Optimal. Leaf size=103 \[ \frac{2}{5} (a \sinh (x)+b \cosh (x)) (a \cosh (x)+b \sinh (x))^{3/2}-\frac{6 i \left (a^2-b^2\right ) \sqrt{a \cosh (x)+b \sinh (x)} E\left (\left .\frac{1}{2} \left (i x-\tan ^{-1}(a,-i b)\right )\right |2\right )}{5 \sqrt{\frac{a \cosh (x)+b \sinh (x)}{\sqrt{a^2-b^2}}}} \]
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Rubi [A] time = 0.0501036, antiderivative size = 103, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.231, Rules used = {3073, 3078, 2639} \[ \frac{2}{5} (a \sinh (x)+b \cosh (x)) (a \cosh (x)+b \sinh (x))^{3/2}-\frac{6 i \left (a^2-b^2\right ) \sqrt{a \cosh (x)+b \sinh (x)} E\left (\left .\frac{1}{2} \left (i x-\tan ^{-1}(a,-i b)\right )\right |2\right )}{5 \sqrt{\frac{a \cosh (x)+b \sinh (x)}{\sqrt{a^2-b^2}}}} \]
Antiderivative was successfully verified.
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Rule 3073
Rule 3078
Rule 2639
Rubi steps
\begin{align*} \int (a \cosh (x)+b \sinh (x))^{5/2} \, dx &=\frac{2}{5} (b \cosh (x)+a \sinh (x)) (a \cosh (x)+b \sinh (x))^{3/2}+\frac{1}{5} \left (3 \left (a^2-b^2\right )\right ) \int \sqrt{a \cosh (x)+b \sinh (x)} \, dx\\ &=\frac{2}{5} (b \cosh (x)+a \sinh (x)) (a \cosh (x)+b \sinh (x))^{3/2}+\frac{\left (3 \left (a^2-b^2\right ) \sqrt{a \cosh (x)+b \sinh (x)}\right ) \int \sqrt{\cosh \left (x+i \tan ^{-1}(a,-i b)\right )} \, dx}{5 \sqrt{\frac{a \cosh (x)+b \sinh (x)}{\sqrt{a^2-b^2}}}}\\ &=\frac{2}{5} (b \cosh (x)+a \sinh (x)) (a \cosh (x)+b \sinh (x))^{3/2}-\frac{6 i \left (a^2-b^2\right ) E\left (\left .\frac{1}{2} \left (i x-\tan ^{-1}(a,-i b)\right )\right |2\right ) \sqrt{a \cosh (x)+b \sinh (x)}}{5 \sqrt{\frac{a \cosh (x)+b \sinh (x)}{\sqrt{a^2-b^2}}}}\\ \end{align*}
Mathematica [C] time = 0.813822, size = 193, normalized size = 1.87 \[ \frac{(a \cosh (x)+b \sinh (x)) \left (b \left (a^2+b^2\right ) \sinh (2 x)+6 a \left (a^2-b^2\right )+2 a b^2 \cosh (2 x)\right )-\frac{3 (a-b)^2 (a+b)^2 \left (b \sinh \left (\tanh ^{-1}\left (\frac{b}{a}\right )+x\right ) \text{HypergeometricPFQ}\left (\left \{-\frac{1}{2},-\frac{1}{4}\right \},\left \{\frac{3}{4}\right \},\cosh ^2\left (\tanh ^{-1}\left (\frac{b}{a}\right )+x\right )\right )+\sqrt{-\sinh ^2\left (\tanh ^{-1}\left (\frac{b}{a}\right )+x\right )} \left (2 a \cosh \left (\tanh ^{-1}\left (\frac{b}{a}\right )+x\right )-b \sinh \left (\tanh ^{-1}\left (\frac{b}{a}\right )+x\right )\right )\right )}{a \sqrt{1-\frac{b^2}{a^2}} \sqrt{-\sinh ^2\left (\tanh ^{-1}\left (\frac{b}{a}\right )+x\right )}}}{5 b \sqrt{a \cosh (x)+b \sinh (x)}} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.152, size = 51, normalized size = 0.5 \begin{align*}{ \left ( -{\frac{ \left ( \cosh \left ( x \right ) \right ) ^{3}}{3} \left ({a}^{2}-{b}^{2} \right ) ^{{\frac{3}{2}}}}+ \left ({a}^{2}-{b}^{2} \right ) ^{{\frac{3}{2}}}\cosh \left ( x \right ) \right ){\frac{1}{\sqrt{-\sinh \left ( x \right ) \sqrt{{a}^{2}-{b}^{2}}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (a \cosh \left (x\right ) + b \sinh \left (x\right )\right )}^{\frac{5}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (a^{2} \cosh \left (x\right )^{2} + 2 \, a b \cosh \left (x\right ) \sinh \left (x\right ) + b^{2} \sinh \left (x\right )^{2}\right )} \sqrt{a \cosh \left (x\right ) + b \sinh \left (x\right )}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (a \cosh \left (x\right ) + b \sinh \left (x\right )\right )}^{\frac{5}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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