Optimal. Leaf size=95 \[ -\frac{d e^{c+d x} \cosh ^2(a+b x)}{4 b^2-d^2}+\frac{2 b e^{c+d x} \sinh (a+b x) \cosh (a+b x)}{4 b^2-d^2}+\frac{2 b^2 e^{c+d x}}{d \left (4 b^2-d^2\right )} \]
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Rubi [A] time = 0.0359479, antiderivative size = 95, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.125, Rules used = {5477, 2194} \[ -\frac{d e^{c+d x} \cosh ^2(a+b x)}{4 b^2-d^2}+\frac{2 b e^{c+d x} \sinh (a+b x) \cosh (a+b x)}{4 b^2-d^2}+\frac{2 b^2 e^{c+d x}}{d \left (4 b^2-d^2\right )} \]
Antiderivative was successfully verified.
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Rule 5477
Rule 2194
Rubi steps
\begin{align*} \int e^{c+d x} \cosh ^2(a+b x) \, dx &=-\frac{d e^{c+d x} \cosh ^2(a+b x)}{4 b^2-d^2}+\frac{2 b e^{c+d x} \cosh (a+b x) \sinh (a+b x)}{4 b^2-d^2}+\frac{\left (2 b^2\right ) \int e^{c+d x} \, dx}{4 b^2-d^2}\\ &=\frac{2 b^2 e^{c+d x}}{d \left (4 b^2-d^2\right )}-\frac{d e^{c+d x} \cosh ^2(a+b x)}{4 b^2-d^2}+\frac{2 b e^{c+d x} \cosh (a+b x) \sinh (a+b x)}{4 b^2-d^2}\\ \end{align*}
Mathematica [A] time = 0.141704, size = 55, normalized size = 0.58 \[ \frac{e^{c+d x} \left (d^2 \cosh (2 (a+b x))-2 b d \sinh (2 (a+b x))-4 b^2+d^2\right )}{2 d^3-8 b^2 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.007, size = 124, normalized size = 1.3 \begin{align*}{\frac{\sinh \left ( dx+c \right ) }{2\,d}}+{\frac{\sinh \left ( 2\,a-c+ \left ( 2\,b-d \right ) x \right ) }{8\,b-4\,d}}+{\frac{\sinh \left ( 2\,a+c+ \left ( 2\,b+d \right ) x \right ) }{8\,b+4\,d}}+{\frac{\cosh \left ( dx+c \right ) }{2\,d}}-{\frac{\cosh \left ( 2\,a-c+ \left ( 2\,b-d \right ) x \right ) }{8\,b-4\,d}}+{\frac{\cosh \left ( 2\,a+c+ \left ( 2\,b+d \right ) x \right ) }{8\,b+4\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.0804, size = 433, normalized size = 4.56 \begin{align*} \frac{4 \, b d \cosh \left (b x + a\right ) \cosh \left (d x + c\right ) \sinh \left (b x + a\right ) - d^{2} \cosh \left (d x + c\right ) \sinh \left (b x + a\right )^{2} -{\left (d^{2} \cosh \left (b x + a\right )^{2} - 4 \, b^{2} + d^{2}\right )} \cosh \left (d x + c\right ) -{\left (d^{2} \cosh \left (b x + a\right )^{2} - 4 \, b d \cosh \left (b x + a\right ) \sinh \left (b x + a\right ) + d^{2} \sinh \left (b x + a\right )^{2} - 4 \, b^{2} + d^{2}\right )} \sinh \left (d x + c\right )}{2 \,{\left ({\left (4 \, b^{2} d - d^{3}\right )} \cosh \left (b x + a\right )^{2} -{\left (4 \, b^{2} d - d^{3}\right )} \sinh \left (b x + a\right )^{2}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 16.198, size = 456, normalized size = 4.8 \begin{align*} \begin{cases} x e^{c} \cosh ^{2}{\left (a \right )} & \text{for}\: b = 0 \wedge d = 0 \\\frac{x e^{c} e^{d x} \sinh ^{2}{\left (a - \frac{d x}{2} \right )}}{4} + \frac{x e^{c} e^{d x} \sinh{\left (a - \frac{d x}{2} \right )} \cosh{\left (a - \frac{d x}{2} \right )}}{2} + \frac{x e^{c} e^{d x} \cosh ^{2}{\left (a - \frac{d x}{2} \right )}}{4} + \frac{e^{c} e^{d x} \sinh{\left (a - \frac{d x}{2} \right )} \cosh{\left (a - \frac{d x}{2} \right )}}{2 d} + \frac{e^{c} e^{d x} \cosh ^{2}{\left (a - \frac{d x}{2} \right )}}{d} & \text{for}\: b = - \frac{d}{2} \\\frac{x e^{c} e^{d x} \sinh ^{2}{\left (a + \frac{d x}{2} \right )}}{4} - \frac{x e^{c} e^{d x} \sinh{\left (a + \frac{d x}{2} \right )} \cosh{\left (a + \frac{d x}{2} \right )}}{2} + \frac{x e^{c} e^{d x} \cosh ^{2}{\left (a + \frac{d x}{2} \right )}}{4} - \frac{3 e^{c} e^{d x} \sinh ^{2}{\left (a + \frac{d x}{2} \right )}}{4 d} + \frac{e^{c} e^{d x} \sinh{\left (a + \frac{d x}{2} \right )} \cosh{\left (a + \frac{d x}{2} \right )}}{d} + \frac{e^{c} e^{d x} \cosh ^{2}{\left (a + \frac{d x}{2} \right )}}{4 d} & \text{for}\: b = \frac{d}{2} \\\left (- \frac{x \sinh ^{2}{\left (a + b x \right )}}{2} + \frac{x \cosh ^{2}{\left (a + b x \right )}}{2} + \frac{\sinh{\left (a + b x \right )} \cosh{\left (a + b x \right )}}{2 b}\right ) e^{c} & \text{for}\: d = 0 \\- \frac{2 b^{2} e^{c} e^{d x} \sinh ^{2}{\left (a + b x \right )}}{4 b^{2} d - d^{3}} + \frac{2 b^{2} e^{c} e^{d x} \cosh ^{2}{\left (a + b x \right )}}{4 b^{2} d - d^{3}} + \frac{2 b d e^{c} e^{d x} \sinh{\left (a + b x \right )} \cosh{\left (a + b x \right )}}{4 b^{2} d - d^{3}} - \frac{d^{2} e^{c} e^{d x} \cosh ^{2}{\left (a + b x \right )}}{4 b^{2} d - d^{3}} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.17611, size = 78, normalized size = 0.82 \begin{align*} \frac{e^{\left (2 \, b x + d x + 2 \, a + c\right )}}{4 \,{\left (2 \, b + d\right )}} - \frac{e^{\left (-2 \, b x + d x - 2 \, a + c\right )}}{4 \,{\left (2 \, b - d\right )}} + \frac{e^{\left (d x + c\right )}}{2 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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