3.609 \(\int e^{-3 \coth ^{-1}(a x)} (c-a^2 c x^2) \, dx\)

Optimal. Leaf size=145 \[ -\frac{1}{3} a^2 c x^3 \left (1-\frac{1}{a x}\right )^{5/2} \sqrt{\frac{1}{a x}+1}+\frac{5}{6} a c x^2 \left (1-\frac{1}{a x}\right )^{3/2} \sqrt{\frac{1}{a x}+1}-\frac{5}{2} c x \sqrt{1-\frac{1}{a x}} \sqrt{\frac{1}{a x}+1}+\frac{5 c \tanh ^{-1}\left (\sqrt{1-\frac{1}{a x}} \sqrt{\frac{1}{a x}+1}\right )}{2 a} \]

[Out]

(-5*c*Sqrt[1 - 1/(a*x)]*Sqrt[1 + 1/(a*x)]*x)/2 + (5*a*c*(1 - 1/(a*x))^(3/2)*Sqrt[1 + 1/(a*x)]*x^2)/6 - (a^2*c*
(1 - 1/(a*x))^(5/2)*Sqrt[1 + 1/(a*x)]*x^3)/3 + (5*c*ArcTanh[Sqrt[1 - 1/(a*x)]*Sqrt[1 + 1/(a*x)]])/(2*a)

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Rubi [A]  time = 0.12013, antiderivative size = 145, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {6191, 6195, 94, 92, 208} \[ -\frac{1}{3} a^2 c x^3 \left (1-\frac{1}{a x}\right )^{5/2} \sqrt{\frac{1}{a x}+1}+\frac{5}{6} a c x^2 \left (1-\frac{1}{a x}\right )^{3/2} \sqrt{\frac{1}{a x}+1}-\frac{5}{2} c x \sqrt{1-\frac{1}{a x}} \sqrt{\frac{1}{a x}+1}+\frac{5 c \tanh ^{-1}\left (\sqrt{1-\frac{1}{a x}} \sqrt{\frac{1}{a x}+1}\right )}{2 a} \]

Antiderivative was successfully verified.

[In]

Int[(c - a^2*c*x^2)/E^(3*ArcCoth[a*x]),x]

[Out]

(-5*c*Sqrt[1 - 1/(a*x)]*Sqrt[1 + 1/(a*x)]*x)/2 + (5*a*c*(1 - 1/(a*x))^(3/2)*Sqrt[1 + 1/(a*x)]*x^2)/6 - (a^2*c*
(1 - 1/(a*x))^(5/2)*Sqrt[1 + 1/(a*x)]*x^3)/3 + (5*c*ArcTanh[Sqrt[1 - 1/(a*x)]*Sqrt[1 + 1/(a*x)]])/(2*a)

Rule 6191

Int[E^(ArcCoth[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[d^p, Int[u*x^(2*p)*(1 -
1/(a^2*x^2))^p*E^(n*ArcCoth[a*x]), x], x] /; FreeQ[{a, c, d, n}, x] && EqQ[a^2*c + d, 0] &&  !IntegerQ[n/2] &
& IntegerQ[p]

Rule 6195

Int[E^(ArcCoth[(a_.)*(x_)]*(n_.))*((c_) + (d_.)/(x_)^2)^(p_.)*(x_)^(m_.), x_Symbol] :> -Dist[c^p, Subst[Int[((
1 - x/a)^(p - n/2)*(1 + x/a)^(p + n/2))/x^(m + 2), x], x, 1/x], x] /; FreeQ[{a, c, d, n, p}, x] && EqQ[c + a^2
*d, 0] &&  !IntegerQ[n/2] && (IntegerQ[p] || GtQ[c, 0]) &&  !IntegersQ[2*p, p + n/2] && IntegerQ[m]

Rule 94

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((a + b
*x)^(m + 1)*(c + d*x)^n*(e + f*x)^(p + 1))/((m + 1)*(b*e - a*f)), x] - Dist[(n*(d*e - c*f))/((m + 1)*(b*e - a*
f)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, m, p}, x] && EqQ[
m + n + p + 2, 0] && GtQ[n, 0] &&  !(SumSimplerQ[p, 1] &&  !SumSimplerQ[m, 1])

Rule 92

Int[1/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_.) + (d_.)*(x_)]*((e_.) + (f_.)*(x_))), x_Symbol] :> Dist[b*f, Subst[I
nt[1/(d*(b*e - a*f)^2 + b*f^2*x^2), x], x, Sqrt[a + b*x]*Sqrt[c + d*x]], x] /; FreeQ[{a, b, c, d, e, f}, x] &&
EqQ[2*b*d*e - f*(b*c + a*d), 0]

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rubi steps

\begin{align*} \int e^{-3 \coth ^{-1}(a x)} \left (c-a^2 c x^2\right ) \, dx &=-\left (\left (a^2 c\right ) \int e^{-3 \coth ^{-1}(a x)} \left (1-\frac{1}{a^2 x^2}\right ) x^2 \, dx\right )\\ &=\left (a^2 c\right ) \operatorname{Subst}\left (\int \frac{\left (1-\frac{x}{a}\right )^{5/2}}{x^4 \sqrt{1+\frac{x}{a}}} \, dx,x,\frac{1}{x}\right )\\ &=-\frac{1}{3} a^2 c \left (1-\frac{1}{a x}\right )^{5/2} \sqrt{1+\frac{1}{a x}} x^3-\frac{1}{3} (5 a c) \operatorname{Subst}\left (\int \frac{\left (1-\frac{x}{a}\right )^{3/2}}{x^3 \sqrt{1+\frac{x}{a}}} \, dx,x,\frac{1}{x}\right )\\ &=\frac{5}{6} a c \left (1-\frac{1}{a x}\right )^{3/2} \sqrt{1+\frac{1}{a x}} x^2-\frac{1}{3} a^2 c \left (1-\frac{1}{a x}\right )^{5/2} \sqrt{1+\frac{1}{a x}} x^3+\frac{1}{2} (5 c) \operatorname{Subst}\left (\int \frac{\sqrt{1-\frac{x}{a}}}{x^2 \sqrt{1+\frac{x}{a}}} \, dx,x,\frac{1}{x}\right )\\ &=-\frac{5}{2} c \sqrt{1-\frac{1}{a x}} \sqrt{1+\frac{1}{a x}} x+\frac{5}{6} a c \left (1-\frac{1}{a x}\right )^{3/2} \sqrt{1+\frac{1}{a x}} x^2-\frac{1}{3} a^2 c \left (1-\frac{1}{a x}\right )^{5/2} \sqrt{1+\frac{1}{a x}} x^3-\frac{(5 c) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{1-\frac{x}{a}} \sqrt{1+\frac{x}{a}}} \, dx,x,\frac{1}{x}\right )}{2 a}\\ &=-\frac{5}{2} c \sqrt{1-\frac{1}{a x}} \sqrt{1+\frac{1}{a x}} x+\frac{5}{6} a c \left (1-\frac{1}{a x}\right )^{3/2} \sqrt{1+\frac{1}{a x}} x^2-\frac{1}{3} a^2 c \left (1-\frac{1}{a x}\right )^{5/2} \sqrt{1+\frac{1}{a x}} x^3+\frac{(5 c) \operatorname{Subst}\left (\int \frac{1}{\frac{1}{a}-\frac{x^2}{a}} \, dx,x,\sqrt{1-\frac{1}{a x}} \sqrt{1+\frac{1}{a x}}\right )}{2 a^2}\\ &=-\frac{5}{2} c \sqrt{1-\frac{1}{a x}} \sqrt{1+\frac{1}{a x}} x+\frac{5}{6} a c \left (1-\frac{1}{a x}\right )^{3/2} \sqrt{1+\frac{1}{a x}} x^2-\frac{1}{3} a^2 c \left (1-\frac{1}{a x}\right )^{5/2} \sqrt{1+\frac{1}{a x}} x^3+\frac{5 c \tanh ^{-1}\left (\sqrt{1-\frac{1}{a x}} \sqrt{1+\frac{1}{a x}}\right )}{2 a}\\ \end{align*}

Mathematica [A]  time = 0.100573, size = 61, normalized size = 0.42 \[ \frac{c \left (a x \sqrt{1-\frac{1}{a^2 x^2}} \left (-2 a^2 x^2+9 a x-22\right )+15 \log \left (x \left (\sqrt{1-\frac{1}{a^2 x^2}}+1\right )\right )\right )}{6 a} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(c - a^2*c*x^2)/E^(3*ArcCoth[a*x]),x]

[Out]

(c*(a*Sqrt[1 - 1/(a^2*x^2)]*x*(-22 + 9*a*x - 2*a^2*x^2) + 15*Log[(1 + Sqrt[1 - 1/(a^2*x^2)])*x]))/(6*a)

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Maple [A]  time = 0.133, size = 183, normalized size = 1.3 \begin{align*}{\frac{ \left ( ax+1 \right ) ^{2}c}{ \left ( 6\,ax-6 \right ) a} \left ({\frac{ax-1}{ax+1}} \right ) ^{{\frac{3}{2}}} \left ( 9\,\sqrt{{a}^{2}}\sqrt{{a}^{2}{x}^{2}-1}xa-2\, \left ( \left ( ax-1 \right ) \left ( ax+1 \right ) \right ) ^{3/2}\sqrt{{a}^{2}}-9\,\ln \left ({\frac{{a}^{2}x+\sqrt{{a}^{2}{x}^{2}-1}\sqrt{{a}^{2}}}{\sqrt{{a}^{2}}}} \right ) a-24\,\sqrt{{a}^{2}}\sqrt{ \left ( ax-1 \right ) \left ( ax+1 \right ) }+24\,a\ln \left ({\frac{{a}^{2}x+\sqrt{{a}^{2}}\sqrt{ \left ( ax-1 \right ) \left ( ax+1 \right ) }}{\sqrt{{a}^{2}}}} \right ) \right ){\frac{1}{\sqrt{{a}^{2}}}}{\frac{1}{\sqrt{ \left ( ax-1 \right ) \left ( ax+1 \right ) }}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((-a^2*c*x^2+c)*((a*x-1)/(a*x+1))^(3/2),x)

[Out]

1/6*((a*x-1)/(a*x+1))^(3/2)*(a*x+1)^2*c*(9*(a^2)^(1/2)*(a^2*x^2-1)^(1/2)*x*a-2*((a*x-1)*(a*x+1))^(3/2)*(a^2)^(
1/2)-9*ln((a^2*x+(a^2*x^2-1)^(1/2)*(a^2)^(1/2))/(a^2)^(1/2))*a-24*(a^2)^(1/2)*((a*x-1)*(a*x+1))^(1/2)+24*a*ln(
(a^2*x+(a^2)^(1/2)*((a*x-1)*(a*x+1))^(1/2))/(a^2)^(1/2)))/(a*x-1)/((a*x-1)*(a*x+1))^(1/2)/a/(a^2)^(1/2)

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Maxima [A]  time = 1.11668, size = 231, normalized size = 1.59 \begin{align*} \frac{1}{6} \, a{\left (\frac{2 \,{\left (33 \, c \left (\frac{a x - 1}{a x + 1}\right )^{\frac{5}{2}} - 40 \, c \left (\frac{a x - 1}{a x + 1}\right )^{\frac{3}{2}} + 15 \, c \sqrt{\frac{a x - 1}{a x + 1}}\right )}}{\frac{3 \,{\left (a x - 1\right )} a^{2}}{a x + 1} - \frac{3 \,{\left (a x - 1\right )}^{2} a^{2}}{{\left (a x + 1\right )}^{2}} + \frac{{\left (a x - 1\right )}^{3} a^{2}}{{\left (a x + 1\right )}^{3}} - a^{2}} + \frac{15 \, c \log \left (\sqrt{\frac{a x - 1}{a x + 1}} + 1\right )}{a^{2}} - \frac{15 \, c \log \left (\sqrt{\frac{a x - 1}{a x + 1}} - 1\right )}{a^{2}}\right )} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-a^2*c*x^2+c)*((a*x-1)/(a*x+1))^(3/2),x, algorithm="maxima")

[Out]

1/6*a*(2*(33*c*((a*x - 1)/(a*x + 1))^(5/2) - 40*c*((a*x - 1)/(a*x + 1))^(3/2) + 15*c*sqrt((a*x - 1)/(a*x + 1))
)/(3*(a*x - 1)*a^2/(a*x + 1) - 3*(a*x - 1)^2*a^2/(a*x + 1)^2 + (a*x - 1)^3*a^2/(a*x + 1)^3 - a^2) + 15*c*log(s
qrt((a*x - 1)/(a*x + 1)) + 1)/a^2 - 15*c*log(sqrt((a*x - 1)/(a*x + 1)) - 1)/a^2)

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Fricas [A]  time = 1.67929, size = 223, normalized size = 1.54 \begin{align*} \frac{15 \, c \log \left (\sqrt{\frac{a x - 1}{a x + 1}} + 1\right ) - 15 \, c \log \left (\sqrt{\frac{a x - 1}{a x + 1}} - 1\right ) -{\left (2 \, a^{3} c x^{3} - 7 \, a^{2} c x^{2} + 13 \, a c x + 22 \, c\right )} \sqrt{\frac{a x - 1}{a x + 1}}}{6 \, a} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-a^2*c*x^2+c)*((a*x-1)/(a*x+1))^(3/2),x, algorithm="fricas")

[Out]

1/6*(15*c*log(sqrt((a*x - 1)/(a*x + 1)) + 1) - 15*c*log(sqrt((a*x - 1)/(a*x + 1)) - 1) - (2*a^3*c*x^3 - 7*a^2*
c*x^2 + 13*a*c*x + 22*c)*sqrt((a*x - 1)/(a*x + 1)))/a

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-a**2*c*x**2+c)*((a*x-1)/(a*x+1))**(3/2),x)

[Out]

Timed out

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Giac [A]  time = 1.14056, size = 111, normalized size = 0.77 \begin{align*} -\frac{5 \, c \log \left ({\left | -x{\left | a \right |} + \sqrt{a^{2} x^{2} - 1} \right |}\right ) \mathrm{sgn}\left (a x + 1\right )}{2 \,{\left | a \right |}} - \frac{1}{6} \, \sqrt{a^{2} x^{2} - 1}{\left ({\left (2 \, a c x \mathrm{sgn}\left (a x + 1\right ) - 9 \, c \mathrm{sgn}\left (a x + 1\right )\right )} x + \frac{22 \, c \mathrm{sgn}\left (a x + 1\right )}{a}\right )} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-a^2*c*x^2+c)*((a*x-1)/(a*x+1))^(3/2),x, algorithm="giac")

[Out]

-5/2*c*log(abs(-x*abs(a) + sqrt(a^2*x^2 - 1)))*sgn(a*x + 1)/abs(a) - 1/6*sqrt(a^2*x^2 - 1)*((2*a*c*x*sgn(a*x +
1) - 9*c*sgn(a*x + 1))*x + 22*c*sgn(a*x + 1)/a)