3.841 \(\int \frac{\cosh ^3(x)}{\cosh ^3(x)+\sinh ^3(x)} \, dx\)

Optimal. Leaf size=38 \[ \frac{x}{2}-\frac{1}{6 (\tanh (x)+1)}-\frac{2 \tan ^{-1}\left (\frac{1-2 \tanh (x)}{\sqrt{3}}\right )}{3 \sqrt{3}} \]

[Out]

x/2 - (2*ArcTan[(1 - 2*Tanh[x])/Sqrt[3]])/(3*Sqrt[3]) - 1/(6*(1 + Tanh[x]))

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Rubi [A]  time = 0.0924765, antiderivative size = 38, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {2058, 207, 618, 204} \[ \frac{x}{2}-\frac{1}{6 (\tanh (x)+1)}-\frac{2 \tan ^{-1}\left (\frac{1-2 \tanh (x)}{\sqrt{3}}\right )}{3 \sqrt{3}} \]

Antiderivative was successfully verified.

[In]

Int[Cosh[x]^3/(Cosh[x]^3 + Sinh[x]^3),x]

[Out]

x/2 - (2*ArcTan[(1 - 2*Tanh[x])/Sqrt[3]])/(3*Sqrt[3]) - 1/(6*(1 + Tanh[x]))

Rule 2058

Int[(P_)^(p_), x_Symbol] :> With[{u = Factor[P]}, Int[ExpandIntegrand[u^p, x], x] /;  !SumQ[NonfreeFactors[u,
x]]] /; PolyQ[P, x] && ILtQ[p, 0]

Rule 207

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTanh[(Rt[b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && NegQ[a/b] && (LtQ[a, 0] || GtQ[b, 0])

Rule 618

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Dist[-2, Subst[Int[1/Simp[b^2 - 4*a*c - x^2, x], x]
, x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin{align*} \int \frac{\cosh ^3(x)}{\cosh ^3(x)+\sinh ^3(x)} \, dx &=\operatorname{Subst}\left (\int \frac{1}{1-x^2+x^3-x^5} \, dx,x,\tanh (x)\right )\\ &=\operatorname{Subst}\left (\int \left (\frac{1}{6 (1+x)^2}-\frac{1}{2 \left (-1+x^2\right )}+\frac{1}{3 \left (1-x+x^2\right )}\right ) \, dx,x,\tanh (x)\right )\\ &=-\frac{1}{6 (1+\tanh (x))}+\frac{1}{3} \operatorname{Subst}\left (\int \frac{1}{1-x+x^2} \, dx,x,\tanh (x)\right )-\frac{1}{2} \operatorname{Subst}\left (\int \frac{1}{-1+x^2} \, dx,x,\tanh (x)\right )\\ &=\frac{x}{2}-\frac{1}{6 (1+\tanh (x))}-\frac{2}{3} \operatorname{Subst}\left (\int \frac{1}{-3-x^2} \, dx,x,-1+2 \tanh (x)\right )\\ &=\frac{x}{2}-\frac{2 \tan ^{-1}\left (\frac{1-2 \tanh (x)}{\sqrt{3}}\right )}{3 \sqrt{3}}-\frac{1}{6 (1+\tanh (x))}\\ \end{align*}

Mathematica [A]  time = 0.0956132, size = 40, normalized size = 1.05 \[ \frac{1}{36} \left (18 x+3 \sinh (2 x)-3 \cosh (2 x)+8 \sqrt{3} \tan ^{-1}\left (\frac{2 \tanh (x)-1}{\sqrt{3}}\right )\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[Cosh[x]^3/(Cosh[x]^3 + Sinh[x]^3),x]

[Out]

(18*x + 8*Sqrt[3]*ArcTan[(-1 + 2*Tanh[x])/Sqrt[3]] - 3*Cosh[2*x] + 3*Sinh[2*x])/36

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Maple [C]  time = 0.062, size = 96, normalized size = 2.5 \begin{align*} -{\frac{1}{3} \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) ^{-2}}+{\frac{1}{3} \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) ^{-1}}+{\frac{1}{2}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) }+{\frac{i}{9}}\sqrt{3}\ln \left ( \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{2}+ \left ( -i\sqrt{3}-1 \right ) \tanh \left ({\frac{x}{2}} \right ) +1 \right ) -{\frac{i}{9}}\sqrt{3}\ln \left ( \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{2}+ \left ( i\sqrt{3}-1 \right ) \tanh \left ({\frac{x}{2}} \right ) +1 \right ) -{\frac{1}{2}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) } \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cosh(x)^3/(cosh(x)^3+sinh(x)^3),x)

[Out]

-1/3/(tanh(1/2*x)+1)^2+1/3/(tanh(1/2*x)+1)+1/2*ln(tanh(1/2*x)+1)+1/9*I*3^(1/2)*ln(tanh(1/2*x)^2+(-I*3^(1/2)-1)
*tanh(1/2*x)+1)-1/9*I*3^(1/2)*ln(tanh(1/2*x)^2+(I*3^(1/2)-1)*tanh(1/2*x)+1)-1/2*ln(tanh(1/2*x)-1)

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Maxima [B]  time = 1.63032, size = 99, normalized size = 2.61 \begin{align*} \frac{2}{9} \, \sqrt{3} \arctan \left (\frac{1}{6} \cdot 3^{\frac{3}{4}} \sqrt{2}{\left (2 \, \sqrt{3} e^{\left (-x\right )} + 3^{\frac{1}{4}} \sqrt{2}\right )}\right ) - \frac{2}{9} \, \sqrt{3} \arctan \left (\frac{1}{6} \cdot 3^{\frac{3}{4}} \sqrt{2}{\left (2 \, \sqrt{3} e^{\left (-x\right )} - 3^{\frac{1}{4}} \sqrt{2}\right )}\right ) + \frac{1}{2} \, x - \frac{1}{12} \, e^{\left (-2 \, x\right )} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cosh(x)^3/(cosh(x)^3+sinh(x)^3),x, algorithm="maxima")

[Out]

2/9*sqrt(3)*arctan(1/6*3^(3/4)*sqrt(2)*(2*sqrt(3)*e^(-x) + 3^(1/4)*sqrt(2))) - 2/9*sqrt(3)*arctan(1/6*3^(3/4)*
sqrt(2)*(2*sqrt(3)*e^(-x) - 3^(1/4)*sqrt(2))) + 1/2*x - 1/12*e^(-2*x)

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Fricas [B]  time = 2.03123, size = 340, normalized size = 8.95 \begin{align*} \frac{18 \, x \cosh \left (x\right )^{2} + 36 \, x \cosh \left (x\right ) \sinh \left (x\right ) + 18 \, x \sinh \left (x\right )^{2} - 8 \,{\left (\sqrt{3} \cosh \left (x\right )^{2} + 2 \, \sqrt{3} \cosh \left (x\right ) \sinh \left (x\right ) + \sqrt{3} \sinh \left (x\right )^{2}\right )} \arctan \left (-\frac{\sqrt{3} \cosh \left (x\right ) + \sqrt{3} \sinh \left (x\right )}{3 \,{\left (\cosh \left (x\right ) - \sinh \left (x\right )\right )}}\right ) - 3}{36 \,{\left (\cosh \left (x\right )^{2} + 2 \, \cosh \left (x\right ) \sinh \left (x\right ) + \sinh \left (x\right )^{2}\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cosh(x)^3/(cosh(x)^3+sinh(x)^3),x, algorithm="fricas")

[Out]

1/36*(18*x*cosh(x)^2 + 36*x*cosh(x)*sinh(x) + 18*x*sinh(x)^2 - 8*(sqrt(3)*cosh(x)^2 + 2*sqrt(3)*cosh(x)*sinh(x
) + sqrt(3)*sinh(x)^2)*arctan(-1/3*(sqrt(3)*cosh(x) + sqrt(3)*sinh(x))/(cosh(x) - sinh(x))) - 3)/(cosh(x)^2 +
2*cosh(x)*sinh(x) + sinh(x)^2)

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Sympy [B]  time = 2.50059, size = 136, normalized size = 3.58 \begin{align*} \frac{9 x \sinh{\left (x \right )}}{18 \sinh{\left (x \right )} + 18 \cosh{\left (x \right )}} + \frac{9 x \cosh{\left (x \right )}}{18 \sinh{\left (x \right )} + 18 \cosh{\left (x \right )}} + \frac{4 \sqrt{3} \sinh{\left (x \right )} \operatorname{atan}{\left (\frac{2 \sqrt{3} \sinh{\left (x \right )}}{3 \cosh{\left (x \right )}} - \frac{\sqrt{3}}{3} \right )}}{18 \sinh{\left (x \right )} + 18 \cosh{\left (x \right )}} + \frac{4 \sqrt{3} \cosh{\left (x \right )} \operatorname{atan}{\left (\frac{2 \sqrt{3} \sinh{\left (x \right )}}{3 \cosh{\left (x \right )}} - \frac{\sqrt{3}}{3} \right )}}{18 \sinh{\left (x \right )} + 18 \cosh{\left (x \right )}} - \frac{3 \cosh{\left (x \right )}}{18 \sinh{\left (x \right )} + 18 \cosh{\left (x \right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cosh(x)**3/(cosh(x)**3+sinh(x)**3),x)

[Out]

9*x*sinh(x)/(18*sinh(x) + 18*cosh(x)) + 9*x*cosh(x)/(18*sinh(x) + 18*cosh(x)) + 4*sqrt(3)*sinh(x)*atan(2*sqrt(
3)*sinh(x)/(3*cosh(x)) - sqrt(3)/3)/(18*sinh(x) + 18*cosh(x)) + 4*sqrt(3)*cosh(x)*atan(2*sqrt(3)*sinh(x)/(3*co
sh(x)) - sqrt(3)/3)/(18*sinh(x) + 18*cosh(x)) - 3*cosh(x)/(18*sinh(x) + 18*cosh(x))

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Giac [A]  time = 1.11437, size = 45, normalized size = 1.18 \begin{align*} -\frac{1}{12} \,{\left (3 \, e^{\left (2 \, x\right )} + 1\right )} e^{\left (-2 \, x\right )} + \frac{2}{9} \, \sqrt{3} \arctan \left (\frac{1}{3} \, \sqrt{3} e^{\left (2 \, x\right )}\right ) + \frac{1}{2} \, x \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cosh(x)^3/(cosh(x)^3+sinh(x)^3),x, algorithm="giac")

[Out]

-1/12*(3*e^(2*x) + 1)*e^(-2*x) + 2/9*sqrt(3)*arctan(1/3*sqrt(3)*e^(2*x)) + 1/2*x