3.280 \(\int x^m \cosh (a+b x) \sinh ^2(a+b x) \, dx\)

Optimal. Leaf size=134 \[ \frac{e^{3 a} 3^{-m-1} x^m (-b x)^{-m} \text{Gamma}(m+1,-3 b x)}{8 b}-\frac{e^a x^m (-b x)^{-m} \text{Gamma}(m+1,-b x)}{8 b}+\frac{e^{-a} x^m (b x)^{-m} \text{Gamma}(m+1,b x)}{8 b}-\frac{e^{-3 a} 3^{-m-1} x^m (b x)^{-m} \text{Gamma}(m+1,3 b x)}{8 b} \]

[Out]

(3^(-1 - m)*E^(3*a)*x^m*Gamma[1 + m, -3*b*x])/(8*b*(-(b*x))^m) - (E^a*x^m*Gamma[1 + m, -(b*x)])/(8*b*(-(b*x))^
m) + (x^m*Gamma[1 + m, b*x])/(8*b*E^a*(b*x)^m) - (3^(-1 - m)*x^m*Gamma[1 + m, 3*b*x])/(8*b*E^(3*a)*(b*x)^m)

________________________________________________________________________________________

Rubi [A]  time = 0.183457, antiderivative size = 134, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 3, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.167, Rules used = {5448, 3307, 2181} \[ \frac{e^{3 a} 3^{-m-1} x^m (-b x)^{-m} \text{Gamma}(m+1,-3 b x)}{8 b}-\frac{e^a x^m (-b x)^{-m} \text{Gamma}(m+1,-b x)}{8 b}+\frac{e^{-a} x^m (b x)^{-m} \text{Gamma}(m+1,b x)}{8 b}-\frac{e^{-3 a} 3^{-m-1} x^m (b x)^{-m} \text{Gamma}(m+1,3 b x)}{8 b} \]

Antiderivative was successfully verified.

[In]

Int[x^m*Cosh[a + b*x]*Sinh[a + b*x]^2,x]

[Out]

(3^(-1 - m)*E^(3*a)*x^m*Gamma[1 + m, -3*b*x])/(8*b*(-(b*x))^m) - (E^a*x^m*Gamma[1 + m, -(b*x)])/(8*b*(-(b*x))^
m) + (x^m*Gamma[1 + m, b*x])/(8*b*E^a*(b*x)^m) - (3^(-1 - m)*x^m*Gamma[1 + m, 3*b*x])/(8*b*E^(3*a)*(b*x)^m)

Rule 5448

Int[Cosh[(a_.) + (b_.)*(x_)]^(p_.)*((c_.) + (d_.)*(x_))^(m_.)*Sinh[(a_.) + (b_.)*(x_)]^(n_.), x_Symbol] :> Int
[ExpandTrigReduce[(c + d*x)^m, Sinh[a + b*x]^n*Cosh[a + b*x]^p, x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n,
 0] && IGtQ[p, 0]

Rule 3307

Int[((c_.) + (d_.)*(x_))^(m_.)*sin[(e_.) + Pi*(k_.) + (f_.)*(x_)], x_Symbol] :> Dist[I/2, Int[(c + d*x)^m/(E^(
I*k*Pi)*E^(I*(e + f*x))), x], x] - Dist[I/2, Int[(c + d*x)^m*E^(I*k*Pi)*E^(I*(e + f*x)), x], x] /; FreeQ[{c, d
, e, f, m}, x] && IntegerQ[2*k]

Rule 2181

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))*((c_.) + (d_.)*(x_))^(m_), x_Symbol] :> -Simp[(F^(g*(e - (c*f)/d))*(c +
d*x)^FracPart[m]*Gamma[m + 1, (-((f*g*Log[F])/d))*(c + d*x)])/(d*(-((f*g*Log[F])/d))^(IntPart[m] + 1)*(-((f*g*
Log[F]*(c + d*x))/d))^FracPart[m]), x] /; FreeQ[{F, c, d, e, f, g, m}, x] &&  !IntegerQ[m]

Rubi steps

\begin{align*} \int x^m \cosh (a+b x) \sinh ^2(a+b x) \, dx &=\int \left (-\frac{1}{4} x^m \cosh (a+b x)+\frac{1}{4} x^m \cosh (3 a+3 b x)\right ) \, dx\\ &=-\left (\frac{1}{4} \int x^m \cosh (a+b x) \, dx\right )+\frac{1}{4} \int x^m \cosh (3 a+3 b x) \, dx\\ &=-\left (\frac{1}{8} \int e^{-i (i a+i b x)} x^m \, dx\right )-\frac{1}{8} \int e^{i (i a+i b x)} x^m \, dx+\frac{1}{8} \int e^{-i (3 i a+3 i b x)} x^m \, dx+\frac{1}{8} \int e^{i (3 i a+3 i b x)} x^m \, dx\\ &=\frac{3^{-1-m} e^{3 a} x^m (-b x)^{-m} \Gamma (1+m,-3 b x)}{8 b}-\frac{e^a x^m (-b x)^{-m} \Gamma (1+m,-b x)}{8 b}+\frac{e^{-a} x^m (b x)^{-m} \Gamma (1+m,b x)}{8 b}-\frac{3^{-1-m} e^{-3 a} x^m (b x)^{-m} \Gamma (1+m,3 b x)}{8 b}\\ \end{align*}

Mathematica [A]  time = 0.226951, size = 114, normalized size = 0.85 \[ \frac{e^{-3 a} x^m \left (3^{-m} \left (-b^2 x^2\right )^{-m} \left (e^{6 a} (b x)^m \text{Gamma}(m+1,-3 b x)-(-b x)^m \text{Gamma}(m+1,3 b x)\right )-3 e^{4 a} (-b x)^{-m} \text{Gamma}(m+1,-b x)+3 e^{2 a} (b x)^{-m} \text{Gamma}(m+1,b x)\right )}{24 b} \]

Antiderivative was successfully verified.

[In]

Integrate[x^m*Cosh[a + b*x]*Sinh[a + b*x]^2,x]

[Out]

(x^m*((-3*E^(4*a)*Gamma[1 + m, -(b*x)])/(-(b*x))^m + (3*E^(2*a)*Gamma[1 + m, b*x])/(b*x)^m + (E^(6*a)*(b*x)^m*
Gamma[1 + m, -3*b*x] - (-(b*x))^m*Gamma[1 + m, 3*b*x])/(3^m*(-(b^2*x^2))^m)))/(24*b*E^(3*a))

________________________________________________________________________________________

Maple [F]  time = 0.089, size = 0, normalized size = 0. \begin{align*} \int{x}^{m}\cosh \left ( bx+a \right ) \left ( \sinh \left ( bx+a \right ) \right ) ^{2}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^m*cosh(b*x+a)*sinh(b*x+a)^2,x)

[Out]

int(x^m*cosh(b*x+a)*sinh(b*x+a)^2,x)

________________________________________________________________________________________

Maxima [A]  time = 1.36379, size = 153, normalized size = 1.14 \begin{align*} -\frac{1}{8} \, \left (3 \, b x\right )^{-m - 1} x^{m + 1} e^{\left (-3 \, a\right )} \Gamma \left (m + 1, 3 \, b x\right ) + \frac{1}{8} \, \left (b x\right )^{-m - 1} x^{m + 1} e^{\left (-a\right )} \Gamma \left (m + 1, b x\right ) + \frac{1}{8} \, \left (-b x\right )^{-m - 1} x^{m + 1} e^{a} \Gamma \left (m + 1, -b x\right ) - \frac{1}{8} \, \left (-3 \, b x\right )^{-m - 1} x^{m + 1} e^{\left (3 \, a\right )} \Gamma \left (m + 1, -3 \, b x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^m*cosh(b*x+a)*sinh(b*x+a)^2,x, algorithm="maxima")

[Out]

-1/8*(3*b*x)^(-m - 1)*x^(m + 1)*e^(-3*a)*gamma(m + 1, 3*b*x) + 1/8*(b*x)^(-m - 1)*x^(m + 1)*e^(-a)*gamma(m + 1
, b*x) + 1/8*(-b*x)^(-m - 1)*x^(m + 1)*e^a*gamma(m + 1, -b*x) - 1/8*(-3*b*x)^(-m - 1)*x^(m + 1)*e^(3*a)*gamma(
m + 1, -3*b*x)

________________________________________________________________________________________

Fricas [A]  time = 1.95132, size = 487, normalized size = 3.63 \begin{align*} -\frac{\cosh \left (m \log \left (3 \, b\right ) + 3 \, a\right ) \Gamma \left (m + 1, 3 \, b x\right ) - 3 \, \cosh \left (m \log \left (b\right ) + a\right ) \Gamma \left (m + 1, b x\right ) + 3 \, \cosh \left (m \log \left (-b\right ) - a\right ) \Gamma \left (m + 1, -b x\right ) - \cosh \left (m \log \left (-3 \, b\right ) - 3 \, a\right ) \Gamma \left (m + 1, -3 \, b x\right ) - \Gamma \left (m + 1, 3 \, b x\right ) \sinh \left (m \log \left (3 \, b\right ) + 3 \, a\right ) - 3 \, \Gamma \left (m + 1, -b x\right ) \sinh \left (m \log \left (-b\right ) - a\right ) + \Gamma \left (m + 1, -3 \, b x\right ) \sinh \left (m \log \left (-3 \, b\right ) - 3 \, a\right ) + 3 \, \Gamma \left (m + 1, b x\right ) \sinh \left (m \log \left (b\right ) + a\right )}{24 \, b} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^m*cosh(b*x+a)*sinh(b*x+a)^2,x, algorithm="fricas")

[Out]

-1/24*(cosh(m*log(3*b) + 3*a)*gamma(m + 1, 3*b*x) - 3*cosh(m*log(b) + a)*gamma(m + 1, b*x) + 3*cosh(m*log(-b)
- a)*gamma(m + 1, -b*x) - cosh(m*log(-3*b) - 3*a)*gamma(m + 1, -3*b*x) - gamma(m + 1, 3*b*x)*sinh(m*log(3*b) +
 3*a) - 3*gamma(m + 1, -b*x)*sinh(m*log(-b) - a) + gamma(m + 1, -3*b*x)*sinh(m*log(-3*b) - 3*a) + 3*gamma(m +
1, b*x)*sinh(m*log(b) + a))/b

________________________________________________________________________________________

Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{m} \sinh ^{2}{\left (a + b x \right )} \cosh{\left (a + b x \right )}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**m*cosh(b*x+a)*sinh(b*x+a)**2,x)

[Out]

Integral(x**m*sinh(a + b*x)**2*cosh(a + b*x), x)

________________________________________________________________________________________

Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{m} \cosh \left (b x + a\right ) \sinh \left (b x + a\right )^{2}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^m*cosh(b*x+a)*sinh(b*x+a)^2,x, algorithm="giac")

[Out]

integrate(x^m*cosh(b*x + a)*sinh(b*x + a)^2, x)