Optimal. Leaf size=123 \[ -\frac{x \text{PolyLog}\left (2,-e^{a+b x}\right )}{b^2}+\frac{x \text{PolyLog}\left (2,e^{a+b x}\right )}{b^2}+\frac{\text{PolyLog}\left (3,-e^{a+b x}\right )}{b^3}-\frac{\text{PolyLog}\left (3,e^{a+b x}\right )}{b^3}-\frac{x \text{csch}(a+b x)}{b^2}-\frac{\tanh ^{-1}(\cosh (a+b x))}{b^3}-\frac{x^2 \tanh ^{-1}\left (e^{a+b x}\right )}{b}-\frac{x^2 \coth (a+b x) \text{csch}(a+b x)}{2 b} \]
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Rubi [A] time = 0.235502, antiderivative size = 123, normalized size of antiderivative = 1., number of steps used = 17, number of rules used = 7, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.389, Rules used = {5457, 4182, 2531, 2282, 6589, 4186, 3770} \[ -\frac{x \text{PolyLog}\left (2,-e^{a+b x}\right )}{b^2}+\frac{x \text{PolyLog}\left (2,e^{a+b x}\right )}{b^2}+\frac{\text{PolyLog}\left (3,-e^{a+b x}\right )}{b^3}-\frac{\text{PolyLog}\left (3,e^{a+b x}\right )}{b^3}-\frac{x \text{csch}(a+b x)}{b^2}-\frac{\tanh ^{-1}(\cosh (a+b x))}{b^3}-\frac{x^2 \tanh ^{-1}\left (e^{a+b x}\right )}{b}-\frac{x^2 \coth (a+b x) \text{csch}(a+b x)}{2 b} \]
Antiderivative was successfully verified.
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Rule 5457
Rule 4182
Rule 2531
Rule 2282
Rule 6589
Rule 4186
Rule 3770
Rubi steps
\begin{align*} \int x^2 \coth ^2(a+b x) \text{csch}(a+b x) \, dx &=\int x^2 \text{csch}(a+b x) \, dx+\int x^2 \text{csch}^3(a+b x) \, dx\\ &=-\frac{2 x^2 \tanh ^{-1}\left (e^{a+b x}\right )}{b}-\frac{x \text{csch}(a+b x)}{b^2}-\frac{x^2 \coth (a+b x) \text{csch}(a+b x)}{2 b}-\frac{1}{2} \int x^2 \text{csch}(a+b x) \, dx+\frac{\int \text{csch}(a+b x) \, dx}{b^2}-\frac{2 \int x \log \left (1-e^{a+b x}\right ) \, dx}{b}+\frac{2 \int x \log \left (1+e^{a+b x}\right ) \, dx}{b}\\ &=-\frac{x^2 \tanh ^{-1}\left (e^{a+b x}\right )}{b}-\frac{\tanh ^{-1}(\cosh (a+b x))}{b^3}-\frac{x \text{csch}(a+b x)}{b^2}-\frac{x^2 \coth (a+b x) \text{csch}(a+b x)}{2 b}-\frac{2 x \text{Li}_2\left (-e^{a+b x}\right )}{b^2}+\frac{2 x \text{Li}_2\left (e^{a+b x}\right )}{b^2}+\frac{2 \int \text{Li}_2\left (-e^{a+b x}\right ) \, dx}{b^2}-\frac{2 \int \text{Li}_2\left (e^{a+b x}\right ) \, dx}{b^2}+\frac{\int x \log \left (1-e^{a+b x}\right ) \, dx}{b}-\frac{\int x \log \left (1+e^{a+b x}\right ) \, dx}{b}\\ &=-\frac{x^2 \tanh ^{-1}\left (e^{a+b x}\right )}{b}-\frac{\tanh ^{-1}(\cosh (a+b x))}{b^3}-\frac{x \text{csch}(a+b x)}{b^2}-\frac{x^2 \coth (a+b x) \text{csch}(a+b x)}{2 b}-\frac{x \text{Li}_2\left (-e^{a+b x}\right )}{b^2}+\frac{x \text{Li}_2\left (e^{a+b x}\right )}{b^2}+\frac{2 \operatorname{Subst}\left (\int \frac{\text{Li}_2(-x)}{x} \, dx,x,e^{a+b x}\right )}{b^3}-\frac{2 \operatorname{Subst}\left (\int \frac{\text{Li}_2(x)}{x} \, dx,x,e^{a+b x}\right )}{b^3}-\frac{\int \text{Li}_2\left (-e^{a+b x}\right ) \, dx}{b^2}+\frac{\int \text{Li}_2\left (e^{a+b x}\right ) \, dx}{b^2}\\ &=-\frac{x^2 \tanh ^{-1}\left (e^{a+b x}\right )}{b}-\frac{\tanh ^{-1}(\cosh (a+b x))}{b^3}-\frac{x \text{csch}(a+b x)}{b^2}-\frac{x^2 \coth (a+b x) \text{csch}(a+b x)}{2 b}-\frac{x \text{Li}_2\left (-e^{a+b x}\right )}{b^2}+\frac{x \text{Li}_2\left (e^{a+b x}\right )}{b^2}+\frac{2 \text{Li}_3\left (-e^{a+b x}\right )}{b^3}-\frac{2 \text{Li}_3\left (e^{a+b x}\right )}{b^3}-\frac{\operatorname{Subst}\left (\int \frac{\text{Li}_2(-x)}{x} \, dx,x,e^{a+b x}\right )}{b^3}+\frac{\operatorname{Subst}\left (\int \frac{\text{Li}_2(x)}{x} \, dx,x,e^{a+b x}\right )}{b^3}\\ &=-\frac{x^2 \tanh ^{-1}\left (e^{a+b x}\right )}{b}-\frac{\tanh ^{-1}(\cosh (a+b x))}{b^3}-\frac{x \text{csch}(a+b x)}{b^2}-\frac{x^2 \coth (a+b x) \text{csch}(a+b x)}{2 b}-\frac{x \text{Li}_2\left (-e^{a+b x}\right )}{b^2}+\frac{x \text{Li}_2\left (e^{a+b x}\right )}{b^2}+\frac{\text{Li}_3\left (-e^{a+b x}\right )}{b^3}-\frac{\text{Li}_3\left (e^{a+b x}\right )}{b^3}\\ \end{align*}
Mathematica [A] time = 4.16194, size = 222, normalized size = 1.8 \[ -\frac{8 b x \text{PolyLog}\left (2,-e^{a+b x}\right )-8 b x \text{PolyLog}\left (2,e^{a+b x}\right )-8 \text{PolyLog}\left (3,-e^{a+b x}\right )+8 \text{PolyLog}\left (3,e^{a+b x}\right )-4 b^2 x^2 \log \left (1-e^{a+b x}\right )+4 b^2 x^2 \log \left (e^{a+b x}+1\right )+b^2 x^2 \text{csch}^2\left (\frac{1}{2} (a+b x)\right )+b^2 x^2 \text{sech}^2\left (\frac{1}{2} (a+b x)\right )-8 \log \left (1-e^{a+b x}\right )+8 \log \left (e^{a+b x}+1\right )+8 b x \text{csch}(a)-4 b x \text{csch}\left (\frac{a}{2}\right ) \sinh \left (\frac{b x}{2}\right ) \text{csch}\left (\frac{1}{2} (a+b x)\right )-4 b x \text{sech}\left (\frac{a}{2}\right ) \sinh \left (\frac{b x}{2}\right ) \text{sech}\left (\frac{1}{2} (a+b x)\right )}{8 b^3} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.072, size = 210, normalized size = 1.7 \begin{align*} -{\frac{x{{\rm e}^{bx+a}} \left ( bx{{\rm e}^{2\,bx+2\,a}}+bx+2\,{{\rm e}^{2\,bx+2\,a}}-2 \right ) }{{b}^{2} \left ({{\rm e}^{2\,bx+2\,a}}-1 \right ) ^{2}}}-{\frac{{a}^{2}{\it Artanh} \left ({{\rm e}^{bx+a}} \right ) }{{b}^{3}}}-{\frac{\ln \left ( 1+{{\rm e}^{bx+a}} \right ){x}^{2}}{2\,b}}+{\frac{{a}^{2}\ln \left ( 1+{{\rm e}^{bx+a}} \right ) }{2\,{b}^{3}}}-{\frac{x{\it polylog} \left ( 2,-{{\rm e}^{bx+a}} \right ) }{{b}^{2}}}+{\frac{{\it polylog} \left ( 3,-{{\rm e}^{bx+a}} \right ) }{{b}^{3}}}+{\frac{\ln \left ( 1-{{\rm e}^{bx+a}} \right ){x}^{2}}{2\,b}}-{\frac{\ln \left ( 1-{{\rm e}^{bx+a}} \right ){a}^{2}}{2\,{b}^{3}}}+{\frac{x{\it polylog} \left ( 2,{{\rm e}^{bx+a}} \right ) }{{b}^{2}}}-{\frac{{\it polylog} \left ( 3,{{\rm e}^{bx+a}} \right ) }{{b}^{3}}}-2\,{\frac{{\it Artanh} \left ({{\rm e}^{bx+a}} \right ) }{{b}^{3}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.59088, size = 266, normalized size = 2.16 \begin{align*} -\frac{{\left (b x^{2} e^{\left (3 \, a\right )} + 2 \, x e^{\left (3 \, a\right )}\right )} e^{\left (3 \, b x\right )} +{\left (b x^{2} e^{a} - 2 \, x e^{a}\right )} e^{\left (b x\right )}}{b^{2} e^{\left (4 \, b x + 4 \, a\right )} - 2 \, b^{2} e^{\left (2 \, b x + 2 \, a\right )} + b^{2}} - \frac{b^{2} x^{2} \log \left (e^{\left (b x + a\right )} + 1\right ) + 2 \, b x{\rm Li}_2\left (-e^{\left (b x + a\right )}\right ) - 2 \,{\rm Li}_{3}(-e^{\left (b x + a\right )})}{2 \, b^{3}} + \frac{b^{2} x^{2} \log \left (-e^{\left (b x + a\right )} + 1\right ) + 2 \, b x{\rm Li}_2\left (e^{\left (b x + a\right )}\right ) - 2 \,{\rm Li}_{3}(e^{\left (b x + a\right )})}{2 \, b^{3}} - \frac{\log \left (e^{\left (b x + a\right )} + 1\right )}{b^{3}} + \frac{\log \left (e^{\left (b x + a\right )} - 1\right )}{b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] time = 2.57823, size = 3370, normalized size = 27.4 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{2} \cosh \left (b x + a\right )^{2} \operatorname{csch}\left (b x + a\right )^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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