Optimal. Leaf size=243 \[ -\frac{3 \sqrt [3]{\cosh (a+b x)}}{b \sqrt [3]{\sinh (a+b x)}}-\frac{\log \left (\frac{\sinh ^{\frac{2}{3}}(a+b x)}{\cosh ^{\frac{2}{3}}(a+b x)}-\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}+1\right )}{4 b}+\frac{\log \left (\frac{\sinh ^{\frac{2}{3}}(a+b x)}{\cosh ^{\frac{2}{3}}(a+b x)}+\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}+1\right )}{4 b}+\frac{\sqrt{3} \tan ^{-1}\left (\frac{1-\frac{2 \sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}}{\sqrt{3}}\right )}{2 b}-\frac{\sqrt{3} \tan ^{-1}\left (\frac{\frac{2 \sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}+1}{\sqrt{3}}\right )}{2 b}+\frac{\tanh ^{-1}\left (\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}\right )}{b} \]
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Rubi [A] time = 0.235853, antiderivative size = 243, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 8, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.381, Rules used = {2567, 2574, 296, 634, 618, 204, 628, 206} \[ -\frac{3 \sqrt [3]{\cosh (a+b x)}}{b \sqrt [3]{\sinh (a+b x)}}-\frac{\log \left (\frac{\sinh ^{\frac{2}{3}}(a+b x)}{\cosh ^{\frac{2}{3}}(a+b x)}-\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}+1\right )}{4 b}+\frac{\log \left (\frac{\sinh ^{\frac{2}{3}}(a+b x)}{\cosh ^{\frac{2}{3}}(a+b x)}+\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}+1\right )}{4 b}+\frac{\sqrt{3} \tan ^{-1}\left (\frac{1-\frac{2 \sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}}{\sqrt{3}}\right )}{2 b}-\frac{\sqrt{3} \tan ^{-1}\left (\frac{\frac{2 \sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}+1}{\sqrt{3}}\right )}{2 b}+\frac{\tanh ^{-1}\left (\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}\right )}{b} \]
Antiderivative was successfully verified.
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Rule 2567
Rule 2574
Rule 296
Rule 634
Rule 618
Rule 204
Rule 628
Rule 206
Rubi steps
\begin{align*} \int \frac{\cosh ^{\frac{4}{3}}(a+b x)}{\sinh ^{\frac{4}{3}}(a+b x)} \, dx &=-\frac{3 \sqrt [3]{\cosh (a+b x)}}{b \sqrt [3]{\sinh (a+b x)}}+\int \frac{\sinh ^{\frac{2}{3}}(a+b x)}{\cosh ^{\frac{2}{3}}(a+b x)} \, dx\\ &=-\frac{3 \sqrt [3]{\cosh (a+b x)}}{b \sqrt [3]{\sinh (a+b x)}}-\frac{3 \operatorname{Subst}\left (\int \frac{x^4}{-1+x^6} \, dx,x,\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}\right )}{b}\\ &=-\frac{3 \sqrt [3]{\cosh (a+b x)}}{b \sqrt [3]{\sinh (a+b x)}}+\frac{\operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}\right )}{b}+\frac{\operatorname{Subst}\left (\int \frac{-\frac{1}{2}-\frac{x}{2}}{1-x+x^2} \, dx,x,\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}\right )}{b}+\frac{\operatorname{Subst}\left (\int \frac{-\frac{1}{2}+\frac{x}{2}}{1+x+x^2} \, dx,x,\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}\right )}{b}\\ &=\frac{\tanh ^{-1}\left (\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}\right )}{b}-\frac{3 \sqrt [3]{\cosh (a+b x)}}{b \sqrt [3]{\sinh (a+b x)}}-\frac{\operatorname{Subst}\left (\int \frac{-1+2 x}{1-x+x^2} \, dx,x,\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}\right )}{4 b}+\frac{\operatorname{Subst}\left (\int \frac{1+2 x}{1+x+x^2} \, dx,x,\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}\right )}{4 b}-\frac{3 \operatorname{Subst}\left (\int \frac{1}{1-x+x^2} \, dx,x,\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}\right )}{4 b}-\frac{3 \operatorname{Subst}\left (\int \frac{1}{1+x+x^2} \, dx,x,\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}\right )}{4 b}\\ &=\frac{\tanh ^{-1}\left (\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}\right )}{b}-\frac{\log \left (1-\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}+\frac{\sinh ^{\frac{2}{3}}(a+b x)}{\cosh ^{\frac{2}{3}}(a+b x)}\right )}{4 b}+\frac{\log \left (1+\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}+\frac{\sinh ^{\frac{2}{3}}(a+b x)}{\cosh ^{\frac{2}{3}}(a+b x)}\right )}{4 b}-\frac{3 \sqrt [3]{\cosh (a+b x)}}{b \sqrt [3]{\sinh (a+b x)}}+\frac{3 \operatorname{Subst}\left (\int \frac{1}{-3-x^2} \, dx,x,-1+\frac{2 \sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}\right )}{2 b}+\frac{3 \operatorname{Subst}\left (\int \frac{1}{-3-x^2} \, dx,x,1+\frac{2 \sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}\right )}{2 b}\\ &=\frac{\sqrt{3} \tan ^{-1}\left (\frac{1-\frac{2 \sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}}{\sqrt{3}}\right )}{2 b}-\frac{\sqrt{3} \tan ^{-1}\left (\frac{1+\frac{2 \sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}}{\sqrt{3}}\right )}{2 b}+\frac{\tanh ^{-1}\left (\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}\right )}{b}-\frac{\log \left (1-\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}+\frac{\sinh ^{\frac{2}{3}}(a+b x)}{\cosh ^{\frac{2}{3}}(a+b x)}\right )}{4 b}+\frac{\log \left (1+\frac{\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}+\frac{\sinh ^{\frac{2}{3}}(a+b x)}{\cosh ^{\frac{2}{3}}(a+b x)}\right )}{4 b}-\frac{3 \sqrt [3]{\cosh (a+b x)}}{b \sqrt [3]{\sinh (a+b x)}}\\ \end{align*}
Mathematica [C] time = 0.0283752, size = 57, normalized size = 0.23 \[ -\frac{3 \cosh ^2(a+b x)^{5/6} \, _2F_1\left (-\frac{1}{6},-\frac{1}{6};\frac{5}{6};-\sinh ^2(a+b x)\right )}{b \sqrt [3]{\sinh (a+b x)} \cosh ^{\frac{5}{3}}(a+b x)} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.038, size = 0, normalized size = 0. \begin{align*} \int{ \left ( \cosh \left ( bx+a \right ) \right ) ^{{\frac{4}{3}}} \left ( \sinh \left ( bx+a \right ) \right ) ^{-{\frac{4}{3}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cosh \left (b x + a\right )^{\frac{4}{3}}}{\sinh \left (b x + a\right )^{\frac{4}{3}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.13265, size = 3081, normalized size = 12.68 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cosh \left (b x + a\right )^{\frac{4}{3}}}{\sinh \left (b x + a\right )^{\frac{4}{3}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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