Optimal. Leaf size=325 \[ -\frac{32 \sqrt{2} a b \cosh (2 c+2 d x)}{3 d \left (4 a^2+b^2\right )^2 \sqrt{2 a+b \sinh (2 c+2 d x)}}-\frac{4 \sqrt{2} b \cosh (2 c+2 d x)}{3 d \left (4 a^2+b^2\right ) (2 a+b \sinh (2 c+2 d x))^{3/2}}+\frac{4 i \sqrt{2} \sqrt{\frac{2 a+b \sinh (2 c+2 d x)}{2 a-i b}} F\left (\frac{1}{2} \left (2 i c+2 i d x-\frac{\pi }{2}\right )|\frac{2 b}{2 i a+b}\right )}{3 d \left (4 a^2+b^2\right ) \sqrt{2 a+b \sinh (2 c+2 d x)}}-\frac{32 i \sqrt{2} a \sqrt{2 a+b \sinh (2 c+2 d x)} E\left (\frac{1}{2} \left (2 i c+2 i d x-\frac{\pi }{2}\right )|\frac{2 b}{2 i a+b}\right )}{3 d \left (4 a^2+b^2\right )^2 \sqrt{\frac{2 a+b \sinh (2 c+2 d x)}{2 a-i b}}} \]
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Rubi [A] time = 0.38078, antiderivative size = 325, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 8, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.4, Rules used = {2666, 2664, 2754, 2752, 2663, 2661, 2655, 2653} \[ -\frac{32 \sqrt{2} a b \cosh (2 c+2 d x)}{3 d \left (4 a^2+b^2\right )^2 \sqrt{2 a+b \sinh (2 c+2 d x)}}-\frac{4 \sqrt{2} b \cosh (2 c+2 d x)}{3 d \left (4 a^2+b^2\right ) (2 a+b \sinh (2 c+2 d x))^{3/2}}+\frac{4 i \sqrt{2} \sqrt{\frac{2 a+b \sinh (2 c+2 d x)}{2 a-i b}} F\left (\frac{1}{2} \left (2 i c+2 i d x-\frac{\pi }{2}\right )|\frac{2 b}{2 i a+b}\right )}{3 d \left (4 a^2+b^2\right ) \sqrt{2 a+b \sinh (2 c+2 d x)}}-\frac{32 i \sqrt{2} a \sqrt{2 a+b \sinh (2 c+2 d x)} E\left (\frac{1}{2} \left (2 i c+2 i d x-\frac{\pi }{2}\right )|\frac{2 b}{2 i a+b}\right )}{3 d \left (4 a^2+b^2\right )^2 \sqrt{\frac{2 a+b \sinh (2 c+2 d x)}{2 a-i b}}} \]
Antiderivative was successfully verified.
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Rule 2666
Rule 2664
Rule 2754
Rule 2752
Rule 2663
Rule 2661
Rule 2655
Rule 2653
Rubi steps
\begin{align*} \int \frac{1}{(a+b \cosh (c+d x) \sinh (c+d x))^{5/2}} \, dx &=\int \frac{1}{\left (a+\frac{1}{2} b \sinh (2 c+2 d x)\right )^{5/2}} \, dx\\ &=-\frac{4 \sqrt{2} b \cosh (2 c+2 d x)}{3 \left (4 a^2+b^2\right ) d (2 a+b \sinh (2 c+2 d x))^{3/2}}-\frac{8 \int \frac{-\frac{3 a}{2}+\frac{1}{4} b \sinh (2 c+2 d x)}{\left (a+\frac{1}{2} b \sinh (2 c+2 d x)\right )^{3/2}} \, dx}{3 \left (4 a^2+b^2\right )}\\ &=-\frac{4 \sqrt{2} b \cosh (2 c+2 d x)}{3 \left (4 a^2+b^2\right ) d (2 a+b \sinh (2 c+2 d x))^{3/2}}-\frac{32 \sqrt{2} a b \cosh (2 c+2 d x)}{3 \left (4 a^2+b^2\right )^2 d \sqrt{2 a+b \sinh (2 c+2 d x)}}+\frac{64 \int \frac{\frac{1}{16} \left (12 a^2-b^2\right )+\frac{1}{2} a b \sinh (2 c+2 d x)}{\sqrt{a+\frac{1}{2} b \sinh (2 c+2 d x)}} \, dx}{3 \left (4 a^2+b^2\right )^2}\\ &=-\frac{4 \sqrt{2} b \cosh (2 c+2 d x)}{3 \left (4 a^2+b^2\right ) d (2 a+b \sinh (2 c+2 d x))^{3/2}}-\frac{32 \sqrt{2} a b \cosh (2 c+2 d x)}{3 \left (4 a^2+b^2\right )^2 d \sqrt{2 a+b \sinh (2 c+2 d x)}}+\frac{(64 a) \int \sqrt{a+\frac{1}{2} b \sinh (2 c+2 d x)} \, dx}{3 \left (4 a^2+b^2\right )^2}-\frac{4 \int \frac{1}{\sqrt{a+\frac{1}{2} b \sinh (2 c+2 d x)}} \, dx}{3 \left (4 a^2+b^2\right )}\\ &=-\frac{4 \sqrt{2} b \cosh (2 c+2 d x)}{3 \left (4 a^2+b^2\right ) d (2 a+b \sinh (2 c+2 d x))^{3/2}}-\frac{32 \sqrt{2} a b \cosh (2 c+2 d x)}{3 \left (4 a^2+b^2\right )^2 d \sqrt{2 a+b \sinh (2 c+2 d x)}}+\frac{\left (64 a \sqrt{a+\frac{1}{2} b \sinh (2 c+2 d x)}\right ) \int \sqrt{\frac{a}{a-\frac{i b}{2}}+\frac{b \sinh (2 c+2 d x)}{2 \left (a-\frac{i b}{2}\right )}} \, dx}{3 \left (4 a^2+b^2\right )^2 \sqrt{\frac{a+\frac{1}{2} b \sinh (2 c+2 d x)}{a-\frac{i b}{2}}}}-\frac{\left (4 \sqrt{\frac{a+\frac{1}{2} b \sinh (2 c+2 d x)}{a-\frac{i b}{2}}}\right ) \int \frac{1}{\sqrt{\frac{a}{a-\frac{i b}{2}}+\frac{b \sinh (2 c+2 d x)}{2 \left (a-\frac{i b}{2}\right )}}} \, dx}{3 \left (4 a^2+b^2\right ) \sqrt{a+\frac{1}{2} b \sinh (2 c+2 d x)}}\\ &=-\frac{4 \sqrt{2} b \cosh (2 c+2 d x)}{3 \left (4 a^2+b^2\right ) d (2 a+b \sinh (2 c+2 d x))^{3/2}}-\frac{32 \sqrt{2} a b \cosh (2 c+2 d x)}{3 \left (4 a^2+b^2\right )^2 d \sqrt{2 a+b \sinh (2 c+2 d x)}}-\frac{32 i \sqrt{2} a E\left (\frac{1}{2} \left (2 i c-\frac{\pi }{2}+2 i d x\right )|\frac{2 b}{2 i a+b}\right ) \sqrt{2 a+b \sinh (2 c+2 d x)}}{3 \left (4 a^2+b^2\right )^2 d \sqrt{\frac{2 a+b \sinh (2 c+2 d x)}{2 a-i b}}}+\frac{4 i \sqrt{2} F\left (\frac{1}{2} \left (2 i c-\frac{\pi }{2}+2 i d x\right )|\frac{2 b}{2 i a+b}\right ) \sqrt{\frac{2 a+b \sinh (2 c+2 d x)}{2 a-i b}}}{3 \left (4 a^2+b^2\right ) d \sqrt{2 a+b \sinh (2 c+2 d x)}}\\ \end{align*}
Mathematica [A] time = 1.59987, size = 237, normalized size = 0.73 \[ \frac{4 \sqrt{2} \left (-b \cosh (2 (c+d x)) \left (20 a^2+8 a b \sinh (2 (c+d x))+b^2\right )+(b-2 i a) (2 a-i b)^2 \left (\frac{2 a+b \sinh (2 (c+d x))}{2 a-i b}\right )^{3/2} F\left (\frac{1}{4} (-4 i c-4 i d x+\pi )|-\frac{2 i b}{2 a-i b}\right )+8 i a (2 a-i b)^2 \left (\frac{2 a+b \sinh (2 (c+d x))}{2 a-i b}\right )^{3/2} E\left (\frac{1}{4} (-4 i c-4 i d x+\pi )|-\frac{2 i b}{2 a-i b}\right )\right )}{3 d \left (4 a^2+b^2\right )^2 (2 a+b \sinh (2 (c+d x)))^{3/2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.98, size = 641, normalized size = 2. \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b \cosh \left (d x + c\right ) \sinh \left (d x + c\right ) + a\right )}^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{b \cosh \left (d x + c\right ) \sinh \left (d x + c\right ) + a}}{b^{3} \cosh \left (d x + c\right )^{3} \sinh \left (d x + c\right )^{3} + 3 \, a b^{2} \cosh \left (d x + c\right )^{2} \sinh \left (d x + c\right )^{2} + 3 \, a^{2} b \cosh \left (d x + c\right ) \sinh \left (d x + c\right ) + a^{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: RuntimeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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