y'(x)=\frac{y(x) \text{sech}\left(\frac{1}{x+1}\right) \left(x^3 y(x)+x^2 y(x)-x^2-x-x \cosh \left(\frac{1}{x+1}\right)+\cosh \left(\frac{1}{x+1}\right)\right)}{(x-1) x}