambda }+C_{2} \end {align*}

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