Optimal. Leaf size=176 \[ -\frac{25 \sqrt [4]{1-\frac{1}{a x}}}{2 a^2 \sqrt [4]{\frac{1}{a x}+1}}-\frac{25 \tan ^{-1}\left (\frac{\sqrt [4]{\frac{1}{a x}+1}}{\sqrt [4]{1-\frac{1}{a x}}}\right )}{4 a^2}+\frac{25 \tanh ^{-1}\left (\frac{\sqrt [4]{\frac{1}{a x}+1}}{\sqrt [4]{1-\frac{1}{a x}}}\right )}{4 a^2}+\frac{x^2 \left (1-\frac{1}{a x}\right )^{9/4}}{2 \sqrt [4]{\frac{1}{a x}+1}}-\frac{5 x \left (1-\frac{1}{a x}\right )^{5/4}}{4 a \sqrt [4]{\frac{1}{a x}+1}} \]
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Rubi [A] time = 0.0714863, antiderivative size = 176, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.583, Rules used = {6171, 96, 94, 93, 298, 203, 206} \[ -\frac{25 \sqrt [4]{1-\frac{1}{a x}}}{2 a^2 \sqrt [4]{\frac{1}{a x}+1}}-\frac{25 \tan ^{-1}\left (\frac{\sqrt [4]{\frac{1}{a x}+1}}{\sqrt [4]{1-\frac{1}{a x}}}\right )}{4 a^2}+\frac{25 \tanh ^{-1}\left (\frac{\sqrt [4]{\frac{1}{a x}+1}}{\sqrt [4]{1-\frac{1}{a x}}}\right )}{4 a^2}+\frac{x^2 \left (1-\frac{1}{a x}\right )^{9/4}}{2 \sqrt [4]{\frac{1}{a x}+1}}-\frac{5 x \left (1-\frac{1}{a x}\right )^{5/4}}{4 a \sqrt [4]{\frac{1}{a x}+1}} \]
Antiderivative was successfully verified.
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Rule 6171
Rule 96
Rule 94
Rule 93
Rule 298
Rule 203
Rule 206
Rubi steps
\begin{align*} \int e^{-\frac{5}{2} \coth ^{-1}(a x)} x \, dx &=-\operatorname{Subst}\left (\int \frac{\left (1-\frac{x}{a}\right )^{5/4}}{x^3 \left (1+\frac{x}{a}\right )^{5/4}} \, dx,x,\frac{1}{x}\right )\\ &=\frac{\left (1-\frac{1}{a x}\right )^{9/4} x^2}{2 \sqrt [4]{1+\frac{1}{a x}}}+\frac{5 \operatorname{Subst}\left (\int \frac{\left (1-\frac{x}{a}\right )^{5/4}}{x^2 \left (1+\frac{x}{a}\right )^{5/4}} \, dx,x,\frac{1}{x}\right )}{4 a}\\ &=-\frac{5 \left (1-\frac{1}{a x}\right )^{5/4} x}{4 a \sqrt [4]{1+\frac{1}{a x}}}+\frac{\left (1-\frac{1}{a x}\right )^{9/4} x^2}{2 \sqrt [4]{1+\frac{1}{a x}}}-\frac{25 \operatorname{Subst}\left (\int \frac{\sqrt [4]{1-\frac{x}{a}}}{x \left (1+\frac{x}{a}\right )^{5/4}} \, dx,x,\frac{1}{x}\right )}{8 a^2}\\ &=-\frac{25 \sqrt [4]{1-\frac{1}{a x}}}{2 a^2 \sqrt [4]{1+\frac{1}{a x}}}-\frac{5 \left (1-\frac{1}{a x}\right )^{5/4} x}{4 a \sqrt [4]{1+\frac{1}{a x}}}+\frac{\left (1-\frac{1}{a x}\right )^{9/4} x^2}{2 \sqrt [4]{1+\frac{1}{a x}}}-\frac{25 \operatorname{Subst}\left (\int \frac{1}{x \left (1-\frac{x}{a}\right )^{3/4} \sqrt [4]{1+\frac{x}{a}}} \, dx,x,\frac{1}{x}\right )}{8 a^2}\\ &=-\frac{25 \sqrt [4]{1-\frac{1}{a x}}}{2 a^2 \sqrt [4]{1+\frac{1}{a x}}}-\frac{5 \left (1-\frac{1}{a x}\right )^{5/4} x}{4 a \sqrt [4]{1+\frac{1}{a x}}}+\frac{\left (1-\frac{1}{a x}\right )^{9/4} x^2}{2 \sqrt [4]{1+\frac{1}{a x}}}-\frac{25 \operatorname{Subst}\left (\int \frac{x^2}{-1+x^4} \, dx,x,\frac{\sqrt [4]{1+\frac{1}{a x}}}{\sqrt [4]{1-\frac{1}{a x}}}\right )}{2 a^2}\\ &=-\frac{25 \sqrt [4]{1-\frac{1}{a x}}}{2 a^2 \sqrt [4]{1+\frac{1}{a x}}}-\frac{5 \left (1-\frac{1}{a x}\right )^{5/4} x}{4 a \sqrt [4]{1+\frac{1}{a x}}}+\frac{\left (1-\frac{1}{a x}\right )^{9/4} x^2}{2 \sqrt [4]{1+\frac{1}{a x}}}+\frac{25 \operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,\frac{\sqrt [4]{1+\frac{1}{a x}}}{\sqrt [4]{1-\frac{1}{a x}}}\right )}{4 a^2}-\frac{25 \operatorname{Subst}\left (\int \frac{1}{1+x^2} \, dx,x,\frac{\sqrt [4]{1+\frac{1}{a x}}}{\sqrt [4]{1-\frac{1}{a x}}}\right )}{4 a^2}\\ &=-\frac{25 \sqrt [4]{1-\frac{1}{a x}}}{2 a^2 \sqrt [4]{1+\frac{1}{a x}}}-\frac{5 \left (1-\frac{1}{a x}\right )^{5/4} x}{4 a \sqrt [4]{1+\frac{1}{a x}}}+\frac{\left (1-\frac{1}{a x}\right )^{9/4} x^2}{2 \sqrt [4]{1+\frac{1}{a x}}}-\frac{25 \tan ^{-1}\left (\frac{\sqrt [4]{1+\frac{1}{a x}}}{\sqrt [4]{1-\frac{1}{a x}}}\right )}{4 a^2}+\frac{25 \tanh ^{-1}\left (\frac{\sqrt [4]{1+\frac{1}{a x}}}{\sqrt [4]{1-\frac{1}{a x}}}\right )}{4 a^2}\\ \end{align*}
Mathematica [A] time = 0.241956, size = 121, normalized size = 0.69 \[ -\frac{e^{-\frac{1}{2} \coth ^{-1}(a x)} \left (-90 e^{2 \coth ^{-1}(a x)}+50 e^{4 \coth ^{-1}(a x)}+25 e^{\frac{1}{2} \coth ^{-1}(a x)} \left (e^{2 \coth ^{-1}(a x)}-1\right )^2 \tan ^{-1}\left (e^{\frac{1}{2} \coth ^{-1}(a x)}\right )-25 e^{\frac{1}{2} \coth ^{-1}(a x)} \left (e^{2 \coth ^{-1}(a x)}-1\right )^2 \tanh ^{-1}\left (e^{\frac{1}{2} \coth ^{-1}(a x)}\right )+32\right )}{4 a^2 \left (e^{2 \coth ^{-1}(a x)}-1\right )^2} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.329, size = 0, normalized size = 0. \begin{align*} \int x \left ({\frac{ax-1}{ax+1}} \right ) ^{{\frac{5}{4}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.60295, size = 232, normalized size = 1.32 \begin{align*} -\frac{1}{8} \, a{\left (\frac{4 \,{\left (13 \, \left (\frac{a x - 1}{a x + 1}\right )^{\frac{5}{4}} - 9 \, \left (\frac{a x - 1}{a x + 1}\right )^{\frac{1}{4}}\right )}}{\frac{2 \,{\left (a x - 1\right )} a^{3}}{a x + 1} - \frac{{\left (a x - 1\right )}^{2} a^{3}}{{\left (a x + 1\right )}^{2}} - a^{3}} - \frac{50 \, \arctan \left (\left (\frac{a x - 1}{a x + 1}\right )^{\frac{1}{4}}\right )}{a^{3}} - \frac{25 \, \log \left (\left (\frac{a x - 1}{a x + 1}\right )^{\frac{1}{4}} + 1\right )}{a^{3}} + \frac{25 \, \log \left (\left (\frac{a x - 1}{a x + 1}\right )^{\frac{1}{4}} - 1\right )}{a^{3}} + \frac{64 \, \left (\frac{a x - 1}{a x + 1}\right )^{\frac{1}{4}}}{a^{3}}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.65404, size = 258, normalized size = 1.47 \begin{align*} \frac{2 \,{\left (2 \, a^{2} x^{2} - 9 \, a x - 43\right )} \left (\frac{a x - 1}{a x + 1}\right )^{\frac{1}{4}} + 50 \, \arctan \left (\left (\frac{a x - 1}{a x + 1}\right )^{\frac{1}{4}}\right ) + 25 \, \log \left (\left (\frac{a x - 1}{a x + 1}\right )^{\frac{1}{4}} + 1\right ) - 25 \, \log \left (\left (\frac{a x - 1}{a x + 1}\right )^{\frac{1}{4}} - 1\right )}{8 \, a^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.16659, size = 217, normalized size = 1.23 \begin{align*} \frac{1}{8} \, a{\left (\frac{50 \, \arctan \left (\left (\frac{a x - 1}{a x + 1}\right )^{\frac{1}{4}}\right )}{a^{3}} + \frac{25 \, \log \left (\left (\frac{a x - 1}{a x + 1}\right )^{\frac{1}{4}} + 1\right )}{a^{3}} - \frac{25 \, \log \left ({\left | \left (\frac{a x - 1}{a x + 1}\right )^{\frac{1}{4}} - 1 \right |}\right )}{a^{3}} - \frac{64 \, \left (\frac{a x - 1}{a x + 1}\right )^{\frac{1}{4}}}{a^{3}} + \frac{4 \,{\left (\frac{13 \,{\left (a x - 1\right )} \left (\frac{a x - 1}{a x + 1}\right )^{\frac{1}{4}}}{a x + 1} - 9 \, \left (\frac{a x - 1}{a x + 1}\right )^{\frac{1}{4}}\right )}}{a^{3}{\left (\frac{a x - 1}{a x + 1} - 1\right )}^{2}}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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