Optimal. Leaf size=54 \[ \frac{b e^{a+b x} \sinh (c+d x)}{b^2-d^2}-\frac{d e^{a+b x} \cosh (c+d x)}{b^2-d^2} \]
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Rubi [A] time = 0.0186246, antiderivative size = 54, normalized size of antiderivative = 1., number of steps used = 1, number of rules used = 1, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.071, Rules used = {5474} \[ \frac{b e^{a+b x} \sinh (c+d x)}{b^2-d^2}-\frac{d e^{a+b x} \cosh (c+d x)}{b^2-d^2} \]
Antiderivative was successfully verified.
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Rule 5474
Rubi steps
\begin{align*} \int e^{a+b x} \sinh (c+d x) \, dx &=-\frac{d e^{a+b x} \cosh (c+d x)}{b^2-d^2}+\frac{b e^{a+b x} \sinh (c+d x)}{b^2-d^2}\\ \end{align*}
Mathematica [A] time = 0.0694216, size = 38, normalized size = 0.7 \[ \frac{e^{a+b x} (b \sinh (c+d x)-d \cosh (c+d x))}{(b-d) (b+d)} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.004, size = 78, normalized size = 1.4 \begin{align*} -{\frac{\sinh \left ( a-c+ \left ( b-d \right ) x \right ) }{2\,b-2\,d}}+{\frac{\sinh \left ( a+c+ \left ( b+d \right ) x \right ) }{2\,b+2\,d}}-{\frac{\cosh \left ( a-c+ \left ( b-d \right ) x \right ) }{2\,b-2\,d}}+{\frac{\cosh \left ( a+c+ \left ( b+d \right ) x \right ) }{2\,b+2\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.51805, size = 176, normalized size = 3.26 \begin{align*} -\frac{d \cosh \left (b x + a\right ) \cosh \left (d x + c\right ) + d \cosh \left (d x + c\right ) \sinh \left (b x + a\right ) -{\left (b \cosh \left (b x + a\right ) + b \sinh \left (b x + a\right )\right )} \sinh \left (d x + c\right )}{b^{2} - d^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 3.03425, size = 167, normalized size = 3.09 \begin{align*} \begin{cases} x e^{a} \sinh{\left (c \right )} & \text{for}\: b = 0 \wedge d = 0 \\\frac{x e^{a} e^{- d x} \sinh{\left (c + d x \right )}}{2} + \frac{x e^{a} e^{- d x} \cosh{\left (c + d x \right )}}{2} + \frac{e^{a} e^{- d x} \cosh{\left (c + d x \right )}}{2 d} & \text{for}\: b = - d \\\frac{x e^{a} e^{d x} \sinh{\left (c + d x \right )}}{2} - \frac{x e^{a} e^{d x} \cosh{\left (c + d x \right )}}{2} + \frac{e^{a} e^{d x} \cosh{\left (c + d x \right )}}{2 d} & \text{for}\: b = d \\\frac{b e^{a} e^{b x} \sinh{\left (c + d x \right )}}{b^{2} - d^{2}} - \frac{d e^{a} e^{b x} \cosh{\left (c + d x \right )}}{b^{2} - d^{2}} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.2214, size = 54, normalized size = 1. \begin{align*} \frac{e^{\left (b x + d x + a + c\right )}}{2 \,{\left (b + d\right )}} - \frac{e^{\left (b x - d x + a - c\right )}}{2 \,{\left (b - d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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