y''(x)=-\frac{y(x) \left(4 a x^2 (a-n)-\left(x^2-1\right) (2 a+(v-n) (n+v+1))\right)}{\left(x^2-1\right)^2}-\frac{2 x (-2 a+n+1) y'(x)}{x^2-1}