### 3.479 $$\int \frac{e^{-2 \coth ^{-1}(a x)}}{(c-\frac{c}{a x})^{9/2}} \, dx$$

Optimal. Leaf size=172 $\frac{x}{c^2 \left (c-\frac{c}{a x}\right )^{5/2}}-\frac{21}{4 a c^4 \sqrt{c-\frac{c}{a x}}}-\frac{11}{6 a c^3 \left (c-\frac{c}{a x}\right )^{3/2}}-\frac{6}{5 a c^2 \left (c-\frac{c}{a x}\right )^{5/2}}+\frac{5 \tanh ^{-1}\left (\frac{\sqrt{c-\frac{c}{a x}}}{\sqrt{c}}\right )}{a c^{9/2}}+\frac{\tanh ^{-1}\left (\frac{\sqrt{c-\frac{c}{a x}}}{\sqrt{2} \sqrt{c}}\right )}{4 \sqrt{2} a c^{9/2}}$

[Out]

-6/(5*a*c^2*(c - c/(a*x))^(5/2)) - 11/(6*a*c^3*(c - c/(a*x))^(3/2)) - 21/(4*a*c^4*Sqrt[c - c/(a*x)]) + x/(c^2*
(c - c/(a*x))^(5/2)) + (5*ArcTanh[Sqrt[c - c/(a*x)]/Sqrt[c]])/(a*c^(9/2)) + ArcTanh[Sqrt[c - c/(a*x)]/(Sqrt[2]
*Sqrt[c])]/(4*Sqrt[2]*a*c^(9/2))

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Rubi [A]  time = 0.293287, antiderivative size = 172, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 10, integrand size = 24, $$\frac{\text{number of rules}}{\text{integrand size}}$$ = 0.417, Rules used = {6167, 6133, 25, 514, 375, 103, 152, 156, 63, 208} $\frac{x}{c^2 \left (c-\frac{c}{a x}\right )^{5/2}}-\frac{21}{4 a c^4 \sqrt{c-\frac{c}{a x}}}-\frac{11}{6 a c^3 \left (c-\frac{c}{a x}\right )^{3/2}}-\frac{6}{5 a c^2 \left (c-\frac{c}{a x}\right )^{5/2}}+\frac{5 \tanh ^{-1}\left (\frac{\sqrt{c-\frac{c}{a x}}}{\sqrt{c}}\right )}{a c^{9/2}}+\frac{\tanh ^{-1}\left (\frac{\sqrt{c-\frac{c}{a x}}}{\sqrt{2} \sqrt{c}}\right )}{4 \sqrt{2} a c^{9/2}}$

Antiderivative was successfully veriﬁed.

[In]

Int[1/(E^(2*ArcCoth[a*x])*(c - c/(a*x))^(9/2)),x]

[Out]

-6/(5*a*c^2*(c - c/(a*x))^(5/2)) - 11/(6*a*c^3*(c - c/(a*x))^(3/2)) - 21/(4*a*c^4*Sqrt[c - c/(a*x)]) + x/(c^2*
(c - c/(a*x))^(5/2)) + (5*ArcTanh[Sqrt[c - c/(a*x)]/Sqrt[c]])/(a*c^(9/2)) + ArcTanh[Sqrt[c - c/(a*x)]/(Sqrt[2]
*Sqrt[c])]/(4*Sqrt[2]*a*c^(9/2))

Rule 6167

Int[E^(ArcCoth[(a_.)*(x_)]*(n_))*(u_.), x_Symbol] :> Dist[(-1)^(n/2), Int[u*E^(n*ArcTanh[a*x]), x], x] /; Free
Q[a, x] && IntegerQ[n/2]

Rule 6133

Int[E^(ArcTanh[(a_.)*(x_)]*(n_))*(u_.)*((c_) + (d_.)/(x_))^(p_), x_Symbol] :> Int[(u*(c + d/x)^p*(1 + a*x)^(n/
2))/(1 - a*x)^(n/2), x] /; FreeQ[{a, c, d, p}, x] && EqQ[c^2 - a^2*d^2, 0] &&  !IntegerQ[p] && IntegerQ[n/2] &
&  !GtQ[c, 0]

Rule 25

Int[(u_.)*((a_) + (b_.)*(x_)^(n_.))^(m_.)*((c_) + (d_.)*(x_)^(q_.))^(p_.), x_Symbol] :> Dist[(d/a)^p, Int[(u*(
a + b*x^n)^(m + p))/x^(n*p), x], x] /; FreeQ[{a, b, c, d, m, n}, x] && EqQ[q, -n] && IntegerQ[p] && EqQ[a*c -
b*d, 0] &&  !(IntegerQ[m] && NegQ[n])

Rule 514

Int[(x_)^(m_.)*((c_) + (d_.)*(x_)^(mn_.))^(q_.)*((a_) + (b_.)*(x_)^(n_.))^(p_.), x_Symbol] :> Int[x^(m - n*q)*
(a + b*x^n)^p*(d + c*x^n)^q, x] /; FreeQ[{a, b, c, d, m, n, p}, x] && EqQ[mn, -n] && IntegerQ[q] && (PosQ[n] |
|  !IntegerQ[p])

Rule 375

Int[((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.), x_Symbol] :> -Subst[Int[((a + b/x^n)^p*(c +
d/x^n)^q)/x^2, x], x, 1/x] /; FreeQ[{a, b, c, d, p, q}, x] && NeQ[b*c - a*d, 0] && ILtQ[n, 0]

Rule 103

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*(a +
b*x)^(m + 1)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/((m + 1)*(b*c - a*d)*(b*e - a*f)), x] + Dist[1/((m + 1)*(b*
c - a*d)*(b*e - a*f)), Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*(m + 1) - b*(d*e*(m + n + 2) +
c*f*(m + p + 2)) - b*d*f*(m + n + p + 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && LtQ[m, -1] &&
IntegerQ[m] && (IntegerQ[n] || IntegersQ[2*n, 2*p])

Rule 152

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[((b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/((m + 1)*(b*c - a*d)*(b*e - a*
f)), x] + Dist[1/((m + 1)*(b*c - a*d)*(b*e - a*f)), Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*Simp[(a*d*f*
g - b*(d*e + c*f)*g + b*c*e*h)*(m + 1) - (b*g - a*h)*(d*e*(n + 1) + c*f*(p + 1)) - d*f*(b*g - a*h)*(m + n + p
+ 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && LtQ[m, -1] && IntegersQ[2*m, 2*n, 2*p]

Rule 156

Int[(((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)))/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))), x_Symbol] :>
Dist[(b*g - a*h)/(b*c - a*d), Int[(e + f*x)^p/(a + b*x), x], x] - Dist[(d*g - c*h)/(b*c - a*d), Int[(e + f*x)
^p/(c + d*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, h}, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rubi steps

\begin{align*} \int \frac{e^{-2 \coth ^{-1}(a x)}}{\left (c-\frac{c}{a x}\right )^{9/2}} \, dx &=-\int \frac{e^{-2 \tanh ^{-1}(a x)}}{\left (c-\frac{c}{a x}\right )^{9/2}} \, dx\\ &=-\int \frac{1-a x}{\left (c-\frac{c}{a x}\right )^{9/2} (1+a x)} \, dx\\ &=\frac{a \int \frac{x}{\left (c-\frac{c}{a x}\right )^{7/2} (1+a x)} \, dx}{c}\\ &=\frac{a \int \frac{1}{\left (a+\frac{1}{x}\right ) \left (c-\frac{c}{a x}\right )^{7/2}} \, dx}{c}\\ &=-\frac{a \operatorname{Subst}\left (\int \frac{1}{x^2 (a+x) \left (c-\frac{c x}{a}\right )^{7/2}} \, dx,x,\frac{1}{x}\right )}{c}\\ &=\frac{x}{c^2 \left (c-\frac{c}{a x}\right )^{5/2}}+\frac{\operatorname{Subst}\left (\int \frac{-\frac{5 c}{2}-\frac{7 c x}{2 a}}{x (a+x) \left (c-\frac{c x}{a}\right )^{7/2}} \, dx,x,\frac{1}{x}\right )}{c^2}\\ &=-\frac{6}{5 a c^2 \left (c-\frac{c}{a x}\right )^{5/2}}+\frac{x}{c^2 \left (c-\frac{c}{a x}\right )^{5/2}}-\frac{\operatorname{Subst}\left (\int \frac{\frac{25 c^2}{2}+\frac{15 c^2 x}{a}}{x (a+x) \left (c-\frac{c x}{a}\right )^{5/2}} \, dx,x,\frac{1}{x}\right )}{5 c^4}\\ &=-\frac{6}{5 a c^2 \left (c-\frac{c}{a x}\right )^{5/2}}-\frac{11}{6 a c^3 \left (c-\frac{c}{a x}\right )^{3/2}}+\frac{x}{c^2 \left (c-\frac{c}{a x}\right )^{5/2}}+\frac{\operatorname{Subst}\left (\int \frac{-\frac{75 c^3}{2}-\frac{165 c^3 x}{4 a}}{x (a+x) \left (c-\frac{c x}{a}\right )^{3/2}} \, dx,x,\frac{1}{x}\right )}{15 c^6}\\ &=-\frac{6}{5 a c^2 \left (c-\frac{c}{a x}\right )^{5/2}}-\frac{11}{6 a c^3 \left (c-\frac{c}{a x}\right )^{3/2}}-\frac{21}{4 a c^4 \sqrt{c-\frac{c}{a x}}}+\frac{x}{c^2 \left (c-\frac{c}{a x}\right )^{5/2}}-\frac{\operatorname{Subst}\left (\int \frac{\frac{75 c^4}{2}+\frac{315 c^4 x}{8 a}}{x (a+x) \sqrt{c-\frac{c x}{a}}} \, dx,x,\frac{1}{x}\right )}{15 c^8}\\ &=-\frac{6}{5 a c^2 \left (c-\frac{c}{a x}\right )^{5/2}}-\frac{11}{6 a c^3 \left (c-\frac{c}{a x}\right )^{3/2}}-\frac{21}{4 a c^4 \sqrt{c-\frac{c}{a x}}}+\frac{x}{c^2 \left (c-\frac{c}{a x}\right )^{5/2}}-\frac{\operatorname{Subst}\left (\int \frac{1}{(a+x) \sqrt{c-\frac{c x}{a}}} \, dx,x,\frac{1}{x}\right )}{8 a c^4}-\frac{5 \operatorname{Subst}\left (\int \frac{1}{x \sqrt{c-\frac{c x}{a}}} \, dx,x,\frac{1}{x}\right )}{2 a c^4}\\ &=-\frac{6}{5 a c^2 \left (c-\frac{c}{a x}\right )^{5/2}}-\frac{11}{6 a c^3 \left (c-\frac{c}{a x}\right )^{3/2}}-\frac{21}{4 a c^4 \sqrt{c-\frac{c}{a x}}}+\frac{x}{c^2 \left (c-\frac{c}{a x}\right )^{5/2}}+\frac{\operatorname{Subst}\left (\int \frac{1}{2 a-\frac{a x^2}{c}} \, dx,x,\sqrt{c-\frac{c}{a x}}\right )}{4 c^5}+\frac{5 \operatorname{Subst}\left (\int \frac{1}{a-\frac{a x^2}{c}} \, dx,x,\sqrt{c-\frac{c}{a x}}\right )}{c^5}\\ &=-\frac{6}{5 a c^2 \left (c-\frac{c}{a x}\right )^{5/2}}-\frac{11}{6 a c^3 \left (c-\frac{c}{a x}\right )^{3/2}}-\frac{21}{4 a c^4 \sqrt{c-\frac{c}{a x}}}+\frac{x}{c^2 \left (c-\frac{c}{a x}\right )^{5/2}}+\frac{5 \tanh ^{-1}\left (\frac{\sqrt{c-\frac{c}{a x}}}{\sqrt{c}}\right )}{a c^{9/2}}+\frac{\tanh ^{-1}\left (\frac{\sqrt{c-\frac{c}{a x}}}{\sqrt{2} \sqrt{c}}\right )}{4 \sqrt{2} a c^{9/2}}\\ \end{align*}

Mathematica [C]  time = 0.0649847, size = 82, normalized size = 0.48 $\frac{a x^2 \left (-\text{Hypergeometric2F1}\left (-\frac{5}{2},1,-\frac{3}{2},\frac{a-\frac{1}{x}}{2 a}\right )-5 \text{Hypergeometric2F1}\left (-\frac{5}{2},1,-\frac{3}{2},1-\frac{1}{a x}\right )+5 a x\right )}{5 c^4 (a x-1)^2 \sqrt{c-\frac{c}{a x}}}$

Warning: Unable to verify antiderivative.

[In]

Integrate[1/(E^(2*ArcCoth[a*x])*(c - c/(a*x))^(9/2)),x]

[Out]

(a*x^2*(5*a*x - Hypergeometric2F1[-5/2, 1, -3/2, (a - x^(-1))/(2*a)] - 5*Hypergeometric2F1[-5/2, 1, -3/2, 1 -
1/(a*x)]))/(5*c^4*Sqrt[c - c/(a*x)]*(-1 + a*x)^2)

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Maple [B]  time = 0.174, size = 626, normalized size = 3.6 \begin{align*} \text{result too large to display} \end{align*}

Veriﬁcation of antiderivative is not currently implemented for this CAS.

[In]

int(1/(a*x+1)*(a*x-1)/(c-c/a/x)^(9/2),x)

[Out]

-1/240*(c*(a*x-1)/a/x)^(1/2)*x/a^(3/2)*(-1260*((a*x-1)*x)^(1/2)*a^(11/2)*(1/a)^(1/2)*x^4+1020*((a*x-1)*x)^(3/2
)*a^(9/2)*(1/a)^(1/2)*x^2-600*ln(1/2*(2*((a*x-1)*x)^(1/2)*a^(1/2)+2*a*x-1)/a^(1/2))*(1/a)^(1/2)*x^4*a^5+15*a^(
9/2)*2^(1/2)*ln((2*2^(1/2)*(1/a)^(1/2)*((a*x-1)*x)^(1/2)*a-3*a*x+1)/(a*x+1))*x^4+5040*a^(9/2)*(1/a)^(1/2)*((a*
x-1)*x)^(1/2)*x^3-1792*a^(7/2)*(1/a)^(1/2)*((a*x-1)*x)^(3/2)*x+2400*ln(1/2*(2*((a*x-1)*x)^(1/2)*a^(1/2)+2*a*x-
1)/a^(1/2))*(1/a)^(1/2)*x^3*a^4-60*a^(7/2)*2^(1/2)*ln((2*2^(1/2)*(1/a)^(1/2)*((a*x-1)*x)^(1/2)*a-3*a*x+1)/(a*x
+1))*x^3-7560*a^(7/2)*(1/a)^(1/2)*((a*x-1)*x)^(1/2)*x^2+820*a^(5/2)*(1/a)^(1/2)*((a*x-1)*x)^(3/2)-3600*ln(1/2*
(2*((a*x-1)*x)^(1/2)*a^(1/2)+2*a*x-1)/a^(1/2))*(1/a)^(1/2)*x^2*a^3+90*ln((2*2^(1/2)*(1/a)^(1/2)*((a*x-1)*x)^(1
/2)*a-3*a*x+1)/(a*x+1))*a^(5/2)*2^(1/2)*x^2+5040*a^(5/2)*(1/a)^(1/2)*((a*x-1)*x)^(1/2)*x+2400*ln(1/2*(2*((a*x-
1)*x)^(1/2)*a^(1/2)+2*a*x-1)/a^(1/2))*(1/a)^(1/2)*x*a^2-60*ln((2*2^(1/2)*(1/a)^(1/2)*((a*x-1)*x)^(1/2)*a-3*a*x
+1)/(a*x+1))*a^(3/2)*2^(1/2)*x-1260*((a*x-1)*x)^(1/2)*a^(3/2)*(1/a)^(1/2)-600*ln(1/2*(2*((a*x-1)*x)^(1/2)*a^(1
/2)+2*a*x-1)/a^(1/2))*a*(1/a)^(1/2)+15*2^(1/2)*ln((2*2^(1/2)*(1/a)^(1/2)*((a*x-1)*x)^(1/2)*a-3*a*x+1)/(a*x+1))
*a^(1/2))/((a*x-1)*x)^(1/2)/c^5/(a*x-1)^4/(1/a)^(1/2)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{a x - 1}{{\left (a x + 1\right )}{\left (c - \frac{c}{a x}\right )}^{\frac{9}{2}}}\,{d x} \end{align*}

Veriﬁcation of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x-1)/(a*x+1)/(c-c/a/x)^(9/2),x, algorithm="maxima")

[Out]

integrate((a*x - 1)/((a*x + 1)*(c - c/(a*x))^(9/2)), x)

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Fricas [A]  time = 2.00998, size = 976, normalized size = 5.67 \begin{align*} \left [\frac{15 \, \sqrt{2}{\left (a^{3} x^{3} - 3 \, a^{2} x^{2} + 3 \, a x - 1\right )} \sqrt{c} \log \left (-\frac{2 \, \sqrt{2} a \sqrt{c} x \sqrt{\frac{a c x - c}{a x}} + 3 \, a c x - c}{a x + 1}\right ) + 600 \,{\left (a^{3} x^{3} - 3 \, a^{2} x^{2} + 3 \, a x - 1\right )} \sqrt{c} \log \left (-2 \, a c x - 2 \, a \sqrt{c} x \sqrt{\frac{a c x - c}{a x}} + c\right ) + 4 \,{\left (60 \, a^{4} x^{4} - 497 \, a^{3} x^{3} + 740 \, a^{2} x^{2} - 315 \, a x\right )} \sqrt{\frac{a c x - c}{a x}}}{240 \,{\left (a^{4} c^{5} x^{3} - 3 \, a^{3} c^{5} x^{2} + 3 \, a^{2} c^{5} x - a c^{5}\right )}}, -\frac{15 \, \sqrt{2}{\left (a^{3} x^{3} - 3 \, a^{2} x^{2} + 3 \, a x - 1\right )} \sqrt{-c} \arctan \left (\frac{\sqrt{2} \sqrt{-c} \sqrt{\frac{a c x - c}{a x}}}{2 \, c}\right ) + 600 \,{\left (a^{3} x^{3} - 3 \, a^{2} x^{2} + 3 \, a x - 1\right )} \sqrt{-c} \arctan \left (\frac{\sqrt{-c} \sqrt{\frac{a c x - c}{a x}}}{c}\right ) - 2 \,{\left (60 \, a^{4} x^{4} - 497 \, a^{3} x^{3} + 740 \, a^{2} x^{2} - 315 \, a x\right )} \sqrt{\frac{a c x - c}{a x}}}{120 \,{\left (a^{4} c^{5} x^{3} - 3 \, a^{3} c^{5} x^{2} + 3 \, a^{2} c^{5} x - a c^{5}\right )}}\right ] \end{align*}

Veriﬁcation of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x-1)/(a*x+1)/(c-c/a/x)^(9/2),x, algorithm="fricas")

[Out]

[1/240*(15*sqrt(2)*(a^3*x^3 - 3*a^2*x^2 + 3*a*x - 1)*sqrt(c)*log(-(2*sqrt(2)*a*sqrt(c)*x*sqrt((a*c*x - c)/(a*x
)) + 3*a*c*x - c)/(a*x + 1)) + 600*(a^3*x^3 - 3*a^2*x^2 + 3*a*x - 1)*sqrt(c)*log(-2*a*c*x - 2*a*sqrt(c)*x*sqrt
((a*c*x - c)/(a*x)) + c) + 4*(60*a^4*x^4 - 497*a^3*x^3 + 740*a^2*x^2 - 315*a*x)*sqrt((a*c*x - c)/(a*x)))/(a^4*
c^5*x^3 - 3*a^3*c^5*x^2 + 3*a^2*c^5*x - a*c^5), -1/120*(15*sqrt(2)*(a^3*x^3 - 3*a^2*x^2 + 3*a*x - 1)*sqrt(-c)*
arctan(1/2*sqrt(2)*sqrt(-c)*sqrt((a*c*x - c)/(a*x))/c) + 600*(a^3*x^3 - 3*a^2*x^2 + 3*a*x - 1)*sqrt(-c)*arctan
(sqrt(-c)*sqrt((a*c*x - c)/(a*x))/c) - 2*(60*a^4*x^4 - 497*a^3*x^3 + 740*a^2*x^2 - 315*a*x)*sqrt((a*c*x - c)/(
a*x)))/(a^4*c^5*x^3 - 3*a^3*c^5*x^2 + 3*a^2*c^5*x - a*c^5)]

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Veriﬁcation of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x-1)/(a*x+1)/(c-c/a/x)**(9/2),x)

[Out]

Timed out

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Giac [A]  time = 1.34761, size = 279, normalized size = 1.62 \begin{align*} -\frac{1}{120} \, a c{\left (\frac{2 \,{\left (12 \, c^{2} + \frac{50 \,{\left (a c x - c\right )} c}{a x} + \frac{255 \,{\left (a c x - c\right )}^{2}}{a^{2} x^{2}}\right )} x^{2}}{{\left (a c x - c\right )}^{2} c^{5} \sqrt{\frac{a c x - c}{a x}}} + \frac{15 \, \sqrt{2} \arctan \left (\frac{\sqrt{2} \sqrt{\frac{a c x - c}{a x}}}{2 \, \sqrt{-c}}\right )}{a^{2} \sqrt{-c} c^{5}} + \frac{600 \, \arctan \left (\frac{\sqrt{\frac{a c x - c}{a x}}}{\sqrt{-c}}\right )}{a^{2} \sqrt{-c} c^{5}} - \frac{120 \, \sqrt{\frac{a c x - c}{a x}}}{a^{2}{\left (c - \frac{a c x - c}{a x}\right )} c^{5}}\right )} \end{align*}

Veriﬁcation of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x-1)/(a*x+1)/(c-c/a/x)^(9/2),x, algorithm="giac")

[Out]

-1/120*a*c*(2*(12*c^2 + 50*(a*c*x - c)*c/(a*x) + 255*(a*c*x - c)^2/(a^2*x^2))*x^2/((a*c*x - c)^2*c^5*sqrt((a*c
*x - c)/(a*x))) + 15*sqrt(2)*arctan(1/2*sqrt(2)*sqrt((a*c*x - c)/(a*x))/sqrt(-c))/(a^2*sqrt(-c)*c^5) + 600*arc
tan(sqrt((a*c*x - c)/(a*x))/sqrt(-c))/(a^2*sqrt(-c)*c^5) - 120*sqrt((a*c*x - c)/(a*x))/(a^2*(c - (a*c*x - c)/(
a*x))*c^5))